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[求助] 本人初学auto mod,有一道题目希望大家赐教

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发表于 2009-10-3 15:08:34 | 显示全部楼层 |阅读模式
刚刚开始学auto mod,这道题目搞不明白,希望大家看看 题目是这样的,
  X% o+ c8 L+ Y/ `/ ~  Create a new model containing three independent processes, each with one operator. In each process, loads first move into an infinite capacity waiting queue, then into a single-capacity processing queue.+ H" Q) L$ e/ o+ w! B4 @
  Loads are processed by each operator for the following time:4 P* M0 A: }# E
  Worker_A does the job in a normally distributed time with a mean of 60 mins and a standard dev of 10 mins.8 q7 ?5 G! |: C3 ~6 n( Z4 N5 B6 e6 w
  Worker_B does the job according to a triangular distribution with a min of 30 mins, most likely value of 60 mins, and a max of 90 mins.+ `( W! J3 y4 k  I8 t/ E
  Worker_C does the job in a uniformly distributed time between 30 and 90 mins.
' f+ e1 P' b3 [Send loads to each pocess at the same rate (an exponentially distributed inter-arrival time with a mean of 68 mins) to understand the difference in the processing times of the three workers.$ H9 {& C# |8 s2 M" m% I2 ]

3 j' C9 c7 [# G: v* ~问题:
2 D/ S+ B) F3 q4 B0 z+ X- UAfter running the model for 10,000 days, what was the average number of loads in each process?
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不胜感激!
发表于 2009-10-6 22:36:13 | 显示全部楼层
begin P_A arriving& a3 l( K2 o$ A# Q+ C* Q  v* F
move into Q_wait /*Capacity is infinte*/
4 R# H/ _' Z6 O* amove into Q_process /*Single capacity*/
# w  P( U# K' s) d6 f" e& G/ l1 [; I5 l! b- _( \
use R_A for n 60,10 min /*Resource A*/
1 l0 m9 x) A  p
5 o9 c/ L! [/ \4 c6 u/ N) qsend to P_B
7 Y- E0 z- U5 e$ x4 p$ Q2 `& n$ s3 Bend
  x) ?' `9 Q- j! O. H( ~+ F1 u
+ [' M. [- i5 E' a3 r9 G7 i; w, VP_B and P_C is similar+ r2 C6 Y; Q/ q, `8 Q" m
triangular 30,60,90 min% D6 R( S1 m9 r/ K7 N# k$ m# x$ _
u 60,30 min1 `& q2 s3 j5 s3 u
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. D; I, @0 [& Z# o4 y+ m7 lin P_C, you need to send to die.
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Then You need to add a L_Control to drive up the whole simulation. and a Run Control of 10000 days.
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* ]# Q& e" Q3 @; jRemember to turn off the animation before you run your model.

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 楼主| 发表于 2009-10-27 23:53:02 | 显示全部楼层
thanks...
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