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发表于 2010-5-11 13:19:52
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用list吧- e! ?, l; Y# U' L% E& I! q
patches-own [wealth rank]
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ca
. }. m( ~ k4 Y# T+ ]2 N ask patches [set wealth random 100 set pcolor green ]7 v/ J) E* m* q# z8 B% a
end
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to go
0 E6 }4 L' U& P# E6 Q* b ~ let mylist1 []2 V" |5 O- O- _& c# x
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
, ]2 U8 d, w ]3 ?( n' B* ? let mylist2 []. S' n- I9 G, G5 h
set mylist2 n-values count patches [? + 1]
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6 K8 q4 s- t0 L6 { ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
, j( b0 O; @9 Z show [rank] of ?1
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let mylist3 []# x7 K# L4 ~$ w( S; Y. s1 x5 O4 r
1 G: I! s: x- V$ J- K set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches! `+ J5 _* f3 T& L- I
show count patches2 u: u& l( N- I) M7 ^2 t
show mylist1 ' \' x1 i$ ]- B) @
show mylist3
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这时的mylist1 和mylist3 应该是一样的 |
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