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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:2 G# d$ z0 Q% t

, e. ^( m! N$ @' E- H/ T) t  D" Z public Object buildActions () {* M. O+ X4 l3 W, S
    super.buildActions();/ e7 Y% n% o( X  q# h6 J  }
   
2 l( V# f8 r7 W/ Q: t    // Create the list of simulation actions. We put these in
- I. v: O0 l, K/ E' s* g    // an action group, because we want these actions to be- \! n3 f8 ?' P0 z  K2 {) ~
    // executed in a specific order, but these steps should
) j. @* d  d+ L    // take no (simulated) time. The M(foo) means "The message
+ V) P5 X6 E( ~+ U0 `    // called <foo>". You can send a message To a particular" z' [5 [4 ^5 A# L
    // object, or ForEach object in a collection.
) N8 k9 Q1 a4 v% t  e) S        9 [/ J2 _; ]- N( E3 G, W
    // Note we update the heatspace in two phases: first run
5 x" ?$ m2 a+ l( s/ L    // diffusion, then run "updateWorld" to actually enact the
2 Y: l4 u+ K9 C& {& Y    // changes the heatbugs have made. The ordering here is/ B) r/ f6 d5 ?& T5 ?
    // significant!
# @* j# v* W! j( ?+ c: R* h, N8 ?5 K        $ I; B: Q/ {! P/ J6 J
    // Note also, that with the additional
9 n' y% J! ^9 I  [7 r, H    // `randomizeHeatbugUpdateOrder' Boolean flag we can% p9 j0 Q+ k& p3 U, n! o# G# d
    // randomize the order in which the bugs actually run
7 M3 ^- x9 K$ ?' T; v3 W4 q" g! i7 Y    // their step rule.  This has the effect of removing any. r! {: k" Z3 {+ Y( M' Z
    // systematic bias in the iteration throught the heatbug: x" `# [2 b# c& p0 r
    // list from timestep to timestep
7 n- c1 c( O0 A: w  C$ h        1 J+ y* @8 _) t, H- A
    // By default, all `createActionForEach' modelActions have5 g% l- m3 H1 A) R2 r7 _
    // a default order of `Sequential', which means that the1 s  F' m, |. T. F) e1 q6 H: x; d
    // order of iteration through the `heatbugList' will be
8 M0 I# o  O2 b" M) H, H" S: q    // identical (assuming the list order is not changed0 g. e, D6 o" o8 t
    // indirectly by some other process).& ^" ]& }! B5 M0 m
    ' t# h3 ]( _* v# l$ |; z
    modelActions = new ActionGroupImpl (getZone ());2 E; l+ b+ N* \% G

8 {( j) U! |+ E( u) ^2 l    try {
8 g/ O, A" M! V& T3 B. G      modelActions.createActionTo$message
7 s9 [( I0 m& G' b. S' V% U        (heat, new Selector (heat.getClass (), "stepRule", false));
. ^+ H4 B& J2 j( x# Z( ]" j    } catch (Exception e) {
/ s# N+ I: y/ O      System.err.println ("Exception stepRule: " + e.getMessage ());* z2 \: _9 X; r
    }
. e$ Z% g% @# k) ~8 V* Q4 [- K2 p# R% q) R: ^, Y
    try {  Q$ Q7 Z' Y! W3 U3 [# Q! B
      Heatbug proto = (Heatbug) heatbugList.get (0);. T4 S2 h& _% S3 j+ b* ]
      Selector sel =
7 _/ @4 g! d: k' l& e4 N2 W, j% Z        new Selector (proto.getClass (), "heatbugStep", false);$ M* ~) m7 P. e; C3 U4 r- m0 x
      actionForEach =9 _8 b* `+ y" {' }  M2 @
        modelActions.createFActionForEachHomogeneous$call
  v$ |4 @: Y' T* _: {$ F7 p# t        (heatbugList,
% X$ E" n7 O% ]; Y" Z         new FCallImpl (this, proto, sel,, P% A" b6 ?' O. j& `
                        new FArgumentsImpl (this, sel)));/ F$ K% b% |# u: h7 }" O$ G& f
    } catch (Exception e) {
) {& [/ v6 T2 y$ K$ ?      e.printStackTrace (System.err);
3 k* P6 Q3 }8 I/ c    }) u2 A' a4 p! y/ }) p9 w6 q. m  c
   
8 R3 G; n3 H: W; @) I    syncUpdateOrder ();) Y: U; W. Y/ s1 F; f- u: R

* D: i2 U2 P( D& y    try {, C8 m$ Q2 W; [% J: ~4 |* c
      modelActions.createActionTo$message
9 A: V& l1 @" B% }: d        (heat, new Selector (heat.getClass (), "updateLattice", false));* k: z- g9 Y6 Z8 Y
    } catch (Exception e) {
, k0 @9 E/ n$ X# k; Y) C# N' j      System.err.println("Exception updateLattice: " + e.getMessage ());  N- G' ]% o& A" _& Y8 x5 ^! G9 }
    }, R1 @, A7 w! M
        ' v' [3 ^# `1 H& {! @
    // Then we create a schedule that executes the0 ?' f5 J; }+ @8 Q& o
    // modelActions. modelActions is an ActionGroup, by itself it3 X8 Y% G7 N+ R# b/ ^7 V) Q; ]3 {
    // has no notion of time. In order to have it executed in
2 O6 j" L/ b4 m- d4 I) F$ \    // time, we create a Schedule that says to use the
9 `* s2 U; V' s* Y    // modelActions ActionGroup at particular times.  This. B5 o) x/ y0 L' D# j' ~4 G) j+ }: n
    // schedule has a repeat interval of 1, it will loop every' [% F! @( P( Y! Y; p
    // time step.  The action is executed at time 0 relative to) f: m+ f1 F) a0 w. M( Y
    // the beginning of the loop.
" H+ s, E  Z" ~
  b1 y  E5 N& r: u8 g+ s    // This is a simple schedule, with only one action that is
8 C# w5 |, u9 S9 A$ o, `    // just repeated every time. See jmousetrap for more
4 S# E9 y+ X% p7 a. T    // complicated schedules.+ u* P$ B/ J* H% R8 `& R
  6 G  z5 M( p. t- a3 s
    modelSchedule = new ScheduleImpl (getZone (), 1);
9 ]# x) f5 {# F' r8 _; S4 }4 O    modelSchedule.at$createAction (0, modelActions);0 g9 g# P$ @; \# S4 @
        
9 U# y! ]+ @& @6 u+ p+ n. p9 e2 }    return this;
5 n: [1 Y/ q+ S  }
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