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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
' P9 _7 M2 u, H% T Vbegin P_in arriving2 T3 {1 T1 Y4 _ j! x
move into Q_in
+ x' r4 T1 i. c" ]8 X( C) S2 w use oper for 2 min
! W+ y3 U5 _2 C send to oneof(0.95:P_in1,0.05:die)( n/ ]5 d1 h3 t, H
end
. ~6 @: {" Z; g# U2 G! @begin P_in1 arriving
# X7 W) A6 E/ E1 A6 b$ z if load type = load1 then# b v0 e5 k4 Q' g/ p
begin
7 r1 Z' a8 h$ q, I9 g move into Q_m14 J, s1 ]9 W% P
use M1 for u 5,1 min9 i: \" w8 D8 D7 Z5 x, T% u
move into Q_out1; n4 |- \/ {5 M9 k3 U ?
wait to be ordered on orderlist OL_1/ w; ^/ F) D" A! j
end
. u5 x; f, E1 K1 S) B if load type = load2 then' w: r/ Q( s! k. C* }; f
begin
4 z8 p5 H. E# i$ l& \ move into Q_m2/ ^+ e/ ? m2 {6 z
use M2 for n 8,1 min
6 w: v- b) f& n* d, V move into Q_out2
* P. O) ^. e4 _& {3 W5 Z+ \2 U wait to be ordered on orderlist OL_2# }- o. l2 ?2 t* f
end
9 M/ f2 x9 H7 X# v" ]- L& mend
' U4 N) }' V Ibegin P_dunmy arriving
) _$ U- w3 s& u5 W- T set i = 10 V7 l+ F5 j6 ?" }* \
while i > 0 do: @ b. o7 [. p: ]0 b
begin
6 G! B& K$ p# t2 r( c# g; r order 1 loads from OL_1 to die- a; e3 x9 N( g& v! z) p
in case order not filled backorder on OL_17 a0 A2 o l4 _
order 1 loads from OL_2 to continue
1 a6 D1 v5 [) h5 S! E in case order not filled backorder on OL_29 Z: K4 u, r" z( n9 T6 u. X! V
move into Q_1; A- F9 j6 d4 O [" h7 L
use Massm for n 5,1 min
9 _8 S2 L! U) Z) B e send to die
% c* ^, s @0 L9 K7 w end
) a- r4 p! j+ N9 K7 E9 kend
: Z9 |) p/ V; h e这是我的报告
( v* m, ^* N/ u( q*** AutoMod 11.1 ***3 V' I7 Q1 \" T6 ~$ L6 U& D* c5 I4 j
Model q
7 f$ `1 H D8 [* I! r5 }8 S9 v9 KStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
( P2 F$ ^- K+ I3 y! j/ [( ^- ^/ I/ yCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
O6 [8 T- G/ E8 Z/ o- dStatistics for Process System "q"
* X1 X, [+ b0 s$ d# A8 FProcess Statistics
* T- e+ _% I' O/ k @8 kName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
7 } @7 {) Z4 ^; J8 U========================================================================================+ [0 d" a5 V2 u6 x" U
P_in 222 1 0.32 -- 2 0 -- 126.04 --, g8 R" K8 u v
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --" U+ z! H7 n# w1 v a
P_in3 0 0 0.00 -- 0 0 -- 0.00 --; Z9 C) R6 ]7 [/ I2 `! x# F+ D
P_in4 0 0 0.00 -- 0 0 -- 0.00 --
1 T3 H2 ] }* L0 G6 ^0 CP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --9 V. H# R0 r/ V$ Y
Process Traffic Limit Statistics
$ \3 I/ Q u; FName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
6 u. O* d) J) r) G' K9 s========================================================================================
7 z/ `6 U9 {5 P6 _* q. V% q# OP_in 222 1 0.32 Infinite 2 0 -- 126.04 -- v! k H4 [) ]' s
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
, t) ^& _: K% {* L6 o6 H$ ~$ _; sP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
' Y$ m6 N* D6 zP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
4 f' G' f: h) |1 LP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --' N% h- P+ H, }- z, A- V) t
Queue Statistics( {: n0 V6 n. y% q% o5 ~
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait% j2 J& |6 L+ Z& g6 @
========================================================================================
! n% ~' @: E3 i) b8 r uSpace 223 0 0.00 Infinite 1 0 -- 0.00 --
/ d# p5 u0 H5 M) S( u( k. TQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --+ ]& L5 h a& y# M) v
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --. h' g9 i+ W1 Z
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
) C/ n( ~' Z0 fQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --% }) W! l' a: f+ h) ?3 O2 s( N
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --& `2 X0 e# e4 h0 K8 {
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00' p1 k2 w3 I, A1 j8 Q+ g- q9 @
Order List Statistics
& B }5 r% [; Z3 b8 Z2 Y8 \, k2 }Name Total Cur Average Max Min Av_Time Tot_Back_Ordered2 i( ]1 \6 x( {, G! a
================================================================================
+ w+ b% U p, ]* G v4 GOL_1 139 139 67.23 139 0 41789.43 1# b6 f1 |7 a8 j' y" o
OL_2 71 71 34.26 71 0 41693.20 1
, l: W1 B1 s2 L m# z6 ]' vResource Statistics4 v* I2 _0 u v, X1 |6 A( P6 q' P1 K
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
. |0 B. Y, k6 T$ z8 O0 l) v====================================================================================================4 ]) {/ j+ v8 t4 P* Q
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
- n& w1 N) z4 I' ZM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
) F7 ?! k3 d9 x/ A! \Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
3 g S4 Q' {. i* ^: q6 S- f! ?3 goper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
4 ^. t4 T" v! \: G6 Q( |Random Number Streams
& d; ]. I6 S* t9 fName Total [8 u' i) r( B v6 z7 ]# K
============================
0 [0 e% T) Z, D( O+ wstream0 455' }: h! b y: Y4 E
stream_M1_1 0
; y& h: D( p0 Z- B W" Nstream_M2_1 0
2 K5 y7 ?" w0 V. F( Bstream_Massm_1 0+ V5 e" d9 ^' l" y t
stream_oper_1 0
* m6 ~8 a9 H8 f( w) C' }stream_load1_1 1842 P9 J4 a2 E4 N
stream_load2_1 76" C+ t; N. x( R- M* U
stream_dummy_1 0
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9 B; M3 R/ u& r# W! d请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
