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[求助] 本人初学auto mod,有一道题目希望大家赐教

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发表于 2009-10-3 15:08:34 | 显示全部楼层 |阅读模式
刚刚开始学auto mod,这道题目搞不明白,希望大家看看 题目是这样的,
( R1 v% s4 s7 t" E  Create a new model containing three independent processes, each with one operator. In each process, loads first move into an infinite capacity waiting queue, then into a single-capacity processing queue.* q; u! z& K9 k- ^
  Loads are processed by each operator for the following time:5 V& K* L- F5 `2 e! A8 U2 n
  Worker_A does the job in a normally distributed time with a mean of 60 mins and a standard dev of 10 mins.; R1 Q* e9 F# B8 M( r- M
  Worker_B does the job according to a triangular distribution with a min of 30 mins, most likely value of 60 mins, and a max of 90 mins.
  w- W1 \3 F* L% b9 h! i  Worker_C does the job in a uniformly distributed time between 30 and 90 mins.
; \2 V, L* H# ^- tSend loads to each pocess at the same rate (an exponentially distributed inter-arrival time with a mean of 68 mins) to understand the difference in the processing times of the three workers.2 o1 [- g; k, a$ u5 m; s/ t
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问题:
0 B  k. v. z7 [, F2 mAfter running the model for 10,000 days, what was the average number of loads in each process?
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) V* X& D2 w5 [2 p. v  N& X1 F不胜感激!
发表于 2009-10-6 22:36:13 | 显示全部楼层
begin P_A arriving3 F. o7 X. B9 H1 e( u2 d
move into Q_wait /*Capacity is infinte*/# l; H( t2 _4 U8 J
move into Q_process /*Single capacity*/& Y6 \: I% Y2 ?9 G( U6 x
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use R_A for n 60,10 min /*Resource A*/1 Q9 M  P. h; y) G" y

7 _" x1 F1 X9 x* t+ m( r6 qsend to P_B
% K0 P4 ], A- e# d$ }/ p( ^end
' e) p3 J/ q2 r- c1 t4 v5 A5 J; ]7 o- X/ `5 {' y
P_B and P_C is similar
, m" S0 d, h, l2 Qtriangular 30,60,90 min  c: @4 n' \2 D9 Q' `
u 60,30 min$ U4 r) r: k. g- h3 |( u/ c
+ e  j3 _) e" T' ], @/ N4 Q

6 i' H! U! v% Xin P_C, you need to send to die.
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- l4 W. x) J; v9 i, GThen You need to add a L_Control to drive up the whole simulation. and a Run Control of 10000 days.6 j* @# H+ k$ E. m" A  @
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0 H0 f8 E0 ]+ L/ c# V' |; \Remember to turn off the animation before you run your model.

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 楼主| 发表于 2009-10-27 23:53:02 | 显示全部楼层
thanks...
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