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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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: w) L4 K& P7 N我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
% v4 X' |3 Y3 G$ `begin P_in arriving
" o5 i3 L: _% w6 K- h move into Q_in
a1 [; Q: |2 `# z use oper for 2 min, m& A, b7 Y$ J' C( h
send to oneof(0.95:P_in1,0.05:die)
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begin P_in1 arriving
6 _! B2 f: h3 i9 s+ L if load type = load1 then
4 F8 i8 I7 u) c4 _4 W( x begin
. Y! ~9 N1 G( c! Z6 J4 _ move into Q_m1
' N$ B' K* @9 h+ L9 V$ Y use M1 for u 5,1 min
- P! T& ^! d% T. R/ z. z move into Q_out1
0 J6 X+ F. B5 m' R$ Y6 a wait to be ordered on orderlist OL_1
6 v7 B5 M8 x. U* A- O" o& Y end# |( E/ u0 Y0 J0 ~7 L0 P& z
if load type = load2 then
2 r, D' N5 p$ u; |) G3 U begin! _! [2 Z( y& ~ g4 [1 L3 b& x8 d
move into Q_m27 ~4 C0 E: V# w1 d& r4 W& Y3 c
use M2 for n 8,1 min
3 K" D+ O9 m) r2 l move into Q_out29 m- }: a) w* N* G" x' n
wait to be ordered on orderlist OL_2! h; S+ Q( j! M5 A3 S( c: o
end
4 Y1 Q( {! U8 }3 ]3 D8 M9 a7 T2 X" Kend
1 y1 N/ S0 x( X- A( U, x5 a/ V* Ybegin P_dunmy arriving8 J& T% X$ t5 t1 f9 \) |
set i = 18 [' |: T( V/ N. r
while i > 0 do
- u# `3 Z! D4 n- R4 }! q) m begin # d* u+ Z% c; O( v
order 1 loads from OL_1 to die$ n2 t9 p, M$ E! n- ?) B3 d! U
in case order not filled backorder on OL_1
9 K# k; `/ l6 c) j! t4 e* O order 1 loads from OL_2 to continue
: Y2 T! O" A- U* U8 E- `# D* ~ in case order not filled backorder on OL_2
7 O+ N' z- h7 v4 n4 r1 b d move into Q_1& c3 @6 a2 t* N$ m6 {- l
use Massm for n 5,1 min/ \8 ~' @6 y2 W; w
send to die
4 h5 D! C- c/ \0 Z end
/ \: n7 ?3 T$ ^6 L; P9 {6 Mend1 `* G, k- r; d, U+ K: K p
这是我的报告( w" q1 z4 k) Z, f* s
*** AutoMod 11.1 ***
/ e% L: J5 n; F5 L; r# IModel q5 m. j8 Q& F! F" P+ V
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
?. G" `/ _4 s/ h: t3 @" sCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
4 \8 ~# Y3 a9 e) BStatistics for Process System "q"
$ w" l% b7 D9 G0 eProcess Statistics
8 Y! d( y1 b8 ^/ LName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
8 P" ?/ U7 ]3 U, L9 I1 S========================================================================================
- w+ R- s, h+ C; y5 c, _P_in 222 1 0.32 -- 2 0 -- 126.04 --! r6 n7 ?6 Q) Z h; @( `3 u
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
. K% Q1 m) K' A) Z6 c) w, z o" dP_in3 0 0 0.00 -- 0 0 -- 0.00 --
" r) \/ c, H& g4 I3 zP_in4 0 0 0.00 -- 0 0 -- 0.00 -- G$ v+ u. T# f
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
) X5 T1 w) m( q3 |+ kProcess Traffic Limit Statistics
5 e+ o. u, _3 F& K |7 xName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
. V; w4 h9 g- ~$ F. X========================================================================================8 g' H/ R3 Q8 W4 R2 p7 K" k
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
I5 x, L- Y! {% e4 T, Z2 N% A: iP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
& G \# K5 Z8 f2 xP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
' l. Y6 d7 P4 `% N% Q7 S, A. @P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --- e6 g7 E. h# v$ n+ p4 v3 r
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --" V8 F: d1 Z, D. X5 M2 t4 B* _1 Z
Queue Statistics' x5 i" R' k0 k6 X
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
# f4 K' m# T: K0 y$ }4 o$ l========================================================================================: Z2 ?, J3 ?# c/ {% u+ V
Space 223 0 0.00 Infinite 1 0 -- 0.00 --* {2 [: ^ B! x3 Y) o! q# [3 L
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --# E6 `8 G; F8 O) }+ v
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 -- ~4 g: ^: y' _: c
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --* x+ [/ V, }# q, z$ Z
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
8 t, g0 Z8 E; UQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --% F3 l! g- Q y) y+ [/ H# ^& ~
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00. A6 s! X; r9 f8 q0 }+ X) @
Order List Statistics
$ L8 {; V" z3 H# a4 d" {; T! ~Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
: ]4 a1 ^* Y6 Q& H8 B0 g- e) t================================================================================5 f; [4 s5 a$ B( D, }% I" k
OL_1 139 139 67.23 139 0 41789.43 1
) o6 `3 v% b3 [' D7 R: T: _8 q- QOL_2 71 71 34.26 71 0 41693.20 1& {1 b- ?5 T6 [" X
Resource Statistics
G, M$ v% o+ ~4 IName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
- s9 c( `% ]. x8 u; ^* T- N- Q0 B====================================================================================================* M2 o+ p2 L% i* J9 R! n
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- # l5 j2 Q8 f8 G- z0 w# r" @
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
- l3 |8 _$ D8 A& eMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- $ w) M& |* S6 W% p; Z
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- 3 d* U0 W. i$ ?8 H# o( w
Random Number Streams. D6 y i4 k& E& {
Name Total % N: Y' d) C7 n- n5 Y) l/ ]
============================
: _& Z+ Y* u. K2 m" \stream0 455
$ w% L0 v/ C0 Rstream_M1_1 0
8 X9 S3 f1 B3 n1 istream_M2_1 0" |+ a( W9 r4 O$ x, D
stream_Massm_1 0. w5 W5 b+ P( P9 R- u- f. w' E
stream_oper_1 07 o1 j# O0 \* h. J; @
stream_load1_1 1849 O4 J ?( n* I- Y% p( a) P+ h
stream_load2_1 76* _- k4 b) ?/ v4 x! v9 j
stream_dummy_1 0 ~; z* M* X( H+ W i3 w; C8 E
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
