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发表于 2010-5-11 13:19:52
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用list吧
1 p% E. ` |( e9 \( dpatches-own [wealth rank]% f6 ^4 t/ ~) v1 M
to setup
6 L* Q' `# {! k* W* L ca# q) r" N6 X \8 ]+ W8 m$ ^3 {
ask patches [set wealth random 100 set pcolor green ]0 t0 t, v& U2 `* x9 J7 z
end8 k1 u! o/ F/ Z. e* s
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to go
3 \+ o* C: P, r! ?+ B* ` let mylist1 []: V t8 m; C. ?8 L2 t/ s
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches) L; X8 T2 _" I1 a4 h2 l
let mylist2 []) Z8 x% I. w4 v9 j5 F8 H
set mylist2 n-values count patches [? + 1]/ ]+ h% ]; H2 Y* K: r0 m
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( foreach mylist1 mylist2
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+ d5 D+ [5 U1 }0 S3 P' ~2 S: z9 g ask ?1[ set rank ?2]2 @, Z3 G$ G5 a* r. ^# w
show [rank] of ?1
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let mylist3 []
# G- `: S8 N9 i & H" f( I& W# g/ |, z: T. z J
set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
# P3 f" e. c1 l, `3 W" n show count patches+ q6 A" Z* `- U6 S5 @
show mylist1 * H6 b0 V! b [) F1 s2 f) j
show mylist3
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8 t7 }- e% T7 P8 F9 N f+ q; X2 B
这时的mylist1 和mylist3 应该是一样的 |
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