设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 10833|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
" u: J% v: ]8 v, @
% ]& t) z6 V% C public Object buildActions () {( \6 M4 f0 A9 i
    super.buildActions();
+ s( N, R" Z) c6 q8 q: t( V- x    * H$ w( R: E5 p9 b; [5 [
    // Create the list of simulation actions. We put these in
, U" @' T( ^; C* l    // an action group, because we want these actions to be4 K* f( [* K3 v+ ^" g) d4 _
    // executed in a specific order, but these steps should3 `$ W+ ~1 J8 K6 m  w& r
    // take no (simulated) time. The M(foo) means "The message/ }7 \) Z2 x/ u( P0 A2 w
    // called <foo>". You can send a message To a particular
" {4 w9 T' q( H    // object, or ForEach object in a collection.
1 x4 J% P0 @9 b3 L3 t        1 b: J$ d. y6 q5 d" C8 {4 y
    // Note we update the heatspace in two phases: first run6 i( c' E+ |% T6 u7 G% {
    // diffusion, then run "updateWorld" to actually enact the
( r: G. H# S! J: J3 ~    // changes the heatbugs have made. The ordering here is
; }5 I1 z& V2 B/ Q* Y. w    // significant!
' z, a% ~0 ?/ l  R. h: K( h        - E5 Y. G7 V5 C9 ?( u3 y8 \8 O
    // Note also, that with the additional
: [$ H4 g; H& i/ A% T    // `randomizeHeatbugUpdateOrder' Boolean flag we can
; G3 Z% F3 c* z5 X- c1 J/ ]    // randomize the order in which the bugs actually run
* k8 d* h+ w4 \0 N# q+ H( b" P    // their step rule.  This has the effect of removing any' [8 E( p" \$ T7 |  b9 Q2 A7 f0 R2 |
    // systematic bias in the iteration throught the heatbug* J% L- ?" d. ]
    // list from timestep to timestep
# C, B% Y3 N! p$ W) w        ' _7 t4 P% Q/ F" H' o
    // By default, all `createActionForEach' modelActions have9 E% g+ @6 n4 H# o7 I
    // a default order of `Sequential', which means that the: b& B4 ~/ [0 D- S; d5 K6 r
    // order of iteration through the `heatbugList' will be4 p! @; v0 m' Z. |
    // identical (assuming the list order is not changed1 @, n/ u2 M3 Y  h
    // indirectly by some other process).
. Q+ ^, H1 j% x' o* @* U; F   
: Y, h4 A0 _* N$ z- x    modelActions = new ActionGroupImpl (getZone ());
/ e% u8 d) b8 [0 H1 X/ F9 `% o7 d% O" m, B2 b
    try {
; F! u9 v) j! k% S; t      modelActions.createActionTo$message
4 D! B: G% A2 J' }# P" A        (heat, new Selector (heat.getClass (), "stepRule", false));, j/ w9 T2 v* p; K& h
    } catch (Exception e) {
3 P2 S6 B' R# R7 S      System.err.println ("Exception stepRule: " + e.getMessage ());
: j% x4 R! T2 @' m- T5 {& _: h    }
- F' G9 r0 N! D+ u3 D
2 ^' O, R8 q' Y6 o% L2 c% V    try {6 {6 ~& p! C$ m/ H
      Heatbug proto = (Heatbug) heatbugList.get (0);
+ a, {* \* m' _2 e: y  }      Selector sel = % w+ n* \! U3 ]5 q. t3 J3 I) n) l& ~
        new Selector (proto.getClass (), "heatbugStep", false);
: b7 c# a# c# @5 H/ K: `      actionForEach =
# y' |1 s! p) u  P        modelActions.createFActionForEachHomogeneous$call8 Q5 X( J2 i  I/ U
        (heatbugList,
- i" r9 c" a" \( S: c' k+ Q  P4 O         new FCallImpl (this, proto, sel,
5 {( F9 u. O: \% u                        new FArgumentsImpl (this, sel)));4 }% O8 F9 d0 i8 ?4 a; V
    } catch (Exception e) {, a% A5 j/ t" p6 u
      e.printStackTrace (System.err);
- L4 E' H. V: ?0 P# r$ q4 L9 P    }
: ]+ e2 }/ {9 v* F/ a3 C    5 q* x( |) }" |# i6 Y5 P, o; Z$ a
    syncUpdateOrder ();/ X' E9 F% J* w; n+ |2 q

% c" j1 f7 L4 l, E# J+ `    try {
. y3 h/ h& k- T2 n* `" d) B2 W9 g; b      modelActions.createActionTo$message $ q& X, J' }# D+ R5 E. W
        (heat, new Selector (heat.getClass (), "updateLattice", false));
/ G4 \* n/ `. Y* f7 Z    } catch (Exception e) {
" v$ q3 z" W5 R  C, L      System.err.println("Exception updateLattice: " + e.getMessage ());% `! r5 N: A- b! y0 l
    }# K, ]& [$ o0 B' w0 k& W& j1 F! Q
        
3 R3 d( }3 y, K    // Then we create a schedule that executes the8 f+ S% p$ g2 L! B$ q$ m, h  \! K
    // modelActions. modelActions is an ActionGroup, by itself it) `$ S% E- b8 j. z6 b, m  a1 r
    // has no notion of time. In order to have it executed in
3 k! p0 g- Q/ O    // time, we create a Schedule that says to use the: \! o+ r5 b3 k" k& c2 C
    // modelActions ActionGroup at particular times.  This$ q( l. q. P* v; O. ?. M
    // schedule has a repeat interval of 1, it will loop every: P! T9 z) g- R, k
    // time step.  The action is executed at time 0 relative to
+ s  w( m8 C! E* n3 O- [    // the beginning of the loop.1 w& N6 a# M2 a6 L9 S, A7 W& ]
; j- W5 G3 ?8 Z0 {: x# k
    // This is a simple schedule, with only one action that is# t0 ?  r+ U. c+ P. M% v
    // just repeated every time. See jmousetrap for more
9 a: {# u" {. [) b    // complicated schedules.
6 n7 a# B7 P% u" _) x' d  
2 K( A0 d1 U& [/ @    modelSchedule = new ScheduleImpl (getZone (), 1);3 b1 h7 l* _8 x. z
    modelSchedule.at$createAction (0, modelActions);. ]! H. C" c/ M
        0 \4 ?! C+ S  Q2 |, g) a- j
    return this;9 B3 Q: t' {3 R
  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-5-22 01:25 , Processed in 0.018864 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表