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[求助] 本人初学auto mod,有一道题目希望大家赐教

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发表于 2009-10-3 15:08:34 | 显示全部楼层 |阅读模式
刚刚开始学auto mod,这道题目搞不明白,希望大家看看 题目是这样的,
, ?6 m- W- q$ C# f  h  Create a new model containing three independent processes, each with one operator. In each process, loads first move into an infinite capacity waiting queue, then into a single-capacity processing queue.
' }! ~" ~8 X" h. w$ p+ F: X* d8 U  Loads are processed by each operator for the following time:6 G( ~5 U, s# I( m
  Worker_A does the job in a normally distributed time with a mean of 60 mins and a standard dev of 10 mins.
: }2 h, G% ~. j  Worker_B does the job according to a triangular distribution with a min of 30 mins, most likely value of 60 mins, and a max of 90 mins.
  n) F+ w* e" C1 I0 t  Worker_C does the job in a uniformly distributed time between 30 and 90 mins.
# p" n# w( ^( n% I( a  K0 ~& O# p* {Send loads to each pocess at the same rate (an exponentially distributed inter-arrival time with a mean of 68 mins) to understand the difference in the processing times of the three workers.3 z/ {+ r- X+ k. L- T% l  S
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问题:
3 L9 M0 o0 y# q: [( r* m/ YAfter running the model for 10,000 days, what was the average number of loads in each process?
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不胜感激!
发表于 2009-10-6 22:36:13 | 显示全部楼层
begin P_A arriving: {# p# b- ^2 H0 D, u
move into Q_wait /*Capacity is infinte*/
1 G# Z. D5 V5 n) S! y- a( qmove into Q_process /*Single capacity*/
1 Z4 u2 `* a+ B) u* E. u: y- \" @5 v* F4 l
use R_A for n 60,10 min /*Resource A*/
5 l% \0 e  a5 L% y  |' y" P
8 J5 n2 c* m$ O7 v0 M% p0 [0 H$ T0 tsend to P_B
9 {# C/ I$ M* x% `8 {4 R/ _& F4 |end( g/ j% I" R+ l, _2 z. o/ V
4 D, a# w0 n( l  J
P_B and P_C is similar
- Q$ d+ A7 R+ R' Atriangular 30,60,90 min$ W7 v7 T4 K7 Z+ |. t+ ~! U
u 60,30 min6 O5 Q) \" z; E& b7 k7 l
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* I6 B# ~: H) _. d" y" T4 V6 bin P_C, you need to send to die.
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Then You need to add a L_Control to drive up the whole simulation. and a Run Control of 10000 days.: e2 ?8 h5 W: {/ S. Q

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% d0 F2 A. l6 Y9 ORemember to turn off the animation before you run your model.

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 楼主| 发表于 2009-10-27 23:53:02 | 显示全部楼层
thanks...
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