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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:" d9 c3 M* n' L: O; e

. E3 r; Q5 Z2 M/ H. t4 d8 K$ w public Object buildActions () {, q, F3 B1 Y$ |& Z/ t5 \# a
    super.buildActions();
) X3 z/ A. x+ W1 c) B   
, T3 D! Y1 i* J6 V5 ~9 A    // Create the list of simulation actions. We put these in
5 H9 ~4 y2 L' }0 B1 l% h    // an action group, because we want these actions to be
1 ^' b' H& }0 ]) |! e+ y    // executed in a specific order, but these steps should
0 \# o8 `6 D6 O& X- P& l    // take no (simulated) time. The M(foo) means "The message
5 j6 O- j' y, m' A( W1 k    // called <foo>". You can send a message To a particular
) v; o) C8 C4 ]# ?    // object, or ForEach object in a collection.' Y% O2 i4 b8 r' Z" Z
        1 [5 r" o* M* H" W2 q, w
    // Note we update the heatspace in two phases: first run1 B. X5 `) D1 B# V
    // diffusion, then run "updateWorld" to actually enact the* G( S0 r  o9 r
    // changes the heatbugs have made. The ordering here is
& P1 A+ U7 B; Q) G    // significant!  e7 x$ u2 }5 C7 F- g6 q; H
        
. i9 y4 g- u+ O( S; a( S' J/ {5 D    // Note also, that with the additional9 Z1 S% g8 B' i& i6 Z; c$ s
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
3 _' o1 E, P2 V' R    // randomize the order in which the bugs actually run. L  L/ Y+ ~- Z- @- G/ ]
    // their step rule.  This has the effect of removing any
$ V& f: X" @" g; o. ~4 @    // systematic bias in the iteration throught the heatbug
- {. y, ^8 ^% J5 d1 C4 o    // list from timestep to timestep8 W2 D9 C; V7 t6 ~7 [6 R
        
% {/ r$ b/ _$ w6 u0 h    // By default, all `createActionForEach' modelActions have& C& I& E9 H1 Z% N( ^$ D7 g
    // a default order of `Sequential', which means that the
" i3 Z$ A  j2 s1 W0 D4 K    // order of iteration through the `heatbugList' will be! U4 |! R) d( ]$ ]" x$ Y" m2 Q
    // identical (assuming the list order is not changed
- W+ x4 @8 |) W7 }) @. |; Z3 {7 F    // indirectly by some other process).
8 r. i6 {  v6 {3 B* D    ' z. V' H7 k$ F1 i2 y
    modelActions = new ActionGroupImpl (getZone ());
, g) S) f: q' d- i; I9 K- ^9 @7 l5 `1 K# u; w# O+ M/ n
    try {$ \: a% c0 R. ~0 {
      modelActions.createActionTo$message
; B9 V8 V# ^- m7 C& h& {        (heat, new Selector (heat.getClass (), "stepRule", false));
5 l3 p0 Z( y; M) U& V3 q$ x" \    } catch (Exception e) {
( S' O& ?, d% ?( y/ {0 E      System.err.println ("Exception stepRule: " + e.getMessage ());
: U% c! O# V. G; K0 M* C: M% M/ G3 ^    }
5 L* m) _2 e2 x0 H$ s5 E8 U/ f$ N' l, y$ h/ e) V9 R
    try {
. m# Y2 R, ?& B- Q      Heatbug proto = (Heatbug) heatbugList.get (0);5 p2 o9 m) T( N8 r  e  Y
      Selector sel = 9 c/ H; D: q; i3 P- s
        new Selector (proto.getClass (), "heatbugStep", false);
2 Z3 o4 p3 w: r% y      actionForEach =
$ x2 |8 q( e, ~" G9 [        modelActions.createFActionForEachHomogeneous$call
3 ~& S  Z/ M7 F3 \! ~. f        (heatbugList,
3 h. c* [% T- T4 d. c         new FCallImpl (this, proto, sel,
7 ^) X+ [8 m6 N+ a2 b# P' \                        new FArgumentsImpl (this, sel)));% J. d( X) `, w3 j. v, I2 F
    } catch (Exception e) {
/ a7 F2 G+ C$ Q8 C7 X      e.printStackTrace (System.err);
) H: Z2 l: P; Z6 X& J    }
9 y4 [' g4 C; Q) A$ e    * Q/ \: J- z+ v2 D' O* ]: M
    syncUpdateOrder ();
" C) t$ U" Q( [( q. {8 S2 n& c" X: `+ @: e7 Y$ u! D
    try {8 d5 s  n0 y& f2 T1 Y9 r
      modelActions.createActionTo$message 1 d2 V) @* D4 `: T# B( ^- z
        (heat, new Selector (heat.getClass (), "updateLattice", false));
+ ~- z9 m$ B  R; Q' [    } catch (Exception e) {
9 G* W5 Q7 ?& Z+ c, e      System.err.println("Exception updateLattice: " + e.getMessage ());1 K5 W) o3 R3 ~
    }
5 I4 f* ~  {! |- w4 [) a' j- {        6 [  R$ F% p3 a* Z
    // Then we create a schedule that executes the
3 k3 k  L& z( T9 U    // modelActions. modelActions is an ActionGroup, by itself it
% U+ \3 F! q/ _' L# K% x    // has no notion of time. In order to have it executed in
, E/ ?+ {: H4 q" J    // time, we create a Schedule that says to use the6 s0 ~! n6 [. B; Y1 E) d# s, Z
    // modelActions ActionGroup at particular times.  This
1 O0 k2 g9 i( _- c, U    // schedule has a repeat interval of 1, it will loop every
# `! i; q; v7 T    // time step.  The action is executed at time 0 relative to4 K3 s6 l% g6 w/ A. f
    // the beginning of the loop.
7 y  f6 ?( M0 t8 t* I
4 ], N, o! p5 C$ y' L( b# g  s    // This is a simple schedule, with only one action that is
4 S! ~+ l% t, V4 W9 p    // just repeated every time. See jmousetrap for more
1 S. m2 C7 w) P4 K6 x6 E8 q; E    // complicated schedules.
; P+ e/ L% p+ e* |: `1 r7 j4 J: v  + F  V9 B5 J) y' `! m
    modelSchedule = new ScheduleImpl (getZone (), 1);
( q# R9 Q& {  S1 _0 u    modelSchedule.at$createAction (0, modelActions);: U6 `$ S# Q3 o3 K- `4 `
        
0 P: Q3 \$ _" x& x+ j    return this;
. `- m, v7 U* x* @( j  }
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