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5仿真币
在使用Order List时,当一个order list满足不了order的数量,要用第二个甚至第三个order list,有一段程序,请大虾解释一下,多谢!程序如下:. A$ @1 |3 j1 l: s
begin P_Order arriving procedure! O- \! ^7 L3 m( I* c
set V_NumWanted to 10; @7 }# }, o( t/ I7 ~6 S
set V_NumOnList to OL_List1 current value
- M4 X; {" y8 o3 x) S* ]9 t order V_NumWanted loads from OL_List1 to P_NextProc7 A" a' C1 y6 S" @( W( j }
in case order not filled
$ |- g, ^4 o% u6 S% ^ begin
5 C/ `! {" e! k6 [) Z3 { wait for .01 sec' k# T' b0 ?' F0 l6 N' q
decrement V_NumWanted by V_NumOnList - OL_List1 current value
( m$ o* x) v$ O: I$ c) H set V_NumOnList to OL_List2 current value+ Q9 q8 y# \1 k! i1 d
order V_NumWanted loads from OL_List2 to P_NextProc
3 q, A! M5 x) y" h in case case order not filled
$ |6 n1 S- c* l ................................................................., b( ~6 W( x- _( V" O7 {* V/ y# H
* E! P( |. {3 V0 t. e6 H+ L, u) w
8 [5 @0 L; P* x) S- Z3 a我就是不明白上面用红绿色作标记的那句,为什么后面要加-OL_List1 current value.用前面绿色部分,即把不够的load算出来就不行了吗? |
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由于有in case order not filled这句,所以我觉得红色部分应该可以去掉。你还是自己测试一下吧,不一定要按书上说的做。
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