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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!
8 Z/ N* @: l( n1 U; e- k大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示+ e4 Z! J! _7 u7 g. m; g+ I
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!2 ?7 e# C3 Y% H# y( j% A
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j,k,nstep,c, scheduleteps,mincomptime:integer;
& \1 l5 `' w& I! U. ^ M:string;
8 D% `0 ~% P, @/ u, Z$ { selecTab:table[integer,integer,integer,string];
/ F5 Q+ ^( T' }" zdo i% V/ Y( H" i/ O( [" t
initorders;/ ^) p& j! ~. C# l
9 W1 e N3 H) q9 p. y) J scheduledorders.delete;
- k X% J' A6 F* d3 R+ X8 r seletTab.create;- N2 G$ A& m& A: X+ g' E1 Q. X- a
+ g) _2 d2 f3 d, ^, ` orders.initialize({2,1}..{2,*},0);- E9 h, B# E. b0 J4 p0 B$ v$ j
orders.initialize({4,1}..{4,*},0);
. y- I( [7 t5 |$ H# H. n, d6 t1 M for j:=1 to numorders loop
7 [8 z( z2 V8 A0 s+ |8 @ orders[5,j]:=orders[1,j][2,1];
3 ^/ m$ C' N5 P) n1 \ next;
( ]* t: E0 B6 t; W1 Z1 }( D1 [ occres.initialize({1,1}..{1,*},0);
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* n$ B# r# @# U h/ D --XUNHUAN
% u' Z6 j. ^- I& i* Q! F for scheduledsteps:=1 to numsteps loop --) B7 B: ~3 [0 d7 q i
selectab.delete;- q, O s6 z' H1 s3 W4 D* r
k:=1;
( {+ r- ]& h+ T! v- q' d; I) w: A for j:=1 to numorders loop _2 Y) s T' i
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nstep:=orders[2,j]+1;
4 t" M, h$ y: t3 C if nstep<=orders[3,j] then" L' W* e0 j0 U
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
) E4 d7 i5 T$ p$ ^$ J0 R9 O k:=k+1;
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4 [) q [0 U* G6 \5 r g9 Z3 v end;
2 M8 E! L& X1 E next;" u8 I. ?: R% X0 Q% Z Z
mincomptime:=selecttab.min({3,1}..{3,*});
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, w/ i% m0 Z/ l from j:=1 until j>selectab.ydim loop/ l( W2 H: C0 q2 n+ S9 m0 B" ~" d
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if selectab[2,j]<mincomptime then
- I# F+ \) I- q% B! `' `( s- ` j:=j+1;
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selecttab.cutrow(j);
l- X5 K1 b& d$ U! u0 T$ Q+ P end;
# M! r+ K9 ~" `- B$ w6 g end;9 M2 N! l% D- }/ Z7 F' }! Y
0 `' t: Z* [! x/ c- t# U Q j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
Z$ I) r/ \9 j u orders[2,j]:=nstep;
. p7 v. M( K6 o+ ~1 Z" h m:=orders[1,j][1,nstep];
) r W9 o U7 {! `1 i- W c:=orders[5,j]6 t, I, Q0 L# X) r" H6 Q( E
occres[1,m]:=c;+ k% @2 a* `" r7 G$ n+ K# q; r
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--jieguo:start,end,res,job,step, L( t+ ?5 M) N& T- ~
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
9 \/ r& r7 y% t3 J# Q for k:=1 to numorders loop6 b+ W$ V" B& B# r. J" m6 d" X
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
1 H. a. d. o% E" D* o( O# r% i --
8 D* C9 s6 T: y+ q+ w then
) ?5 z3 K% ] L* v/ n6 p orders[4,k]:=max(c,orders[4,k]);3 \+ X; x" _8 C' ^
--1 `% k& h3 [ s$ q
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;
; h6 i9 M' b. Y! o& Z next;8 k3 F8 b+ i" E0 x/ V
nstep:=orders[2,j]+1:# u- h2 I3 L8 S% H4 t; a; I% Y/ j
if nstep<=orders[3,j]$ C8 P' F0 F9 B8 F% T- d6 |
; P, G# U8 l5 Q, R" t1 Q$ Z1 @5 O then
+ g8 b& d+ a% U6 e: l orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
0 R$ P( A2 S" J: {4 }( b$ S- L6 ~ orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
2 f5 q7 J/ X6 R& n/ X end;
# u, ?. I, Q) l next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});7 I& T$ D6 d2 U$ k
mygantt;9 k# _5 t7 _" Y
ens;
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