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本帖最后由 soso001 于 2014-12-17 14:53 编辑 7 Y! S8 U! w9 d0 X: C
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不好意思,打错了个字母,呵呵呵!
6 \; P j" x" ]8 D; S: E" R4 x; v大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
: y1 M v" F5 I3 C; p; o1 p; |“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!! Q2 W8 q, f1 L+ k, V
is
8 j! G' y' v1 U j,k,nstep,c, scheduleteps,mincomptime:integer;
' E' p4 }/ B8 ^ M:string;
c2 G0 V( `) T selecTab:table[integer,integer,integer,string];
9 `* }4 Q5 h7 t0 B* p7 }) s. ~do
. M% x6 P+ t7 G( R$ X/ v initorders;
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scheduledorders.delete;
- c5 J7 d4 |! T, D. D8 Z% f9 L! b seletTab.create;- o, ]% `9 f- Y7 {
) [* g G$ ~5 i1 s0 y8 J orders.initialize({2,1}..{2,*},0);
# x3 A" ~4 J K# j; o orders.initialize({4,1}..{4,*},0);4 L- A0 e, J* n9 V6 M
for j:=1 to numorders loop
* _6 ~" y/ {4 g/ u4 f: r orders[5,j]:=orders[1,j][2,1];
2 _. |! k7 C' G' a next;
8 q2 d6 ]1 M3 O* K occres.initialize({1,1}..{1,*},0);8 Y3 G5 l0 U5 c) r" m: X
! o1 j0 s' }" T) A' \( Q8 K1 L --XUNHUAN& w/ e4 b, O: `7 u! }
for scheduledsteps:=1 to numsteps loop --
* ?/ O0 B; u9 i, }0 D2 w9 Q- ?/ i% } selectab.delete;( v9 S1 Y: U) J, D) i
k:=1; j+ r; w2 v2 k3 Y8 O% e
for j:=1 to numorders loop
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nstep:=orders[2,j]+1;& w$ i, I9 q$ [
if nstep<=orders[3,j] then$ @2 K8 H! h8 X3 _% V, g% V
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
# { E; b5 K1 P5 g( X/ l k:=k+1;* R; z+ f: X# F6 U0 z8 ^4 q9 [( u
0 ?- D+ d: e, f3 h end;0 j- a- a7 {7 |4 m% T
next;8 j: E; @9 N, E( X
mincomptime:=selecttab.min({3,1}..{3,*});
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from j:=1 until j>selectab.ydim loop
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7 H& ~1 r7 ^+ i2 @9 n% B6 f if selectab[2,j]<mincomptime then, M5 `/ b. c( J# `* j8 h5 }
j:=j+1;
# s2 N7 j' t1 g: g else
( C$ n) F; Q/ e/ l$ ^1 c selecttab.cutrow(j);
. l' |/ p( y( t! _7 U# L3 W1 j end;
9 T9 ^8 u( X6 h% S" j end;
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;! [5 A2 Y! {1 h z* }" j q
orders[2,j]:=nstep;! R% b$ Q( @, |# M
m:=orders[1,j][1,nstep];* J/ I% t J% |6 v5 n9 x
c:=orders[5,j]/ n( X7 m3 y/ x" R) G
occres[1,m]:=c;1 l. s& O. Z% J7 o* o7 \8 S( _
5 p0 L1 F5 h7 t0 {- a2 v) ^8 [' K --jieguo:start,end,res,job,step
) A3 P) s, A( L0 l' }0 m, N3 T scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);* r8 D/ s; S w0 j5 i- d; h
for k:=1 to numorders loop
& Z" l$ M& ?/ f9 G! M0 f: X; n nstep:=orders[2,k]+1;% j I& W! n& V# Q- b" S
" m# ?- V: V/ {1 G! U q if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
: C9 v7 g: P& X2 [1 p) O2 @+ x --
+ A, W2 h6 g4 G$ A1 | then
) l k$ g) V) ]2 g orders[4,k]:=max(c,orders[4,k]);8 ^& H3 c! v- \' ]/ f0 D9 v2 y
--
+ x2 ^: D! k& c; C orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];% _0 C& }+ H" n# T' S6 K
--# T+ l" F& u2 h1 v& T' Y/ v' h
end;
0 x$ {6 G0 X. E next;
0 _* g# O4 T8 b; |; T1 ? nstep:=orders[2,j]+1:
& C6 N) B. L" f& {( N! e) V if nstep<=orders[3,j]
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then
* y" \6 }0 Y, S orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
5 P' D0 u* n# f0 f orders[5,j]:=orders[4,j]+orders[1,j][2,nstep]; v4 F# s9 P& t/ D. ^
end;
! `9 P4 q/ V- J. X3 T/ B. d& r5 e- S next;* _) S/ |5 G9 @3 b
* j3 Y" L7 e \/ b% l print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*}); b ~! i V. u) Z w
mygantt;# j' E) w8 m; L ]7 r* [
ens;
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