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[求助] 本人初学auto mod,有一道题目希望大家赐教

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发表于 2009-10-3 15:08:34 | 显示全部楼层 |阅读模式
刚刚开始学auto mod,这道题目搞不明白,希望大家看看 题目是这样的,
7 }3 }0 W% U- H! y/ u# j  Create a new model containing three independent processes, each with one operator. In each process, loads first move into an infinite capacity waiting queue, then into a single-capacity processing queue.7 M2 T- }- y  j6 j2 t) [
  Loads are processed by each operator for the following time:
4 g) y6 f/ k" D! y  Worker_A does the job in a normally distributed time with a mean of 60 mins and a standard dev of 10 mins.
8 \& N' R8 w% G  F7 G% U7 r6 t3 c  Worker_B does the job according to a triangular distribution with a min of 30 mins, most likely value of 60 mins, and a max of 90 mins.
: F9 c% G2 r8 ^( b  Worker_C does the job in a uniformly distributed time between 30 and 90 mins.* e6 [# X% P# R( g5 D, _# o; o/ ?
Send loads to each pocess at the same rate (an exponentially distributed inter-arrival time with a mean of 68 mins) to understand the difference in the processing times of the three workers.
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问题:
- j- H0 x2 ^0 R% N" H# L! b" Y& vAfter running the model for 10,000 days, what was the average number of loads in each process?4 r: D, ?- M. r
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不胜感激!
发表于 2009-10-6 22:36:13 | 显示全部楼层
begin P_A arriving$ }6 A% S# T. F+ a: ]% W
move into Q_wait /*Capacity is infinte*/
! D* O" p" z2 @7 V9 p& C! Mmove into Q_process /*Single capacity*/7 h" B6 R7 q/ O# r5 i5 I. ^# l

  ?2 z+ L- r8 u0 r3 H% yuse R_A for n 60,10 min /*Resource A*/$ L. R0 u4 o+ {" L1 H1 s2 z

! V( p( q" q. z: |5 \& Z' C3 _  S+ Bsend to P_B" G9 B6 S1 _$ O* ]4 T' h8 ~4 O
end+ u% c$ \* \, J6 S9 U& q4 L# y
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P_B and P_C is similar! J( p& w6 m5 z) V
triangular 30,60,90 min( ?% C4 d' Q1 ^! g4 z0 W" E
u 60,30 min" m# O1 v" [& ~* D
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in P_C, you need to send to die.! _6 E: Y/ N* r

; n( J% E; v/ [/ ~& c( `3 H: r! jThen You need to add a L_Control to drive up the whole simulation. and a Run Control of 10000 days.0 H+ r* M8 A8 [/ j" E: g5 n6 K

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Remember to turn off the animation before you run your model.

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 楼主| 发表于 2009-10-27 23:53:02 | 显示全部楼层
thanks...
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