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[求助] 本人初学auto mod,有一道题目希望大家赐教

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发表于 2009-10-3 15:08:34 | 显示全部楼层 |阅读模式
刚刚开始学auto mod,这道题目搞不明白,希望大家看看 题目是这样的,
! y; B7 f0 v; P. n0 ]( h) Z  Create a new model containing three independent processes, each with one operator. In each process, loads first move into an infinite capacity waiting queue, then into a single-capacity processing queue.
/ S0 a* K7 U7 P4 t( [' y3 w# M% S  Loads are processed by each operator for the following time:9 B- O( ]( _$ w, F  r
  Worker_A does the job in a normally distributed time with a mean of 60 mins and a standard dev of 10 mins.
& N  w9 T6 H2 E7 e  I: n  Worker_B does the job according to a triangular distribution with a min of 30 mins, most likely value of 60 mins, and a max of 90 mins.& |- t; I! c7 b
  Worker_C does the job in a uniformly distributed time between 30 and 90 mins.
, e1 T8 R. s* A$ {7 }5 nSend loads to each pocess at the same rate (an exponentially distributed inter-arrival time with a mean of 68 mins) to understand the difference in the processing times of the three workers.0 z9 j' a+ }% c; A5 {% Q

5 e( J3 G, n) K4 K' `4 e5 m" J2 N7 B问题:8 A+ c0 O: s* W: m+ \
After running the model for 10,000 days, what was the average number of loads in each process?- {2 m9 u. p, O5 A# R- f
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不胜感激!
发表于 2009-10-6 22:36:13 | 显示全部楼层
begin P_A arriving
/ e$ g! d% M9 s$ wmove into Q_wait /*Capacity is infinte*/
2 H" q3 g& p# O5 h* q' omove into Q_process /*Single capacity*/
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use R_A for n 60,10 min /*Resource A*/
  Y  y) y5 S0 q4 i) W/ N' Y& u- [- \0 {2 _) Q  j
send to P_B! ~3 S3 M0 ^) F2 A6 S# I
end0 D6 |# g7 q5 p6 s

/ |) C) ]7 g$ a# p" C- gP_B and P_C is similar- y* w" Q0 ~1 k# M9 _6 T6 U
triangular 30,60,90 min
) G8 `2 S' G) I1 i0 f% s/ Zu 60,30 min
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, M% L- h; Y0 I- o2 z) g- r7 Fin P_C, you need to send to die." r% k3 w; r+ Y. S
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Then You need to add a L_Control to drive up the whole simulation. and a Run Control of 10000 days.3 z" k- R) _( N: f) Q$ m# M

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6 d, U3 x4 d$ k+ h  ^8 d; C  L( ORemember to turn off the animation before you run your model.

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 楼主| 发表于 2009-10-27 23:53:02 | 显示全部楼层
thanks...
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