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发表于 2010-5-11 13:19:52
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用list吧9 Z' @6 g! u# M0 g
patches-own [wealth rank]
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ca
" o. p5 P- ?; y ask patches [set wealth random 100 set pcolor green ], H6 ?; S3 G0 Q9 _2 R
end
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let mylist1 []6 N5 h; C! c0 @1 @3 z
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
4 s/ u4 y) K" m2 y+ D1 q( I1 N let mylist2 []
' c- a+ _$ I/ i$ E; c' Y2 ] set mylist2 n-values count patches [? + 1]) a* B+ a. N9 H/ G I
4 ?. l. i# X: w9 m ( foreach mylist1 mylist2
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3 Y6 I# o% e# e9 L0 W ask ?1[ set rank ?2]* R0 ~0 f, o5 U5 N1 i- H
show [rank] of ?1( g- H1 O5 w7 ^% M
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let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
- ?! ^7 \5 f9 }$ f- M+ k; s$ s' | show count patches5 g) O; r* [/ p- Y
show mylist1
6 A) k" r, `' C* C. g( s9 ] show mylist3' t1 u' n6 X+ w( D$ v9 I, i
end
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这时的mylist1 和mylist3 应该是一样的 |
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