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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:  c+ ]2 s% c* y6 ?
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public Object buildActions () {0 h; j* T) k/ l9 R* p7 U
    super.buildActions();0 T: h% q/ ~. g
   
$ \) m) N0 D8 K) m' S6 v+ o7 s  }    // Create the list of simulation actions. We put these in
# u) q; j5 j1 M: j6 w. m    // an action group, because we want these actions to be* p% c7 L- S4 G0 }/ K- Q
    // executed in a specific order, but these steps should) Z/ g; d& @0 t
    // take no (simulated) time. The M(foo) means "The message# Y) n1 E- j& u
    // called <foo>". You can send a message To a particular
4 X9 s1 T) W& A- g2 Y* g    // object, or ForEach object in a collection.4 y, Y- p5 p. U
        * W; D* `: X: |8 S
    // Note we update the heatspace in two phases: first run2 T  ~' Q- d6 @+ Y& ?( `1 Z
    // diffusion, then run "updateWorld" to actually enact the8 \, t$ \4 D2 t0 K6 U) h: Q
    // changes the heatbugs have made. The ordering here is
4 t( Y- M% u# b, [    // significant!
( n; W, l+ \% r. D        
2 U, w) w2 n1 c    // Note also, that with the additional
  n  c+ {. m5 u; b: w    // `randomizeHeatbugUpdateOrder' Boolean flag we can
) t/ O$ k% y( p) _    // randomize the order in which the bugs actually run1 d3 _1 e4 X/ a4 m1 w
    // their step rule.  This has the effect of removing any) Z3 P$ a9 E5 v3 `' ?, m
    // systematic bias in the iteration throught the heatbug
5 d; G; r$ G: c; H    // list from timestep to timestep' B! C6 r5 T$ Z4 @
        
8 v1 f6 X7 ]7 y# |, g; `5 E0 k    // By default, all `createActionForEach' modelActions have( r1 U: w5 d4 U3 J1 n) u
    // a default order of `Sequential', which means that the5 q( y1 v# x* f1 J3 o% ~; `
    // order of iteration through the `heatbugList' will be
1 O4 h" g0 h( k- ?$ B. m3 h4 d) R    // identical (assuming the list order is not changed" I" o+ W- J# p0 ^% `; C& n
    // indirectly by some other process).
! M2 C. }& a: r0 A; G    4 x5 H5 Z; u, J& Q. C! ~
    modelActions = new ActionGroupImpl (getZone ());
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    try {
5 M; M" X: L  L0 f$ v8 ]1 S      modelActions.createActionTo$message  `( z$ H: ?; O+ P
        (heat, new Selector (heat.getClass (), "stepRule", false));
/ V0 ?8 g7 o" M! y: |    } catch (Exception e) {
  |; n& O, t2 {7 {& h5 V% ^      System.err.println ("Exception stepRule: " + e.getMessage ());
. N; s8 \" o+ R2 [8 z# u6 E2 ^" y  N( N! O) s    }4 {' [' U  Y. w: [

% e. A# Q& P7 r    try {7 c0 m' i1 l" N8 Q2 |! o" @
      Heatbug proto = (Heatbug) heatbugList.get (0);- K! ^5 H' h8 a
      Selector sel =
  z1 z+ C! j9 Q- E( L0 d        new Selector (proto.getClass (), "heatbugStep", false);
$ _2 ^1 s/ ?5 i8 c/ m4 q      actionForEach =
  l3 b- q! C/ ~% V+ I* \' |        modelActions.createFActionForEachHomogeneous$call
# c. O8 P( C+ H: d( X7 K. m5 ]        (heatbugList,
1 V4 }' a1 `+ P5 m) m9 O2 W         new FCallImpl (this, proto, sel,+ u* Q7 L. K% d4 L
                        new FArgumentsImpl (this, sel)));8 C% A6 I9 {# e( x4 U) N. V9 i3 w
    } catch (Exception e) {9 [. m/ g' p- e, y! b
      e.printStackTrace (System.err);
% w; f; X+ J6 d    }
$ A: A- q- ^3 x$ Y; z   
; g8 A3 U8 q3 d- F    syncUpdateOrder ();
, H: P2 o7 S0 n% s% @
3 Z0 s) K: o# T0 m    try {
3 O2 F4 A9 i( J! a& l8 C( U      modelActions.createActionTo$message
0 m! H: q, e  T9 Z+ {( \        (heat, new Selector (heat.getClass (), "updateLattice", false));
  E8 d. o6 f6 ~6 K3 f) l0 A9 f    } catch (Exception e) {; ]  c/ v6 H. U, g6 l
      System.err.println("Exception updateLattice: " + e.getMessage ());
* L% c5 x9 W+ B% C- b5 k    }
, `" o9 S! J: r8 ~7 c  c        5 ], y/ j* Z$ X9 i/ Q9 N, T7 ]
    // Then we create a schedule that executes the, p) ]. B- E8 ?5 j4 l
    // modelActions. modelActions is an ActionGroup, by itself it
1 f6 i6 r$ f  M: q5 @* Q    // has no notion of time. In order to have it executed in) l$ G7 D- x0 u( G# d9 s
    // time, we create a Schedule that says to use the
" X1 l6 ^' [( y8 l$ ]    // modelActions ActionGroup at particular times.  This
2 |$ a4 ?7 i! [    // schedule has a repeat interval of 1, it will loop every
% ^/ \& f8 a' N3 ~2 v3 @5 T9 v$ f    // time step.  The action is executed at time 0 relative to8 S0 C7 s0 x; E1 \; X
    // the beginning of the loop.7 w$ K7 Y5 ]- s* {9 C; g! k

- \% I+ ~5 b1 i  w    // This is a simple schedule, with only one action that is
5 _. [! y! t: O    // just repeated every time. See jmousetrap for more
& T# ]& v, k) @    // complicated schedules.6 Q0 X  u7 ^, \7 C4 }; K
  
2 t+ J6 @. t4 L- o    modelSchedule = new ScheduleImpl (getZone (), 1);6 X- T" @3 O  x7 Y  m, s# c+ o
    modelSchedule.at$createAction (0, modelActions);
/ s, e0 K) b% y% J) K" x        
& o+ @9 V# ?% \5 A    return this;
5 {8 U) v. r! r! \% v- I* t: u0 A  }
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