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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!+ ]* l/ A3 j' h1 P
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示, r& c# N) p! w" ~4 X r2 d$ B
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;
& x& n8 @) _2 O8 O* O! i M:string;1 m" Q* s, z- H( P/ \
selecTab:table[integer,integer,integer,string];
$ u% `9 ^! A; Z& Ndo
; t6 K" V7 }( w5 @9 h5 v initorders;; s* y# i% c2 q" _4 F, v8 }
$ t# t' `( ?" i+ i' P1 f* s5 t/ e scheduledorders.delete;
5 p G& J0 n$ C2 g8 A$ G* {6 f seletTab.create;
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4 m! P& M& E% l. w+ U6 n, A orders.initialize({2,1}..{2,*},0);
& J# ~* t3 z3 K6 G2 o | l$ j9 h orders.initialize({4,1}..{4,*},0);, Q/ a2 |# M. ~8 J# H0 ?% r
for j:=1 to numorders loop' l( m" B7 ~3 s7 R' n, W
orders[5,j]:=orders[1,j][2,1];
0 A- d: R; {% @* X1 Y next;
3 t' L+ U% P4 l occres.initialize({1,1}..{1,*},0);1 y; K5 J v7 C. E9 O3 p+ y/ @
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--XUNHUAN
+ S6 I! U) M: k6 |1 n+ T for scheduledsteps:=1 to numsteps loop --
! M- `6 r8 c* S8 q' G" s selectab.delete;/ l' x8 q; u+ ]6 L' v# X5 B
k:=1;" T' j- r' l6 l+ E' o
for j:=1 to numorders loop' i4 M. W" W. W. X G% g
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nstep:=orders[2,j]+1;
+ S* w9 G1 Y8 D$ ` if nstep<=orders[3,j] then
3 T- O' b! C( _, R1 I+ m+ Z selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
( X& F h& ^; I7 Z2 R4 m k:=k+1;
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end;' i# w" S" {# G, P/ T# w
next;" D8 r! v! a8 a: U
mincomptime:=selecttab.min({3,1}..{3,*});
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6 i% {# t3 k \! I from j:=1 until j>selectab.ydim loop0 b$ w! h4 @- C# w1 N/ g( u
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if selectab[2,j]<mincomptime then
* }% ?. j( O J: J& H0 ^1 Q) q j:=j+1;
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selecttab.cutrow(j);& Y' q* g2 o+ ]& ]: ~1 B
end;
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j:=selectionrule(selecttab);. `. L: ^& m4 _4 q& ?) |, _9 O
5 Z4 [& E0 G0 \5 x' `* i# C nstep;+orders[2.j]+1;
, o% o* J E4 l' a2 _ orders[2,j]:=nstep;+ R# m% n2 [% F' U0 j
m:=orders[1,j][1,nstep];# f$ j: h$ e* U& t# X$ q
c:=orders[5,j]
# l4 A* P; `1 D: V/ |7 H6 k0 V) L occres[1,m]:=c;0 O$ z; |( B/ j+ ?* D
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--jieguo:start,end,res,job,step r: X8 x8 ~& k- {# T" {
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
2 D" e( k7 @2 N, r for k:=1 to numorders loop8 E9 |8 P- w1 x6 p' x
nstep:=orders[2,k]+1;# X4 `$ @' `5 _
' g5 b! L1 B) c1 }0 O4 ?- x if nstep<=orders[3,k] and orders[1,k][1,nstep]=m7 n" U m( u: `4 @) ^
--, D& i) X9 `2 @* m9 g+ y3 }
then
' C. b5 k6 C4 X2 ^) r8 l orders[4,k]:=max(c,orders[4,k]);
6 \# U0 L$ N/ W% {( H# Y --
( r" n9 w1 h8 i. @ C5 i4 ` orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;4 {, Z! J% h% {& g+ Y
next;: I$ Q4 ]$ u+ u4 A$ {$ C
nstep:=orders[2,j]+1:
) t O% Z$ B2 b6 H2 S$ s if nstep<=orders[3,j]" S4 z/ H/ X3 ~* S8 `7 A5 B
& n9 L1 M6 C" f9 Z9 K) H then
/ |7 O/ p+ p/ u8 n orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);$ F" l+ z. e& Z- @( ^
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
9 P2 W8 n! B k1 |) b0 a end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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