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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 & A, g6 \, G) G0 O* s7 f% }! a
; o( y% R. k/ P! i: n D9 h% z1 a我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：. W8 ]( Y2 {2 M4 s9 e& u, ]
begin P_in arriving
) I6 Z. f; h( v' T6 E move into Q_in) ]8 M& T, S7 |% I
use oper for 2 min
- L, S1 h8 W$ w. \5 f+ `5 I+ x send to oneof(0.95:P_in1,0.05:die)
5 a# \9 ^0 j# \; o1 D' qend
5 ]) y" H+ f/ C( D* e. Kbegin P_in1 arriving
1 e1 f6 U5 K5 E3 @ if load type = load1 then
. m/ m; w9 a0 `2 A5 ^ begin
3 b* y' \: X. N5 \ move into Q_m1
`! R4 @2 }2 s* B$ [ use M1 for u 5,1 min
& D; m7 x8 p+ s, ^1 r, I( h move into Q_out15 c. z$ D' t+ M3 j
wait to be ordered on orderlist OL_1, X* }# p# D& m* q
end1 c1 w# P* C$ j
if load type = load2 then' e0 c' x- W0 z/ a
begin
k& A. j6 m4 k$ f move into Q_m2" i" B+ H n$ K( K: x- U n3 x5 \
use M2 for n 8,1 min5 ?" K% m4 w ?, I' S# C; h5 t
move into Q_out2
/ D& E5 X6 T9 h, O wait to be ordered on orderlist OL_25 b- h! P+ e. X; }( Z, k
end
" }; s4 h) |+ i( E! T8 [1 vend% l0 q6 e2 n; G; Z- ^" K- |
begin P_dunmy arriving
8 }) {" F* @! F" p! n( W set i = 1
1 g( ^$ m( P3 ]0 M; b: Q while i > 0 do7 k5 N# ^3 Q7 `8 t) N" J
begin
2 M/ L" O. {2 l0 b9 h order 1 loads from OL_1 to die6 E* I- r' f3 l; L
in case order not filled backorder on OL_1
' d5 R4 L1 O p" [ order 1 loads from OL_2 to continue
4 }% p# A* o( [7 v4 w: w0 c9 ^, | in case order not filled backorder on OL_2
0 `2 i' X5 Z4 t; I move into Q_1
0 f/ s- F# [( Z( q, \ use Massm for n 5,1 min
/ F1 L1 i% A6 C0 C send to die* |) {% a: G9 h, h3 W- s
end- w3 x3 L5 } d7 S& P( e6 J
end# I/ M/ e) o- L& e0 G
这是我的报告1 M) @2 j$ p" T7 n! C+ l
*** AutoMod 11.1 ***
, }' f4 Q. h5 f7 n, e IModel q& j7 K, u ~5 J# J% a
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
$ f' s1 T8 x; X- MCPU time: Absolute: 42.859 sec, Relative: 42.859 sec* g+ G" q1 P* l$ a: T
Statistics for Process System "q" s9 p+ \! c) R% r
Process Statistics
1 u+ e# B# @5 E4 |6 ^" kName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
# ^4 }7 e! ~: I% C R========================================================================================
! L5 j4 ?/ l _P_in 222 1 0.32 -- 2 0 -- 126.04 --" ]9 w+ N' A1 j. U! s6 E
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
" P$ T& z; t' I( Y% t9 vP_in3 0 0 0.00 -- 0 0 -- 0.00 --6 K+ w% u6 H! i4 s, a( H# f) e1 D. j
P_in4 0 0 0.00 -- 0 0 -- 0.00 --
2 P- J. z: |8 D* p. y, O( l& T+ b- eP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
3 r7 v% A& _) p' |# O8 |, \2 v- U3 f) O9 n# ]Process Traffic Limit Statistics) I c) `( E2 e5 k# ~
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait& v. }: @. C1 l T
========================================================================================5 E# X! A6 @% n
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --7 q* [1 Z! ^& [# B, ]% k
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
+ v$ o& {$ H; H& q# y3 HP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --& d8 T0 l8 \% C
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
6 O( \8 y; [+ y# w& IP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
$ y- w% Q% m4 r9 uQueue Statistics9 G& I u8 p$ f: f9 x! e! i
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
8 N3 q" S1 n$ i: H7 E# f b+ D========================================================================================' k% \5 C6 y; W
Space 223 0 0.00 Infinite 1 0 -- 0.00 --
4 C9 H) U$ P! Z7 t9 F( ?( fQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
( H7 ]3 t9 y" D. \ FQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --+ B" A% x1 C. w% L
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
5 y6 {* O. ^9 b# e% _4 nQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
0 D" H& P1 n {7 h. d8 wQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
7 ^. k& ~5 w T }- w' kQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00
* _0 m& a( U: C+ Z$ i+ VOrder List Statistics
; S4 `$ O _5 Q5 u5 _* T1 TName Total Cur Average Max Min Av_Time Tot_Back_Ordered4 p, B0 H$ I/ Z- r* P- z
================================================================================ v A& @6 Q* f3 w* G4 E
OL_1 139 139 67.23 139 0 41789.43 1
/ I! F( `, x2 h+ ~5 ]# gOL_2 71 71 34.26 71 0 41693.20 18 ~% M0 e4 A/ Q5 I
Resource Statistics
9 U' _( P! s/ h3 A! s4 iName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
5 \* G; k( X0 [4 m5 O; ^====================================================================================================
% R8 e) Z8 A$ d5 F2 w" h- l) HM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- 8 D" Q- t$ U$ L' K2 m! b! U
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- * ~; J' `) o# A& k3 o
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- 2 ]0 s, ~1 ~8 ~ D/ h4 z
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- * v5 w1 @% ], k0 L3 \, [
Random Number Streams$ G- v# G& s& v" K% J
Name Total 0 }+ @* f0 q0 H- C0 Z
============================
9 q& [9 z( ^0 `. S# @; k9 D# bstream0 455+ F2 [$ C1 u8 u4 v/ l
stream_M1_1 0
9 N3 ~- r" _3 [' |. l$ Estream_M2_1 0
9 x+ p5 r7 ]/ o- x, P8 xstream_Massm_1 00 x: I1 y' d. W# L
stream_oper_1 02 c2 s; Q# B: t1 O. Z! z# _
stream_load1_1 184, D! V, c3 d6 _# S
stream_load2_1 76
) d% {& X) g8 z0 Fstream_dummy_1 0+ V+ D: v. O+ H/ |$ z9 p- P
' v' B: |( v# ?1 i. t. t1 {' C
请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
