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本帖最后由 soso001 于 2014-12-17 14:53 编辑 ; E, H; Q [, h2 z1 F2 I# A
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不好意思,打错了个字母,呵呵呵!3 i. ]5 S; G: K) s- R3 t
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
* H0 v7 t- q6 \' O: v“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;
& m8 @1 Z8 X5 K* G0 e( u* ] M:string;! Q- w7 P7 l" s% [3 m" `2 T
selecTab:table[integer,integer,integer,string];
3 Z' @, _! c( I1 j3 Ndo
* Q* X! `; w2 x" a initorders;8 ~2 ?/ g3 d: w- \* b" D# m" b
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scheduledorders.delete;. R# ?' J. r. U4 R* g: E4 U7 {
seletTab.create;
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orders.initialize({2,1}..{2,*},0);
2 m) J9 B |5 I! l) P0 @# W8 N orders.initialize({4,1}..{4,*},0);7 {. ]# M+ Q7 m7 V( X4 Y
for j:=1 to numorders loop
% u/ S0 R8 v1 L* `& w1 a orders[5,j]:=orders[1,j][2,1];1 t& S% V+ u6 `% T
next;
" h+ h2 @0 K) r1 s! _% L occres.initialize({1,1}..{1,*},0);; W' J$ E A6 A y
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--XUNHUAN
0 @: X Q8 y- d+ t$ ? for scheduledsteps:=1 to numsteps loop --
7 G$ \" D N3 S0 J& |* J selectab.delete;
( I2 q! T! ~* c( x' D7 u k:=1;1 I! O+ s% l, ?8 v. T, @
for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
6 {6 M$ b3 q9 `% P' x7 E if nstep<=orders[3,j] then. C1 I7 H% e) t8 c0 Y5 d- }
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];8 T4 L. I; g7 J! {" k# N
k:=k+1;
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) d/ L" ^, o' Y7 B! v* R" a end;
- X' ~# |) V# U1 Z# x next;
1 e5 @" `* b& `$ P n: w mincomptime:=selecttab.min({3,1}..{3,*});7 Y" Y3 _# d9 u
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from j:=1 until j>selectab.ydim loop' P: N# b; E! m; o
{/ S* J2 U3 n1 U5 E5 R* d if selectab[2,j]<mincomptime then/ W" m0 ~' U+ v' B
j:=j+1;
4 B: X& R' e' f* F" j6 [4 O else
5 T# d% X( l( |+ D6 f1 _! j selecttab.cutrow(j);
; J- Q' A% H$ V& n end;' r |: j) a4 ^
end;
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j:=selectionrule(selecttab);
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2 Q1 E8 E) {" p1 m2 V nstep;+orders[2.j]+1;
6 H, U0 J' J# w v* R& Q: m orders[2,j]:=nstep;
+ ]+ G$ A6 M( T$ v' J% h: F m:=orders[1,j][1,nstep];$ e" T4 F! x9 l# {1 l3 D7 n2 t
c:=orders[5,j]
7 W# T0 I5 J$ q' f occres[1,m]:=c;9 y5 _ m5 Z3 e! ^/ T/ [. J
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--jieguo:start,end,res,job,step# H+ r6 I$ @6 _! t! f4 `/ X
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
1 M2 W+ V! V8 h+ q+ E for k:=1 to numorders loop
- E. s! z6 L& z nstep:=orders[2,k]+1; Z0 j7 o# a0 A- s4 `
# b! ?8 @/ [2 `9 g$ Z; S if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then
: h7 e4 z( f# _9 ?, t; q$ s orders[4,k]:=max(c,orders[4,k]);( X3 l# W# c" p0 ?+ P
--
; V7 M6 \% m4 a v j orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
# J9 n* b6 S9 n --
; r1 T4 Y1 \2 k7 K end;
8 w+ `1 e) i8 ? |7 V0 M0 B next;
& E- k# f/ |" i: C1 Q nstep:=orders[2,j]+1:
! R3 P6 ~# }! P/ I' P* \0 C5 ^1 @ if nstep<=orders[3,j]
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then$ q) k- o: {. Z8 G
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
# {/ p4 X- Y3 a orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
& J7 S5 [0 ~/ _* f7 W! a end;5 e) O A% B$ S8 N: b- x4 E0 k/ g
next;1 R! ?& G( E1 u
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});: p% ]7 V1 r; _# R! g b3 e2 j8 I
mygantt;
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