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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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- [/ Q2 d6 C/ X# q Z& @1 \- H不好意思,打错了个字母,呵呵呵!
R& e" O& T2 K$ W! X3 [大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示. t; s2 ]% b- k" N
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!6 V n& ]& X' ~# [
is
+ L( W7 p- r! G j,k,nstep,c, scheduleteps,mincomptime:integer;
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selecTab:table[integer,integer,integer,string];( {0 y x, y9 R5 t* [
do% V0 ^5 F* ^- h7 e' B$ N( r( J- w: v
initorders;0 i- M- H* m% z7 j2 j; f
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scheduledorders.delete;, Z( A, M" p7 R
seletTab.create;. @" D+ g5 j0 D* m
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orders.initialize({2,1}..{2,*},0);) k9 H: V7 a* A( Z
orders.initialize({4,1}..{4,*},0);' ~/ O, ^7 ]8 m& O# _4 \
for j:=1 to numorders loop
^" c) o. g) C/ P7 i+ ?% u orders[5,j]:=orders[1,j][2,1];- t% k3 Z* w6 I* H5 s
next;3 r8 T9 \/ y/ `" `- k# I
occres.initialize({1,1}..{1,*},0);
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( Y5 F- F% E& X, c --XUNHUAN% l3 r: m' A r, p @
for scheduledsteps:=1 to numsteps loop --( h' g. u1 o) C; _
selectab.delete;
, g' F' z7 @' A8 n k:=1;9 b4 |. F! @! S! M3 P% j: U" y# J
for j:=1 to numorders loop: ? [5 D' j! g
9 U: [- g6 b" L5 _7 d nstep:=orders[2,j]+1;
/ F+ t; A+ {6 m: u* I* ` if nstep<=orders[3,j] then
2 n$ g' M( [* V( r selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];; K. Z; ~5 ~' P: `% `
k:=k+1;
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end;
; x4 v- _1 ]' R7 O8 k0 V next;3 V" a) s$ j' ]3 D& r# w
mincomptime:=selecttab.min({3,1}..{3,*});% ~, C* }' j+ Q, e# N$ z
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from j:=1 until j>selectab.ydim loop. m/ S ^& h; ~. K- N( q: u: O
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if selectab[2,j]<mincomptime then. T9 d& y: p0 V8 I) a! L+ d
j:=j+1;: u* S3 u! g: d9 k6 w9 L
else4 C; I* b& W6 K( l
selecttab.cutrow(j);' w0 D5 p, T! {" i
end;
) z; i2 N, g) m E3 O end;
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1 c* ]" Y& |6 r# h7 { j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
4 o: [% W5 Z- ^0 J$ c6 r# D, n8 i6 t orders[2,j]:=nstep;
" S" h) ^! S3 I% i4 q/ W m:=orders[1,j][1,nstep];
. B/ w0 r0 p5 V/ x* y c:=orders[5,j]6 [2 Q. m- h& `5 U" g$ \
occres[1,m]:=c;5 y5 r; x' }2 Z E
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--jieguo:start,end,res,job,step8 V- b2 r2 J' C9 }: ?0 [+ w
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);, J* K |( M4 L( N( B' p) v
for k:=1 to numorders loop$ p& O/ ^9 s- [, e. |
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m3 d; Y% q! y8 @/ l$ o6 o+ b
--
9 e7 g5 R6 F! t& P# k2 g! j( q then
& W+ l/ Q! r, N9 G5 ~ orders[4,k]:=max(c,orders[4,k]);& x0 c o: t! m" L5 a$ l
--1 v% t+ @3 b, l3 A. P; m) c' [
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
: j$ u' H" H! ]% T5 D5 h2 G, k- Z --
?/ v# V; N" ]) G( v6 S' H4 B end;- ?' L1 `& ?9 ~9 e: {: Q
next;3 H5 L9 O6 m# d) T, [- @4 \/ p
nstep:=orders[2,j]+1:
- K( j1 R$ \1 j" u1 l if nstep<=orders[3,j]' f# F% z9 {& n2 U6 @3 t
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
0 C; K* k/ Q( c8 A6 D4 _' y; M orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
; w( D- b c2 U9 i6 Q- k/ M4 k5 D end;
5 M4 a7 R" T! y" ^$ D8 B next;
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. F `5 w0 |9 j3 j print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});- B1 b3 o0 [0 ^& o
mygantt;
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