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楼主 |
发表于 2008-4-19 16:11:18
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好像可以了
to go
* l( O$ f+ g1 S/ N set t t + 13 W* n# e) `+ ]2 T
grow
# J7 S) e4 ^9 G& \1 r( Q update-list-of-m4 G7 `5 V7 h+ q! ~! ?4 N8 K) S
do-plots. R, @, X; i- o6 I& a7 r
tick
; a, d/ D0 G3 E. R* s ifelse t > 8
l7 o: h! g9 w7 c! [ [if abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)))< 0.01 and
) M5 P7 r* B/ L* g abs( mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 and) k7 ?# ~ v7 ~/ l( Y
abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 ) v, }- G( h: K- e
[stop]]
C& T7 q' w8 x4 l [ ]
m% S! _8 f& I. B0 d/ xend( g3 T: g# N! x3 I6 w2 J$ o3 `
各位大虾帮忙看看,这样好像可以了。以前用while之所以不行,是不是因为如果报告为true,那么就会反复运行后面的命令导致死循环啊?
' l1 U6 f1 n, e2 \* S8 G% m, p还有就是[ ]是不是意味着不执行任何操作,返回set t t + 1,然后再grow,再 update-list-of-m,再 do-plots,再 tick ..........这样一直按这种顺序循环直到停止。
2 ~% |0 N. X/ e; T4 T- i. b- Q2 N0 J) u2 C% ]2 d
[ 本帖最后由 wjcpcahu 于 2008-4-19 16:19 编辑 ] |
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