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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 & M$ ~8 H8 U! D5 z& x
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
, ~4 `/ d. p5 a9 q* vbegin P_in arriving# s! J- A% a; V7 v: X% o. l
move into Q_in1 _2 p- X' @% _) S* e A
use oper for 2 min1 c; I, p9 ]5 }6 M! S
send to oneof(0.95:P_in1,0.05:die)0 R2 v7 Y9 T& j9 w( H
end$ w( c* \2 F1 h i% \3 Y) i# [
begin P_in1 arriving4 S; T0 s5 @' t7 g# k. K
if load type = load1 then
5 J4 t, N5 C# f4 r& g* p begin; A/ w1 a' ?' _. s0 b3 m. b F8 S
move into Q_m1
9 O9 O$ Q0 A9 y8 v* D/ s' ? `/ y use M1 for u 5,1 min/ Q/ y- Z. @: |: ?3 n0 s# @
move into Q_out17 S. u0 o7 x0 b5 T }. \; F6 T
wait to be ordered on orderlist OL_1+ }% {# i& U1 L+ [% C
end n. Z. ^, j& z& _$ c# K
if load type = load2 then! p3 T2 l7 r$ D) h4 { D
begin
0 W' @8 H7 x9 O0 Q( r1 V0 s move into Q_m22 B! a$ {+ k( v: c& Z; R: j5 z, |
use M2 for n 8,1 min) |# y9 U2 F! M& n+ a% p
move into Q_out2
) ?. H% w# m4 U9 a) k" Z( w wait to be ordered on orderlist OL_2, V5 A5 u5 O3 V; ]6 ~6 B0 P
end
. B7 g. N) ^7 Oend0 h* E9 [# \2 A7 W2 [! K
begin P_dunmy arriving1 M3 q5 j# V5 m4 u" k N
set i = 1! Z: ?) K1 `, r
while i > 0 do
* X. q; W( s) d/ y e5 ` i begin , g! _) I; B# H9 Q
order 1 loads from OL_1 to die
6 a" V- r: q/ }' R" \, O8 \# M in case order not filled backorder on OL_1' c& _. ]& w, P8 M; @/ {
order 1 loads from OL_2 to continue1 w8 |1 g# M9 p- x
in case order not filled backorder on OL_2
3 {8 q- J. p8 c. b! v move into Q_1) U9 C$ B x- q. {8 K! U
use Massm for n 5,1 min
7 {* i; y7 }8 k3 E- @, Y# {, c1 {0 R send to die" }% v3 x( C5 _ m. \
end
9 Q, q7 p6 S* v9 I/ iend
/ ]* P& X# }1 @- s: N* ]1 s这是我的报告, o! v9 V8 j$ a- X: e1 p
*** AutoMod 11.1 ***
- N' x1 ~* [. ?, Z1 B. }) KModel q
C7 f- I3 H) U6 N3 @" u1 IStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.000 |5 U' `7 C5 _7 C S+ k) T/ ~# z
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec! q# L/ S+ f2 S& C0 s2 ]
Statistics for Process System "q"
0 U; K5 l8 ]: ? h1 mProcess Statistics
/ x( ]0 V* J- R7 P' J4 q5 a$ IName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
6 ?) ?' n7 t( R" V========================================================================================* h4 L1 f( f) M. h7 E
P_in 222 1 0.32 -- 2 0 -- 126.04 --
0 U9 g5 C/ j: w2 e& DP_in1 212 210 102.38 -- 210 0 -- 41725.92 --5 z. g. w/ u3 @
P_in3 0 0 0.00 -- 0 0 -- 0.00 --! n3 s, W; G# u. N. B
P_in4 0 0 0.00 -- 0 0 -- 0.00 --) y/ v4 a' z9 _9 N% ~7 W& W3 |
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --: C3 s- A: @$ P: |
Process Traffic Limit Statistics5 T% q' G: R! y* s
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait; ?+ c1 p; w5 p* ~, m. a
========================================================================================0 t6 T/ A( f: C! |8 o* a
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --0 Y5 n9 j1 J9 m. h. l7 i9 [
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --7 z4 Q) ^" p4 r5 K% Y' \+ K2 d
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
* K- `( w0 v) L5 f" c; S& D, gP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --9 Q$ c& R3 f& q
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
' j8 q7 `! Y+ R' t7 [* V6 _ YQueue Statistics; l+ K4 h) I% \1 t1 G/ x, J- p
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
X/ P& P4 [8 t a' [8 p1 o5 n" {5 J========================================================================================
2 f, p- b3 T2 R- k# @Space 223 0 0.00 Infinite 1 0 -- 0.00 --
, W8 q5 X; u7 j( x5 XQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
( _% f' `9 r) [8 D2 \Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --3 y' F0 n) i0 U) \
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
- y& L) ^( [9 [Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
+ {% C5 @" O9 @Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --3 ?. U/ q6 `/ _9 ^9 S
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
- a% r8 u9 `0 E( [& Y$ d4 ZOrder List Statistics
) R- w U# K/ z* k) @+ ?9 ~Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
% A4 z! F( g' J1 @2 R================================================================================
" u0 g5 e% ~- m+ h+ tOL_1 139 139 67.23 139 0 41789.43 1# A( J% d4 T8 t/ v* [1 o" B5 r
OL_2 71 71 34.26 71 0 41693.20 1
2 M, v9 v9 C7 I* ?Resource Statistics' D1 g4 A: e7 h
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State 4 G7 H$ P+ @: o+ t1 ^/ Y1 c
====================================================================================================' M' z3 s3 ^ b& B6 P2 q' U
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- - O: P% s4 T8 A2 h6 ?- ?
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- ! R1 w5 a% K+ Z6 w/ R
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
+ t# P5 Q8 ?) n8 F$ i; C: D& Moper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
& j0 \7 B1 K: }4 d0 QRandom Number Streams5 }6 G# I3 d4 C
Name Total
3 }2 q" @1 s! d============================
# @' c5 `( Y% J) Z6 ]# y3 Astream0 455
7 @+ Q! S% G- Ustream_M1_1 0
8 D7 J, K9 u/ i, W! Gstream_M2_1 0
7 t( F5 S' R3 |( P0 i- _stream_Massm_1 0+ c& p9 q* L, b" I
stream_oper_1 0! A P, V# o- R. _- a6 I! `. Z
stream_load1_1 184; t) B# N3 t' i, d: N0 P! I! b: K
stream_load2_1 76& c8 R- J- t9 s/ q7 k" N8 {
stream_dummy_1 00 z/ ?# Q$ m. @! _
E" Z' c! ^- x请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
