本帖最后由 GJM 于 2009-12-5 21:43 编辑 8 S; t. U; m I% D: b/ F
9 K" h: ]& O1 E- n( f底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去. Z9 c! d+ q* S: G
" L J0 c2 L8 ]7 g" T% F不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!: Y' z3 R5 L3 |( Y1 n. a
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begin P_something arriving* l4 ~' f) w9 ^) ]8 f V8 S9 P" n
move into Q_wait6 N8 _2 I; |6 g! \7 V: m
move into nextof(Q_mA,Q_mB,Q_mC)
3 h7 F/ X) g }. A- l( n use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min
X/ ]4 m2 P. B' K send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean)2 x, m# X, V3 G& |6 g; K4 J/ r) q) k, l
send to die: K2 M, ?8 Y) h8 c
end
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A4 }( P% f0 f9 Kbegin P_mA_down arriving) r$ h) ?' Y2 M0 v( T4 h
while 1=1 do + |& S$ K: q6 T; i' e/ ? f
begin
5 E* R i0 C) V; y4 w. O wait for e 110 min' w( ?& m' S" H% E0 ?$ b
take down R_mA* s& H9 |& y' L6 P8 E2 M, l
wait for e 5 min
( f+ i' {* n! b! Z: Y% i. X bring up R_mA+ L; X! t* j0 q( P" p) G! Q
end
0 x7 I% X7 q) S$ F/ d2 G- l' |end
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begin P_mB_down arriving0 W- p9 E% ]& o! g
while 1=1 do/ O$ X5 G: A* F- W6 |% X- T3 l# B$ @/ r
begin
' }. f6 m/ D2 W- Q/ _! a wait for e 170 min7 ~( F- w5 z2 L
take down R_mB4 ?, q+ F8 H$ T# U- ^5 b
wait for e 10 min
/ Y/ M$ W2 Y, I8 N bring up R_mB
2 K/ L6 \! G) P$ c( n" D4 O% f end) Y5 k3 |& `% ?5 g, |- Q+ c
end' C/ X: W; G; B e7 s4 ^0 I
0 a ]) ` L/ k' c- p$ i, Bbegin P_mC_down arriving/ X. [8 T9 K( W
while 1=1 do
5 Y j# F! j: q% _4 Q- D- t begin8 D6 f, g+ _0 |, v, D
wait for e 230 min
+ s$ v" ?9 k/ V* ^+ w4 C; R" G8 Q; q4 U take down R_mC( [2 E, l; G1 C3 E3 u+ ?1 Z D
wait for e 10 min
, b: t' k3 |2 p6 m bring up R_mC3 E$ x8 t# r b9 r' {
end
( G5 q9 N: G+ n$ D, l3 w1 c8 kend
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, w8 J* S3 J0 j' k- u# Zbegin P_mA_clean arriving
! {1 E" p5 O1 `# r1 i' p! r while 1=1 do
- N! f y* N1 V# ^- t begin
: J7 a9 n9 r" _9 {# O wait for 90 min& I$ y* ]/ @2 C0 ~7 F' G
take down R_mA2 _& X. m# S) K1 y+ G0 w5 G) l
wait for 5 min; M. r0 `8 A6 z u Y1 \$ U o5 N
bring up R_mA
0 x ?/ e. ?. e. O( m" C1 h9 e end1 X7 C" _. ^2 {3 B. Q9 m- @8 ]
end; p% O0 R d1 z+ y. N7 S
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begin P_mB_clean arriving% M6 o# V) f8 f: x( w' e% ]
while 1=1 do
3 m7 l2 U& m) t( m begin
+ G4 g; w( M$ V' I( p1 ] wait for 90 min
% ^) ~! r$ N @4 V take down R_mB
4 z) g2 i( _2 k) |8 l( |6 `& Y5 ~$ F wait for 5 min
5 c5 ^! E' ~; t* z# e9 V bring up R_mB$ T& @5 F* ^6 R1 R6 k
end( [* b7 X( |( N: C# J0 `
end
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begin P_mC_clean arriving
9 k# t% X; K# I+ ]* w9 k while 1=1 do
7 A( o* r) `$ n( k- A$ M, q begin
! m e$ D* g; a+ W3 s& C. { wait for 90 min* U8 {' h/ \" P4 Z B
take down R_mC
8 m& x5 ^- M5 e+ R8 l% p8 L) l& g wait for 10 min
) `2 S4 M) W% u" k& P1 D bring up R_mC& `4 c6 G- b9 Z; t7 T4 F
end1 b u8 N! `8 U9 o1 W1 b
end& o' f, S0 m4 M# B/ Q" z% M/ s
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7 L( j8 H" k0 l8 m5 I6 |Exercise 5.9
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G7 a3 h4 Z- F& ^, uCreate a new model to simulate the following system:! C. F" w5 S- Q! k1 n- P! J
Loads are created with an interarrival time that is exponentially
' [1 I0 j- q4 F- t8 ?0 i* B! d1 Edistributed with a mean of 20 minutes. Loads wait in an infinite-
) c5 _5 r/ s% K- `9 Acapacity queue to be processed by one of three single-capacity,
9 p) s2 t9 }2 a/ s* Qarrayed machines. Each machine has its own single-capacity queue 7 \. }/ b7 a1 f( k( N7 {8 ]
where loads are processed. Waiting loads move into one of the three 0 O% T* n; q# W- {0 O1 O! @
queues in round-robin order. Each machine has a normally , r3 L) p$ U4 `
distributed processing time with a mean of 48 minutes and a standard 1 C4 I6 O: G- |/ n& B5 w
deviation of 5 minutes.
! P5 R1 B* D/ n# I* d3 T4 bThe three machines were purchased at different times and have & c @* x( G5 J
different failure rates. The failure and repair times are exponentially
. d; Q2 }. e, Ndistributed with means as shown in the following table:
9 c/ z# g7 X" m' {4 JNote The solution for this assignment is required to complete - d G0 R8 ]0 O2 Z7 L
exercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of
& J# }" O5 ]* n1 r9 xyour model.
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. ^6 \5 V$ k8 c! s" [3 f7 ?& fMachineMean time to failMean time to repair
8 t2 W8 D' y& l0 f5 \A110 minutes 5 minutes$ D% H# y( o/ D5 s- N) q
B 170 minutes 10 minutes
4 p* d- z. R% J% a( K' kC230 minutes 10 minutes. h- a o( t6 z0 v- K8 Y9 p) a
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The machines also must be cleaned according to the following ( _0 J2 ?+ T0 i* ^( q( Y
schedule. All times are constant: 7 T5 I$ {& V0 u2 i0 F
! |$ I' H- G. s) U4 J* I
MachineTime between cleanings Time to clean) @4 {2 R& ^7 ]8 }
A90 minutes 5 minutes
! J! D0 }! D2 E3 c& ]! x+ x1 RB 90 minutes 5 minutes
- A. l2 Z' n) C V+ x; Z- t/ m/ SC90 minutes 10 minutes
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i/ |1 i7 ~- z& |Place the graphics for the queues and the resources.
, b( g9 ? i" c. _Run the simulation for 100 days.* r# H# {1 I- q' O) t( g
Define all failure and cleaning times using logic (rather than resource $ N/ G4 j$ f# N* b$ k9 s1 E$ I) ? x* \
cycles). Answer the following questions:; c+ C2 d w( Z+ u: g/ |* Y+ ]
a.What was the average number of loads in the waiting queue?
1 E$ Q+ h- m J9 W+ o2 y# tb.What were the current and average number of loads in Space?
8 {- C. D/ s, z8 K3 I4 B0 a y& fHow do you explain these values? 3 c, z2 z3 C+ O' c6 H5 F( r6 U
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