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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
: }- C/ Q* z) [9 K8 k1 e  @2 A' m3 k$ X/ j
public Object buildActions () {
" D2 z1 h7 S) p  B2 @$ g    super.buildActions();
8 J' v# ^. p7 D* c    ! b3 q; {! l2 A: e6 f3 `
    // Create the list of simulation actions. We put these in
" }$ G) h* \4 l    // an action group, because we want these actions to be& Y* n8 i( Y' R) ]5 c4 j
    // executed in a specific order, but these steps should
( m" J/ ?. ^- m( G- O    // take no (simulated) time. The M(foo) means "The message: u& c3 y! X0 U) I# N) }! J
    // called <foo>". You can send a message To a particular
9 g7 T: e% J% P+ W) u: ^" t    // object, or ForEach object in a collection.
2 r" v4 f" N2 L; m        
6 ?* Q- u" E* V) r. D( P    // Note we update the heatspace in two phases: first run% c/ h- }+ L3 ]' S  \  ~! N
    // diffusion, then run "updateWorld" to actually enact the
/ m. r, f+ @* p1 x0 U1 q    // changes the heatbugs have made. The ordering here is' D  ?, b9 }- E* W) Z; T
    // significant!6 D: [* x8 P- W- b2 ^3 x
        : w' |) Y$ f& M4 d9 N% X8 {
    // Note also, that with the additional5 h) B0 ]% e$ H4 w
    // `randomizeHeatbugUpdateOrder' Boolean flag we can% @. d' [# k" z7 y5 z8 O
    // randomize the order in which the bugs actually run7 ]) _/ ?- w: y7 x3 ^, {
    // their step rule.  This has the effect of removing any& Y7 |" T$ {/ z( _7 t/ v. d) F
    // systematic bias in the iteration throught the heatbug
( v9 u6 J: G3 B% i* E    // list from timestep to timestep( E* X7 W! A$ B# ]/ G. B, R" ]3 B
        
  s3 P- X9 J! P/ g) S% N    // By default, all `createActionForEach' modelActions have
- B6 ]: ^3 ^. O6 ~) W    // a default order of `Sequential', which means that the+ {, ^  K" K' F) F$ _
    // order of iteration through the `heatbugList' will be* f8 N$ Q+ m5 J6 \' i* `
    // identical (assuming the list order is not changed
7 U/ }# ^: W  }3 k4 @; ?    // indirectly by some other process).
8 H9 b( ~$ A* e! }0 [   
) k7 ]6 }# Y5 G; c) U2 R- i+ p    modelActions = new ActionGroupImpl (getZone ());
( t2 [3 X2 U. n" {9 k+ Z6 L
. F9 i* X+ Q/ k( U3 {    try {
  ]& w. U/ o) s- o$ @) X      modelActions.createActionTo$message
: U, y$ r0 e8 b- q3 j        (heat, new Selector (heat.getClass (), "stepRule", false));
+ _5 y5 K; _5 o, t    } catch (Exception e) {" x; n3 K1 w- m9 y2 b* t& w$ x3 [
      System.err.println ("Exception stepRule: " + e.getMessage ());: L- P0 H- }4 ~9 G. [4 v# S' a
    }" C9 z9 J, ^1 l0 u4 _, Y
0 p* \# l: f+ E  ~7 l0 T! {+ D
    try {0 b0 [; W# w) }
      Heatbug proto = (Heatbug) heatbugList.get (0);) E, @6 u1 ]: D! c* v% J
      Selector sel =
' d. `5 q1 ]# X! C0 |        new Selector (proto.getClass (), "heatbugStep", false);: `( J. V0 S4 u) ]' C/ i: {
      actionForEach =! R# w( H2 g" E
        modelActions.createFActionForEachHomogeneous$call
6 h: L2 o) n3 m. }! W% }8 ?$ o( l' }( _        (heatbugList,
4 ]  B& C: E; j& P/ D) d! W         new FCallImpl (this, proto, sel,5 F2 W, R% I0 \4 s8 n7 v
                        new FArgumentsImpl (this, sel)));
: U$ M. D+ A  U; _( k    } catch (Exception e) {% b' z4 L& W+ H
      e.printStackTrace (System.err);
3 \9 X0 a/ c2 ?" y4 \    }; ^5 K: Z* J5 A7 X9 k& n' K
    ; a6 A1 d. G. a# x
    syncUpdateOrder ();
  h2 N2 g5 L9 C4 w; H4 h7 t/ F2 m% M3 R4 ]1 N8 q6 t: P1 Q8 Y, S+ \
    try {
! S! f3 o4 L% p0 n      modelActions.createActionTo$message
1 Q$ D6 c9 s* z" N        (heat, new Selector (heat.getClass (), "updateLattice", false));) \6 }, v, ^' q# m/ ^* C
    } catch (Exception e) {
) V- |& n- j- G" J: I      System.err.println("Exception updateLattice: " + e.getMessage ());
  x$ x1 W$ P6 P1 M2 V    }
4 m( M  ?& Q. X; K  [" t        
: B; d  Q# v7 C1 V    // Then we create a schedule that executes the$ j' b* }% C+ Y" ?! s! Z
    // modelActions. modelActions is an ActionGroup, by itself it9 a  u$ m5 `* p( s7 h
    // has no notion of time. In order to have it executed in/ _" Z- {. d2 X2 {1 U% G
    // time, we create a Schedule that says to use the
% m  x. c1 z$ R  l    // modelActions ActionGroup at particular times.  This. I. ~. ~" b! A+ ]
    // schedule has a repeat interval of 1, it will loop every" O) E, u; {, z* [7 G
    // time step.  The action is executed at time 0 relative to
. _* I. t; C3 l  n1 i, k    // the beginning of the loop." f1 E$ \4 y( X: d
9 C1 g$ Q5 |. g/ o3 _/ P5 m  E- h0 j* |
    // This is a simple schedule, with only one action that is4 C# C5 {/ E: z
    // just repeated every time. See jmousetrap for more  S. V9 K6 s. y* `$ X, I' G5 s
    // complicated schedules.  p$ ?0 V5 Y3 q8 ]* w3 q7 x# r
  : _( k$ L  ]7 P, \" o) G. p  q
    modelSchedule = new ScheduleImpl (getZone (), 1);7 C  |; `2 w5 S. K5 z
    modelSchedule.at$createAction (0, modelActions);
. D" F6 b0 n. E& f" U/ w% \        
/ s+ U3 j- d4 o% x/ _    return this;
7 ^0 A% G% S& _6 }6 w  }
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