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楼主 |
发表于 2008-4-19 16:11:18
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好像可以了
to go
3 } {0 w$ z. y- d0 K% R7 b2 K set t t + 16 `9 r" F. ?" n4 g4 w5 V
grow
+ l8 C1 ^$ M F+ _7 s! H update-list-of-m( W$ m6 _1 w; ?' ?# B! B# i
do-plots
4 _/ U7 u. t, ` tick
( q5 _" J( J) Q# j0 v/ N, ~4 ^ Z4 c ifelse t > 8
4 D2 j8 o- P5 z j [if abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)))< 0.01 and
1 |+ g1 o7 f0 U$ v abs( mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 and
) Y4 ^5 y4 N1 l3 u9 _+ z8 B1 s abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 ! X+ u w: h1 h1 G
[stop]]
% y7 u$ Y' f( t! ~9 n [ ] , J/ h, c" ]: k+ c# `, y; a7 l
end @, t) h1 \/ h7 v
各位大虾帮忙看看,这样好像可以了。以前用while之所以不行,是不是因为如果报告为true,那么就会反复运行后面的命令导致死循环啊?
) U2 C9 ^" U* [1 \8 \3 B" i- N还有就是[ ]是不是意味着不执行任何操作,返回set t t + 1,然后再grow,再 update-list-of-m,再 do-plots,再 tick ..........这样一直按这种顺序循环直到停止。+ z. d7 z9 u& u* \
; j1 v0 n- ^9 ^. H! t2 y[ 本帖最后由 wjcpcahu 于 2008-4-19 16:19 编辑 ] |
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