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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：" b2 l6 Z- `0 }
begin P_in arriving" N; o1 J$ G# @' i/ }" P# y
move into Q_in Z4 R* z0 c* s/ f4 c9 a: }
use oper for 2 min
; E% f: m) k' T6 Q+ Q send to oneof(0.95:P_in1,0.05:die)1 b6 k% q! d @8 g
end0 v* S) E4 P) I; p
begin P_in1 arriving
# `5 v; N, V* f# ?& b if load type = load1 then+ b! P T" z% r+ p1 q
begin5 l8 l% y3 J0 R- z+ d# o( t
move into Q_m1
+ j( ` \# g, ~0 A0 s4 i1 p use M1 for u 5,1 min) H* ]& f/ T/ o& L: a, \2 a; q/ p
move into Q_out1
' f- p6 d1 P6 A ^5 K wait to be ordered on orderlist OL_1$ `( b7 \. o! ]8 x1 M# p
end0 i7 f2 u8 r2 L( k, ^! w/ m
if load type = load2 then+ j9 @0 i2 p; F+ @2 Y$ |* ?
begin& o' o3 O7 e7 i
move into Q_m2
, y5 T9 l% _, h9 J4 l# E use M2 for n 8,1 min
4 a- Z& I( K" X9 O" E move into Q_out2
: p; X1 u- N7 E2 d8 i wait to be ordered on orderlist OL_2
+ p; u& O5 O. ?( W2 v3 A- v end$ v' j M$ x3 V# b# |; T( W" ]8 w
end: L& t) p3 k0 Z
begin P_dunmy arriving2 L1 H" `/ t/ l4 r8 B
set i = 1
I9 l0 [ c! r+ n" K5 B+ L2 u while i > 0 do
- L# q+ H1 |9 j7 g8 S; y begin
0 a t. L. ~! a/ }1 A order 1 loads from OL_1 to die
- N* U% @# w0 z: z in case order not filled backorder on OL_1
8 ?# c0 c0 j1 K5 ~8 ^$ \ order 1 loads from OL_2 to continue
5 M& k! u( k: y1 n7 S' _ in case order not filled backorder on OL_25 ?0 D3 q/ N! I/ A
move into Q_15 p( q& m( |# Q' ]# o1 N1 `
use Massm for n 5,1 min
$ G# O# ?$ x8 q& S* r2 g send to die8 d% G" b4 r' O& p5 O8 Q
end
! h, G, s1 \0 C8 G! |end4 Z7 v* D# K& i O
这是我的报告1 H% u2 y) \: n" F. L
*** AutoMod 11.1 ***
% S6 r3 Q E! p6 O; R$ S7 HModel q
/ B) k) k; C0 d. A4 GStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00/ d$ p& t. M$ C" [0 x) G* \7 n( E3 h
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
, T1 u( A; N4 @+ U, q1 b3 H4 J; P5 AStatistics for Process System "q"
- A( }! u* S( m T8 l6 g0 gProcess Statistics
$ l9 w1 `6 d# |3 w& e& l7 L, kName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
( M/ |* \$ `' W! m/ T" m========================================================================================% S3 @7 i1 P0 n* p0 A- |4 P
P_in 222 1 0.32 -- 2 0 -- 126.04 --
+ X9 }& @( r3 T% OP_in1 212 210 102.38 -- 210 0 -- 41725.92 --
, ~1 C& H( c# H) IP_in3 0 0 0.00 -- 0 0 -- 0.00 --7 v# C6 N8 d/ B; K
P_in4 0 0 0.00 -- 0 0 -- 0.00 --: c0 w2 w% o9 [: w
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --' ^2 b! I& o6 A; @. c3 ]6 |5 Y
Process Traffic Limit Statistics0 t8 J8 N3 U9 g t
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
' j0 r+ `4 j9 I4 u8 _========================================================================================" i# Q+ G% h) m2 @, E
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
3 m, A- ^1 o' y8 A6 @1 iP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --( {; `: d! r$ V% R- b
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --6 z4 H& f% o# v1 l/ ^3 t
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
+ I/ G' r+ U/ u( y, G4 i+ rP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
$ N- M9 d" ~, O IQueue Statistics
7 u7 f% M0 v+ G! sName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
- G; p x! B7 ~0 i) y========================================================================================
! u% E( Z5 m5 m2 U/ M; c7 {Space 223 0 0.00 Infinite 1 0 -- 0.00 --& Z2 w5 j1 o! B5 m0 G
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --$ y- e T, e: R" B
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --4 a+ M& q$ r0 D
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
" ?' g% i" r q! |: n4 C3 WQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --8 d; N) b5 B8 s8 T1 Q
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
$ [# F% K; c3 PQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00
8 s0 Y* ]# K7 n- H8 K- N9 P( dOrder List Statistics. ~* V8 x! L5 ]8 v9 K% n0 |7 X
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered; W9 t2 n& S8 _. j: J
================================================================================
7 X& }( b7 I. h# h/ B, kOL_1 139 139 67.23 139 0 41789.43 1
4 b% e9 s v s& ]/ R9 M3 ~( AOL_2 71 71 34.26 71 0 41693.20 11 k* a( q& X) I6 A1 \- P4 |
Resource Statistics0 h, F# o/ m# x3 F. S* l. s4 a
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
. P8 s5 l/ r( ~" _. l====================================================================================================
6 D- R9 |& W0 X$ b5 J/ G1 MM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- 9 l& W7 s& s& h4 Q0 m
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
. H8 t7 t. ]) m* M; XMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- * Y+ I( i; \) M) E9 h
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- : I$ ~8 ]+ y0 O* b
Random Number Streams& B' ~0 k0 K! E( S! z! N- C
Name Total
: t- C0 V$ Q( \: H============================
" h { o1 i8 Q0 Tstream0 455
. b- |: I$ H. g8 f; C ^- `stream_M1_1 0
$ n$ L+ W, y" W0 O9 f, tstream_M2_1 07 a) `2 }0 Z+ G3 G F8 O
stream_Massm_1 0/ O/ L7 X8 `3 W" X* D' O, ~. V
stream_oper_1 08 {2 Y) n) D" V) i
stream_load1_1 184
/ x- G; b6 j- w, u8 T: F) m$ astream_load2_1 76- j, \1 w& J% X2 S" N
stream_dummy_1 0
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
