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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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/ O4 k4 ~, @9 V) N" N$ s不好意思,打错了个字母,呵呵呵!
) {: ^# X/ p/ g, V2 f大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示& ?: l/ U; g2 G0 Z. d
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;, U) W/ K& L' [9 Y
M:string;
3 g2 O- p1 V# |: L: B selecTab:table[integer,integer,integer,string];
+ D/ F4 \( |, M1 b. fdo
. K. m( Q. K2 \1 W5 a4 W2 _' \ initorders;
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scheduledorders.delete;! ^/ s: G G, B$ S2 {: e# M
seletTab.create;
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3 ?5 x( a6 l m; } orders.initialize({2,1}..{2,*},0);* t. q6 Z- P( V* g9 [. m" m
orders.initialize({4,1}..{4,*},0);0 }7 i6 e6 E( w A
for j:=1 to numorders loop! d* y( d# S6 H/ `/ P- z t$ h
orders[5,j]:=orders[1,j][2,1];
8 k# a/ T. @) O' g, O6 I next;
" p z, {5 g& q; S) |( G1 F% C- \7 b occres.initialize({1,1}..{1,*},0);6 [8 d$ I1 @5 S' Q8 W% c
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for scheduledsteps:=1 to numsteps loop --0 K* l. a' K' M- {; m/ \0 e! `
selectab.delete;
], B7 T( w) G& b k:=1;
9 \) O' }' C1 X- q for j:=1 to numorders loop* {5 F7 ]* u4 t: K$ r
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nstep:=orders[2,j]+1;$ ^: J1 t5 Y# I
if nstep<=orders[3,j] then0 M" D) |; f M- j
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];. r7 _! ^6 f' V3 [" e( `* G0 f4 C
k:=k+1;- L1 @% g& l' T+ F' b$ l+ @; r9 M, N: [
) ~, Z0 a+ ^$ K; O; N end;& a* |+ Z3 i5 D( w ]1 v8 C
next;
; X. ]2 R; l0 Q mincomptime:=selecttab.min({3,1}..{3,*});0 w! j# A5 s- l( B; Z
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from j:=1 until j>selectab.ydim loop( m2 q! y7 U+ Y3 v9 `, R0 b; A
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if selectab[2,j]<mincomptime then
7 }; o% H% q+ x: w, k j:=j+1;
; o5 [) A% M E* ]# k; B: ? else! t& o" F" z1 {1 c- [
selecttab.cutrow(j);
& t1 z2 e, j/ t% w7 n" U Y/ ^. H; Q end;" ?, q, B( U' J
end;2 v% r$ ?: N* s( N7 Z
' y# [ w" o% h9 L: \ j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
. h- y# s; J1 H5 G$ Z5 v orders[2,j]:=nstep;7 W0 G0 m) t* W8 a0 S
m:=orders[1,j][1,nstep];; q* D: e `4 A& h) _
c:=orders[5,j]
5 R- X1 @* k8 H$ [: { occres[1,m]:=c;
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# f1 z& c+ m4 E/ f+ [: L --jieguo:start,end,res,job,step8 d: @! O' v1 T0 v) [1 H
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
/ }( E' h+ S9 {+ B- t for k:=1 to numorders loop' ?" N3 D" _, F% z- z1 Q* O. f
nstep:=orders[2,k]+1;
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/ w) j+ ?+ w8 S" y if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then
5 ~8 h X; Y L- o4 m0 B+ i orders[4,k]:=max(c,orders[4,k]);, X/ d' y, e6 H7 ]9 [. d
--
5 h: G6 d: [7 E% R0 F! g1 A6 w orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;2 c" q+ p* o5 P, b9 ^* A5 D
next;' ~8 v: E& l: H5 Q6 V$ |
nstep:=orders[2,j]+1:
' m- J* V, s$ g9 c if nstep<=orders[3,j]
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then
4 p+ s+ z, @3 Y* q: h; U) Z6 S+ M orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
6 Z: J9 X/ V) ]# H orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
! g6 R# \3 j. y5 T r* L5 { end;! L% @& _: x6 D; q7 ?
next;% x, {4 g; k0 G# e' _ G
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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ens;) Q6 ]7 V+ _1 |
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