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本帖最后由 soso001 于 2014-12-17 14:53 编辑 h9 e, Y; w& @. G
1 O' F+ {1 V9 v不好意思,打错了个字母,呵呵呵!% y9 i" R- P( e" N! r
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示, A* ^( x2 E+ t$ u6 p: U. `# o
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!1 U+ }% \6 g5 u4 e% @
is
2 Y# B7 o. V/ ]# L) H" C j,k,nstep,c, scheduleteps,mincomptime:integer;
! V# K h" `' E" k9 m9 I2 S3 b M:string;
# \* H# G* ~- ^ selecTab:table[integer,integer,integer,string];
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initorders;* {. x- \; G# A' M
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scheduledorders.delete;
( M N, o$ d* @7 O seletTab.create;1 K' ~* ]; `; X4 u1 p! A8 t
+ t& y+ d- X% `9 n) @" I, Q orders.initialize({2,1}..{2,*},0);
* G# b" O5 A- R6 W8 I orders.initialize({4,1}..{4,*},0);
H2 {3 j0 C! d% {. b0 ~7 }9 I for j:=1 to numorders loop% Q0 P6 ~( U5 C4 x9 w6 Z
orders[5,j]:=orders[1,j][2,1];+ y0 g: V6 ~ e3 ]1 N
next;1 ^& }3 g9 ?+ a1 ?9 g( _9 V
occres.initialize({1,1}..{1,*},0);2 ?4 |! c- o2 s3 m. k1 l# O W
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--XUNHUAN! [1 B+ x; P5 i0 n0 D
for scheduledsteps:=1 to numsteps loop --
: j2 A7 D, U1 B selectab.delete; r7 J @8 f1 n7 i( p* Y" D
k:=1;
; I9 b& q, V, k: H) a3 _) N, k3 H6 z for j:=1 to numorders loop& v& F4 F) f) R) Q, }; Q
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nstep:=orders[2,j]+1;
2 j7 c7 {( n. c8 P( H6 ?9 f$ O if nstep<=orders[3,j] then
7 k' {, y+ M. A+ E& x- {+ b selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];$ @7 t/ s5 Q9 d- M0 D: F) V/ R
k:=k+1;
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end;: p1 w3 I# r+ T2 k( |
next;
' F5 i* d) s% [8 p+ L5 G6 T mincomptime:=selecttab.min({3,1}..{3,*});; W' p U4 y8 \. _ b
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from j:=1 until j>selectab.ydim loop
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7 r9 R7 w6 p2 j if selectab[2,j]<mincomptime then+ f6 t6 }% F6 e# P- c3 s) v
j:=j+1;/ h" ]* E, O4 C- B9 l3 R: I8 [5 m
else7 {! m/ X& m: C7 R {
selecttab.cutrow(j);# j) P( g, f2 ` `0 K1 C
end;
k5 l8 t8 h. N0 A G. Y, ?- m end;
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0 X2 R2 V. b" J) K. h5 W+ P4 v j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;# p) k: B* y7 L+ G* Z
orders[2,j]:=nstep;* U& d, u. N- U/ Y
m:=orders[1,j][1,nstep];. M2 I/ Z3 u9 P. i
c:=orders[5,j]
, `" Z8 `' [! r0 T" D occres[1,m]:=c;
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--jieguo:start,end,res,job,step# ^) O) E) N4 M- Y) D
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
, U+ s2 U3 S a) ? for k:=1 to numorders loop3 j! l% z) l+ b) k; ^
nstep:=orders[2,k]+1;: \5 Q5 k2 Y5 O% a8 z
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m( i V4 d; X( C
--7 T' j4 _& C1 O. y6 d8 y' I$ S
then# n& W2 E2 j! y. U2 V
orders[4,k]:=max(c,orders[4,k]);+ L* H; z( s3 g5 r3 ~. g
--9 X, E& ~* y2 d8 W
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;1 u8 C. z3 T. B3 y
next;: p- }+ K& X! C& }" K6 B- C
nstep:=orders[2,j]+1:* E% h! {# H0 j$ e! ?
if nstep<=orders[3,j]- b5 j' F, M* T3 U! f
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then7 i9 b0 j c' I- z' G. A* d# K
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);+ L# D9 u4 ~- D1 N8 q
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];& [( m4 Q; ?" W. a8 P
end;: X0 V" N& A ^3 ^
next;$ ?- Y: f0 Y! v4 l' w, j3 r
( d. S( j( O. r- l; f0 C print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
# }8 G9 o3 r' h C! h mygantt;
/ s8 v! D9 f5 ^; l ens;( K$ m) ?0 x% K3 ?& @/ w+ ?4 b2 H* U
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