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本帖最后由 soso001 于 2014-12-17 14:53 编辑 * E( Q' S- i D
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不好意思,打错了个字母,呵呵呵!6 l$ ?7 }& j' B
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
0 ?, Z. \9 l* x* q0 M“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!; m% u0 E! n9 \: D
is
5 h8 P! @' j* Q) `$ }% }6 \6 y j,k,nstep,c, scheduleteps,mincomptime:integer;
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selecTab:table[integer,integer,integer,string];
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initorders;
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5 y; ^0 {$ a" C5 N( w$ r2 L: J/ v( j scheduledorders.delete;1 Z, } v" U; Z! S$ {# A
seletTab.create;
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9 b& Q$ W7 V0 y5 A+ ~ orders.initialize({2,1}..{2,*},0);
' V5 @- C. F2 V1 t7 s) l orders.initialize({4,1}..{4,*},0);
" F. [, ]7 r& A7 J' H for j:=1 to numorders loop& {0 M; n$ L" z/ R" l
orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);
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--XUNHUAN
- f) i; B% z2 j4 b7 @1 i for scheduledsteps:=1 to numsteps loop --
/ m1 k" ~7 _' v7 t# f4 `( }2 ? selectab.delete;0 ~8 ?: A7 Q; R$ x) v
k:=1;
3 z( t: I) D$ X; h for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
/ }* p& K, e; ], A7 B+ G; |" N if nstep<=orders[3,j] then) Q# m u8 H! E' L* R
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];+ `! K2 N3 u* _
k:=k+1;" F" D5 B, A( c( _3 r
9 L0 n9 C7 _% a( @/ ] end;# s1 I0 t0 D6 j7 k+ D6 [3 O
next;$ G+ y, n5 K. Z8 l
mincomptime:=selecttab.min({3,1}..{3,*});
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from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then/ ?; ^4 u" \. V
j:=j+1;
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selecttab.cutrow(j);
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end;
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1 k& j+ i3 g1 Y5 g8 B- L' b j:=selectionrule(selecttab);* b5 ~. {9 X9 m
{; m5 Z1 C5 m+ g nstep;+orders[2.j]+1;
' S3 k9 U V$ o' H9 ]- W orders[2,j]:=nstep;* m# M2 E/ z# c8 p3 l
m:=orders[1,j][1,nstep];
- D' I1 x/ @7 o# F4 j6 N c:=orders[5,j]
+ r P9 w9 R2 | occres[1,m]:=c;8 z; p3 v0 e! u/ [. k9 z! `
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--jieguo:start,end,res,job,step/ f3 M" t. h; r( t0 X5 @# b( `: a
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);( f8 e' G% J E) d2 d$ c0 _& Z8 A# b( @( Q
for k:=1 to numorders loop! w' z, A6 R+ A# T |
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m( R6 X# M3 Z. p. K+ g( M7 k6 ?6 a
--
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orders[4,k]:=max(c,orders[4,k]);
2 r T3 t# h8 F. [3 h5 f& H --
! |& ]$ t! G0 T6 r5 K orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
$ a0 d) o3 ?1 S2 f$ w1 S --
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next;* Q- H% k }# f5 g; t7 X" B
nstep:=orders[2,j]+1:
: R4 k; n7 l3 u3 A6 o if nstep<=orders[3,j]5 b- q7 z& r! u& E) V/ [1 \4 W
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]); X* ^" V$ x0 V: L& l; P% S8 `
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
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$ D; J# M4 D ?% w3 P O' b/ x+ b print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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