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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
& H$ n4 |* a% `2 S7 N  y' M9 h* N6 V+ w
public Object buildActions () {
: p9 H4 U4 M6 g3 m' J& J5 ~3 a    super.buildActions();' F, k7 K2 d# [! F7 j3 e! Y5 D
    % J5 c; z$ k$ Z+ z9 Q! j% a
    // Create the list of simulation actions. We put these in# P" ~5 j# v5 S* ~, _! g0 c
    // an action group, because we want these actions to be
# T) r' ~9 C$ D# F$ z. S8 _; ]    // executed in a specific order, but these steps should9 m7 X  q7 P* a- U6 j  [
    // take no (simulated) time. The M(foo) means "The message! W  Q% V# Q" o
    // called <foo>". You can send a message To a particular- p9 y4 H9 c. S) {  N' \, O4 d- R
    // object, or ForEach object in a collection." M, V# ~9 k5 L( M' W6 r+ X
        * _9 }( W* k: u2 c$ i) T4 Y' s5 O: g
    // Note we update the heatspace in two phases: first run# |7 X; i8 H) ~* T
    // diffusion, then run "updateWorld" to actually enact the$ @* k( n0 k4 _& c
    // changes the heatbugs have made. The ordering here is3 `0 b: @9 I/ @
    // significant!
7 q; o$ ?3 W' I        / a) O3 p+ p! V0 C1 c
    // Note also, that with the additional' Q- s7 y0 @1 }! O" D
    // `randomizeHeatbugUpdateOrder' Boolean flag we can- X& M& d9 w, c; k  l
    // randomize the order in which the bugs actually run
* B5 p- u; M6 {7 q* v    // their step rule.  This has the effect of removing any9 c$ C( G; D- h  i& W, k
    // systematic bias in the iteration throught the heatbug1 i7 R8 n  ]: W5 T' U
    // list from timestep to timestep
, ]" C1 d6 M  M& O9 q) d        ) X6 J+ g7 `5 \- p
    // By default, all `createActionForEach' modelActions have
" m" ~7 S3 I; W! ]5 t9 C    // a default order of `Sequential', which means that the3 y. ?/ w/ \4 A3 c9 k( Y
    // order of iteration through the `heatbugList' will be
: z8 u7 A  U5 e% R. ]2 m9 s7 Q    // identical (assuming the list order is not changed
1 m9 `* Y. g" U' g$ \    // indirectly by some other process).
- T5 d% L& j+ _% x   
" \1 [' B! h% s: _! Q2 O1 P    modelActions = new ActionGroupImpl (getZone ());
( m- s- _/ l" B+ o5 |% Q, E* _6 `
9 S  C3 U  _2 x  b# B2 s0 `    try {
. d; t8 y* c5 e4 k1 f6 ^6 c      modelActions.createActionTo$message
: c: h- Z' E' _) Z1 S# f$ }; t- b' ]        (heat, new Selector (heat.getClass (), "stepRule", false));$ Y; ?5 P, o. ]1 E8 C, b
    } catch (Exception e) {
- F6 B: U- C& V! l( U1 T6 x      System.err.println ("Exception stepRule: " + e.getMessage ());
+ u5 N8 j9 n0 K# s    }
" o& U2 n: D& p: Y7 J5 p- r/ L& j0 a% n, l. X9 H
    try {0 k8 Q9 C& O/ U+ f  V* d
      Heatbug proto = (Heatbug) heatbugList.get (0);
$ @" R' f" H9 R      Selector sel = - K; J+ m( H" C
        new Selector (proto.getClass (), "heatbugStep", false);
( o5 J1 ^, n: m+ H3 N      actionForEach =
2 b# w6 w( o' d        modelActions.createFActionForEachHomogeneous$call, z2 {$ A/ `  U( H# a
        (heatbugList,* P" O$ @" Q  V4 F
         new FCallImpl (this, proto, sel,: i) `/ v+ o, O  V2 Q' R
                        new FArgumentsImpl (this, sel)));0 F, O) C( P* b' M: [. t6 j+ v
    } catch (Exception e) {5 D7 M) D3 q" _7 r# A( }; `) M
      e.printStackTrace (System.err);0 Q) ~3 \& [/ g- Y$ D
    }
. s4 @' h- k3 T    & H$ @! o+ Z$ Q: m
    syncUpdateOrder ();
( i/ h$ k) Y/ J% I
. O  f/ h' K8 O" L! }6 Q: C& n$ h    try {
8 y# E, E3 {' X  ^  e/ C      modelActions.createActionTo$message   x9 z+ N) `& n; O6 |
        (heat, new Selector (heat.getClass (), "updateLattice", false));# j" i" _- ~; h+ _4 C, _( K8 f
    } catch (Exception e) {
2 M9 V% n* s# Z( h# o% ]- g! V      System.err.println("Exception updateLattice: " + e.getMessage ());' B3 R* K) M. |% A# Z) Q: Z+ I
    }# U. f' t" ]9 j8 K8 D, W! {" R
        9 c* W' Y. t# G/ h( x. v1 Z
    // Then we create a schedule that executes the. H, u8 m$ f9 `
    // modelActions. modelActions is an ActionGroup, by itself it
  F4 V& q6 n/ R7 B2 T    // has no notion of time. In order to have it executed in
: d! N4 j1 H1 h. o    // time, we create a Schedule that says to use the. |+ a4 M3 m( l* j& Y) x9 T5 i
    // modelActions ActionGroup at particular times.  This
/ x) A5 f! j& o5 ]    // schedule has a repeat interval of 1, it will loop every
* p* T- c# J4 P! Y) u    // time step.  The action is executed at time 0 relative to' `7 I/ ?& Q' x+ `1 ^) Z
    // the beginning of the loop.
5 k" k; ~' q7 f$ ]7 O$ C7 M3 W
: J; j9 g( W2 P1 ]! J  L4 f; ~    // This is a simple schedule, with only one action that is
5 J/ |7 q+ P- `: j, i. w    // just repeated every time. See jmousetrap for more
% `% N% S8 w+ e    // complicated schedules.
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    modelSchedule = new ScheduleImpl (getZone (), 1);
! y7 }5 M" f# j& Q    modelSchedule.at$createAction (0, modelActions);
1 D- P+ a& ]. {8 t, Y! ]        ( G! x3 ?  F5 ^
    return this;4 E  ]. X& c2 J2 m
  }
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