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发表于 2010-5-11 13:19:52
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用list吧
u# T3 ?& g8 }' ?patches-own [wealth rank]
$ z8 n7 s2 R! P8 A" y0 \, }to setup
- v2 p {- q8 K* d# X ca
+ J0 |0 U C9 c4 O$ m ask patches [set wealth random 100 set pcolor green ]1 M5 L- V+ o8 b2 H7 \% Q
end0 B' L x9 h8 j% ~+ B! j {, |
6 Z/ M6 d, L" |9 Zto go- ^4 ]0 Z" q- U' j0 A
let mylist1 []
2 k1 S+ Z* I# F+ ~- K1 N) R& k set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches# ]/ f2 u* ]) [. q
let mylist2 []4 t8 j4 X0 {. g. `. j) v3 L3 G
set mylist2 n-values count patches [? + 1]
$ q9 F, M# A# ^% \7 c# R* x" K + k) X; R! h9 _0 R2 E$ J8 F( Y
( foreach mylist1 mylist2
% _7 {/ x( [! B6 B6 u _. N [6 i; I4 O4 E- p5 M' }) ~* P4 L5 _( a
ask ?1[ set rank ?2], J ~$ M0 M: d
show [rank] of ?1
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]
% `9 v. D9 v3 C ), u4 @4 T- W- y
let mylist3 []" R: {7 M. u3 e* W4 d) \/ @
& [$ `: W* m. S set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
/ K( [ D \! b/ C show count patches, f/ i; z8 S+ J; _. d
show mylist1 6 T* e# d. x1 ^
show mylist3& O7 o1 Z; M# w6 s
end; E2 `1 q$ ^5 x8 @' T
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这时的mylist1 和mylist3 应该是一样的 |
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