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发表于 2010-5-11 13:19:52
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用list吧
0 m; x( M! T) V' {. w6 ?# Ppatches-own [wealth rank]
5 W$ R( }' n$ j T0 ]. r1 S/ B" ato setup
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6 H6 Q7 j1 b2 ~# I ask patches [set wealth random 100 set pcolor green ]+ @5 b4 H! A- J( m( Q$ ~. Y
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to go
2 g8 x* r' M5 P9 Q; k let mylist1 []
2 ^3 a( h. v$ }+ X8 o& G9 b set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches1 M6 |; ?9 L4 X6 I- E& d$ h
let mylist2 []
! n$ T7 k0 z- I set mylist2 n-values count patches [? + 1]' J q/ y/ W6 J5 u# A
- h7 H# k% x1 l! k9 n8 j! G ( foreach mylist1 mylist2
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# `* Q# V% l1 k" M9 K* L ask ?1[ set rank ?2]
3 t& g7 B2 C* |6 Z" f& F4 | show [rank] of ?1
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9 u5 I" Z' K2 h* q3 M4 P let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
w9 w0 f+ G/ q* l' X. k show count patches
3 K' ?/ r! n/ c- M show mylist1 - D; \5 c/ Z, }5 V+ h+ F
show mylist3* X n M& ^$ w h! q, i J" D
end0 H6 k) E6 _: G# {
5 j7 j, _; C& O5 A# X+ F0 W4 M+ H这时的mylist1 和mylist3 应该是一样的 |
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