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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
- I: d$ J8 U2 w7 p% obegin P_in arriving# E2 i9 q, z( P2 j+ ]" ~7 W* E f
move into Q_in
1 }- ^* f( n! \4 h+ o use oper for 2 min. X% S, I t. e1 |) K
send to oneof(0.95:P_in1,0.05:die)' M' h. R A6 O
end! m- l) A0 h6 w, E
begin P_in1 arriving
1 b" ^" Y: w$ t5 ` if load type = load1 then
0 F! |9 k( y; k! e# M2 m begin
6 G. k% p2 _4 q9 s2 a move into Q_m11 y$ t1 o" f* N3 j. X. I) E$ {
use M1 for u 5,1 min$ H7 L" p3 ?% }; [0 z+ Z4 ~1 O, X6 z0 w
move into Q_out1: Z/ h/ t9 g. w! }: R+ F
wait to be ordered on orderlist OL_17 Z7 g" \) a" |# z1 q
end
, Y( |4 R8 J5 k. c0 t if load type = load2 then
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move into Q_m2
1 W3 ?& r7 S% M" N* E0 F' G use M2 for n 8,1 min0 o+ F. [4 u6 ^! y
move into Q_out2
/ y) @4 l0 q2 [8 k* ] wait to be ordered on orderlist OL_2$ g H1 _) N8 A3 a& S
end( T, K$ j, V% J2 s8 c
end
. O! h0 T' W6 p% K4 dbegin P_dunmy arriving% c5 C/ q/ C9 v0 g n7 U
set i = 16 y5 w+ G9 L# P& |! D$ D! G
while i > 0 do
: } S% G9 S8 }1 @' N, q( u7 g begin
, x1 h W. E$ w& _" c9 p( } order 1 loads from OL_1 to die1 D m+ n+ u4 g/ \: F
in case order not filled backorder on OL_1
' m2 v/ K A& _/ U( M order 1 loads from OL_2 to continue
' Q6 S' X* P5 N+ P e' n4 a in case order not filled backorder on OL_2
% x/ A( V0 d2 ~, X# I move into Q_1. @: S8 U" U/ O0 X: }
use Massm for n 5,1 min
$ d; l6 o/ R2 Q c# G send to die8 |* s7 d; _# n+ c) i+ Y
end" {- B7 _! Y) L: J; K
end, H0 ?- C( H8 H }1 G. g
这是我的报告* Y4 R2 H; Q% @, E- i7 f( ?
*** AutoMod 11.1 ***: z2 J1 z. [$ N, O' o* R! ]0 y/ O0 R
Model q+ U& N. R, s8 ^' y' m
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
2 N5 ] V3 e. U5 l- D; ?CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
/ N6 A$ C! Z- B7 F1 Q% f8 DStatistics for Process System "q"
8 c3 C( E- I% k JProcess Statistics
: _8 ~7 I. p8 b, YName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
, z- ^0 J' B( j3 {========================================================================================, M3 j; `- T; n7 [- L
P_in 222 1 0.32 -- 2 0 -- 126.04 --% l- V/ K. S0 D
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --/ g: S! f1 f4 N L
P_in3 0 0 0.00 -- 0 0 -- 0.00 --0 y6 w7 {% F" v! F7 w
P_in4 0 0 0.00 -- 0 0 -- 0.00 --; m5 s# Y9 k7 @3 X/ X8 y
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
' E5 D4 A" h5 {, C# R/ kProcess Traffic Limit Statistics
- d: w, X |+ o4 n# X. z: ?5 r( sName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
+ D' r3 [! k, i========================================================================================, e+ n$ C) R1 G, u* D2 U. j
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --( n7 g$ i3 a. Y; o) r
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --2 e" S1 H [+ j1 `
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --+ N6 s' w! v4 q, p" Y% H: t
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
( t: j" {+ p; b* YP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
F! x7 G, b2 A' c. xQueue Statistics
- ?4 P* j x r" e% x. U xName Total Cur Average Capacity Max Min Util Av_Time Av_Wait- _" ?( S _. k
========================================================================================* ] x5 {* d7 O+ O5 N. C
Space 223 0 0.00 Infinite 1 0 -- 0.00 --
$ @# w9 H% p: ^9 U2 }Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
& D2 w) R. n2 u' h1 Y! {0 {4 M! M6 ^3 d# tQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --# ~& u3 [# J6 z* S, O; j- }
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
9 r+ h0 t: M1 }( \7 ~7 zQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --4 F- ]) e+ n7 g' Q6 M1 N9 x! s# \
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
5 q$ A+ ]# p4 f1 Z3 v: UQ_1 1 0 0.00 1 1 0 0.003 277.31 0.008 V1 N* U/ u) N
Order List Statistics5 r" @' j. `5 F8 l' S' x
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
! A h' \' V! u; m' R================================================================================
! z- k7 u) W7 JOL_1 139 139 67.23 139 0 41789.43 18 B; `+ j* _7 A1 e! Q$ L
OL_2 71 71 34.26 71 0 41693.20 1
( o0 w- L! h2 `* |0 ^Resource Statistics
( J2 C4 u! z7 u# h& X$ ?7 BName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
5 k& a; U# S' z====================================================================================================
; ~- G8 U4 c! S8 y/ I- CM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
$ n: w5 J& A! X( _) MM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- 0 Z( R5 Q( `+ ~$ e/ {
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
, I$ L" x, I; R9 d8 E' q0 `* aoper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- / q9 V0 r. \, Q. J% ~2 w1 |
Random Number Streams
2 @# z. c" _- @: L Y: |9 LName Total
6 ^$ w. f" ]+ K" Z1 W3 f4 N============================
/ z* L& q( }+ O: n2 x, z# r) cstream0 4552 w) I2 N8 S$ R5 d3 q9 n* ~ ?# h+ m9 d
stream_M1_1 0
% q* a" J( [: U2 O& t/ Rstream_M2_1 0
4 R# K' i: [7 R1 kstream_Massm_1 0
9 r5 I ^3 A7 ?$ W4 v/ G* ystream_oper_1 0" Y! Z& _4 T% H; C0 \3 K3 L& S. N$ k
stream_load1_1 184$ \5 }7 d% N, v
stream_load2_1 76
7 P9 y$ w5 w8 p. \6 \; `6 l; Astream_dummy_1 0
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
