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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:6 w% T8 F, J" s- Z* d, F; A2 M& U8 x4 `

1 m' {- y$ r1 b+ ]: p# B public Object buildActions () {2 m! X( C  L5 G5 T4 H3 C
    super.buildActions();  I5 D, r# k2 Y. @/ \1 z9 h1 v) n, m
    ; U* O6 ?  k. w4 v- x
    // Create the list of simulation actions. We put these in9 _, {! |, k1 I( B/ f
    // an action group, because we want these actions to be  h' N$ P  k# ?2 j+ i; U
    // executed in a specific order, but these steps should- B6 j) p& M6 W$ u& b7 c1 w
    // take no (simulated) time. The M(foo) means "The message
* R0 [7 U& T3 D! X" ]) g, K0 ~+ R, P4 [    // called <foo>". You can send a message To a particular6 z# k' \) B" L" i8 M6 e" Y
    // object, or ForEach object in a collection.  j& F; D3 e- {) E
        
, {. c3 q2 ]/ o2 e    // Note we update the heatspace in two phases: first run4 t% ^; A; b& F! b2 \
    // diffusion, then run "updateWorld" to actually enact the1 F# X, a$ @# P" ]" o' [
    // changes the heatbugs have made. The ordering here is% U. j, D  V8 R# B+ E8 L/ @9 E# ^) n
    // significant!* G4 b. G& L! m, n2 D
        5 i) D# C" o& V' a% N0 }( m  x
    // Note also, that with the additional+ w9 J7 O; L% [4 g+ b! u% ^
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
. \" ]5 E4 g# r: r3 b$ I) B    // randomize the order in which the bugs actually run
! N( ?8 y- F% X, a: P1 H/ K    // their step rule.  This has the effect of removing any5 U3 Z+ G1 n! v# \3 v1 R6 N
    // systematic bias in the iteration throught the heatbug
5 ]) l7 y5 Z3 i# Y4 C    // list from timestep to timestep
' z. r  Z7 u8 s+ U; N5 [        
# s9 h7 R0 |/ q' O% I: `' X. b% g* s! B    // By default, all `createActionForEach' modelActions have9 e$ w" |- [4 u- N; w& c5 b
    // a default order of `Sequential', which means that the
, {1 q& s- ^6 r. f    // order of iteration through the `heatbugList' will be6 {5 A) z- G* J* o4 D
    // identical (assuming the list order is not changed9 K" x8 g& s" m3 ^  L" S7 ^
    // indirectly by some other process)., Z6 U% ~4 N/ e' Y5 J; _
   
8 c/ D/ T! ?$ c9 U- `. p) n* E    modelActions = new ActionGroupImpl (getZone ());& q$ w, u$ i$ Y" ]0 j5 n

, Q2 S2 h7 T' R2 A8 q    try {
+ e% M5 }$ f' s+ v# W' v  L( @      modelActions.createActionTo$message4 K: s8 y" l8 }$ v% Z! d: Y3 P& I
        (heat, new Selector (heat.getClass (), "stepRule", false));$ u3 K/ m, e  L6 P; l5 ~- X3 r( k
    } catch (Exception e) {
6 Z+ F. ^4 i, H/ `% g      System.err.println ("Exception stepRule: " + e.getMessage ());
/ _" Q1 M- N$ Z8 C1 C# w    }
' X2 Z( _3 j  K5 p" N2 [
" X4 c! ]& m: e+ g1 b    try {
: ~7 S4 Q' m1 a1 o      Heatbug proto = (Heatbug) heatbugList.get (0);
4 H  @2 b3 Y5 y& a  i7 m      Selector sel =
6 g* L' b* |6 t; q' L        new Selector (proto.getClass (), "heatbugStep", false);7 v% I% F7 w; q0 R" Y8 r( [, R
      actionForEach =5 v6 w% U) M1 R, F
        modelActions.createFActionForEachHomogeneous$call# e4 W: s5 }( i$ S, g
        (heatbugList,' s" B. K4 M; m+ F
         new FCallImpl (this, proto, sel,
5 X# d* F# b& g) z$ b/ y                        new FArgumentsImpl (this, sel)));
' G* j0 [: ^# q: P, H/ _    } catch (Exception e) {
9 T1 j1 E9 H  j' l. m7 x      e.printStackTrace (System.err);, T# S1 ~4 ]! i* G" }! e0 n& H
    }" z% Q' K( ]# ~9 T3 _
    ' D1 n+ Y: g) d* Z2 L- A: V% F0 ~, E0 g
    syncUpdateOrder ();
. M9 V8 W; r% S( _% @% \- s7 ?2 b/ K) M; }: N( ]
    try {
/ f. ~- L, _& J      modelActions.createActionTo$message 2 E' N+ ?7 ?( ?' w! x
        (heat, new Selector (heat.getClass (), "updateLattice", false));
9 e0 V/ b% I3 g1 Q. g- P/ B1 r" U    } catch (Exception e) {
9 [' l' B; z2 t; C, e# o& z      System.err.println("Exception updateLattice: " + e.getMessage ());
7 S4 L3 P# f) A; G; Q! K- `6 J    }/ k! p, C" Y$ c# B( T8 l4 K1 {
        2 Q- @5 x5 N9 j( N
    // Then we create a schedule that executes the- z" S& t, i; C& J, J
    // modelActions. modelActions is an ActionGroup, by itself it- B: ^8 g, L( q$ C
    // has no notion of time. In order to have it executed in
5 F% v) x# y- q    // time, we create a Schedule that says to use the
3 k8 Y/ h  N8 \    // modelActions ActionGroup at particular times.  This$ r5 b# l  h" H& n; Y8 @1 E
    // schedule has a repeat interval of 1, it will loop every
/ G8 R/ Y2 ]$ i    // time step.  The action is executed at time 0 relative to$ P( o' W0 L' f6 o; U& u
    // the beginning of the loop.0 V* H% E9 S1 ]8 t6 D  e* w- L& n
9 i. g# R! U4 }6 g( R* F& y
    // This is a simple schedule, with only one action that is: W" T7 V3 o3 S, ?$ F! s+ e) C# |( k
    // just repeated every time. See jmousetrap for more; L0 ]) V+ n+ U9 f
    // complicated schedules.
+ a4 x) l# u+ H! u4 o( i) ]& v( J  2 ^. m/ P0 m1 C& Z
    modelSchedule = new ScheduleImpl (getZone (), 1);
1 Q. P1 W, \7 A- {: k* G# X    modelSchedule.at$createAction (0, modelActions);
5 S- m- P3 j3 I        
8 }6 c7 P0 {- U2 ]0 ^# D$ |    return this;5 N# o' Q$ i2 W- z; N: t
  }
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