设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 9364|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:/ h- v0 x& G. ^" ]: p
, B% J; F8 v& u0 k1 {4 k
public Object buildActions () {
6 f+ Q  c" @: ^    super.buildActions();: x0 Q2 }; T7 ^, l7 O& q% G
    2 I4 k; k) u+ ~( o' W6 u
    // Create the list of simulation actions. We put these in. u3 Z4 d# [( i$ Q; I
    // an action group, because we want these actions to be
! v; I+ U2 h7 a5 i3 S    // executed in a specific order, but these steps should
5 x* @7 o; m& R- ]  N    // take no (simulated) time. The M(foo) means "The message0 M7 B1 H7 E) T
    // called <foo>". You can send a message To a particular$ Y3 H+ b0 q& x7 ^0 N
    // object, or ForEach object in a collection.
, X3 M% f5 u8 M" e        7 [7 w2 Z* ^9 X9 ~3 ?  C; h
    // Note we update the heatspace in two phases: first run
# q1 i* M+ U, D    // diffusion, then run "updateWorld" to actually enact the
" @: R& q6 E7 @& V- Q    // changes the heatbugs have made. The ordering here is
" e* U$ l1 n+ H    // significant!
4 P) q3 E' W& O        
1 K# E+ Q0 r: R' _7 F  {    // Note also, that with the additional
! N* \' {( y/ Y6 U$ K5 ^+ _    // `randomizeHeatbugUpdateOrder' Boolean flag we can2 ~; z! r- |$ R- c6 s& f) X
    // randomize the order in which the bugs actually run
" l2 v& M5 ^: `/ x6 x( d    // their step rule.  This has the effect of removing any
( X4 X5 x3 b7 v; y# R    // systematic bias in the iteration throught the heatbug
# ^0 n/ I8 G' [( }: h1 @4 ~, ]7 I; K    // list from timestep to timestep
; e2 p8 m; o% B( S) r7 T/ ~        
4 \7 G9 R! B' I+ \' [2 C4 R" [    // By default, all `createActionForEach' modelActions have6 Y! Q3 Z7 B5 V5 d
    // a default order of `Sequential', which means that the& S! }0 _9 ]  b& @# P3 W$ G0 N) Z
    // order of iteration through the `heatbugList' will be
# h. B: t1 t# S! Z3 V    // identical (assuming the list order is not changed8 _. [3 Y/ G" E
    // indirectly by some other process).
% [! F( ]' T5 p3 ^, c) y! N- i   
7 r' V' x! y0 K: G" F2 L    modelActions = new ActionGroupImpl (getZone ());6 k* R$ C' ?# |2 o  ?  @

: }0 L1 T5 |% G6 C. Z: Q* n; Y    try {* H$ L& y  g, l+ ~7 b
      modelActions.createActionTo$message
; x+ M( e1 A" J        (heat, new Selector (heat.getClass (), "stepRule", false));: j5 f) k2 t! H. u* h
    } catch (Exception e) {
: s5 [! H% A; ~- z2 Y- f# H      System.err.println ("Exception stepRule: " + e.getMessage ());
+ M+ ~( E" B% L1 l    }9 S2 o3 {- z- {4 e4 V8 s& j4 U1 V/ Y
) r4 C2 ?' `' S1 Y# S
    try {
, ^* |9 X( g% j      Heatbug proto = (Heatbug) heatbugList.get (0);
' T3 {9 z, p1 s/ i0 e; L1 V      Selector sel =
* F% l+ Y: e/ R( R0 J' n* Y        new Selector (proto.getClass (), "heatbugStep", false);
( n# X6 w1 _7 _" k  B      actionForEach =
8 t/ e3 i& s* ~$ A        modelActions.createFActionForEachHomogeneous$call5 ]3 j. Y1 K+ i# k
        (heatbugList,; C) D/ ~; y5 h& o
         new FCallImpl (this, proto, sel,
! U: i* j6 [7 \                        new FArgumentsImpl (this, sel)));
7 d) t5 I8 P! W8 E7 `) H, w    } catch (Exception e) {) c* i1 _6 e1 p. d* i
      e.printStackTrace (System.err);
* j" b2 d6 `8 v- w    }/ W  A8 Z" }) G7 ]
      `0 k: z; |8 s
    syncUpdateOrder ();% I5 z9 b: j' S6 t" E

$ e  n7 p  V4 |4 v- @    try {
' S# O6 F$ n& E) q, |. Z4 d- q      modelActions.createActionTo$message 2 {2 V* k! l, V1 P4 M
        (heat, new Selector (heat.getClass (), "updateLattice", false));1 w5 n! E) Q- c, h2 W, y
    } catch (Exception e) {2 k6 B$ |: }/ J
      System.err.println("Exception updateLattice: " + e.getMessage ());3 R6 L3 ]8 b' G
    }" S  c! f9 \% j; ~. N( b
        0 ~+ c$ G8 F. X* b, S0 t
    // Then we create a schedule that executes the, H% O# j2 @! D7 M& g
    // modelActions. modelActions is an ActionGroup, by itself it
0 y$ _% L2 N  g) t" b    // has no notion of time. In order to have it executed in
7 T* i" Z) }% D3 e, j    // time, we create a Schedule that says to use the
0 ~3 w/ K( i  j" a    // modelActions ActionGroup at particular times.  This( z9 q! ^7 U: P. Z: ]
    // schedule has a repeat interval of 1, it will loop every
. t* t2 f/ M5 v6 i5 o8 u% Q    // time step.  The action is executed at time 0 relative to5 d4 H8 O/ ~+ z0 C
    // the beginning of the loop.! h5 _6 j# W& s$ N
) v# b7 A: q" z. W3 @
    // This is a simple schedule, with only one action that is( ]: T  S$ r" l, B* w1 P' o( Z- O
    // just repeated every time. See jmousetrap for more  b9 _/ g: Y% d+ ]
    // complicated schedules.
6 I2 v* ]8 X% {; R9 g% I4 s  ( `; D) p; b/ i
    modelSchedule = new ScheduleImpl (getZone (), 1);- v( Z3 E1 |7 u( L9 U# h1 k
    modelSchedule.at$createAction (0, modelActions);$ ^! A. g; o- ~# T  d
        
  \/ u5 ~4 R$ y; I: i, z    return this;3 H/ d5 [3 Z/ w. z- J
  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-2-26 03:01 , Processed in 0.020401 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表