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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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; a" s, k8 p) X ?0 e( H- V不好意思,打错了个字母,呵呵呵!7 Y# W* r2 r- W
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示- e2 a% R% F! k8 ]( Q# r9 o
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;% M6 ]# o) J' k2 `4 |
M:string;
% B6 n2 a* R& |2 B: v' N selecTab:table[integer,integer,integer,string];
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8 i" u) r# l" x+ n) g initorders;
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scheduledorders.delete;
8 A6 n" D. Z9 y2 R# w seletTab.create;
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% X; Z* |, O3 @6 G2 a orders.initialize({2,1}..{2,*},0);
: p( e$ k% \* C, t# B" u orders.initialize({4,1}..{4,*},0);
! Z6 n7 w0 y( Q- s' k for j:=1 to numorders loop: n% ~0 U$ D) }/ |0 ]; J9 h6 ^
orders[5,j]:=orders[1,j][2,1];
: U6 }: r7 c# h7 k3 u( r next;
# Z, ^$ j# f8 R" G# f- Y occres.initialize({1,1}..{1,*},0);7 g* C* E7 A* _* U% O& Z
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--XUNHUAN
( s8 `" N* K$ I8 p for scheduledsteps:=1 to numsteps loop --. A- n( r- `8 U* X/ t) I5 y# m
selectab.delete;, `3 J3 X: H2 s
k:=1;
* q1 F2 j& F# I' b3 D" q for j:=1 to numorders loop- ?! m# [. P# v+ I
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nstep:=orders[2,j]+1;
1 {% T f) U* q `# i! f if nstep<=orders[3,j] then: I5 B7 I; R, \. P7 Q9 K0 |/ f
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
+ `. N# N+ ]! r/ b7 |% z) K k:=k+1;4 L5 |& u+ c! |7 e7 Q
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end;) g; i4 M: [- A7 ~2 W$ }
next;# w! q: `) i# T3 F: D v$ E. ~
mincomptime:=selecttab.min({3,1}..{3,*});( V1 |; [" u) Q1 F9 k7 F
3 r: M5 B1 Q: C& O0 Y0 B0 N, }' A from j:=1 until j>selectab.ydim loop o4 [7 U6 i( L/ f) l
3 R% {" L9 c. B( {/ d$ K2 } if selectab[2,j]<mincomptime then* @. G* R2 f' A
j:=j+1;
1 z. s6 ]; n) G, @: J) f2 ~! D# } else
9 g! C7 m* h+ c% u/ o- n selecttab.cutrow(j);$ [3 I# ^8 H, `. D
end;
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j:=selectionrule(selecttab);3 n" Z# l0 s' w
7 r. x: L( n# O* X nstep;+orders[2.j]+1;1 d- ?; c2 @9 [1 e' k3 u
orders[2,j]:=nstep;
- ]/ c1 Q4 {* q0 t* U m:=orders[1,j][1,nstep];
7 c. b- |" L, t* \* t, ^4 u) r( ^; E c:=orders[5,j]" Y: [/ |0 [' }( k1 U
occres[1,m]:=c;
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--jieguo:start,end,res,job,step
0 |- _5 q0 H8 K" n# X3 z2 H7 ] scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);9 B3 j2 w; ^5 P6 a. n `
for k:=1 to numorders loop
: x$ }8 v# c: R1 x nstep:=orders[2,k]+1;+ _1 w: s8 R7 C) }# r, P
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
/ U, k, K! j3 c% k3 t: \ --
$ `+ t3 ?, e/ q5 p then
4 ^: F( C* o2 P orders[4,k]:=max(c,orders[4,k]);& k% w# ^. T+ Y: N- }$ @2 n; C
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];' @4 v( s) A; {
--
) ?4 ~% D5 B- q6 F; l end;
8 y4 f# u4 ?: v* ^7 @) K next;
& s1 i D, s& l nstep:=orders[2,j]+1:
4 E3 ^7 @+ z* T- h if nstep<=orders[3,j]1 Y& j! n, {1 n; Q/ s
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then
( i- U% N6 b/ } orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
5 n( E( e! q- N2 |6 J2 ^ orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
4 ?4 m* {0 H: ?" Y8 ` end;" L% u3 t: G9 H& {. A
next;
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: }" l5 S8 P; U2 ^. p' _. @( K print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});! F! z' A2 ~* O* \. |
mygantt;
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