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发表于 2010-5-11 13:19:52
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用list吧" V8 H& b; Y' c7 H1 K; O, U
patches-own [wealth rank]
2 I u; h- s+ ^# {. h+ tto setup
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% x9 q6 b& y' n0 [( N3 k T ask patches [set wealth random 100 set pcolor green ]
8 {( e) K. K8 _0 ]% V3 e# Vend) p5 I# A% M# [. Y2 i
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to go7 Y* I) y/ r2 S7 v7 a
let mylist1 []3 \) d2 Y: f0 J7 e0 m: Z# G* B
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches- l0 ?; s; i2 l8 X2 F$ }) i5 j
let mylist2 []+ L: f0 u" [9 ~& ^+ D3 o0 Q
set mylist2 n-values count patches [? + 1]' T4 i* ~0 N6 Y% f5 n
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( foreach mylist1 mylist2& b$ Z6 U* P& W% J/ S& t$ V3 ^
[5 n% z: a9 M0 j" [5 Y9 f; k" h
ask ?1[ set rank ?2]
# `+ w k0 N1 G/ v show [rank] of ?1/ z/ q/ O" L" i$ C5 I
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let mylist3 []8 Z0 A8 T6 j, R6 L) b" ?
7 G: n" e. l/ y8 K+ W set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches1 U& v) w! }5 L' u
show count patches+ `- e Q9 {; H+ J
show mylist1 & q3 b5 D8 M2 f# s
show mylist3( U: N5 ^2 Q7 p _; x2 ~
end
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1 u j9 J' C8 o f+ T- E这时的mylist1 和mylist3 应该是一样的 |
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