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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
! C) {7 |" V: q; h3 t; g  T1 \. O" L, `% J. l0 p2 `' k2 S
public Object buildActions () {
9 J# A9 _" o6 m  }6 {5 `1 `    super.buildActions();
8 q3 Y% r7 V+ u    & x/ d4 Y( v& D/ u
    // Create the list of simulation actions. We put these in4 h0 s3 F  ~+ a- B& c3 C! @
    // an action group, because we want these actions to be
. L( i+ `$ _% t! _9 T( `( t4 T. L    // executed in a specific order, but these steps should+ h& X6 s2 x* r9 m
    // take no (simulated) time. The M(foo) means "The message: O, _1 a+ u! v4 O5 ]5 ^% h  w
    // called <foo>". You can send a message To a particular; x* o& ?# H  k# }/ ]. s& o
    // object, or ForEach object in a collection.' [( `  T# r# \7 a" D* I
        
- h( p8 i8 D: V9 l8 j0 i    // Note we update the heatspace in two phases: first run. o4 ]( T' R4 f8 q5 n, S
    // diffusion, then run "updateWorld" to actually enact the; ?! C6 Y/ E$ P) \' x
    // changes the heatbugs have made. The ordering here is
: Y$ D' k3 c( m" u; v: N7 K    // significant!
- l/ l$ w2 ~  y4 C        
% @! ~+ z: l$ M! s1 r    // Note also, that with the additional
2 k1 X' y. m. j7 @6 d6 q8 e. o) u    // `randomizeHeatbugUpdateOrder' Boolean flag we can
7 [5 v) H5 z% A  R8 g4 k0 S) V    // randomize the order in which the bugs actually run9 J/ ]! P; h: ~& K+ n* O2 v  ]
    // their step rule.  This has the effect of removing any
- q* |4 G3 @  J) z$ o. ]7 S5 P    // systematic bias in the iteration throught the heatbug1 m+ B( l+ y+ k$ _0 w& X6 ~2 c" K* i' r
    // list from timestep to timestep
7 I  Y' v& c8 E. E+ R, Z        # U/ K6 r) i# X& x/ W; R
    // By default, all `createActionForEach' modelActions have* D6 c6 J/ l  [2 l4 b
    // a default order of `Sequential', which means that the$ V4 ^1 W: |  M# Q' m: l9 F
    // order of iteration through the `heatbugList' will be
) f) L4 M; U1 a. g    // identical (assuming the list order is not changed
( N4 A8 X& E, R    // indirectly by some other process).0 O2 H/ w) q0 C# V7 ~6 \: W, C
    7 N; z& s; w5 a- Z2 Y; ?
    modelActions = new ActionGroupImpl (getZone ());
' |( K- F' U% n# [/ O, |
2 ~$ |+ B7 r% u7 c( x    try {) \* l! B7 [0 y+ h) `
      modelActions.createActionTo$message) H1 j" H4 G" L) p6 C
        (heat, new Selector (heat.getClass (), "stepRule", false));
8 ]+ |8 ?$ r5 q/ L* H    } catch (Exception e) {
: f7 |1 W. ?* a3 {" K- N      System.err.println ("Exception stepRule: " + e.getMessage ());
7 M* v# O- |- ^, D% q( G" n) s    }* ^! y- _5 L6 r: z. J
* q& h2 E. u  R) h* u, q- Z
    try {
5 D8 f% Y7 ]1 [( @# W      Heatbug proto = (Heatbug) heatbugList.get (0);
& f- K/ f, e8 @+ b6 v      Selector sel = % Q3 S; m' ]4 r" t
        new Selector (proto.getClass (), "heatbugStep", false);, s/ h0 P# b/ Z% V: [
      actionForEach =% O0 [( O4 W& b- C! X) r' l
        modelActions.createFActionForEachHomogeneous$call. c/ n3 Y  i4 a$ J5 O- c) J4 C
        (heatbugList,
) U" J' T6 Y8 y% k$ Y         new FCallImpl (this, proto, sel,
2 t9 h% [( T# v" Z% }, N  W5 U                        new FArgumentsImpl (this, sel)));
/ Z" b9 @; k2 l1 U9 w/ x5 @# N+ ?    } catch (Exception e) {$ P; h% X2 b5 g% [4 S
      e.printStackTrace (System.err);
2 ^* T# C1 g  `. O' r" t, B7 R    }
0 p9 d5 t' O+ L0 b6 b  P' T    + ?! |: h& v$ }5 k
    syncUpdateOrder ();7 M# n* Y! G1 x7 q0 t4 V$ D! e9 e" @
9 W  s' Q: X9 u. Z
    try {5 Q& ]7 b3 `: A2 r0 b
      modelActions.createActionTo$message
3 y2 w5 r: V# H0 j- O        (heat, new Selector (heat.getClass (), "updateLattice", false));' s2 L  p. x  E- c. a. j; \
    } catch (Exception e) {
9 w: E8 y& B* d" i" W: g: R      System.err.println("Exception updateLattice: " + e.getMessage ());
6 `# _! ?5 l2 H- S  u; m# |    }
1 V! M% I2 n0 r4 N        6 w4 b9 w7 Q; t7 `0 E
    // Then we create a schedule that executes the8 i3 C9 B3 ~- ^3 w" u
    // modelActions. modelActions is an ActionGroup, by itself it; A7 n" [9 `% M1 I! Q- B0 |$ N
    // has no notion of time. In order to have it executed in
7 K8 q. z& n" X9 \/ A7 z2 F) t    // time, we create a Schedule that says to use the
2 w4 x) G, `. L    // modelActions ActionGroup at particular times.  This0 v8 H- G1 G/ z. N
    // schedule has a repeat interval of 1, it will loop every+ k# _; N" x$ Z* z5 [
    // time step.  The action is executed at time 0 relative to
. `) _* u, [, d6 G7 ~2 B" _3 y; M    // the beginning of the loop.
' C8 I9 L: l3 O4 |4 p2 q6 {- `: y  {" x/ I3 N7 b3 z
    // This is a simple schedule, with only one action that is
) y" |  b2 E  ^& y+ V& D- i2 f    // just repeated every time. See jmousetrap for more4 x3 _  M; G, q  c( d8 c2 k
    // complicated schedules.6 L3 ?* b& ~! l
  # W9 b% c# q5 \+ K% I* U0 R6 k
    modelSchedule = new ScheduleImpl (getZone (), 1);% k; ], ~: K0 ~/ T8 v2 a4 ]* M
    modelSchedule.at$createAction (0, modelActions);! U# R8 y% M6 i+ h- X
        & {" B. h3 }1 D( ^' C4 f6 b# o
    return this;3 h) y3 j# E+ |( _/ m
  }
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