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发表于 2010-5-11 13:19:52
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用list吧9 E- Z/ v& x# i
patches-own [wealth rank]& P$ P2 B. Q1 R1 o H( q
to setup
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ask patches [set wealth random 100 set pcolor green ]
$ {. {/ T$ F. S% U: H9 c8 }end( v( T. e; W# z" u% K, @7 H
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to go o3 Z! q0 e2 ]' _' S% |' v/ s
let mylist1 []
& `& ]7 Y' F; K* w* d& T0 a9 ? set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches; H7 ~# A+ o2 b# y! W& C
let mylist2 [] k. u6 n' ^$ u
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist24 R2 \5 H% z( [ q8 |
[, P! j0 b/ Y d5 H
ask ?1[ set rank ?2]
/ [ t$ e% u( H show [rank] of ?1, C. D+ E: X4 {! w' c, l3 y
% ]! |1 D% D/ E
]
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" C) H: l" l% V B$ T let mylist3 []7 T+ B8 _9 }& ^1 j
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches! P9 ?4 c2 F/ m% h8 ~3 G6 q' h
show count patches. w4 y0 t. O0 a: N
show mylist1
% F v. I2 x1 } show mylist37 d& m, c; I9 c' L4 D7 p* O
end
% M3 r: o* _6 r2 `3 f6 d a- E9 v1 M
这时的mylist1 和mylist3 应该是一样的 |
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