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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:6 [6 q& r' z+ t9 X) k# H9 P& t
! V7 X0 y: z9 {" {* v
public Object buildActions () {( u6 q; w0 P2 _' R2 \: [: D3 l. z! S
    super.buildActions();
* O% o8 _+ H0 C) q    " r1 j9 J% |6 L0 M
    // Create the list of simulation actions. We put these in
: |# N6 W& z$ c3 u5 ~8 @/ F    // an action group, because we want these actions to be
; e5 X* q% C. `- ~5 e9 d; o    // executed in a specific order, but these steps should
1 f& N4 v$ L& c9 e; k- O    // take no (simulated) time. The M(foo) means "The message
6 [9 x+ X: e& r    // called <foo>". You can send a message To a particular: i" N  C" J* p- f
    // object, or ForEach object in a collection.
) f+ M7 r8 V6 B, h( w        
7 U3 I3 y2 l6 N0 v2 r3 c    // Note we update the heatspace in two phases: first run- H9 v, D; a% I; H
    // diffusion, then run "updateWorld" to actually enact the' a  C, Z, d6 L  h0 Y' h2 O
    // changes the heatbugs have made. The ordering here is
6 I. L- _2 I" k& J- G: S8 a    // significant!
) s* |( W0 ]! h        
6 ?2 t5 d" c% a* j5 g: j" j) l    // Note also, that with the additional
, ?4 `, m2 M4 q    // `randomizeHeatbugUpdateOrder' Boolean flag we can0 Y5 n: g! g, Y+ [1 m2 f. O0 u
    // randomize the order in which the bugs actually run8 A% W1 f+ E  c+ I* _
    // their step rule.  This has the effect of removing any! R4 B% B* o0 C& S" w0 f
    // systematic bias in the iteration throught the heatbug
/ a' M  F4 l4 L) t' h' `: }6 Y: z. }    // list from timestep to timestep
: [1 {; u+ t) |: n- `/ y        - f$ g. F6 O6 D4 E. V
    // By default, all `createActionForEach' modelActions have
  z  Q$ {  Y, @    // a default order of `Sequential', which means that the
& e# L) W5 @$ u2 c4 o5 j' s7 c    // order of iteration through the `heatbugList' will be
+ |7 |# O5 I. L    // identical (assuming the list order is not changed* a2 i5 d8 s/ Z( z8 b$ N# b2 [. `
    // indirectly by some other process)./ J8 O; D/ Y; a  f8 U1 O! z
    - I0 H$ l6 y9 a: [" ~3 a
    modelActions = new ActionGroupImpl (getZone ());$ x+ s! c  x# B" |" g$ Y$ H

( |& a1 Q- ?8 T( f7 q# P    try {3 G" ?0 a9 r% _2 ?( `
      modelActions.createActionTo$message# p  G7 ^- q% |+ Z! i/ b& T$ K( b
        (heat, new Selector (heat.getClass (), "stepRule", false));
2 ]% b* ]; f- e+ I6 \& B: T' V    } catch (Exception e) {
$ N4 X0 S% N2 Q9 P      System.err.println ("Exception stepRule: " + e.getMessage ());
9 I7 [, k# `. C( r; d: R    }0 X. e* D. F) L. L

) w7 w  @! U  X& ^    try {4 D( S/ A* q1 C# I# l2 u; f2 z
      Heatbug proto = (Heatbug) heatbugList.get (0);
' j- X- }8 I/ M; H0 s      Selector sel = / r3 Y" h$ s; g4 T
        new Selector (proto.getClass (), "heatbugStep", false);
: L2 Q! Z1 o0 Z: O! o2 ]1 b      actionForEach =4 w" o/ }2 t; \9 Z" c
        modelActions.createFActionForEachHomogeneous$call
7 s% ?2 U$ U. w& l- B3 [+ f        (heatbugList,- k4 X3 ?# }" @0 T: r+ y+ p
         new FCallImpl (this, proto, sel,8 M5 u" L9 @7 ~' e6 `
                        new FArgumentsImpl (this, sel)));
: @' L) R- [6 }: ~$ X6 y+ U0 _    } catch (Exception e) {1 a( l8 x$ W' S' {2 ?6 ?
      e.printStackTrace (System.err);
, A' r& I# ]& H* A    }
  l) l; c) ~1 C1 R6 R  R7 C    1 p) Z$ ]5 f3 i) s9 R. N; r" P0 ]
    syncUpdateOrder ();0 I- Q" U8 {& q

; l% {9 Y6 U* x& ]1 G5 S    try {
0 n9 P# t7 Y/ V: m# I( N) A      modelActions.createActionTo$message + _( ^6 r! y. A3 _) g
        (heat, new Selector (heat.getClass (), "updateLattice", false));9 z' }! p1 S. J+ c$ u6 m, N
    } catch (Exception e) {
) j1 j" e/ C1 E* w      System.err.println("Exception updateLattice: " + e.getMessage ());% T) d! y9 P4 u' y( K
    }
' j5 B: v9 B/ h# d; {' _        . Q' _# B" k7 i, f/ C- R, U
    // Then we create a schedule that executes the
) T9 I) E' R. A* F    // modelActions. modelActions is an ActionGroup, by itself it
- O. ?) \- D( f# K    // has no notion of time. In order to have it executed in' q6 p# x$ v, [4 Z9 ?
    // time, we create a Schedule that says to use the% @9 H4 b: L; N/ U  U6 Z
    // modelActions ActionGroup at particular times.  This4 R" z) W( L$ u0 P4 V! ^7 D1 L
    // schedule has a repeat interval of 1, it will loop every
. A, H( M0 w& `1 j4 o7 z    // time step.  The action is executed at time 0 relative to
4 W: Q& }- k2 v) i& A  o/ X9 [# _7 _    // the beginning of the loop.
( V6 i' n/ A4 L4 `. i5 {+ t7 W" Q( m
    // This is a simple schedule, with only one action that is( g" ?) R; C/ D
    // just repeated every time. See jmousetrap for more8 b5 q# k0 ~, ^1 x; m3 e
    // complicated schedules.
+ _2 p. G7 d% t) L# Z8 `, D% `  
* O* i8 N  d1 J' B0 h( J    modelSchedule = new ScheduleImpl (getZone (), 1);
8 o% V  J) z; H7 c, Y    modelSchedule.at$createAction (0, modelActions);
9 J9 u8 Q  ~1 W" H" d/ e% o        4 M0 J7 D: M# o' M
    return this;1 F& _  B. k/ N
  }
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