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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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/ e5 L: S. K: T- _9 G l不好意思,打错了个字母,呵呵呵!+ r% @, f" H0 A" T; M
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示& W- \ A+ a j$ f/ B
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;8 { t# n. L9 W% d. |) H
M:string;
0 `/ V& m. Q, X6 Y7 ^ selecTab:table[integer,integer,integer,string];
T6 N9 E' s9 L( b: k" rdo
; w) X! q: c* i0 u2 H) z7 _7 v, ` initorders;% R ?: }% Q: Y% `
/ ~0 I X0 _$ K$ j scheduledorders.delete;9 z% |0 x: Z2 c/ \) v/ n
seletTab.create;" D8 ?% C. U+ d: x4 e
1 C7 J* X4 W/ u0 b orders.initialize({2,1}..{2,*},0);8 Q0 U% s' ~7 F' h$ `
orders.initialize({4,1}..{4,*},0);
# w$ N. i0 \" o& h for j:=1 to numorders loop [% n. r* M/ {8 w
orders[5,j]:=orders[1,j][2,1];9 d3 `0 k1 R6 x. \; w! x( T
next;" Y/ x( M5 d+ `4 N
occres.initialize({1,1}..{1,*},0);5 f- F' ]0 U- y5 [, p$ v
. _2 J3 y5 C6 H+ U: a8 w --XUNHUAN3 ]. y! ~% B8 U* w$ n
for scheduledsteps:=1 to numsteps loop --
# m( d# q# G8 O1 G. H selectab.delete;1 U- ]: B8 P& o Q( T% q* Z6 {9 n* N
k:=1;' h7 Y _" y) Z2 C5 {, r' j# {
for j:=1 to numorders loop
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3 p, ]2 }( E& K# n4 c& Y nstep:=orders[2,j]+1;! L! r" z, Y( u6 m2 D- X6 `
if nstep<=orders[3,j] then) K6 Z' K* W5 t6 U0 I
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];9 ~7 O7 v) Z2 \
k:=k+1;
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next;
& m& D3 a# ^% \4 w7 w mincomptime:=selecttab.min({3,1}..{3,*});
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/ ?7 S/ x; ]6 |6 K" ?2 X from j:=1 until j>selectab.ydim loop
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# O2 M! C4 ^! h4 ` if selectab[2,j]<mincomptime then! j& ~: c; |% N. y
j:=j+1;9 M/ P8 G# W8 d& w6 c5 E! o7 o
else
, x/ @3 Y/ n# Z- G$ w- m3 N selecttab.cutrow(j);8 h- O( Q. d2 |% e5 m M. |( ]" F( f
end;
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;- N# G9 G z0 l" [0 k/ o
orders[2,j]:=nstep;* l8 y/ m) F) Z; ^
m:=orders[1,j][1,nstep];
' ~% D6 _7 X( ~ c:=orders[5,j]
# i( N+ w9 ? h0 D/ ]7 Q1 U occres[1,m]:=c;
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--jieguo:start,end,res,job,step
) f8 t1 p0 E3 c scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);, A2 t. e. M' S( w4 q0 t) X4 H! L
for k:=1 to numorders loop3 t: o( z# [+ m- H" A
nstep:=orders[2,k]+1;
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4 O; c J5 q: \- x if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
% [5 J/ ~3 m, d2 u o( e --
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orders[4,k]:=max(c,orders[4,k]);
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];- j9 `- y! Q* \ J8 T5 U6 s
--
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next;
N* f6 r& B9 K6 x nstep:=orders[2,j]+1:
" g# ~, i# g4 A4 L- T( B if nstep<=orders[3,j]7 h. T5 r0 a2 r1 Z% p
, P7 p0 R% D& N6 F& X: s then
: ]; p* S* f6 D! M. g/ {7 M( V& t8 B& j# O orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
: W/ w* y4 G' F orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];: G/ d9 i' M: {1 n* q. Y
end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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5 v* z( W0 W2 {3 H+ v7 i% J ens;
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