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[求助] 本人初学auto mod,有一道题目希望大家赐教

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发表于 2009-10-3 15:08:34 | 显示全部楼层 |阅读模式
刚刚开始学auto mod,这道题目搞不明白,希望大家看看 题目是这样的,$ _& z, q; _( ^
  Create a new model containing three independent processes, each with one operator. In each process, loads first move into an infinite capacity waiting queue, then into a single-capacity processing queue.
0 |: Y; ^7 h2 U, C' _  Loads are processed by each operator for the following time:. S: {, K5 m6 H! M( M" v2 R, I
  Worker_A does the job in a normally distributed time with a mean of 60 mins and a standard dev of 10 mins.
- r  Y. V9 P" T, E  Worker_B does the job according to a triangular distribution with a min of 30 mins, most likely value of 60 mins, and a max of 90 mins.
4 k$ t1 x5 \( f& G5 m  Worker_C does the job in a uniformly distributed time between 30 and 90 mins.
* [" b) D) u! Q! r6 m& MSend loads to each pocess at the same rate (an exponentially distributed inter-arrival time with a mean of 68 mins) to understand the difference in the processing times of the three workers.
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) P  G5 p# g7 p4 ]% e; G+ L5 z问题:9 E. Q( v9 |5 X7 @7 s/ ]3 b' G4 N
After running the model for 10,000 days, what was the average number of loads in each process?* S0 A9 m$ z9 F' q8 b
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不胜感激!
发表于 2009-10-6 22:36:13 | 显示全部楼层
begin P_A arriving, k( m7 \. Y" V3 p% ^5 ^
move into Q_wait /*Capacity is infinte*/" X/ y' ]+ J; d- F
move into Q_process /*Single capacity*/
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! z3 ]) Q" p$ ^use R_A for n 60,10 min /*Resource A*/* W; f0 f/ d, ^7 U. Q* v2 P8 m: S

) C- d' J/ H5 @* v  h2 w) Y% `send to P_B4 o: k7 x7 k0 z6 D
end
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P_B and P_C is similar
9 R" d2 N+ y2 U/ }0 \triangular 30,60,90 min
7 e0 q1 I3 ^4 i2 h- g& L  cu 60,30 min- u- k5 P. g' A  ?* P

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. \& Z! V; z" k4 Q  m' g' m6 hin P_C, you need to send to die.5 G) q$ L% r# H" T3 U, A8 L' _/ P

" u) {6 j. j4 m( u4 T3 X- ^Then You need to add a L_Control to drive up the whole simulation. and a Run Control of 10000 days.) f. E2 w% a' r3 D4 F' l

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. J+ s6 K% y/ Q8 x. f; z, i6 K  WRemember to turn off the animation before you run your model.

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 楼主| 发表于 2009-10-27 23:53:02 | 显示全部楼层
thanks...
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