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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 - A* Z3 x% E( Z# c# M' `
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我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:1 _$ k+ G5 b5 m- N. G1 e
begin P_in arriving
2 y. Q& {0 {" N* ^6 e move into Q_in& U; @. V1 M @% i# R5 q
use oper for 2 min. c* w1 Q+ J3 I9 _- r
send to oneof(0.95:P_in1,0.05:die)
+ K2 Y# w5 H8 S; fend# M8 V8 U: t- n
begin P_in1 arriving
" \4 o3 P7 V: L8 ~$ y% n* I if load type = load1 then7 }+ n1 a# g2 [ V
begin5 a* U( [! W& g; J8 b
move into Q_m1
4 J6 q& o+ U: J4 c% x6 O. K use M1 for u 5,1 min
- I8 Y( ?4 w* e1 w move into Q_out15 i& r, a8 a, T: D- S3 {/ a8 e8 X1 r
wait to be ordered on orderlist OL_1! A: J4 M( x) G# D
end7 d% s5 D' j% n; J, G
if load type = load2 then
' [4 Z+ n* {0 ?' N! Y& f begin3 ?. K/ `; W9 b; \) E2 K) X. v
move into Q_m26 Q! a9 w' \. @9 L) `! W$ ^
use M2 for n 8,1 min! B- D7 r3 Y! d2 i4 b
move into Q_out2
% @5 M( U2 P$ N$ Z/ \$ N wait to be ordered on orderlist OL_2
3 A9 R( |/ Q4 Y) C8 D, h) Q end4 W1 z+ U1 H" S7 u z: f" m
end
$ U; W @0 m7 F" @+ d% ]4 {* j4 kbegin P_dunmy arriving# T5 A0 K* u# u9 e
set i = 1* S' N3 S8 [0 D- I$ k, |
while i > 0 do; E' m# ?' v) m6 ]* @
begin " ~0 ^5 t+ r( b0 q- f" S/ }( t0 G
order 1 loads from OL_1 to die
, I/ X! u6 G8 C% } in case order not filled backorder on OL_1
7 G- {& n: M' B5 A order 1 loads from OL_2 to continue7 u& Y& i3 N$ }6 |- _. A
in case order not filled backorder on OL_2# g4 c( j, T$ Z# q
move into Q_1
0 R% c& K& M0 S8 P) z* @ use Massm for n 5,1 min) a$ }! ?# U- y7 q! t' X0 @" P
send to die) o t, X- a% n& T6 S+ I
end
5 C8 |% \1 a- n3 ?1 C2 Uend
9 D% T+ p7 B O. m, ~! |- o这是我的报告
$ \8 e3 [' h- F*** AutoMod 11.1 ***
" v" c3 n# v8 y7 Y1 _Model q
% H/ ^- b: `, o! P% \0 j' I1 |Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
1 M: @2 k5 p! C3 B- FCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
P4 j1 s( l/ s5 @1 v! \. ~6 b2 v( `/ y8 TStatistics for Process System "q"4 ]) ^/ u) K: ?/ `4 R
Process Statistics. z$ U$ ]* I- G
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
& o% ~: z5 ?' V; R [% N3 h2 n: W8 G========================================================================================$ h( t7 y% v' C/ a% x7 a* K: `
P_in 222 1 0.32 -- 2 0 -- 126.04 --/ G+ y) K5 A+ E3 O8 H
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
& j% |0 Z3 i) b) fP_in3 0 0 0.00 -- 0 0 -- 0.00 --9 {% T' t1 |: y: q1 N
P_in4 0 0 0.00 -- 0 0 -- 0.00 --
# L2 m6 X8 e# [8 x+ b! ?) OP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --. @" N; o9 b6 x' k- {# v
Process Traffic Limit Statistics
) m; ~( F. e3 T! f; M8 @7 IName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
: n6 G" n8 K+ I' a7 V0 J========================================================================================# t# y( b u1 d8 c8 [
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --, t" H5 K* T* _/ y+ ^* @
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --/ g$ l+ P7 o, t2 |, e! D
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --+ W& @! V& \4 H X
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
( U! l% F: i3 [, e$ x5 {P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
2 e/ C6 G3 G0 }$ ]Queue Statistics# {" ]) D9 O/ H
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
# M& q% c _/ D Z ~$ [- F; t========================================================================================
, P4 v5 v' X7 X7 sSpace 223 0 0.00 Infinite 1 0 -- 0.00 --
" o" A6 U/ l0 a/ pQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --% e F0 o$ X- b; w) D) q
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
: L% ]# G" R, u2 EQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
6 M& O5 ?4 i0 L0 ?3 S' sQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
5 ?* f. z; v3 C- Q( v8 j EQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
8 ~$ U2 M: t" M, q; |+ AQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00" N3 _" W4 L, {
Order List Statistics; _, y) i& I/ Q6 b5 h
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered5 |9 r# f7 M8 A) t
================================================================================7 _; f8 Y& J6 U8 `/ u& V- K; R
OL_1 139 139 67.23 139 0 41789.43 11 N: l' D3 M$ r
OL_2 71 71 34.26 71 0 41693.20 1
2 I7 W* Y% n# ^Resource Statistics$ j" V- W' p2 y
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
9 z/ p2 Y4 c3 K: I4 |0 {+ i====================================================================================================* K2 h% a! G; }
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
2 r% _) g* }* d' DM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
% k P* A& x$ u3 K' b% ?! UMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- c: R$ e$ x, J- Y" N
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- . N9 X: ]# X4 v; w Z
Random Number Streams
6 L$ g z* o' x T! D8 cName Total , I J4 T# s" C2 I3 E+ V
============================
) Y% c' N1 m& Gstream0 455( t; r! W* F4 n' B: U1 D" p
stream_M1_1 0- v: t: A0 f2 [% U0 \
stream_M2_1 0" |1 ?( M/ H3 f+ M( Y" Z
stream_Massm_1 0
; Y% A( a% s7 Qstream_oper_1 00 l9 [2 L& u- w
stream_load1_1 184
, R9 T, Q! H+ N$ ~4 w, |stream_load2_1 76* E1 I6 l" q+ I1 w+ s# i
stream_dummy_1 0
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' i% l; `6 N1 y1 h5 }1 R5 o8 t, t请问我的错误在那里?我用的版本是11.1的学生版 |
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