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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
6 q( Z1 u, N" Q0 u& R, f6 s, b1 z f7 ], L1 { ]9 R& \( F& |8 _# P% G
我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
# S: p9 K7 @, [# O2 K7 O m2 rbegin P_in arriving. N. {) b9 f/ u1 Z% C' C R! X0 j
move into Q_in2 G- a) \+ m' q- `; w
use oper for 2 min- N0 z! d$ h d
send to oneof(0.95:P_in1,0.05:die)9 z, m1 s: W. B2 T1 P5 E7 c
end% M4 f1 @' C! g% f
begin P_in1 arriving
; N8 o, x1 s* g8 m. A0 [ if load type = load1 then
$ M# }: F0 J. K; Q' { begin" ~% [$ t6 D c
move into Q_m1
) Z9 C1 Y% H2 \5 W+ X, a0 W: ^5 c use M1 for u 5,1 min
7 P6 L9 T. K' V7 \4 o/ | move into Q_out13 e( S9 h0 o z' n6 A1 ]2 w" S
wait to be ordered on orderlist OL_14 K4 k, V% v* c# ~% D
end
( x y% U$ I* A- k& l" C& O P" ] if load type = load2 then
. ^: [& B! k" Y begin8 H3 N( H4 y: @% T& v' q2 F
move into Q_m2 [" H2 S0 r: `7 L; o
use M2 for n 8,1 min l3 b) L9 [1 N& P6 _# A$ {
move into Q_out2
: U+ j, l3 |/ _$ a. B, Q wait to be ordered on orderlist OL_2, m/ u% I# |9 b0 ~1 o. ~
end
% X6 D& k) b9 t; d0 V# D2 xend0 X% |( ~* I i* f2 U6 l
begin P_dunmy arriving+ B6 Z0 a& D; ]' Q
set i = 1- G+ N: L, }! u0 z' l" j
while i > 0 do7 e: R' T4 o4 ]( ?! x `8 Y! R
begin
3 X1 V+ W+ K) U5 S/ [. h order 1 loads from OL_1 to die: @, _2 Q* R9 A2 i6 b
in case order not filled backorder on OL_1/ Z7 x. W9 ?- U' X4 v* |+ `
order 1 loads from OL_2 to continue
/ ?/ A2 K% b6 v. J, ^# I3 u& y; k in case order not filled backorder on OL_2/ |1 ]" _( `1 D' i
move into Q_1- i6 i$ S2 ?, x( L- m: c+ g
use Massm for n 5,1 min
4 J' q# w# q' Z send to die
) g* ] K% a+ d( c- Y3 `, e- f( ~ end
e: t0 n4 G- e I# w, a5 uend
/ i9 [7 p/ ?1 V6 c这是我的报告1 [* E+ f& q$ [) n9 G' ^
*** AutoMod 11.1 **** X* E' j+ ]+ n1 P+ B/ N
Model q. f' t9 o2 h5 U, f3 _ }! b
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.009 C5 ?' e( k) Y6 o9 c8 ?7 H
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
1 y. t9 J! B- _$ l1 |' M( e4 Y( ?Statistics for Process System "q"
1 ]( @, X4 ]2 x$ q! H; _ B+ S/ Z+ {Process Statistics
# A5 c2 K$ I+ W. YName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
& ? c e. S8 a g======================================================================================== D x2 N1 d/ @+ u
P_in 222 1 0.32 -- 2 0 -- 126.04 --
, n) z, `& o6 V8 d3 S% ?9 uP_in1 212 210 102.38 -- 210 0 -- 41725.92 --/ W" a5 z; x; {3 J" \5 w, i
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
4 Y; O; U& R- L* ?2 GP_in4 0 0 0.00 -- 0 0 -- 0.00 --$ B% x! Z& m! n7 B& T
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --( y4 y0 k2 W( v! I9 H0 Y
Process Traffic Limit Statistics! h2 y- s" G7 o7 Y9 L Y
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait& }. N: m; l# O1 s
========================================================================================" r+ k9 V$ i- K8 O& r. D
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --$ t' E6 q! _- ^% I
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
' Z# ?/ I. k9 w6 ^P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --" [$ x3 S. Q% ?
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
/ F5 S9 s' o( Y. t' _P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
7 t( L% C0 @1 t; C( d7 M3 |& ^Queue Statistics) a, t+ C9 |; \- U7 S
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait% ~7 z0 Y+ c+ e8 _, S
========================================================================================
5 w, o0 S* V! ?Space 223 0 0.00 Infinite 1 0 -- 0.00 --
: y# v9 a0 i! x) U* x+ SQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
+ s& @( ~ Z4 _* ]# @% f9 w3 B4 jQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
" |- E9 L/ L3 d' s' e* Q: `: wQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --9 J3 A! |+ b( {2 D& z4 e* o- F+ `9 m
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --' G$ |7 _; {7 M+ S9 L
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
+ V- I( b* a4 n- lQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00. ~4 Q3 ?" g& n u/ v# I# y3 t
Order List Statistics
' ?9 T6 n: D9 H4 N! LName Total Cur Average Max Min Av_Time Tot_Back_Ordered6 e7 t% Y5 E5 E# J
================================================================================. q) ~) |2 X1 Z
OL_1 139 139 67.23 139 0 41789.43 1
' R( ?% m. @* }' s% d7 [8 r: q8 `OL_2 71 71 34.26 71 0 41693.20 1
$ [% `! p" P# M0 V: Y& HResource Statistics) N- j0 p2 e$ e4 w5 S6 B
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State 4 ~0 z6 K- d! L2 P5 ]. g8 V
====================================================================================================# g' I% Y Z8 \
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- " m4 Y) [( S' U; k6 p
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
6 ^, Q; o' {* ]Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- - J0 Z2 e+ a1 u# ?& v
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
& ^0 f) k2 j: b! tRandom Number Streams7 u, [/ U" d* {; W8 f8 x! @6 R3 i
Name Total
' _# \: C7 j! ]$ Y2 m ], i) l============================. j8 W: t9 A& n' A9 n
stream0 455
7 }9 }+ t( g: O( F, I: p5 Y- pstream_M1_1 0
+ f- x: F6 S7 s0 H" r' @' o& [8 z* lstream_M2_1 0
$ X+ ~" s" B! F4 ^! estream_Massm_1 0
- }3 u* J# P! S& s C- Sstream_oper_1 0! Q3 R+ B: v" F/ z _
stream_load1_1 1840 n2 Q% i9 o: {8 a' N9 i
stream_load2_1 76( Z) E3 H, W" f1 C/ l T/ m7 s) S
stream_dummy_1 0# [( G j- _) [& { l$ `, X6 Y* x
U! o. C" [! a: K, d8 ~请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
