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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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K8 O% `# `' j1 y Q大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
3 K' @5 i+ X2 `, R9 {% I“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!1 }* G; R* [ n5 _- k
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j,k,nstep,c, scheduleteps,mincomptime:integer;) A6 q Y4 p- Y# b
M:string;+ a7 k$ j. i2 F1 ]; w
selecTab:table[integer,integer,integer,string];
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- s3 f3 R4 t5 y( ]7 J initorders;
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, V5 U5 W$ B8 \/ U" [0 b- d6 d8 j scheduledorders.delete;% E! _4 g. ], S; ^' W) L5 U( ]# P
seletTab.create;
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0 i) X. ^# h5 S/ u orders.initialize({2,1}..{2,*},0);3 c+ r, K L* p! C$ j
orders.initialize({4,1}..{4,*},0);
: ?. ~* d t0 Y" Q for j:=1 to numorders loop
7 T3 C6 @# p! j' B. a4 i9 n# m orders[5,j]:=orders[1,j][2,1];
; s" m/ S* C, J$ a next;! o1 j% v: I0 D
occres.initialize({1,1}..{1,*},0);/ ]) i4 q3 O( M
% _& ^* |/ E0 f: Z7 J+ e --XUNHUAN: B9 Z4 l `# _! N- n
for scheduledsteps:=1 to numsteps loop --
/ K8 c% C1 V( H7 r selectab.delete;
( g$ T4 x2 }# L. M k:=1;. g) D0 M0 x+ ]* m+ ~8 O. P
for j:=1 to numorders loop/ L% {" h+ A% _: T- S; c6 K' |; ?" @( `( g
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nstep:=orders[2,j]+1;
& R/ c+ I! q. w4 S7 z# D if nstep<=orders[3,j] then2 |6 Q& u0 d5 ~( }4 i+ k4 B
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
; [1 @- }8 W* D3 i Q k:=k+1;
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, I" O& n, c4 E2 g& M# o2 K end;
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mincomptime:=selecttab.min({3,1}..{3,*});
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from j:=1 until j>selectab.ydim loop
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* T+ W1 ~# ^# D3 V7 W& b if selectab[2,j]<mincomptime then
: x) _5 W- w# H0 F& k j:=j+1; I6 z$ H$ ]' H8 }" `! Y
else$ W$ K2 W) O/ @" Q* x
selecttab.cutrow(j);& F/ r2 O: b, I9 ?: G; P
end;
8 D& h. s1 y+ C' x& L) r end;
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j:=selectionrule(selecttab);) f, I9 W4 \ J. w8 Y8 A
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nstep;+orders[2.j]+1;9 [! h; ~ S( m4 C
orders[2,j]:=nstep;! Y0 l0 p5 _$ M) d" w) D! S
m:=orders[1,j][1,nstep];! [# _4 x+ Z5 i# J d% b. \5 j2 h H
c:=orders[5,j]
Q1 o1 o) v! D& e' H; @ occres[1,m]:=c;
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8 I9 u) _( T) Z( G- w" f7 A5 l --jieguo:start,end,res,job,step
7 i' E9 g* f0 _3 o) L1 O0 g+ F* R scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);4 M6 R0 P* P) f) K1 I* P, d
for k:=1 to numorders loop
, e) L$ E5 P, w" r5 a nstep:=orders[2,k]+1;, x$ W* L+ S8 K8 r3 c% ^
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
' b. X' u% ?' S --
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orders[4,k]:=max(c,orders[4,k]);
! N" S; Q/ k% N --
0 k9 z- ^3 V. R( W5 O" ~3 a% f) A: d2 E4 Y orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];, W5 x6 J- C6 L
--! B9 b4 F$ y# L# V% ~' J
end;" _; e, ?. y7 Z: X; E/ k! }9 o
next;' g% X5 t/ P& ?" P$ r$ C% Y/ H
nstep:=orders[2,j]+1:7 {# i Y* {& |8 o2 d7 x
if nstep<=orders[3,j]
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then
9 Y% q7 L: k8 `2 v& t8 T H orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
! `' W: `! n' j+ B. u orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];& ^6 i ]/ c! o1 g m# Y
end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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