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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:
* O# j0 J+ f" M n) h6 I9 w' xbegin P_in arriving
0 |, r1 ]' h& l: R# Z+ F" a) w! A move into Q_in
5 N* `/ O! ~7 I+ \, R. A use oper for 2 min+ |7 `6 f& R6 t7 I
send to oneof(0.95:P_in1,0.05:die)
8 f9 l" Z6 N- ]* e. m+ kend( A7 m1 |) o7 Y% u
begin P_in1 arriving$ p; d9 L. k6 W6 }# t1 \
if load type = load1 then8 A! E& E; X5 z6 s" ?
begin! ?8 o1 X! V7 N/ I: A/ X' n! h' O! |
move into Q_m1
7 k. K2 Z+ |- y8 K( T! N, E9 b2 g use M1 for u 5,1 min8 J+ P+ C! W; u
move into Q_out1: ~3 { e0 S3 L
wait to be ordered on orderlist OL_1" a8 E/ y( }, _; s) S
end
" e# z0 J$ M0 ^$ P! w: n+ B j if load type = load2 then
. n! B( {, q3 v- @ begin
, G0 T2 Q0 u4 K' d5 f) x$ ~% o" A3 t move into Q_m2
1 S5 k& e5 E; u( K# t4 k use M2 for n 8,1 min: r" h B# ?! {- G- t
move into Q_out2 M* _$ g9 c4 X& W. M
wait to be ordered on orderlist OL_2/ z+ Y/ [ J+ `9 _, H
end1 r0 ~+ h0 r/ ^- r4 f# a/ p
end4 g0 A0 G: a" o& d
begin P_dunmy arriving* s4 w0 |$ D& j7 |
set i = 13 I1 U) g9 c2 M
while i > 0 do
9 e# \, @8 x) C4 P! W p4 `% J7 m begin
( n& _& N! k4 y0 ?: `. R0 v* o order 1 loads from OL_1 to die5 T6 A/ u/ n# C( U; h
in case order not filled backorder on OL_1
0 D. q [ m! K" c# A* V# k, X order 1 loads from OL_2 to continue" u6 O: L6 r: X4 k+ ~/ e7 I
in case order not filled backorder on OL_2
+ _+ a5 t) i: i5 W6 f* ` move into Q_15 Y6 `3 m! Q7 |) u# U* `9 |
use Massm for n 5,1 min8 C' F( C$ ?4 w' j% ?) T4 y
send to die4 H; ^1 p4 P) ?# @
end
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这是我的报告
. n: W% q$ D! I*** AutoMod 11.1 ***
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Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
1 X2 c0 i% K W& f& uCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
" \% r% ?: h) }1 }! K7 B8 aStatistics for Process System "q"( K+ o+ n Y' g5 n ?( g
Process Statistics* ^1 L9 j/ N L6 T; u- ~
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait% A" X3 {; U2 P. ]
========================================================================================' `9 Z' k! ?5 X) M; N, R ^
P_in 222 1 0.32 -- 2 0 -- 126.04 --
) A7 f0 W* X4 L% M1 y1 uP_in1 212 210 102.38 -- 210 0 -- 41725.92 --' L' T! M2 d* p7 a$ U0 }
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
, x9 @ i' R% {- z- j; _P_in4 0 0 0.00 -- 0 0 -- 0.00 --
! m. a& `7 p( _$ \- d* VP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --! F/ l' F, f$ m5 M& g! q
Process Traffic Limit Statistics8 j/ \/ R1 O4 l0 u
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait$ h$ V6 h C% o) i" N c' `
========================================================================================
" m% B( j! Y/ [P_in 222 1 0.32 Infinite 2 0 -- 126.04 --/ x% _% @' v2 H* ?. R/ [& p W+ c
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --% \1 c' C: Q, v7 K' |' |+ L; q% l
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
( B! Z! w1 Q9 |' t' \2 z& OP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --" |9 p8 I' ]+ a% D& A( p% a
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
2 a" p8 B) L+ [& e1 u5 TQueue Statistics0 i" B/ N2 \) Z- z$ _" P# o
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait) a! A2 a# v) U. e4 \. Q* W
========================================================================================
9 I- c/ O3 X* e0 r) [, ~7 cSpace 223 0 0.00 Infinite 1 0 -- 0.00 --
$ O' G* m" |' e( TQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
7 e1 i/ W1 c% u7 ~5 w& lQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
( I( `" p T# ]# jQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
( r: U* k2 \: ]7 K; I) VQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --* I4 M! Y6 \5 y# R
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --& M+ S- l2 P: x+ h5 s/ C/ o; d
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00. e' S2 t0 R2 I- v/ T. `1 B+ N
Order List Statistics) _- l) Y# ^" P4 w
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered5 I0 ^- P | \7 r% t6 \7 X
================================================================================5 y6 E4 e0 L! z$ ?9 V
OL_1 139 139 67.23 139 0 41789.43 1# k9 ?2 I8 Y- d. v9 _
OL_2 71 71 34.26 71 0 41693.20 1) q6 H1 W1 N9 f0 l
Resource Statistics! \4 M8 s, H& r4 O
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State ( R* W* Q J) @& }' k; D+ T4 h' c
====================================================================================================
1 f3 L' N5 {7 A2 ?$ l9 _) LM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- % ?* U/ m3 L% L. L4 g1 d
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
! g6 S; n7 i7 F3 VMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
& u$ |% f8 c8 O9 K4 b7 h; ]oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- 9 q4 [) o* `6 \: F
Random Number Streams" j) y3 x, z/ P1 K
Name Total
2 m7 g9 W+ r1 `% p. T============================
/ G' b2 A. u$ K* Astream0 455" ~& U3 V, U6 L+ }
stream_M1_1 0' R' ^, D, _& N9 Z3 q S: v
stream_M2_1 0 E& Y; o/ _( d) ]$ F D
stream_Massm_1 0
+ c- {2 c( ?9 b8 c3 o ~% }9 J( v: ystream_oper_1 06 I0 I2 a+ s8 t+ r- y% h# {
stream_load1_1 184
9 _8 b) W0 A g4 Y+ L* F- Cstream_load2_1 76
C$ d) u+ c% O7 C$ I7 Z% Y0 }1 Ustream_dummy_1 0! C# i+ t6 ~+ p$ V5 A, v! M% P
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请问我的错误在那里?我用的版本是11.1的学生版 |
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