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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
; A4 l& a9 @( Y4 B0 ~; f( h! d) ?) Q- A* M  e) e6 q' ^7 \% V; ?0 ?" `
public Object buildActions () {9 Q3 O; _" J! j6 V% S% ^; _8 ?
    super.buildActions();" N, l! F: R3 R! A/ t4 A' x* ^
    * ?# S! y. Q( Q! U5 m! W7 z9 N
    // Create the list of simulation actions. We put these in4 D, \; j. d* [5 R9 m6 P
    // an action group, because we want these actions to be9 t: L1 e1 C8 s. x' S; [! C8 k
    // executed in a specific order, but these steps should
" l" n( F! \7 T, l! m3 Z! U* B7 T    // take no (simulated) time. The M(foo) means "The message1 t( }. F; Y7 W# r; Q! b
    // called <foo>". You can send a message To a particular
$ @0 }8 x2 q2 d; z; A    // object, or ForEach object in a collection." C! Q* S: {, F- p6 Z% P  U
        5 o& y& K- l, l: N6 k
    // Note we update the heatspace in two phases: first run7 b* ?$ w, Y: p4 ~
    // diffusion, then run "updateWorld" to actually enact the3 q1 q9 a9 t/ @# N* R
    // changes the heatbugs have made. The ordering here is
, z9 [8 S3 j) \6 g8 `3 A, `! D    // significant!5 V, l( J, R+ z1 `) \
        
/ _2 H2 z+ q" R  _+ ?+ k    // Note also, that with the additional
; U# Z) Y9 B; `4 m. w    // `randomizeHeatbugUpdateOrder' Boolean flag we can' l* y, ?5 \+ \5 k
    // randomize the order in which the bugs actually run4 }5 u! h) G6 g/ V% A! X! O3 u
    // their step rule.  This has the effect of removing any
1 S* ~1 y5 r8 ^0 J1 F* d    // systematic bias in the iteration throught the heatbug; Y* s* [3 C% `6 ]+ V
    // list from timestep to timestep
9 k. V$ w. Q1 X9 |1 m        7 n% U  x" g! x$ q" B$ ^
    // By default, all `createActionForEach' modelActions have
! G$ M/ G% p1 v* v0 W) E" ^    // a default order of `Sequential', which means that the
) R8 r( Y! s+ P- A8 r' R    // order of iteration through the `heatbugList' will be# c) H. d, A* s: S" e/ K! f
    // identical (assuming the list order is not changed
- G, K% t# [. X3 u& n9 A    // indirectly by some other process).
  j% h6 ^+ ~5 H2 q1 s2 g      C: ~. j: U: E, a2 ~
    modelActions = new ActionGroupImpl (getZone ());& ~- b& Y& n# D3 K

: {; `1 D6 X! c8 ]  Y0 J    try {
% f9 d, b- @, o' {% p$ U  `; k      modelActions.createActionTo$message
6 K+ ~6 l. j4 C* G        (heat, new Selector (heat.getClass (), "stepRule", false));
8 b8 M6 m; b. B5 C    } catch (Exception e) {
4 I: o9 B" y" S* J3 @      System.err.println ("Exception stepRule: " + e.getMessage ());$ f) M9 R  W' v# V( Z" X
    }
2 @- w" b8 Z) B5 N6 f
# t) N" s  e) e1 j9 Q# l    try {
  R- S  m9 a% f& Y9 A% b      Heatbug proto = (Heatbug) heatbugList.get (0);5 o* L( m1 @! l# x" M1 c7 _7 x
      Selector sel =
1 g1 _" e- S! C& t! H+ O        new Selector (proto.getClass (), "heatbugStep", false);
6 d; R* f. z* C      actionForEach =
0 F  K2 I/ q0 w1 `9 P# G        modelActions.createFActionForEachHomogeneous$call
0 T: R" S$ e' l: q: `0 p        (heatbugList,
7 T3 H3 g* `, J( M% t3 d/ O         new FCallImpl (this, proto, sel,+ w  H, a/ S" Y( E2 q
                        new FArgumentsImpl (this, sel)));$ d4 i( {' T6 B: U
    } catch (Exception e) {
0 b9 l5 w7 ^1 s, Y  l4 M      e.printStackTrace (System.err);
" O/ k5 u9 Y. d  H" v    }
$ d2 v4 h3 c) P% T. T$ T7 l# E) X2 ~    + q+ _6 B9 f1 E/ y
    syncUpdateOrder ();+ M0 L# ]3 \& Z8 R& w3 o9 a- n
  ]8 g8 {$ w8 G" |; {+ p/ j$ e
    try {8 B, V5 R4 Q1 H) y! n/ ~$ l' y" S9 V+ \
      modelActions.createActionTo$message
; }, T" D/ A0 v        (heat, new Selector (heat.getClass (), "updateLattice", false));
) u/ m% k1 x- L    } catch (Exception e) {
, S! z1 d* `+ P. L      System.err.println("Exception updateLattice: " + e.getMessage ());
1 ]" E! C  g: X. F/ z! E! Z    }
8 F7 \+ M0 [0 f* Z8 u$ `5 X        4 W- V; n: `  m& w& m6 n
    // Then we create a schedule that executes the' v8 ]. k; y# Q# p1 ^* s5 \# o
    // modelActions. modelActions is an ActionGroup, by itself it; y- ^5 y+ d4 R9 o- l
    // has no notion of time. In order to have it executed in
- ]+ ]6 \- a+ t2 T    // time, we create a Schedule that says to use the$ [* j8 V3 a" _1 f8 o$ Y
    // modelActions ActionGroup at particular times.  This
0 {2 t. B: r4 i! Z! r2 E    // schedule has a repeat interval of 1, it will loop every
) h! `7 r: E/ s& U# l! h    // time step.  The action is executed at time 0 relative to
  G3 F& Z" W% `) y: ^    // the beginning of the loop.
  {6 D. e  f( N: x. x) {
1 W# Y1 U& C( ~# |& `    // This is a simple schedule, with only one action that is3 \, s2 n; W( B
    // just repeated every time. See jmousetrap for more
  k, ~, u' o( J9 t4 }7 V# R* w    // complicated schedules.9 H" h2 O8 v( V( G$ u
  3 p; R/ R  M3 @  f  Y+ Y6 b* L
    modelSchedule = new ScheduleImpl (getZone (), 1);
5 W6 Q2 W+ B  E' P5 ]0 ^3 Y    modelSchedule.at$createAction (0, modelActions);! Q8 ]9 G2 P* _+ {% U
        * |  W: H( V  i
    return this;
+ q; ]  a. y0 ^) v0 F, V  }
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