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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
7 L+ m' W% N; t6 `* c, y; D
6 ~' K- e# @+ |, V7 D我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
+ D' Q/ n8 q+ t. O( Vbegin P_in arriving
$ F" u+ L2 `3 T% V% F- u, ~ move into Q_in# X) d9 t5 W4 {. @0 }9 j
use oper for 2 min
* W+ k% N6 f" ^& i send to oneof(0.95:P_in1,0.05:die)* X0 Z1 [/ @7 i
end# R% b* S: s2 l) c+ |4 u3 j! b
begin P_in1 arriving
0 g' C; J$ u$ A6 g if load type = load1 then
6 H t }6 t F1 _ begin
5 ~9 f6 `1 o+ n. z% `: Y, Z move into Q_m1) I1 C- k+ G1 F4 l9 o
use M1 for u 5,1 min
. e* d5 L! e6 a move into Q_out1
2 F9 J: L- K b- h6 i8 _ wait to be ordered on orderlist OL_17 Z( ^, @6 K: c
end
( w- V8 ~" E/ m1 f! \ if load type = load2 then! \/ X9 K2 \) Q9 A
begin
5 j$ O9 b: A8 I+ k6 W8 i& O move into Q_m2
: ?. L1 y7 H3 _; v p! P1 D use M2 for n 8,1 min. ]! m1 @0 ?9 ]+ {) G* d( T
move into Q_out2
& l" w6 i$ T. a2 L' s+ C wait to be ordered on orderlist OL_2$ ^/ H! C' x. C
end
4 C' c$ s4 N z# lend
5 A! c1 p# X4 B5 X, v9 ~begin P_dunmy arriving. y y3 C+ r; m4 s
set i = 19 x4 M6 R- l. q5 }9 G, u7 g2 E
while i > 0 do
9 K, ?8 L0 G9 ?( @ begin E* o2 G/ O# [' v
order 1 loads from OL_1 to die% \$ {' x* _- V
in case order not filled backorder on OL_12 `4 _$ m! Q0 r- N7 M. g
order 1 loads from OL_2 to continue
+ ]0 D9 A- e# M: @+ M5 M0 D in case order not filled backorder on OL_2
6 T% g! U* w4 \- y: J- A1 m% B move into Q_1
! W$ t4 n+ Q5 ]1 i& V use Massm for n 5,1 min
- c' w' Q7 U5 c' B. m send to die% w% ]: q* t. d/ P1 n7 }+ q
end
1 n* f0 f; L4 {; V2 |, k _" K7 J# ]$ Oend4 f2 P- B7 `' M$ n+ ?4 f# |
这是我的报告" t6 Q$ ~' w7 V I# K! w) X D6 j
*** AutoMod 11.1 ***9 N3 Q1 h5 y: Z
Model q
# q# H# u0 ^! q( B9 C: l% _9 C& bStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
7 d- l8 H, T: D0 RCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
3 g$ s8 f' N1 R& }8 h9 ~Statistics for Process System "q"9 F. n, B" ?/ R T8 ]
Process Statistics& o+ W9 L: {4 u, j! c q& B6 r
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
( ~" x. _+ M/ V, P, g========================================================================================# F3 {: n3 m) {9 {
P_in 222 1 0.32 -- 2 0 -- 126.04 --8 J8 l- U/ b0 j: x) D9 _
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
& z$ R2 r" ~ `2 t) \P_in3 0 0 0.00 -- 0 0 -- 0.00 --9 v3 W/ n$ D/ G' f) R; h% ]
P_in4 0 0 0.00 -- 0 0 -- 0.00 --
5 J6 K1 N# |; y. m2 q; jP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --, x9 D* }9 g( l) z0 }. [
Process Traffic Limit Statistics
/ p# D, g$ J2 KName Total Cur Average Capacity Max Min Util Av_Time Av_Wait* j: a3 Z8 r4 q- m n0 s
========================================================================================3 Q5 V# a, @, V. ~
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --0 f' B8 |( w5 x% u% o: F+ C
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --9 @# X3 P. T2 C- @. A
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
4 l. v# R$ B) f% D* YP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
+ E" @+ q, {, e3 RP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
( T6 _* j/ _: i6 w: c/ YQueue Statistics( }! @3 H+ Y9 A- L
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait% ?% D8 B: B1 r, u! E
========================================================================================% e z6 U+ ^8 A6 P9 m( [4 H
Space 223 0 0.00 Infinite 1 0 -- 0.00 --2 Z0 f p! ~$ R2 p! O6 I
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
, X h! i2 n2 U: m/ d a+ f; `2 S! DQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
: d$ d/ F" V: |8 [9 Y3 TQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
4 Y0 U$ s* Q) EQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --" {) x+ O( S. w. Y' r, x
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --8 i# M: k+ g+ n4 h' Q E1 S: [
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00$ l( k: d" V: e
Order List Statistics N1 y6 O8 W, r' W5 |( }
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
1 b8 u/ p8 q$ {* R================================================================================% n S) [) ~+ @) w' ?; S- M
OL_1 139 139 67.23 139 0 41789.43 10 `2 z1 b6 `/ K3 m
OL_2 71 71 34.26 71 0 41693.20 1
- M6 B$ r/ q6 V7 Y' N- qResource Statistics
* o# ~! S( q% fName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
2 q8 j: b$ M/ o====================================================================================================) x5 s) x" V; A/ a
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- . H# G T: a9 E7 ?
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- - T! N8 E1 W$ [3 l$ C' P4 E, P
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- " |! J1 u9 J, |( [9 a7 K3 _
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
: @$ @; r3 @ [7 E$ Z! W: K3 qRandom Number Streams: J; G+ c% ]( o7 z4 J) h
Name Total % z( g; K! C& i; U
============================6 a" J* m7 m' }* I
stream0 455
! w1 a' }1 U [2 P" z( vstream_M1_1 09 {/ o! n2 S; g" {- h, J
stream_M2_1 09 ~- S+ P3 d2 b9 D L
stream_Massm_1 0
3 [. g M8 r% A6 kstream_oper_1 0% x0 G, l& a' M [+ h3 p' o5 W# V
stream_load1_1 184
/ S9 M+ A% T% R4 Z1 z9 j% Sstream_load2_1 76
n0 _1 G, i0 R6 |stream_dummy_1 0* I% E2 u- F3 o9 B2 h# b% \1 s
4 \, O$ o$ [( P+ p请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
