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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
9 m* {. S7 E' N/ ?* _. J" c1 a! y
我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
4 J1 G, p' H; \% G- K( f7 t6 ?begin P_in arriving
- `( C% j- C, F! C/ b5 l move into Q_in2 L# ^/ R/ c! d0 C m3 Z9 G) s, l3 ?
use oper for 2 min
* \& h. ?4 @4 d) a; @( R; N send to oneof(0.95:P_in1,0.05:die)2 Y( o9 E) K: M$ t% G6 K& k% Q
end5 u8 m l8 Q8 D3 S9 ] H
begin P_in1 arriving
9 Q* |1 d. `; V) r if load type = load1 then
, y& ?4 q; S; s) i H; ]9 j6 z' w begin) J3 z! r6 J% }
move into Q_m1# P L T3 }2 q0 `
use M1 for u 5,1 min
+ E0 n, @% K. W move into Q_out1
/ k" v: a3 ?3 D9 _ wait to be ordered on orderlist OL_1
/ f, U* Z d) ?7 b" W9 U end& C {" ?' X9 k @) l! s' S
if load type = load2 then7 Z7 q/ m5 ?8 E8 Q
begin
a# O/ t, t( N% p) X move into Q_m20 r3 C. S' F, J
use M2 for n 8,1 min, F1 L Q% F* L* ?3 L' s
move into Q_out2# q4 C1 Q5 Z, A/ C& r. Y+ ^) E- v1 G
wait to be ordered on orderlist OL_2; O( r# G; d4 Z
end4 P. g( Y( J; G5 x, J% Z8 u
end0 [: p& S3 M; j; \2 P: k) i' G( Y
begin P_dunmy arriving
$ Q$ Z! r" P' | set i = 1
& J( m$ D% u# C, ] while i > 0 do
/ A, P% z4 J- a begin
" }8 _/ B* ~. a# f7 Z order 1 loads from OL_1 to die
( [( E. J2 b6 z: h, w l. k in case order not filled backorder on OL_1
5 Q2 s) e) x. u order 1 loads from OL_2 to continue
( J# e) c, ^% V# X in case order not filled backorder on OL_2
r3 s! K( }8 V" k. n `, S% v& M1 @ move into Q_1
& t& L2 J2 b( a; Q+ e$ p4 m use Massm for n 5,1 min
3 Y2 F( c* |% {- w- X send to die8 w5 C+ s8 q# \# _: z5 `7 Y
end
4 P ~, N( a7 B1 S6 W4 yend' ^6 `6 C$ r2 `8 `( V
这是我的报告8 D+ Y0 D2 g& D; R; L* R
*** AutoMod 11.1 ***! r- [; \. f% w( Y& h+ ?
Model q
! i6 {* L* A+ O2 |! [6 |# qStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00" F( g& B- {( L0 }
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec/ n* B# [, h o& ?
Statistics for Process System "q"
! C( r8 q. H7 y( U" M* p" EProcess Statistics* I( j/ a7 p8 x
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait; D# x( O' p' Z: n- g7 _% _
========================================================================================/ x* U3 x& V/ h0 @2 L: I4 \$ C
P_in 222 1 0.32 -- 2 0 -- 126.04 --6 K& q% w/ T! z$ M; G* v+ W+ x
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
1 b3 H; z: C; I" g) L/ L* nP_in3 0 0 0.00 -- 0 0 -- 0.00 --
3 c* B9 @" y/ Z4 b" g% W6 zP_in4 0 0 0.00 -- 0 0 -- 0.00 --
. N$ T, K1 g6 b( jP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --/ K/ c" t4 o2 P p; V& C! M" d
Process Traffic Limit Statistics) y% X7 D% w% H. V
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait& J/ U/ B3 d1 D5 C$ B
========================================================================================: n0 v+ C b8 S; w
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --/ z8 |0 A& u8 ^9 z j( c
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
' L4 [! A4 Q y" vP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --3 K' E. [; A7 @$ @! e# w, h& a
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --: [8 c+ C5 ~9 A1 Q. E0 b$ y
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
5 r6 K2 g, d5 Z" d" `. R5 fQueue Statistics" y6 o6 k1 {. \4 x" y
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
O' g( Q4 n9 N========================================================================================- l+ U5 L% P) D: D. \7 F6 Q
Space 223 0 0.00 Infinite 1 0 -- 0.00 --
8 [' }6 s4 Z9 z; p% E4 [Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
$ T: C) t+ R4 ~8 ^/ z; lQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --2 `3 P! B$ p" S( Q! T* D; [
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
( m4 N1 o; e5 ?, M8 lQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 -- A% W4 \1 d: n, p4 i4 _: j" M* R
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --0 A$ s7 u% f. I' c
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
- C4 G, Z: D0 c- G4 M2 eOrder List Statistics
5 r. X. j3 C$ j4 \7 [Name Total Cur Average Max Min Av_Time Tot_Back_Ordered: @- \, d9 y8 B4 Z: G; M
================================================================================
5 o6 d* c2 t$ EOL_1 139 139 67.23 139 0 41789.43 1
, A$ e+ [$ s" t, {" U) Z& B% aOL_2 71 71 34.26 71 0 41693.20 1
k& o( i, {& L, k0 V4 CResource Statistics" b% ]* Z5 A6 ^' s) q
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
! v' S5 F0 Z, p3 \7 F. C; ~6 M====================================================================================================, c* D( u9 e. e7 H" c0 w
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- ! Z1 r3 @6 Y7 [$ r$ {. j8 L
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- % C, U3 ~- D7 w
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
2 X0 f7 H4 {1 j* g; ~0 J& Qoper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- 5 _1 \: z2 z6 G {! g
Random Number Streams
; g; C: O ?4 N, |9 a% ?- fName Total 1 p+ [% Y+ l* O& F# K
============================2 _6 J' s" ?' \9 S
stream0 455
y. [/ V, Y* z1 n# kstream_M1_1 0
( K: d& ?$ U3 H. k( Astream_M2_1 0+ ?2 V8 |4 `8 U9 G+ I, ^
stream_Massm_1 08 v k" ]) K, o, K6 [; r0 K4 L2 q* O& w
stream_oper_1 0
4 j/ c" K/ @1 S9 pstream_load1_1 184
9 ]6 o3 G/ `1 ~6 \' y7 Wstream_load2_1 762 V, ?# t- r5 R; u: D0 b7 Z
stream_dummy_1 0* O9 c$ ?; s1 d7 Q% ]
+ j3 V# \( S' e) w9 |! B请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
