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楼主 |
发表于 2008-4-19 16:11:18
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好像可以了
to go
$ N& g( Y* f" o ^3 Y7 H+ K set t t + 11 Z+ y- B1 ~" B# i7 J
grow
/ J: @* E) }6 o update-list-of-m
" ^# C f, P2 [: S do-plots! l# d: K% E, M. W
tick - d. C& Z! j& A
ifelse t > 8- c# v" F+ Q; O( [; r2 Z
[if abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)))< 0.01 and/ B8 H2 ` m9 h9 B! u
abs( mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 and2 l+ V, f, ^7 s; N. j. N" j
abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 ) }9 y% T6 P1 `; D0 P9 w) N
[stop]]7 ~% q+ I% `7 K3 W& ~% S- m- H
[ ]
. e5 Y& [) V- {7 |! U4 C& \7 {end& f3 p ^7 X& Z; Q/ [1 a1 E
各位大虾帮忙看看,这样好像可以了。以前用while之所以不行,是不是因为如果报告为true,那么就会反复运行后面的命令导致死循环啊?
: D1 m [ X- E% s% A; g还有就是[ ]是不是意味着不执行任何操作,返回set t t + 1,然后再grow,再 update-list-of-m,再 do-plots,再 tick ..........这样一直按这种顺序循环直到停止。; {8 P* U) }5 Q
1 D- G) ~5 I D0 \" k
[ 本帖最后由 wjcpcahu 于 2008-4-19 16:19 编辑 ] |
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