设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 8158|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:4 p; l/ w7 \" y# ?6 s$ W

5 J  W$ z9 q, s; S* Z5 a0 e9 v, L public Object buildActions () {8 B  r+ m" b+ j* S5 b" e8 X7 T* c
    super.buildActions();
5 u" }! j- _) W0 z   
2 y" Y+ B. w3 g5 D2 K& S& v    // Create the list of simulation actions. We put these in. L7 X! m& ]! \3 m
    // an action group, because we want these actions to be0 S8 c$ T: b, L0 o
    // executed in a specific order, but these steps should
: w, ?  w! `3 p  h0 }2 D    // take no (simulated) time. The M(foo) means "The message, d9 a' `- o0 F: t
    // called <foo>". You can send a message To a particular/ i+ d9 A) n: R+ s8 R; p
    // object, or ForEach object in a collection.
. ^! w! F  Z2 i        
6 @- `. ~' K7 z; w( W    // Note we update the heatspace in two phases: first run$ K/ u) |, M* Q; r* ?
    // diffusion, then run "updateWorld" to actually enact the
' ^4 D+ h6 v; ?, q, \' Z* K    // changes the heatbugs have made. The ordering here is
: a! j; a9 p& G6 G/ z    // significant!
+ k8 q+ h: O8 Z* W* N        
7 u8 \9 y% }, B. b  p( p( U    // Note also, that with the additional2 v, e. j( H2 n, q' c
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
3 K2 o" f8 i+ q- K    // randomize the order in which the bugs actually run
+ s5 l; W+ K) h; M    // their step rule.  This has the effect of removing any
9 m5 G. N' n/ A) x) D8 l( e    // systematic bias in the iteration throught the heatbug
1 F7 ~$ F  W& u) d( c    // list from timestep to timestep  U2 K5 |) `# ?2 j+ u4 d0 x6 ?
        
$ U( W4 O5 q0 ?& @) Q( F7 P9 X' k    // By default, all `createActionForEach' modelActions have1 q2 f! J5 Z3 |7 P( k
    // a default order of `Sequential', which means that the
: V8 ^" f9 @. q5 ?8 D    // order of iteration through the `heatbugList' will be
3 O- {# A& ]- M/ a7 p* T    // identical (assuming the list order is not changed+ e7 f. T  q4 _
    // indirectly by some other process)., }7 @$ D- M5 |9 ?) |
   
, v2 E$ a: D! Z1 Q2 k    modelActions = new ActionGroupImpl (getZone ());) Q( [# _' v2 Q& D

/ C3 [. G) W5 i    try {
7 X; z* Q9 ]" N/ v0 Y9 d3 P      modelActions.createActionTo$message
; ?& P  Y/ _. K; |        (heat, new Selector (heat.getClass (), "stepRule", false));  i% D+ x% ^9 V' R# C2 i0 b
    } catch (Exception e) {$ f, B1 J5 Y& z8 b* g  C
      System.err.println ("Exception stepRule: " + e.getMessage ());
( K/ S  _1 G' i& i4 m/ u( c" P    }. B- `' J, O9 \7 b

& W  g/ I0 |, y" @  {7 q8 g    try {+ S# b  I9 m( i( q" b/ @0 Z4 ~8 {
      Heatbug proto = (Heatbug) heatbugList.get (0);0 M+ [* C" Y  L+ i
      Selector sel = - z1 c4 n+ t" D
        new Selector (proto.getClass (), "heatbugStep", false);
/ }/ U4 ~) g- W# \7 V      actionForEach =" w8 G( N; K& e4 L
        modelActions.createFActionForEachHomogeneous$call
4 Y8 v! a, o5 _8 V) p3 H, f        (heatbugList,+ C2 ]: s. u7 A) l
         new FCallImpl (this, proto, sel,
1 k9 X* o1 `! d& v! b& x! r, k                        new FArgumentsImpl (this, sel)));2 y% S  A/ p* b7 `9 s
    } catch (Exception e) {
5 ?. G! S$ V7 s- _7 W% {* N      e.printStackTrace (System.err);" s2 w% l9 T9 u  @. I+ T
    }; b* c% F, G' ^7 Q
    / n9 }$ V! d- J) ^- k' t1 K
    syncUpdateOrder ();8 D! H0 W; Z& q6 i1 ]

/ X4 S1 J9 n7 A5 K6 N    try {( T" g. ~' W: y
      modelActions.createActionTo$message
% k# |: G* W" z, b        (heat, new Selector (heat.getClass (), "updateLattice", false));
7 ]: ~5 \# c- H    } catch (Exception e) {
' Q! H9 q  Q, ?3 z8 T: H+ y      System.err.println("Exception updateLattice: " + e.getMessage ());
9 ^/ w0 V% x2 [: |- M& a    }
% k2 U5 y- _7 |9 K        ' N- C/ @  a  D$ F
    // Then we create a schedule that executes the, N9 f  X3 C& t) o( M
    // modelActions. modelActions is an ActionGroup, by itself it
0 U6 ?- T5 z, {$ @$ U    // has no notion of time. In order to have it executed in' L8 s# X' h" a% h" c* ^
    // time, we create a Schedule that says to use the4 F3 k5 A4 I2 P( P  E2 n$ |9 J
    // modelActions ActionGroup at particular times.  This$ y( S3 O' d# A3 E* G
    // schedule has a repeat interval of 1, it will loop every2 T+ v) E6 R1 u; E0 A' q- C
    // time step.  The action is executed at time 0 relative to
2 m1 O3 u6 ]" V; C* J+ n    // the beginning of the loop.
1 M$ k+ n; n4 n( h& n% P  V! K5 X( O$ ~9 S2 ?4 [8 x( I9 Z: l2 C  H
    // This is a simple schedule, with only one action that is
  V) f; f' b6 D/ I4 W6 Q; _- X    // just repeated every time. See jmousetrap for more
$ I4 t! J1 {- `% y/ X' @& A' d( u    // complicated schedules.
0 }4 P& t4 v7 i6 m- R1 \4 E: d  
; d1 n& j. l0 a' o    modelSchedule = new ScheduleImpl (getZone (), 1);
) O- T3 `2 E: @9 \: ]    modelSchedule.at$createAction (0, modelActions);
% ^' q* \3 P  @% S( I0 p% g        , F: b% L% J2 }' S# f
    return this;
3 E+ c) j6 S" o3 a: j8 q  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2025-12-9 16:15 , Processed in 0.016746 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表