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本帖最后由 soso001 于 2014-12-17 14:53 编辑 : ^5 A- Z: S, ?6 T% w% b
, C/ M7 s% t+ _ H不好意思,打错了个字母,呵呵呵!
( q L+ C. F1 Z" b: S! U3 K大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示% w" U. Y2 B- c8 Q. ~
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!8 w2 K ~2 X- {) A/ P) V0 v& t; ~
is
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M:string;# B$ a0 m# b* x% A. I4 e5 n& P
selecTab:table[integer,integer,integer,string];
5 M* M" _2 g7 U( ` Odo
( I. f5 n, x5 E" b+ Y8 N initorders; {: {1 t8 A/ o6 f( J9 L) |
( ~! Z3 t" W. E+ e scheduledorders.delete;
2 b" N7 p9 s4 O' F9 v2 E seletTab.create;
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. S7 y1 C# Y% F+ |! K orders.initialize({2,1}..{2,*},0);
+ k5 V; B F) D; b9 t3 W$ B orders.initialize({4,1}..{4,*},0);
; O* R! ]+ j2 i& G6 V- J9 x for j:=1 to numorders loop
# I1 Y u% k; f) @2 F. A orders[5,j]:=orders[1,j][2,1];( {+ ]. v7 ?. ~% e4 t* P
next;8 c! |3 C$ E- N3 Q0 U( e
occres.initialize({1,1}..{1,*},0);
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--XUNHUAN7 Z4 B1 s! l0 X$ s
for scheduledsteps:=1 to numsteps loop --
9 K; R5 F7 q3 I8 H8 [6 h! q1 }/ i# W selectab.delete;; L8 w3 O1 i+ w. h4 ~. U
k:=1;
$ {: B: H( h( {1 K for j:=1 to numorders loop5 L* b" V9 A% a
+ U3 |/ p% ]9 ]! i9 P1 x/ P; [6 e* P nstep:=orders[2,j]+1;" S$ b6 Q% h8 ^+ s% \6 r5 y
if nstep<=orders[3,j] then
( V5 W% {' M8 G selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
1 i9 E: C- r7 Z k:=k+1;) ]+ n6 q+ h z5 m b, K' s
3 |2 f$ r/ t+ Z9 d9 |/ h
end; W& J4 ~6 y. m# }# t! e5 r
next;8 d1 A. r* B* }; k0 E1 k
mincomptime:=selecttab.min({3,1}..{3,*});( q1 b6 k: \& D$ ?
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from j:=1 until j>selectab.ydim loop
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5 F% H# F4 G1 ?( E [3 I6 n if selectab[2,j]<mincomptime then
! C! q/ E' @+ L j:=j+1;
+ Q1 ^" A L8 M- B( k5 ~) W else, [' D! t+ h3 ^9 O! h: n
selecttab.cutrow(j);1 T% O& o: U9 O; e9 W Q
end;
) U" g. b. u) @& ?/ Y& G2 n; e end;: C" z9 k8 S6 `- z
$ H0 q- l* Y4 B+ i, j1 l j:=selectionrule(selecttab);
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' T$ z, T, G5 X4 I nstep;+orders[2.j]+1;
* {+ K) |$ q) m* L3 w* I orders[2,j]:=nstep;
3 ]6 k1 X. s/ [! e( R$ x$ s8 Y- r m:=orders[1,j][1,nstep];* T; D+ c' B7 F
c:=orders[5,j]
0 @+ _; \9 `) D1 v occres[1,m]:=c;& y4 ` n! K+ M1 f! r7 v# u
! y1 c4 Z' n0 Q4 R5 j8 o) `( Z3 u --jieguo:start,end,res,job,step
g# P+ n! y; r- x) G4 [ scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
# u9 R' s$ a% M) A" d7 K6 i) B for k:=1 to numorders loop
( n; ^( n& g5 |$ q+ q l2 `* o, N4 ~ nstep:=orders[2,k]+1;! g" m' P* }" x
) a' U6 {! I7 R$ u1 s if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then& C! d3 p8 l" U3 j Y! _0 q
orders[4,k]:=max(c,orders[4,k]);
2 e3 K$ K+ b" a# A4 V/ o --
' [2 p- C1 ?8 ~ orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];% n# M' ]; _$ P, }2 j% _/ t
--- B! x/ y6 v7 Y7 R; @! } W
end;
0 n0 P5 n2 p+ l* [! M! M next;
1 t8 Y W' Y% N: n% x; j( j nstep:=orders[2,j]+1:5 Z& E D d/ e
if nstep<=orders[3,j]. {: {+ L& B1 T$ S) `
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);. ]4 ~0 \; V: k. N+ W7 R' z8 S" \
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
6 g, }9 m! c, v# l" l end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});) c1 X7 n- Q' B0 B
mygantt;
; Y, e& C+ ]) A2 H/ H1 i ens;
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