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发表于 2010-5-11 13:19:52
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用list吧
7 Z& w. y6 C2 f m0 xpatches-own [wealth rank]9 g6 g( A/ k, N" q8 [
to setup. v# t' P' g0 e8 i. ], U
ca
' u( G0 P8 ~. ]: y ask patches [set wealth random 100 set pcolor green ]
; V! b0 k, E8 S/ [# hend
0 A) ` A t2 N; h% ^0 `0 u5 c5 Q+ F Y# P
to go
3 g* e( x- `( _7 v* Y let mylist1 []
/ ~% |' Y( i7 e+ t) v8 ~% m set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
, @# z; ]6 x4 D/ z let mylist2 []
! L9 |( v9 W& a3 `: m9 x% n set mylist2 n-values count patches [? + 1]. S7 _! m5 a3 ]6 e6 q7 J0 g/ ^0 \
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( foreach mylist1 mylist2& y! ~" B. J8 q+ `
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ask ?1[ set rank ?2]
* B1 V2 }1 S/ s' R2 D show [rank] of ?1
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]
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7 j U2 B- o6 T2 L let mylist3 []& R4 [. j, p+ u* h y. m
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches, Y. ^" {9 f+ ]! E
show count patches
7 a4 Z& W, q3 k. ?4 c9 N show mylist1
2 v3 S/ C' x0 L6 a2 J6 _4 X show mylist3! Q1 [7 ^3 Q: [ `9 ]* o7 h5 }# o
end$ `* F$ ^' _( C$ }- P/ V: C
0 H. H0 w9 _0 ~! m这时的mylist1 和mylist3 应该是一样的 |
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