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[求助] 本人初学auto mod,有一道题目希望大家赐教

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发表于 2009-10-3 15:08:34 | 显示全部楼层 |阅读模式
刚刚开始学auto mod,这道题目搞不明白,希望大家看看 题目是这样的,& K, _/ `. j! ]$ F. Q
  Create a new model containing three independent processes, each with one operator. In each process, loads first move into an infinite capacity waiting queue, then into a single-capacity processing queue.+ @) x9 ^% N. r2 v, E1 y7 A
  Loads are processed by each operator for the following time:
2 I9 j3 R$ o) Z4 u9 R' R  Worker_A does the job in a normally distributed time with a mean of 60 mins and a standard dev of 10 mins.
- B5 {; h& D4 R, H  Worker_B does the job according to a triangular distribution with a min of 30 mins, most likely value of 60 mins, and a max of 90 mins.
. h/ h. }, {/ e( E9 p1 w6 b  Worker_C does the job in a uniformly distributed time between 30 and 90 mins.7 s5 u; {2 V  @7 }1 e
Send loads to each pocess at the same rate (an exponentially distributed inter-arrival time with a mean of 68 mins) to understand the difference in the processing times of the three workers.1 Q. C' k/ h/ S6 ~% D( j
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问题:
4 A8 M2 Q) l# A7 Q, E$ ]After running the model for 10,000 days, what was the average number of loads in each process?) ]- u( w" m% e! G' D* n1 h; n3 j
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不胜感激!
发表于 2009-10-6 22:36:13 | 显示全部楼层
begin P_A arriving
& N; o- Z5 w( G) C9 o& Cmove into Q_wait /*Capacity is infinte*/
) `' a; l% c  _% D; F3 Q6 Gmove into Q_process /*Single capacity*/
# e  w* ?: k/ o0 m; I* P6 F* R  c0 s2 s7 I+ y, J* \7 h6 [1 h, D
use R_A for n 60,10 min /*Resource A*/
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3 k) F2 x7 a0 T$ qsend to P_B" N. o" Z6 y" j' a* H
end, X) u6 Z+ V, J! S9 I
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P_B and P_C is similar! r9 s) I" d$ D( I1 C
triangular 30,60,90 min
# r  o0 F$ V% `. V# [7 J" ^) \" Y: U$ `/ Cu 60,30 min
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: B! I* x! E* U* {7 P6 v% z! zin P_C, you need to send to die.$ P6 |6 w+ G" C6 b" f$ T( j+ _

+ g0 \! f% G% y- M1 R7 \Then You need to add a L_Control to drive up the whole simulation. and a Run Control of 10000 days.1 m& ?7 a- N% t
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; I! P: f- |5 V. H) t+ ~2 TRemember to turn off the animation before you run your model.

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 楼主| 发表于 2009-10-27 23:53:02 | 显示全部楼层
thanks...
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