HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:% m5 Y3 ~/ W9 F* a
% G$ h- d$ l2 |3 ]6 _9 O z public Object buildActions () {6 B, N2 Q2 w# R# {3 k
super.buildActions();
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// Create the list of simulation actions. We put these in
" \1 P; a6 C% K5 } // an action group, because we want these actions to be4 o) n9 V% P" i# B+ F/ s
// executed in a specific order, but these steps should
- J! t% S" d& L0 w" R // take no (simulated) time. The M(foo) means "The message4 Z: N. h$ @! |9 Y5 ~2 e: ~. a
// called <foo>". You can send a message To a particular# k- k5 v+ u1 z9 d% C
// object, or ForEach object in a collection.) E. d# f, C$ l5 F( k. b
: m6 _4 T- r9 r$ y) z // Note we update the heatspace in two phases: first run" D( b/ t3 O3 |
// diffusion, then run "updateWorld" to actually enact the' m) [) K4 e. ^8 A
// changes the heatbugs have made. The ordering here is9 d) c0 y' b C3 _6 a
// significant!. T2 [3 T/ v1 b" w S) e
6 x2 D) O5 p1 ^& y; x# { // Note also, that with the additional' [: k, a% h" T4 h
// `randomizeHeatbugUpdateOrder' Boolean flag we can
. W. f% W7 @/ W // randomize the order in which the bugs actually run( t5 a, c3 B0 i6 L3 y' K
// their step rule. This has the effect of removing any
/ f: n2 C& @9 [ // systematic bias in the iteration throught the heatbug9 R( d I! D+ R: r- J
// list from timestep to timestep
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// By default, all `createActionForEach' modelActions have0 p" g! [4 |& q
// a default order of `Sequential', which means that the8 M, ]7 d! y9 d" u- G" N: D1 P/ f
// order of iteration through the `heatbugList' will be }' J' o9 `- _9 m# o+ e3 q+ V
// identical (assuming the list order is not changed- q# U( [+ S! I+ v
// indirectly by some other process).
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3 r+ h3 a) |# C! L8 ] _1 B modelActions = new ActionGroupImpl (getZone ());
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8 e$ D/ a: k' E5 y/ v. J* o2 k try {) B. [- R% |. S) H: d
modelActions.createActionTo$message
/ J' J/ P2 Q3 e& G- F5 w% e+ I (heat, new Selector (heat.getClass (), "stepRule", false));, B. \( f5 x3 V$ e3 l6 I* _
} catch (Exception e) {
% W3 w3 {, I* A7 R } System.err.println ("Exception stepRule: " + e.getMessage ());
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try {
( p/ c" c/ y# O/ M4 V Heatbug proto = (Heatbug) heatbugList.get (0);: k, I/ z9 D# z
Selector sel =
0 }/ m8 {5 J& c% p3 O% s0 Y new Selector (proto.getClass (), "heatbugStep", false);
9 A3 I! c8 U$ C actionForEach =: ^3 q3 Y- E0 ~& K/ i9 k2 U2 U
modelActions.createFActionForEachHomogeneous$call; @; R, G% [% {! }
(heatbugList,
7 E9 `# ^' @5 C" v1 f new FCallImpl (this, proto, sel,! Y* L+ f9 l) B" {9 Z
new FArgumentsImpl (this, sel)));
" g4 U- X" z9 u& m1 A6 D } catch (Exception e) {
5 W+ m6 `& b* Z& y9 ? e.printStackTrace (System.err);
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: b) G& E0 I% v3 @ syncUpdateOrder ();: n+ j! x& Q' ~) ~7 v6 C0 ^
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try {
# M4 f: I6 a1 t1 g) Z' ? modelActions.createActionTo$message
! v+ S, ]* b5 S2 i (heat, new Selector (heat.getClass (), "updateLattice", false));9 q2 T3 }9 C# l# ~, h3 K
} catch (Exception e) {' M2 _1 k9 `2 D; y5 l
System.err.println("Exception updateLattice: " + e.getMessage ());
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# \3 |) @! O6 a, ~ // Then we create a schedule that executes the
# c' \# y. M. m; N( E" l // modelActions. modelActions is an ActionGroup, by itself it
' `1 p, `9 Q3 d+ u9 l/ P // has no notion of time. In order to have it executed in
9 s2 n$ Y. g9 o% l // time, we create a Schedule that says to use the
3 Z1 a( K* D( r9 F7 J4 } `: ]( E // modelActions ActionGroup at particular times. This
8 N. K, x6 H. l // schedule has a repeat interval of 1, it will loop every
1 L" m9 l( T8 A6 `( _ // time step. The action is executed at time 0 relative to
$ v4 p5 L# a" J // the beginning of the loop.
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// This is a simple schedule, with only one action that is
& p a0 B5 {5 E4 _8 v& e // just repeated every time. See jmousetrap for more Z0 p- u# G; o9 p" [0 k' n
// complicated schedules.
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8 D4 k3 L$ }. s modelSchedule = new ScheduleImpl (getZone (), 1);
/ u. t' p* i9 s: t$ ~6 x2 c; B modelSchedule.at$createAction (0, modelActions);* P' y0 d- k* W/ G" p
* j* F9 w. o# U) N- R9 n return this;
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