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发表于 2010-5-11 13:19:52
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用list吧1 a/ P4 f8 k* Q0 y# ?
patches-own [wealth rank]
0 x3 ^3 c( L, Y9 q* U. Eto setup
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8 z. X3 k( ~" Q3 _- Q; q ask patches [set wealth random 100 set pcolor green ]
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& [" {' u0 C7 t* i% `& [ jto go* e9 F9 m& f+ {; A, @9 T
let mylist1 []
# u0 @' m+ F; _7 a! t# B set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches* E- A$ D, u8 ^0 j! o) Y
let mylist2 []
- c0 e7 }* s9 ~0 V7 [0 J% Y$ z set mylist2 n-values count patches [? + 1]- g. H2 k; _8 r6 F
0 \- s2 _0 X, X: ]% D* x ( foreach mylist1 mylist2
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) q. i ?; i L& B ask ?1[ set rank ?2]
% Q8 d2 z* n6 D2 k3 l show [rank] of ?1
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' O1 b/ c& c) y0 `8 @. | ]
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+ e* x: `7 S1 _) z6 j L let mylist3 []
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% U7 U' U8 V) l. ^6 l& Q2 B set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
" c# {4 H' O. p0 _* v3 l show count patches6 t3 z# C4 l q# r3 w( r+ v
show mylist1
# ^: z k1 R" O( {4 h2 o' z' y show mylist3& {3 U( G% g' O* t
end7 H* |3 b" s; d0 @, B: n! R9 ~
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这时的mylist1 和mylist3 应该是一样的 |
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