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发表于 2010-5-11 13:19:52
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用list吧( ?7 V1 q* T, u$ Y3 w! [* f( Z
patches-own [wealth rank]
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ca! J% S5 `1 ?" z, b2 ]
ask patches [set wealth random 100 set pcolor green ]7 K! S _9 k% B7 w! D
end( `4 `) E& w8 A8 `3 |
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to go
- j. S @* x- w+ K! Q6 y let mylist1 []8 S0 ]) M9 R; S8 t0 h
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches" m& W4 ?- t* q" R, |& c
let mylist2 []
2 h0 x- T- D6 O5 `! d9 k" {' U set mylist2 n-values count patches [? + 1]
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2 r( v0 ?% B. V. r& A* H2 ]$ T* m' \ ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
+ L2 ?3 A* k9 Q; N( ?: u/ ?7 o2 _ show [rank] of ?1
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]
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& q- t+ O/ ], J# a7 B0 L let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
# r1 F9 y, S& B- ]# _; n show count patches/ k6 ^! `- G$ N, }" c$ B) l) m O
show mylist1
7 R+ ~8 Y c* \5 ~ show mylist3
9 U( ?' s& j( E$ jend
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- n6 }, ?1 t5 }% k这时的mylist1 和mylist3 应该是一样的 |
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