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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:+ K' L1 F. @. u. D  r0 R  _

5 c4 A  Q' M: w, P# Y% W% u7 f) A- D public Object buildActions () {
3 a8 F! A7 h+ ?4 P5 G' x$ F    super.buildActions();
& K; m/ N2 `2 g; f) I( l   
, Q7 e, t; X- \) e3 A5 a& z% l) k    // Create the list of simulation actions. We put these in5 `4 c0 o! }) z5 R( O
    // an action group, because we want these actions to be
( b& d+ [+ S3 y3 n- z! ~) S    // executed in a specific order, but these steps should
* H9 T8 I) _2 h    // take no (simulated) time. The M(foo) means "The message; @7 Y( v7 H. E1 \- T# p
    // called <foo>". You can send a message To a particular. ~3 m/ M. |0 m3 w( A) T
    // object, or ForEach object in a collection.# S4 }/ F" k! ]7 v( x1 Q" c, b
        
4 _8 x7 C1 s7 {# a# T. r7 O0 S$ ~) o    // Note we update the heatspace in two phases: first run! q" L8 u2 v  P( F! f+ W& u5 v
    // diffusion, then run "updateWorld" to actually enact the5 @3 n, p  T# y7 b/ a6 m0 v2 R6 z
    // changes the heatbugs have made. The ordering here is. j% o3 U: h) a& h
    // significant!
, q) P5 B/ J2 k4 E: z6 [        
" [% [9 J4 h( y& b  l# C1 F    // Note also, that with the additional
6 h) p: y8 `: S, l$ T/ I    // `randomizeHeatbugUpdateOrder' Boolean flag we can& _3 f$ O# I' T, ?5 G# {1 \/ Y
    // randomize the order in which the bugs actually run& w$ L0 h3 I: o5 ]( }
    // their step rule.  This has the effect of removing any; i# i4 R4 G  I2 c8 S$ n
    // systematic bias in the iteration throught the heatbug( U4 W( O4 J( ?5 I1 T! z/ y, H9 ?
    // list from timestep to timestep
, U- ]7 ]7 {- I, `9 c7 P+ E        
) u$ q* T0 z5 m1 ^5 C3 B    // By default, all `createActionForEach' modelActions have
* F/ \5 p) {" E+ {: X/ N8 K) J    // a default order of `Sequential', which means that the
7 `9 {& t: I$ G' `3 w6 k' N    // order of iteration through the `heatbugList' will be
6 t6 p. `3 ?9 W% S) _6 p    // identical (assuming the list order is not changed& s$ e* d5 b" Q9 a6 ?
    // indirectly by some other process).- U4 p0 H* b( S* k) k9 N" f7 W! ~
   
8 t! k) e* i6 d$ F' E    modelActions = new ActionGroupImpl (getZone ());; r/ Z% m1 ~! Q
2 R  P5 m3 [/ K! O5 B. ~
    try {  E5 i, J2 E- X9 C# [
      modelActions.createActionTo$message3 p; R& q! [& \% h) V
        (heat, new Selector (heat.getClass (), "stepRule", false));$ W1 P+ t* H( Q- O% \/ c
    } catch (Exception e) {, K- i; h& o, k
      System.err.println ("Exception stepRule: " + e.getMessage ());7 B; [0 M: L. Z9 |$ q& p
    }$ m) U" o. Z# A9 v

1 ^" Y/ u, N7 f# ^+ s    try {8 E$ _8 J' \+ F$ f5 b4 c
      Heatbug proto = (Heatbug) heatbugList.get (0);. W9 E" B; b) ]
      Selector sel =
4 j* g( c) x* x! Y6 F$ r8 M( o        new Selector (proto.getClass (), "heatbugStep", false);
$ w5 [6 e) R0 D/ y1 _. C  X9 U9 U      actionForEach =+ I* u! x+ o. S8 g/ b! X2 K
        modelActions.createFActionForEachHomogeneous$call4 R7 A0 t1 G5 g5 i  v
        (heatbugList,
) F& I: O* ~/ T7 N         new FCallImpl (this, proto, sel,
/ x) m" H+ L% n  U: l                        new FArgumentsImpl (this, sel)));% y& P8 v! Z6 P* O* X5 W) P( u
    } catch (Exception e) {1 D* ?1 r! Y: t- \# {6 G- l1 F! F
      e.printStackTrace (System.err);( q( v1 j* J8 C" A
    }( h0 ^2 ]# }# _5 H  x, N
    8 F) N# L' F' {/ v
    syncUpdateOrder ();1 M7 t, Y8 D+ ^4 a5 F. l
2 i, t4 K, K2 n/ C! B  D
    try {5 w, j+ o; N. M8 s; f
      modelActions.createActionTo$message 3 a+ _; t* c" n- i$ K+ d2 u4 }
        (heat, new Selector (heat.getClass (), "updateLattice", false));4 F9 @- G% z( O, F8 |( F* J
    } catch (Exception e) {
& |% t; O, m+ ^0 G' r7 [      System.err.println("Exception updateLattice: " + e.getMessage ());% T+ Q5 R+ X9 T/ H* X
    }* h1 A' }% R" P2 _* ~' Z
        
8 N4 G" q. C! M  @    // Then we create a schedule that executes the: A/ }, _& ~! F
    // modelActions. modelActions is an ActionGroup, by itself it5 j& R" \. z9 [* N. ?$ L
    // has no notion of time. In order to have it executed in9 H1 C5 z0 e; C2 S2 E
    // time, we create a Schedule that says to use the: }; T2 Y  Z6 H  U
    // modelActions ActionGroup at particular times.  This
; w4 F0 s3 k' a! Q# z  Q    // schedule has a repeat interval of 1, it will loop every
" d4 }: x; l. S* |) x: ~    // time step.  The action is executed at time 0 relative to
( T; U4 ~* d. M: w    // the beginning of the loop.
& \. ~- C' l. t, c# n2 J# y- i& c9 L% k- J& d! R" S
    // This is a simple schedule, with only one action that is
0 \6 v$ E$ G  }3 w9 {( Z    // just repeated every time. See jmousetrap for more
# H- x% B% Y6 W  |* i0 A    // complicated schedules.7 J) Z- D- P* @) S- o' @
  5 s! H* h: M5 U# k* k) ]9 ?4 p6 C
    modelSchedule = new ScheduleImpl (getZone (), 1);
" v' K( w1 Y' I. E    modelSchedule.at$createAction (0, modelActions);
0 X/ i8 D- G2 Q2 B( R8 N: M2 O7 [. u        
/ m4 W( D, S& z+ R2 |9 I" G    return this;
% l( S7 Z8 l" @' H& l! M' r  }
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