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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:" n: U! ?1 i9 m( y' q- ~
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public Object buildActions () {3 \- }. y4 Q' X  \& @2 l
    super.buildActions();/ A; J3 W% `" d" S. w& V
   
9 }/ d4 c" g4 G0 e- p6 z    // Create the list of simulation actions. We put these in
4 S' I: e( K# O; ]* g" V    // an action group, because we want these actions to be
9 j6 T& T# K* H7 Z) g' O/ S    // executed in a specific order, but these steps should
9 z8 T: H+ k* v& ]. b4 o4 w! i    // take no (simulated) time. The M(foo) means "The message9 R/ q* Y5 \8 h" ^) @3 }: A
    // called <foo>". You can send a message To a particular0 ?  \) }9 F: G& L
    // object, or ForEach object in a collection.
' Q: m4 U0 L, M8 G1 i4 c. r        & c% h; S+ T! V# d7 @& K
    // Note we update the heatspace in two phases: first run% b% Y' d7 z, g/ B% Q
    // diffusion, then run "updateWorld" to actually enact the
2 p! p, j: t/ Y7 E; P5 o( `    // changes the heatbugs have made. The ordering here is
- s) A' G+ R6 `; X+ ]" y& |    // significant!; Z; [, x7 ]+ H. \
        - ?" W% c0 w# I( F
    // Note also, that with the additional
( \- C8 L" j3 {3 t9 K( b    // `randomizeHeatbugUpdateOrder' Boolean flag we can
$ H/ C% _8 J, v0 Z" I% O7 W* J    // randomize the order in which the bugs actually run; t1 l9 x+ n$ V; a
    // their step rule.  This has the effect of removing any3 C3 {& \: r$ C( f
    // systematic bias in the iteration throught the heatbug& m9 Q* m; b$ d% S  f3 F2 C
    // list from timestep to timestep
: x4 W3 U$ o1 O/ r7 k        
) o: t; ]5 N' i( ~% W# Y9 `    // By default, all `createActionForEach' modelActions have
/ E6 }8 A: a/ a! `    // a default order of `Sequential', which means that the
6 p- B  S) F* u9 f% s" N3 q    // order of iteration through the `heatbugList' will be) g/ X. H! u! k" S+ V8 p" V
    // identical (assuming the list order is not changed
7 d* V6 {4 d2 b( @( |    // indirectly by some other process).  C2 z' q; j# s
   
5 F( K  P( j2 V! K8 n* l5 p. Y; ~    modelActions = new ActionGroupImpl (getZone ());
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! v, R1 H# o! n; t. w    try {$ g+ F4 X4 q% k
      modelActions.createActionTo$message
& X0 t3 f# P% U; E) ~        (heat, new Selector (heat.getClass (), "stepRule", false));4 \: p. K! n7 j$ U" p1 m
    } catch (Exception e) {
- l# w1 y8 A9 K2 f      System.err.println ("Exception stepRule: " + e.getMessage ());
9 C. Q$ O5 q6 C. G    }/ S& n" r$ J3 s$ Q0 H% e" ]
* P2 u* e7 }/ H
    try {
  l3 |  s; s2 Y4 c5 {      Heatbug proto = (Heatbug) heatbugList.get (0);
8 Z  k# v7 m, y: i      Selector sel =
/ Q: A8 R: J9 L: A        new Selector (proto.getClass (), "heatbugStep", false);3 W* O: Y0 g% _5 r% _0 j
      actionForEach =
# o5 d( J& i) B# U        modelActions.createFActionForEachHomogeneous$call' K: v3 ]' Q, M; p2 o% N
        (heatbugList,* `: ^" J+ s: a5 Q2 S2 r
         new FCallImpl (this, proto, sel,
# y& X% S4 O' r) G6 F$ t5 z                        new FArgumentsImpl (this, sel)));
' _' G, X& f; G0 V3 u1 p    } catch (Exception e) {! n0 a9 r1 M& C
      e.printStackTrace (System.err);0 `$ t. S: A4 w1 w* C
    }! O& d; j1 k4 R1 C* T* f
    : R/ J3 B8 r/ G& @1 o7 o# T
    syncUpdateOrder ();1 _6 `6 q; j, V5 X1 E7 l
0 ?9 U7 t- K+ y. O3 {0 \8 e
    try {
- s+ R  e9 T1 N! m7 I- N6 A      modelActions.createActionTo$message
. C5 ]5 h2 R: B# q0 x8 P7 D. h5 Q        (heat, new Selector (heat.getClass (), "updateLattice", false));' n6 S4 y3 U- Z
    } catch (Exception e) {
; V3 H/ ^& z% N" x5 I; y      System.err.println("Exception updateLattice: " + e.getMessage ());1 V9 Y. i4 T) o, i: n
    }
- l2 O& I; s5 u) a; C% a4 d        8 K. Y. G' P4 c
    // Then we create a schedule that executes the
1 n! s* A4 A( V    // modelActions. modelActions is an ActionGroup, by itself it. \0 |# D6 B% o2 M. x
    // has no notion of time. In order to have it executed in5 D9 U- }+ `: U  t0 \% S
    // time, we create a Schedule that says to use the
% a# X( [6 W  G2 Z. P    // modelActions ActionGroup at particular times.  This6 {; ]% l: s6 t( Y  @+ u2 u
    // schedule has a repeat interval of 1, it will loop every" I4 @2 ^* z! A4 M: h/ X% T- p; ]
    // time step.  The action is executed at time 0 relative to
0 Y5 F( i- W6 Z5 m    // the beginning of the loop.
% v! F0 [; u5 E) v6 P( f8 _: G8 m
    // This is a simple schedule, with only one action that is
1 P; p% a. _9 V: T    // just repeated every time. See jmousetrap for more( G+ E1 X5 ?! M# d- H3 S7 Q8 [8 O
    // complicated schedules.
9 i3 M' p: i# M7 [  * K9 t6 N) C$ c! R
    modelSchedule = new ScheduleImpl (getZone (), 1);5 Y1 x0 w* W* w6 N& b1 N, I
    modelSchedule.at$createAction (0, modelActions);
! l% h3 E3 R  A- q+ Q. r        * X& J: A7 O& g& L% w& ]- |5 f. g$ m; H
    return this;3 Q. c0 c" H) v9 ], ?6 w, }
  }
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