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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
; [6 J1 u5 T0 C* a  {1 r, o8 `5 |4 i. o' y+ r/ X9 [: c
public Object buildActions () {& r5 k1 O3 Y4 {5 g% V  L$ I2 Z  y
    super.buildActions();% j9 `( H" p+ U: i# p& D0 S" S
   
& U2 H0 v1 D! ?' m. F& X9 Q3 ]! b& V2 |% H    // Create the list of simulation actions. We put these in- A7 P0 I. E% \+ g% t- n
    // an action group, because we want these actions to be
* ?- o0 P. f: e* o% b: j; V, v    // executed in a specific order, but these steps should
/ n5 D; V! U7 I* \    // take no (simulated) time. The M(foo) means "The message
, l1 W7 V- t$ t6 h. \    // called <foo>". You can send a message To a particular6 z) f" [( m& g: R; \* n
    // object, or ForEach object in a collection.) ]5 [7 v3 l! @; s
        5 t, p8 @8 T( n- o7 n- ?5 K. Y
    // Note we update the heatspace in two phases: first run* L* B9 x" R  B& \5 D# w: _! x  O! V1 O
    // diffusion, then run "updateWorld" to actually enact the9 l$ M2 b2 e9 Y7 O* L$ n
    // changes the heatbugs have made. The ordering here is/ ?( H/ ?9 I% X' _2 a
    // significant!/ a! C. _5 q6 r
        3 n3 C6 l: Y" s% P' H, j
    // Note also, that with the additional
4 J- s3 ~$ u! d) s! e, q    // `randomizeHeatbugUpdateOrder' Boolean flag we can5 Z+ T3 Q  N6 G3 ^  D4 F' b
    // randomize the order in which the bugs actually run
9 a. q7 y1 Q+ J* I/ t    // their step rule.  This has the effect of removing any( _% W; z$ j9 B; |' Z/ Y1 G
    // systematic bias in the iteration throught the heatbug0 Q3 a6 T/ [# K; ~' t/ ]
    // list from timestep to timestep% Y4 _; H9 v7 ?0 K& L9 p# }, [
        2 o  Y3 n, K  P, A& s5 M4 u) E
    // By default, all `createActionForEach' modelActions have* _9 j! g: h' F; k: R# A2 `8 G
    // a default order of `Sequential', which means that the* s8 B$ j$ Y0 N. o1 ^% K/ A
    // order of iteration through the `heatbugList' will be& V7 _1 L  l2 P5 u. w2 J
    // identical (assuming the list order is not changed
  a& `( S  p- Y; D& p2 U& [4 j6 F    // indirectly by some other process).
9 w4 R$ x5 ?4 l( p, t$ m   
6 {  Q. O5 h( b0 ^7 t7 h    modelActions = new ActionGroupImpl (getZone ());
% q+ s2 y8 X3 @! O+ M/ N5 `8 [$ i# V; P/ v6 j1 {" y
    try {/ W% w/ |; ]/ N3 k5 a6 |8 l# r- `
      modelActions.createActionTo$message
9 @- A! {" `( K% Z0 G* h        (heat, new Selector (heat.getClass (), "stepRule", false));
: y+ X- ~+ E* K2 i    } catch (Exception e) {) ]) O+ |. L/ O& y
      System.err.println ("Exception stepRule: " + e.getMessage ());3 z  M* T- J) W
    }; h* S3 L4 c9 a" D0 n' x

" ~$ r. j; t$ K- \$ g. n, \3 ]- c    try {
( R# O  y" z( M      Heatbug proto = (Heatbug) heatbugList.get (0);/ U/ p3 K" |) Y# D6 n+ [+ v# v
      Selector sel =
) V/ g( A6 X2 U, F$ R3 u" Q; v        new Selector (proto.getClass (), "heatbugStep", false);2 y# q; g0 k8 H; i
      actionForEach =
% v4 R/ ]+ V" {9 B4 p6 h2 }        modelActions.createFActionForEachHomogeneous$call7 [+ N2 s4 V1 |# P; O& g6 T- ?
        (heatbugList,+ U1 V9 ^& `) K; _
         new FCallImpl (this, proto, sel,
4 M7 e# ~6 L1 {7 s                        new FArgumentsImpl (this, sel)));$ V8 j+ W  l$ P7 v7 C
    } catch (Exception e) {
0 n9 Z- N6 m5 S8 @+ h& Q  Y- e      e.printStackTrace (System.err);" d9 [/ Q' `8 X4 Z* ~
    }: f6 f+ m" e4 }2 ]+ Q9 Z
    - V9 d$ ]/ @+ j/ U. t2 W
    syncUpdateOrder ();6 h, l7 c& Q& A  h
; }: i% c: h, ?6 N' C
    try {
. d8 M. _; R" s      modelActions.createActionTo$message
! A0 d. V' y( X" z) I# N) J- A# l        (heat, new Selector (heat.getClass (), "updateLattice", false));4 p% y" Q5 Q  g, E/ e. m# ~
    } catch (Exception e) {
# \, n% P2 Z/ |5 b9 O1 ?" l! j      System.err.println("Exception updateLattice: " + e.getMessage ());
0 D  t6 h  m2 j' w    }
9 o: i% X4 M" V: b$ j        
( C* q# ]- z0 b' {" Y    // Then we create a schedule that executes the
0 E* K3 R5 V! D0 F3 m    // modelActions. modelActions is an ActionGroup, by itself it
( e. f3 C: {' ]$ t) S. w0 I# |1 B! h    // has no notion of time. In order to have it executed in
, d6 L. m- p, \1 z0 I* z    // time, we create a Schedule that says to use the
6 S) {) x. g$ ~4 r& I" @* b    // modelActions ActionGroup at particular times.  This0 D  i3 t/ l2 w' a' j
    // schedule has a repeat interval of 1, it will loop every9 z# {7 ]5 d4 j$ ]9 g( p" p, D+ i
    // time step.  The action is executed at time 0 relative to- L6 q. Y1 U$ r# ^& L2 F
    // the beginning of the loop.
9 ?" H4 w* D% b( h2 Y
' E- X' b' T: m. C: `4 l! ?    // This is a simple schedule, with only one action that is
; I- q/ [6 m/ u" D" [( m$ g6 f, `    // just repeated every time. See jmousetrap for more
( F9 C6 z) v0 a4 b( [. V& z) z    // complicated schedules.8 W7 k9 ^& F5 T& R
  
- O9 K, c6 }( R" a" v( c1 H& Q    modelSchedule = new ScheduleImpl (getZone (), 1);* H& K: g$ B6 ]6 c
    modelSchedule.at$createAction (0, modelActions);
/ L. p5 N9 N$ {$ O+ a5 q        
3 v$ e6 q  V' j' M* m* j( _# Q    return this;
4 S& u* A4 _# X/ o  }
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