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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:; p# M, K8 w3 e- q; o6 z6 C% m

' J& x* n% C( g  I( d# i5 D public Object buildActions () {
8 X# E* G5 G8 o+ S% }" g& R    super.buildActions();
- b- }7 q4 n( P# C/ z    ) f  t: u: ]( _6 X
    // Create the list of simulation actions. We put these in6 Z! t6 y7 g0 h" B5 W
    // an action group, because we want these actions to be: e# P) B. a4 [( H
    // executed in a specific order, but these steps should
) K9 }- e+ I0 q* D* u    // take no (simulated) time. The M(foo) means "The message6 o/ a6 g& H5 @' @1 }& ]+ `
    // called <foo>". You can send a message To a particular
) W: \$ h- ~" h3 u% d/ v    // object, or ForEach object in a collection.
- K4 ~/ `7 [* n- r8 o  x        
) O2 V. _: E' j" {    // Note we update the heatspace in two phases: first run4 Y7 M+ i( ]/ W6 L3 P
    // diffusion, then run "updateWorld" to actually enact the
7 H1 m+ n0 |2 [    // changes the heatbugs have made. The ordering here is  r/ j" S/ j5 Q6 k# C* ^
    // significant!
: C7 r. x4 r; B* q        
+ f+ E0 r+ c- @+ Z: E' F1 T3 w    // Note also, that with the additional, Q7 d1 O9 I* F+ ^3 ~' G
    // `randomizeHeatbugUpdateOrder' Boolean flag we can  A8 A9 C. I  J" V, _3 z
    // randomize the order in which the bugs actually run6 [( j% M- \: F) K
    // their step rule.  This has the effect of removing any$ s& a; a+ m( V4 \( s" e3 [: |* u
    // systematic bias in the iteration throught the heatbug
3 V* j$ F2 f+ S% q  I4 B& n5 x7 \    // list from timestep to timestep
0 c$ B. F- k- ^5 g        % I. S; v) I6 N8 M: e8 Z
    // By default, all `createActionForEach' modelActions have. T$ U3 ?: l( Z7 N' k) E7 ]
    // a default order of `Sequential', which means that the
5 j: k( p! Y, Z    // order of iteration through the `heatbugList' will be
: d! R: N/ m* J1 ^- B3 P2 e% M    // identical (assuming the list order is not changed2 \0 u; q9 q- @. z+ Z/ S, w" C2 [
    // indirectly by some other process).
3 Z" N- [6 [# A" B    2 H. F# F5 d2 E. T- V3 K
    modelActions = new ActionGroupImpl (getZone ());3 I3 F9 Q& Y3 s1 Z
6 R9 A( C6 ?" l1 a# J2 S, s& c
    try {
- |1 R) q7 N  r      modelActions.createActionTo$message) M* ]& n" B, ?' R
        (heat, new Selector (heat.getClass (), "stepRule", false));, R+ f6 I: L/ b8 C3 c' ]# l
    } catch (Exception e) {1 h% C* V) ]2 l- u% k
      System.err.println ("Exception stepRule: " + e.getMessage ());2 n; [$ @3 J( I! U  C% ^. n0 @
    }
# D" A/ x! u0 n+ I5 B# f
. f( u7 F4 C: y2 m8 }9 A    try {
6 J* g# p3 j& q- @/ r* i. M      Heatbug proto = (Heatbug) heatbugList.get (0);
9 N3 \# r+ U; D2 u      Selector sel =
/ g( c3 G( }5 B        new Selector (proto.getClass (), "heatbugStep", false);
- _6 e/ s" S! m( m# n      actionForEach =# i# L, }4 Y' V* s7 @* F6 T
        modelActions.createFActionForEachHomogeneous$call( \, N. g  l- p' u. V3 c6 g
        (heatbugList,
. b' P# a3 |4 e/ Z0 m# T* Y2 a         new FCallImpl (this, proto, sel,' f  w+ W6 H/ f" E' c$ C7 t1 Y6 g
                        new FArgumentsImpl (this, sel)));, X5 m6 l1 ?- ~* W3 V: K, N( N, J
    } catch (Exception e) {% h& S) {* D" L7 G
      e.printStackTrace (System.err);7 B( |& l2 ?' B7 Q& e$ E& C; z) V- m
    }
& d, C4 H! q9 s' N' H* p   
6 `& K- d9 l. u    syncUpdateOrder ();
6 }. C5 s  E: R5 P
, A' t: J7 x! ]" T' D- ?6 L+ L    try {
" Y+ k2 Q% E- F+ A      modelActions.createActionTo$message ! l% T( d0 ]7 M% b
        (heat, new Selector (heat.getClass (), "updateLattice", false));$ g! v. }8 B! i$ t$ E, B
    } catch (Exception e) {
* Q/ ^5 `0 B* W! Z- E4 O      System.err.println("Exception updateLattice: " + e.getMessage ());$ O) m8 a7 d# x9 Z3 T+ v  V
    }) N4 C9 _2 x2 _. ^
        
! T; w8 ]0 j# j- D    // Then we create a schedule that executes the
+ d4 H% G: L$ F; x    // modelActions. modelActions is an ActionGroup, by itself it
! _  a9 \- K# J9 b: D; x    // has no notion of time. In order to have it executed in% s5 Z! q% w: E/ j- X
    // time, we create a Schedule that says to use the. f9 P! [; X( w2 C& ^3 s3 N
    // modelActions ActionGroup at particular times.  This" {8 E, ]4 [- Y+ \8 t
    // schedule has a repeat interval of 1, it will loop every
$ ]. _0 u+ [) H) B! T) ]4 e* K1 R: g    // time step.  The action is executed at time 0 relative to$ v+ T, ]( d5 i; O
    // the beginning of the loop.
; J/ u/ v. C" M( P" @% ]& n6 x, `$ E' J, }
    // This is a simple schedule, with only one action that is7 A9 y  f) H5 h6 B: q5 T( Z
    // just repeated every time. See jmousetrap for more, p0 ^+ a2 x- Q8 |- X4 M6 b! h
    // complicated schedules.  e$ V! P7 \5 U
  : e. Z) v0 A! Y5 v) t
    modelSchedule = new ScheduleImpl (getZone (), 1);! p& B" c& d( F) c+ A  b) {
    modelSchedule.at$createAction (0, modelActions);
$ x0 g% d$ N6 ?, n0 I6 \        0 o8 ?. z' X9 {  x7 w) K- H
    return this;. y4 a. y6 n5 Z" ~! ~
  }
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