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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：) O$ s: O/ E8 p
begin P_in arriving& ]. q& f4 ?8 p) T7 |- ^2 W
move into Q_in
* h8 U' U0 d, E9 t) ~' n: x% k use oper for 2 min
2 T1 I; t: [3 {* {$ f send to oneof(0.95:P_in1,0.05:die)
" ?& `, r" X4 z& a4 u6 j6 T+ T( Lend7 q7 O8 o) c7 K J* a: \% C& n
begin P_in1 arriving
( r; K, D- T, E. i if load type = load1 then
! ]! V' D6 j+ R4 q/ J% H' s- l begin
( o! w& K8 ^) K6 J3 }# |) G move into Q_m1& {" N/ M: \9 Z; S
use M1 for u 5,1 min, B& k" U, b) @8 y5 H! ^5 u
move into Q_out1
8 Y5 ]5 K: G* C. V wait to be ordered on orderlist OL_1
1 o) l- |9 _4 O" k j) S6 z$ x end; Y8 }/ H- R- o
if load type = load2 then. y3 J* q4 a- P+ G
begin
o1 U8 V5 d) L" N5 M5 J; n move into Q_m22 q, M: Y: q3 }9 h& C9 N# B
use M2 for n 8,1 min
) i4 x( n1 x1 Z move into Q_out2
+ ^) U1 x7 ?: u wait to be ordered on orderlist OL_2, O! @) c# B9 i/ [
end
' Y0 A% h. K8 w' a" Uend) h6 Z5 D" \0 K' Z
begin P_dunmy arriving
- x! L* z; h0 T& r8 f8 g5 s- g' p set i = 1
) n: N+ U+ N4 m6 |* c6 ~ while i > 0 do+ J U3 y2 _) W5 W: v9 R0 O
begin 0 |1 `) N7 g8 D7 O6 b
order 1 loads from OL_1 to die
" t' R a- M2 s9 W* C in case order not filled backorder on OL_1( `/ K! T6 ]; i
order 1 loads from OL_2 to continue
% W) E, R k$ X/ b) A* z in case order not filled backorder on OL_2& ^$ B& R/ @: T# k1 l5 E
move into Q_1( M% d3 K+ D; b/ K+ t
use Massm for n 5,1 min
- u1 y1 M. |7 M send to die
: T: Q8 T, E/ i% w4 N' V9 [) s end7 A4 }7 D/ v7 c+ L/ Z) e8 e
end
6 q) y* X: B; I. t3 L! J1 q- b; d这是我的报告1 Z8 x ]* m# F Q! Q# W, i
*** AutoMod 11.1 ***; e9 w; e$ D6 M* K* }) x
Model q# I' g5 _: _, J
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
5 j! z" V) j1 w& U2 E3 ^5 z' j' [CPU time: Absolute: 42.859 sec, Relative: 42.859 sec8 w! \) t2 w& Z7 q ^; _
Statistics for Process System "q"1 e" {& Z! P' a2 s( k
Process Statistics$ d# T6 ]) v, u/ g, ^& @
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
' D5 _! ^$ D' v, {. R========================================================================================8 i6 |2 `1 A' P& R# N& q
P_in 222 1 0.32 -- 2 0 -- 126.04 -- E/ I* ?8 r- z: S2 b8 b$ J; C) p
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --/ ]: A1 C5 Y" D
P_in3 0 0 0.00 -- 0 0 -- 0.00 --2 G) f8 |: X* u2 `* V8 p0 j. U
P_in4 0 0 0.00 -- 0 0 -- 0.00 --, a8 H$ K5 V3 m; I) j5 K0 D9 T
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --! z; r) o8 U1 y- P& }4 m( t
Process Traffic Limit Statistics1 Q0 t8 Z: I2 s) z5 c
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
9 U8 r- ?5 q+ F1 ?========================================================================================
$ h% k6 L7 w- g5 W$ A' t. iP_in 222 1 0.32 Infinite 2 0 -- 126.04 --
3 n9 w0 \/ T wP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --- d+ X& n; U) A+ R
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --8 ^% |9 q8 x4 _ Y/ u" q
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
( w8 k, P7 |2 rP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
: t# K& M! D, PQueue Statistics/ `! B! C0 f! a5 p( f4 N
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait0 A) f# h/ d0 V: M* `
========================================================================================5 i; d/ @) v0 s5 n- J$ y& E. `
Space 223 0 0.00 Infinite 1 0 -- 0.00 --
/ u' ?9 n' ~4 W7 S | YQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
2 Y9 s+ B! F6 h+ gQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --# Y5 y$ v5 d4 C# D. l1 y
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --7 Z% S% |. F4 G; f$ T
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
2 X( B# L( d& D5 t6 p) ?Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --5 J; N# `/ d9 D3 v6 a4 E+ f
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
8 U8 V9 e; ?9 W9 ]Order List Statistics
i/ a7 G, [' Q3 B0 W kName Total Cur Average Max Min Av_Time Tot_Back_Ordered" z; b: u' a4 N
================================================================================6 D& u5 d! [3 {$ ~
OL_1 139 139 67.23 139 0 41789.43 1
Z' D' u! B$ ^OL_2 71 71 34.26 71 0 41693.20 1) v# Y% u' w5 {" S6 ]# H
Resource Statistics
6 e5 x. X# w: mName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State ( |6 g- {: o2 N5 R z( o# B* G
====================================================================================================5 S! r8 a4 W. s) I |
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- ( T$ ^) x! y \$ L
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
3 H' B' I4 E$ k5 }/ F0 r' j# GMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
9 C, Q$ ~3 ^" K2 ~oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- / {6 g1 i6 r8 N1 r* _
Random Number Streams
- q1 `4 x7 t( u n) ^) k4 RName Total % K) P: B2 ?" V+ J( {
============================& }3 J. F( O0 v* E: q& c; E, T
stream0 455
' B8 ]# \0 A2 K8 ^/ s9 a5 _8 o5 Nstream_M1_1 0
& x# P6 {1 i7 I# C1 ^! ~stream_M2_1 0
# s+ t0 d' j0 C9 h5 ]stream_Massm_1 01 e b3 _1 n# ^, X, u
stream_oper_1 0
8 w5 P. l; W( X5 Z* C( p# ~stream_load1_1 184
; Y/ q6 q2 M1 z+ Qstream_load2_1 76' b) A, L" B% o( i7 `
stream_dummy_1 0, s o# Q8 e( H. T8 T
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
