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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
" a) I' e8 ?" p' K1 W3 R- F1 r4 H: F3 Q' S* |9 W" Z3 s
我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
5 K7 v7 h1 c. K7 f5 T2 Obegin P_in arriving
' ?1 ~; b) `5 Y) C m9 g: W7 s: j+ _ move into Q_in2 Z& C4 }# k& @$ A ]; b* N
use oper for 2 min0 @, L0 ^; u* P$ V( n8 ~
send to oneof(0.95:P_in1,0.05:die); S3 z8 q9 y0 Z# q5 X) T
end# s/ f8 W$ f% t$ U
begin P_in1 arriving
* H9 O! N4 E U- i7 \2 ]0 j if load type = load1 then4 ~& x ~ @' j, z0 x; Q
begin7 ~; n$ a/ w. k( I+ }
move into Q_m1, u! b! g' G$ R8 w% x
use M1 for u 5,1 min9 @3 a8 @! G: x0 e* X: n
move into Q_out19 ^1 V* {) u( J
wait to be ordered on orderlist OL_1
$ n# Z6 [. c- b) w/ m0 m, y end" l9 R7 Z, m2 l* Z
if load type = load2 then0 }" f8 s9 H( n k
begin% `$ b4 _% z& N" |
move into Q_m2
3 ^' h) x4 v6 U; l! |" z7 i use M2 for n 8,1 min
# Z- w- ^( ^& M4 S% S( J move into Q_out2/ v9 q9 a( q$ u" A
wait to be ordered on orderlist OL_28 \9 O/ j$ s7 l' S& Q3 R/ U$ l6 {3 @1 O
end
/ }$ U+ Z- C6 A% x; ~end
; R7 e( X) n- p; N8 Ubegin P_dunmy arriving: d; s. @) J) n9 j5 N8 j
set i = 1
0 Z* g! _' P2 `) J! |0 E; I while i > 0 do
. X/ b4 D, p1 W9 m% D begin 5 l# I; T6 Q* ~) P! c5 s3 c
order 1 loads from OL_1 to die
; \# n9 Y6 ?1 c) q. @ in case order not filled backorder on OL_1
! ~2 W+ O. w) }$ o# Q* S' J1 }% G/ f order 1 loads from OL_2 to continue
+ x! u5 u! N- x in case order not filled backorder on OL_2" X( _+ C0 D. C) Y
move into Q_1$ ?" q8 ]! \1 k
use Massm for n 5,1 min
% V: m) T& b) C G% r send to die& F# \" {% K: K I
end& U+ g' t7 }1 x& p, s& L$ W) F
end( a4 E, x' f ?8 j' W/ b
这是我的报告3 E# D8 H6 O" w( l2 p& W
*** AutoMod 11.1 ***& p: y: G3 k0 P1 X0 Z& I& d
Model q6 N( u8 w2 ]) a/ ]9 W/ G$ x
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00# T W3 w. }& M
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
1 K1 B: r/ S. v8 E: bStatistics for Process System "q"
$ [; q& W& K% o8 L# P: iProcess Statistics
/ ?) c2 G, Y4 c& q) ~# VName Total Cur Average Capacity Max Min Util Av_Time Av_Wait) p+ u5 f* l5 H
========================================================================================' k' C! a- p! ~5 g# N5 Z
P_in 222 1 0.32 -- 2 0 -- 126.04 --
\" h5 V9 U o) x+ M |P_in1 212 210 102.38 -- 210 0 -- 41725.92 --- c0 @9 D) a2 `
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
0 j2 w8 l; `. U' k L. _P_in4 0 0 0.00 -- 0 0 -- 0.00 --
3 e) j, f) |+ jP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
$ g- d8 i& f9 t+ f' zProcess Traffic Limit Statistics X9 \3 m' h D6 ~
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
8 w( E7 d, e0 D9 |) Y========================================================================================; W8 U5 A" i$ g, G) }0 N
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
1 z! ], R6 \$ O; c% r- [, T4 GP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --; D# a/ Z1 B6 G- p3 p1 |1 B6 x
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
3 c) p0 o! k) l2 S. ?P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
3 P( w- s: \9 h4 FP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --$ p, ?) q5 T( k: ?2 Z+ S
Queue Statistics
0 h5 W+ G; p/ P3 jName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
1 M) j; J. j: F9 R, v9 \1 M; e========================================================================================% A1 ?' f* N5 t) k, ^& H
Space 223 0 0.00 Infinite 1 0 -- 0.00 --! l/ n5 W9 \3 N8 O* q" I2 d' K
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
7 _6 I3 u* C3 p, n$ @4 OQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --0 _9 Z6 Z7 ^* w' I( v
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
" |4 J+ F& `% ] cQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --9 F. ^8 c9 O7 O3 b T- W) v' ~
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --2 d5 i% \/ y! j2 }5 a5 D
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00% n) c7 u! [& N$ W$ `
Order List Statistics
% V7 H" s- a7 q- u0 RName Total Cur Average Max Min Av_Time Tot_Back_Ordered
' I0 ]! |( S4 T8 _! b# g================================================================================
8 y) h; P1 S A( A) W# x: i+ DOL_1 139 139 67.23 139 0 41789.43 1
: J0 S- c4 l, AOL_2 71 71 34.26 71 0 41693.20 1" ]+ N: b; t7 F, l* @
Resource Statistics
( e3 E) ~) p6 t# t; |5 pName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
) P8 i$ ]; E6 _) c6 A====================================================================================================+ x1 i. R8 i8 O: l* X
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
& u6 Z% Z0 Q4 z( |) C; sM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
3 o( M; r9 u; z$ g% ?Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
, n, E3 I$ {: Y" M. R7 y" X1 c4 Hoper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- 3 {( Q( C2 J3 x5 o: V! i
Random Number Streams
, w' z6 j3 Q9 QName Total + w6 y/ c4 g. B1 L! q, b/ W1 x
============================% Y0 O; y k% a s _
stream0 455
9 {0 q; I- h7 x8 Gstream_M1_1 0
8 {0 t0 y) M6 Y Z# f( v: f) |/ x% G; qstream_M2_1 0; c, @5 ^" n$ \" X
stream_Massm_1 0
4 _6 m9 k" t; \* C0 _stream_oper_1 04 L0 ], ~, n: l7 \8 k1 @& j/ p2 m9 B
stream_load1_1 184
! V3 Q; m, L8 Q2 X; M' A3 l! g' \stream_load2_1 76- |. w' w$ m1 H1 f. N' c- d' M
stream_dummy_1 0; r T0 B, V& P! d6 ^
3 ~; e8 v- |7 O0 H请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
