本帖最后由 GJM 于 2009-12-5 21:43 编辑
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* c. R5 y/ x. ^) {: _9 C& K6 ^3 M底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去2 ^- }, P6 D7 M4 z- ]# `
" X6 p3 ]9 S$ M; X; | N3 q不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!
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begin P_something arriving
8 P! J3 m# p! Z9 \- o' \ move into Q_wait* C9 @' E+ t# b; q
move into nextof(Q_mA,Q_mB,Q_mC)/ O) J5 K& l h: T3 x" V% g- |* I$ J
use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min
& ~* I7 a: @7 X7 F/ g0 @/ g5 | send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean)6 e+ n/ ?" F7 M
send to die8 V ]- g+ o/ @/ b- w
end
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begin P_mA_down arriving
" ]$ o7 z7 F+ H while 1=1 do
- K' i9 W' a+ L1 }( d! l begin, U D3 U6 R: f* ~
wait for e 110 min
7 P, [. S2 k/ X take down R_mA' @! J+ T; o+ l6 A7 P
wait for e 5 min
6 n- L x6 b6 }( V# U) P& ~# J bring up R_mA# j% z( v! V: P% w, G; A
end; S# a s: \! j6 a' Z
end# R" j( H' x" ]
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begin P_mB_down arriving+ A/ b6 ~; G9 T$ t) P$ L
while 1=1 do
2 @- l; t: J% {7 W1 u! _4 c begin$ H# |2 W0 b% P" n7 a1 [
wait for e 170 min; P1 O5 a: @5 B" C) b6 z
take down R_mB
! n$ U7 V* S6 A! x4 h$ z; M# M wait for e 10 min7 g! f, S. Q0 j9 J$ N9 L! O
bring up R_mB
- W% c6 W0 V& [) t1 V0 N# o end/ ?2 s9 B( \, } b( m, J: E
end
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5 D5 w* @4 }" U0 i7 U+ W" b- D& p3 Ebegin P_mC_down arriving
8 \- C' e4 C, m t& a. V- ` while 1=1 do 5 I! P, N0 E) F& J& ]
begin+ K0 }. x) j8 X, v, ^5 ?: i8 M
wait for e 230 min
6 a* n4 ~" |; s# O9 C5 V+ T take down R_mC
5 G, D6 z! e' y& p+ O1 g wait for e 10 min
0 C( a: u3 P6 Z" X( A; O bring up R_mC
8 l8 @2 y' q7 Z) I3 H end/ x9 z" U) S5 x6 J; R) }
end' ~/ \7 t* j f2 e# u
! o/ m$ H5 _0 R# W/ g5 Z! Bbegin P_mA_clean arriving
( d' Q* B8 `1 Z4 ]. S+ u* \! X4 g while 1=1 do+ s5 i& B" [) s; y1 p7 m
begin
. C2 H3 |" o2 T# A1 k; X& }8 j; ]. Z) X wait for 90 min% D! U/ M0 l! P" L* V; _, C- q
take down R_mA. M* v. ^0 f% ?+ @
wait for 5 min$ Q' m( L( F: J: x
bring up R_mA/ z' N$ f7 E& ?, L% i' D
end* Q; `5 ]& i# q4 s
end
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begin P_mB_clean arriving
' q1 N# G2 Z$ s# h$ j# Q2 H while 1=1 do
) [& j5 y9 ~6 U7 |% \ begin
& W+ M! K$ r1 a6 C8 u! I wait for 90 min
. x% }0 v7 k" t' r. n) b take down R_mB
. z8 P$ L! K5 a. R! S6 @2 O wait for 5 min' |( ]8 |# G( m2 \4 W
bring up R_mB7 [ v: h( E; B
end
' ]9 q, {! _, e3 Y- Uend2 @( Q- S; a, B1 F+ [
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begin P_mC_clean arriving" {+ v+ Z5 u7 {* k
while 1=1 do
4 O# T. q7 g4 L V F; D. n! ^ begin0 l+ v6 c& p, C/ u1 w
wait for 90 min
' j- O& ]2 m) @ take down R_mC( ~: J( h) B, H
wait for 10 min$ f( e4 k; \: ?/ c2 r; i3 E t
bring up R_mC3 s7 G, `. p4 _; s9 b( U+ z
end
$ S7 R- U; L0 o1 {end. T% Q5 {4 s! [" ]% A+ o
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2 x$ K% P8 N: m' M! h* YExercise 5.9
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" I" C$ a# f4 \3 U/ I. k. o, ?* l2 qCreate a new model to simulate the following system:
4 D3 F) E7 }: `8 N1 X* zLoads are created with an interarrival time that is exponentially . @0 I0 M; }* l$ [! X; _
distributed with a mean of 20 minutes. Loads wait in an infinite-8 N6 p% T3 e& @
capacity queue to be processed by one of three single-capacity, / X2 u* r! Z, k
arrayed machines. Each machine has its own single-capacity queue ! n& z# O( |/ t. U
where loads are processed. Waiting loads move into one of the three
2 A4 H4 _! H# f9 `# E+ }queues in round-robin order. Each machine has a normally 7 V; G3 b" x" K5 m( M8 V
distributed processing time with a mean of 48 minutes and a standard
8 y4 a' H( L* h- @% Ndeviation of 5 minutes.. g7 x' a2 [2 Q9 k) p- |
The three machines were purchased at different times and have ' n# d1 P: w! @2 \
different failure rates. The failure and repair times are exponentially 8 ^' `2 d5 P- A/ g& h
distributed with means as shown in the following table: : E* D: s% {1 ^9 P" G
Note The solution for this assignment is required to complete
2 g- A' k, \+ M) o! L) e8 `exercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of 9 C, ^0 J) @4 b2 X
your model.
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: [$ N# ]: K. w+ K6 x# u' QMachineMean time to failMean time to repair8 t4 T! Z8 ]) `, ?% y1 M
A110 minutes 5 minutes/ N6 q0 _; Z, O1 c
B 170 minutes 10 minutes% P6 u4 p! g; A* C& @* @
C230 minutes 10 minutes( U$ e2 v5 C$ v+ \9 p9 W
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The machines also must be cleaned according to the following . ~% R3 G7 V0 g7 j+ ?% o8 e
schedule. All times are constant: % A& r; u8 j3 U: h5 p% d
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MachineTime between cleanings Time to clean
! ?% h P5 m. A( c' W8 o5 tA90 minutes 5 minutes
1 [7 E# \) T! q9 oB 90 minutes 5 minutes
% p$ M$ n4 r; k) ^; h AC90 minutes 10 minutes' d6 y* V. V1 Y, {! ?% f
. Q8 {* M# Y1 |) w1 rPlace the graphics for the queues and the resources.
3 ]) }4 O) V% u2 _" _Run the simulation for 100 days.
, }8 h5 i& q7 B T& O8 X" q$ lDefine all failure and cleaning times using logic (rather than resource : S1 m5 R* r: Q& M1 C
cycles). Answer the following questions:4 J G( L0 s, w" d0 Z- h; p
a.What was the average number of loads in the waiting queue?
5 k! p2 m5 g# \( B# Gb.What were the current and average number of loads in Space? 9 Y6 \" A8 M* k2 X( d2 \) h S
How do you explain these values? " _0 ]3 t |" R7 \- x& p
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