设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 8262|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:' a; N/ O0 d# u* ?
- D. U# z# [- Q4 M/ R
public Object buildActions () {3 x7 W( C# L- b8 [
    super.buildActions();2 _# E' `5 M: e( _/ y. P# p: i: {
   
3 |% j8 t* y0 M& z    // Create the list of simulation actions. We put these in
$ G3 E/ T! c7 |5 \    // an action group, because we want these actions to be* K0 |& Y& A7 ~
    // executed in a specific order, but these steps should
, g/ T8 n; u9 S( D( T0 O; G- P' \    // take no (simulated) time. The M(foo) means "The message
% n/ K7 |( x) c% ^. a    // called <foo>". You can send a message To a particular
; ]3 {. Q  @# O% e    // object, or ForEach object in a collection.
+ W! L( [% t' s1 X; Q/ b1 C9 H        # r) \) Q$ J* g& e9 M  P2 n
    // Note we update the heatspace in two phases: first run7 ?1 G! ?1 {8 n5 P, H8 H
    // diffusion, then run "updateWorld" to actually enact the9 [: K) ?9 |7 N$ h. |% y4 d
    // changes the heatbugs have made. The ordering here is
/ G' I8 d: s6 }. y- y% o& r, Q  ^    // significant!
& q: Q4 s- u3 z9 ?; @        
6 \* j" U7 Q. Q, Q0 E    // Note also, that with the additional. {5 m' b8 b0 s+ ]/ P  h7 u
    // `randomizeHeatbugUpdateOrder' Boolean flag we can( Q# N2 Z. K# b1 v
    // randomize the order in which the bugs actually run6 Z, j: u% H/ L- V; u
    // their step rule.  This has the effect of removing any
+ z# G9 m6 {! V! R5 R( b! L2 \    // systematic bias in the iteration throught the heatbug% N& G1 x3 ^; k1 f' H, O
    // list from timestep to timestep$ x6 H% n. I& }
        " Y0 m3 _% ?+ [5 n2 ?& }
    // By default, all `createActionForEach' modelActions have) q4 C, {8 ]3 w- X: _3 ^, ?
    // a default order of `Sequential', which means that the
# ~4 S( N- J4 T    // order of iteration through the `heatbugList' will be6 I6 O4 C9 G& h# h5 j; f
    // identical (assuming the list order is not changed
1 u7 ~, t: Y( G    // indirectly by some other process).
5 b) h" [/ T/ g; v- |, Z. c9 @( L# U    ; |) y5 m$ x; s1 r
    modelActions = new ActionGroupImpl (getZone ());% \9 y0 l0 @5 i  k. p: B% [

! |3 r% y% m( z& ?: s    try {/ g: w7 A& V. @2 i0 i, z
      modelActions.createActionTo$message  {0 l. x8 X* C: j; Q
        (heat, new Selector (heat.getClass (), "stepRule", false));) \5 _$ ^: Y9 F# o1 [* D3 [: v
    } catch (Exception e) {
- H# }5 b' e1 F8 \      System.err.println ("Exception stepRule: " + e.getMessage ());; f0 |- m( g1 f) N: |# v
    }
; P) d' ]8 H4 L2 j8 b: O) B3 v  j7 t% L9 Q# e
    try {
" X& Z6 e$ q2 l      Heatbug proto = (Heatbug) heatbugList.get (0);
# `$ C- |" s" n1 [5 D; _9 K      Selector sel = $ [  z8 T$ W- I2 @) a
        new Selector (proto.getClass (), "heatbugStep", false);
4 `9 L5 q6 j* T# f) }' B* a. y      actionForEach =
$ Z, _6 T3 E( Q& a) h; L        modelActions.createFActionForEachHomogeneous$call! M, Q& d# M7 S9 f
        (heatbugList,
6 l: c3 y) w; M         new FCallImpl (this, proto, sel,% O  L$ `5 v+ |0 _7 Y4 r
                        new FArgumentsImpl (this, sel)));
' l5 A4 E, y# {, D    } catch (Exception e) {/ X/ Z9 X+ y2 i8 O1 b
      e.printStackTrace (System.err);
) u+ j2 H& z! N( M4 y7 `% v' l    }
# N) o0 F$ A3 u/ \) U5 ^      q3 d% Z0 N5 q
    syncUpdateOrder ();
; r% E' t- x/ T8 x0 [5 r3 r
, T5 G' W$ N: m3 B$ G    try {
! t# Z. R2 _) ^6 r/ C1 C      modelActions.createActionTo$message
8 W4 s& ^- s( z+ N        (heat, new Selector (heat.getClass (), "updateLattice", false));2 K+ {* f& N5 Y
    } catch (Exception e) {
1 e# g) G4 g" ~7 Z- W( J      System.err.println("Exception updateLattice: " + e.getMessage ());$ l4 `6 Y0 {5 w. l
    }
# j2 h& c$ ?4 K* i% @        
6 A3 r* p5 [  Y$ R    // Then we create a schedule that executes the& r! h- Z( @3 s( V$ f
    // modelActions. modelActions is an ActionGroup, by itself it
' u) m, d9 q9 l0 x    // has no notion of time. In order to have it executed in: @9 v# H+ o6 M; Z# k) \  F+ a
    // time, we create a Schedule that says to use the
3 Q1 d, u, c! @! P& h% H    // modelActions ActionGroup at particular times.  This
, p" R5 L0 w8 B$ ~7 D% ~$ C5 F& v" `    // schedule has a repeat interval of 1, it will loop every  Y% _, Q8 b" O  L# }8 e# x
    // time step.  The action is executed at time 0 relative to
% ^8 Q6 F: B; N& Q, [' t    // the beginning of the loop.
# j6 R% j& l* x. v& j$ N
) O: D9 Z' V( D! c    // This is a simple schedule, with only one action that is
/ x9 \( y" p) `9 w9 h    // just repeated every time. See jmousetrap for more8 u) P" r1 Y6 B2 f6 }6 V: P: c
    // complicated schedules.& [3 M6 e6 t, x% t8 p* K+ ~+ q
    B: E0 R" p/ e9 i2 {! M
    modelSchedule = new ScheduleImpl (getZone (), 1);
: E: D0 j  Z7 }' |    modelSchedule.at$createAction (0, modelActions);
8 _+ l0 t% t) U- X, d        
5 f5 {; i! e7 G& m; O    return this;# r/ l6 s2 i' u
  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2025-12-16 19:02 , Processed in 0.013824 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表