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本帖最后由 soso001 于 2014-12-17 14:53 编辑 3 T1 {0 M N$ F5 Z: a
5 m, X# y, w! t q不好意思,打错了个字母,呵呵呵!
" i' h9 |" J( C O# s! O. b8 j大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示$ r! U5 ~( z# K3 ] Y3 m
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!# e* a2 m7 \1 H/ U
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j,k,nstep,c, scheduleteps,mincomptime:integer;. {5 a" t3 ]+ _$ D
M:string;2 Q3 w; _. p4 M
selecTab:table[integer,integer,integer,string];6 b6 e X8 h7 _) g0 N
do& a$ e$ M, R/ e/ ~5 H
initorders;7 _# y C3 p6 z. \: z. n8 M
+ o& j! h4 ^& I scheduledorders.delete;
" M8 |* m4 R: N% ~& l seletTab.create;
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3 G6 Y+ P, K: f/ N orders.initialize({2,1}..{2,*},0);
8 p4 |; N u2 z7 `9 s: u orders.initialize({4,1}..{4,*},0);9 \( T. l2 D8 u; Y9 p
for j:=1 to numorders loop
6 T9 O% B/ q& e7 M orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);# p; y, @3 S$ k& f( g) T" F# @
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--XUNHUAN: a* h4 X0 _' X
for scheduledsteps:=1 to numsteps loop --) m7 M) R$ @; V0 q% b
selectab.delete;
6 G5 W0 [9 n0 d' p/ G% o k:=1;1 q% V2 ~" i4 j# U
for j:=1 to numorders loop2 W6 N! q/ p6 y; o; a0 i
/ l, s1 M u) R+ I% w1 R; H nstep:=orders[2,j]+1;* Z) w* X8 f6 s" B) ^" `* q
if nstep<=orders[3,j] then, M a2 B9 R2 m
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];5 x! f+ ~1 w. A- F
k:=k+1;7 }( \/ z `+ j3 r0 u n
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end;
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mincomptime:=selecttab.min({3,1}..{3,*});* y8 J) x$ U. E6 c
+ ^9 O8 `. h+ k' M6 t: w from j:=1 until j>selectab.ydim loop- W. x0 I" {( V# [8 n
3 i# G3 ]1 c& c6 o& P0 X, p if selectab[2,j]<mincomptime then; o! o' b# ?9 M' A: n! S
j:=j+1;
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selecttab.cutrow(j);2 P. } G$ o: e; V3 U
end;
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% M7 b3 Z: T( i) U1 o' O j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;* H9 H* _! N% n' Y
orders[2,j]:=nstep;9 V6 z) h/ r& f# i0 F
m:=orders[1,j][1,nstep];
/ \4 p1 ]+ e' ]. e/ }4 q: Y c:=orders[5,j]0 e$ X0 V; i$ C$ ]4 W1 P' r
occres[1,m]:=c;$ z7 z, R/ W' n& e& J8 T1 I7 N
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--jieguo:start,end,res,job,step, U$ J/ E9 |) B) R, j- u
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
% m# Y! y1 @6 \ for k:=1 to numorders loop* ]* P" F; u& ]# s' x
nstep:=orders[2,k]+1;6 F% }- _' g3 o% p
9 J3 a2 z1 V+ u9 e; |: r if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
- v" I4 S3 ]! t* I- ~ --
( D4 S$ y) u) B& j, K then
: _3 J6 S2 v" n8 u3 @) ] m7 \ orders[4,k]:=max(c,orders[4,k]);2 N6 Z8 b1 I. }/ D/ e6 Y- {
--
) D( p* X! \ b B orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];; W0 U+ `+ g. w" [/ g0 n
--- _) k0 }1 {7 o* b0 O
end;
+ Y8 |) f- {/ f! h& Z' R next;* C/ D, |$ a6 X9 j0 F2 E( }
nstep:=orders[2,j]+1:% J6 w2 j% p) F: D' m$ H$ b
if nstep<=orders[3,j]9 R2 b: {" F) G
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then
; e& R/ K! d( g& L' R# |3 K) ? T orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);) H# b1 |9 j& r" _% c9 \ D
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];1 G; B9 ^& |! O
end;
' S( P: X$ m2 r& b6 D next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
5 i3 M3 l) w5 W3 a+ @+ _ mygantt;
$ T; P/ d* A6 @, `: g ens;
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