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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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" l" C; Y7 R) ^0 W% n; Z不好意思,打错了个字母,呵呵呵!
n+ C8 V } [9 E大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
" K( N0 l8 ?- c6 G* W6 ^“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;
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selecTab:table[integer,integer,integer,string];
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initorders;
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scheduledorders.delete;
9 W0 F3 X8 @; o3 f: h5 m2 j% ~ seletTab.create;5 H, D' t2 C1 d; }+ Z
5 G4 O. S: D' [' x. R& ] orders.initialize({2,1}..{2,*},0);4 L4 b" G V% W! m
orders.initialize({4,1}..{4,*},0);
$ L% `$ g2 O. {" p* _ for j:=1 to numorders loop
. ^$ K. {. `8 Q' K9 U" e# V5 U" W orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);$ t: q' @/ E% ?- R3 X" A, S8 W
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--XUNHUAN- D% I3 F! e0 _8 ^
for scheduledsteps:=1 to numsteps loop --
1 x9 i" d. r$ T) a selectab.delete;& f4 y2 m2 P# g6 t4 g
k:=1;
$ d/ G, E+ ]4 p for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
7 R1 ^% j: }0 I/ r0 Q if nstep<=orders[3,j] then# H" p n- u3 _, L; J( U. c+ s" X
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
+ q4 L% t' h4 l k:=k+1;
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end;
( q w2 M# g0 n2 P0 J next;
! S. Y6 W* n; |% K, k* w) b8 R, _ mincomptime:=selecttab.min({3,1}..{3,*});
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, B) M9 x; v7 C; E7 F8 @4 J from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then7 H; ]6 m' Q# `1 X8 E: D! Q
j:=j+1;! ^, `7 y6 g4 m3 ]0 E% h+ A
else
$ q, J0 R4 V% F+ t' t' i( Z selecttab.cutrow(j); r: [' y: G4 e" d/ _
end;1 A3 {, Q. V3 p# K9 y
end;6 B9 {* o6 W9 _% S! l
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;, L& B) G+ C& x+ ?/ b
orders[2,j]:=nstep;$ r, }# i' d, f, @/ V' C
m:=orders[1,j][1,nstep];8 U8 Q. ]3 g5 c3 |
c:=orders[5,j]5 d! D. B& J; Q7 m, x
occres[1,m]:=c;5 _% x/ X' E! n. M. R0 H
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--jieguo:start,end,res,job,step
! ^3 ^& V6 y! A" a scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
! x. h) T7 h7 D: n, ~ for k:=1 to numorders loop2 |' m. C% D( Z. N7 f K& b
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then
& D5 j2 U- I9 X% ]5 F orders[4,k]:=max(c,orders[4,k]);
+ J: J- o' Z8 g* n. C# { --
$ Q, x( e* [# \+ \3 f7 Y2 M: W orders[5,k]:=orders[4,k]+orders[1,k][s,nstep]; k4 l& Z) v' n
--
O$ X5 C4 c$ Y) j; {, o8 Z end;$ w# Z" T" `. q4 ]
next;
4 F/ N7 W( k6 W* ^; B$ W nstep:=orders[2,j]+1:
* @* T3 \ c5 A if nstep<=orders[3,j]
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then
' k0 o7 L4 B3 }/ z1 v orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);0 I4 `7 J A- L9 r
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
8 M# T7 V9 o+ m( j: d end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});# O6 t! y- |! a% k: f2 A% P
mygantt;
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