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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
3 `8 a) h  o5 p, t+ `3 c; ]0 e& W: O
public Object buildActions () {: {8 ~' k3 u" @- Z3 t" D
    super.buildActions();" v, }# e  t( h1 c2 _3 q- E
    - o; {* }/ b  s! u
    // Create the list of simulation actions. We put these in- y5 c* R0 Y; v. v$ O! J2 u) M
    // an action group, because we want these actions to be5 Z+ [/ B' H* e  X' L* Z) x- _$ n
    // executed in a specific order, but these steps should8 D8 p2 M2 R4 |0 {& O8 @0 A
    // take no (simulated) time. The M(foo) means "The message
" p' R5 n; S' T2 K* x/ n9 E9 s    // called <foo>". You can send a message To a particular
1 p  n0 x4 C8 E* o* {  {    // object, or ForEach object in a collection.
- y* E% O+ ~* b% `# M        
. C' p  v3 F9 L  D; e    // Note we update the heatspace in two phases: first run
+ h$ i* [. h) o5 v. l2 V  ?  g2 Q    // diffusion, then run "updateWorld" to actually enact the
% R2 ?1 R- I: b0 H' V    // changes the heatbugs have made. The ordering here is
- z& K, F0 {7 ?+ j, l& V# F( c* T    // significant!
/ o/ f# a- t# ?" \1 \, ]9 U        
  X) H4 w" f( z: p1 A    // Note also, that with the additional& P6 o! `- U& F. l  A: H
    // `randomizeHeatbugUpdateOrder' Boolean flag we can, ?& ^" ^9 K. e7 ?/ S
    // randomize the order in which the bugs actually run9 Z5 B7 J) @, }% S! T" ?
    // their step rule.  This has the effect of removing any% m# v6 f6 m" X, N) F
    // systematic bias in the iteration throught the heatbug; c3 y% U2 K0 {0 ~' f
    // list from timestep to timestep( X5 I0 A; K& i, `6 W. \
        
4 ^" v  @8 d' n* z0 Q1 d    // By default, all `createActionForEach' modelActions have
) q; @7 I% u* G3 V! `% s3 J1 A    // a default order of `Sequential', which means that the
; M: }$ J7 }3 [    // order of iteration through the `heatbugList' will be
! k" c3 {: u/ |! s    // identical (assuming the list order is not changed
8 ~6 ^; n  W" Q8 B    // indirectly by some other process).
% `0 R6 I( O5 O9 J/ k  ~   
3 W- |3 n  ?4 n6 G) i3 u    modelActions = new ActionGroupImpl (getZone ());
5 o8 T) k; B# B9 Q- y6 K/ A: J9 p' C' l5 e1 l1 k# o1 i
    try {2 t! ~0 Z. b5 |+ I
      modelActions.createActionTo$message
% Y+ G# h- P2 j* b        (heat, new Selector (heat.getClass (), "stepRule", false));
0 e2 t$ F8 O; x; D    } catch (Exception e) {
: ?* o1 U3 Z3 X      System.err.println ("Exception stepRule: " + e.getMessage ());( ]2 F$ ?% r; `$ \
    }* R6 k: x3 s% ^& Z  P" w
; p) y$ p  F5 j% e. \5 B* H  `
    try {
: _  ]; i: b: W* u1 F% e      Heatbug proto = (Heatbug) heatbugList.get (0);+ u/ a/ H/ }/ s
      Selector sel =
* J9 z: @! A5 J: q; ], K: `        new Selector (proto.getClass (), "heatbugStep", false);
  E6 L2 Y3 E3 l! p$ Q: e) `      actionForEach =
! P! I0 O1 N7 E! o# f* l0 t        modelActions.createFActionForEachHomogeneous$call
: y( j( q  H1 u& j" ~        (heatbugList,
6 f  K0 C! C$ U9 j# C+ N  g! x. n9 j         new FCallImpl (this, proto, sel,1 T+ T% z" ^  |  O7 v5 [
                        new FArgumentsImpl (this, sel)));
! i! |% s$ k- D5 o' L7 |9 r7 J8 S    } catch (Exception e) {
% ^! Q! F3 a3 A      e.printStackTrace (System.err);
0 d1 f6 P4 v) _7 u0 a4 p& l    }$ F# y. H3 A; A
    3 J  B! l# p! I1 I$ e: D7 A
    syncUpdateOrder ();) q. w$ J4 T. S: K5 R

: e' H0 u% z% O. |4 r5 z    try {
2 A& r0 r# U9 u$ G. ~      modelActions.createActionTo$message
8 C1 {$ t0 B  x) v/ U5 m! U        (heat, new Selector (heat.getClass (), "updateLattice", false));
! n% G, b' k! ?2 _1 C    } catch (Exception e) {
+ r" i- q( \6 ^3 }2 i      System.err.println("Exception updateLattice: " + e.getMessage ());3 e6 ?9 h6 O8 M+ m3 Q( w2 U) W5 b6 E' r; A
    }
- X8 v, G. u' x8 M% `: Q        
( M: l/ s# Q/ }+ m    // Then we create a schedule that executes the+ M2 x$ y2 X/ ]- m. \
    // modelActions. modelActions is an ActionGroup, by itself it
, N% S: R8 @4 y. _; U, e5 b/ `    // has no notion of time. In order to have it executed in
- K$ J! N0 J" g. M    // time, we create a Schedule that says to use the5 Z7 N' G3 d; S& j5 I
    // modelActions ActionGroup at particular times.  This% o6 T$ r( y5 k" O/ Q& M/ }
    // schedule has a repeat interval of 1, it will loop every3 _2 e/ d9 E& ?) p6 N0 d
    // time step.  The action is executed at time 0 relative to3 o+ p. P0 {, _  j/ S5 E$ v0 @8 U
    // the beginning of the loop.
* k5 t8 _3 f7 ]+ u0 D2 m) C7 `3 z6 M: _: m5 u# a
    // This is a simple schedule, with only one action that is) H, ~6 U* f: q* x4 c: E" y8 L* B
    // just repeated every time. See jmousetrap for more
/ b! R7 P# ~. _) M7 k    // complicated schedules.
: v4 i3 Q0 f7 t% X* p% H# Y7 P6 ^  3 y6 {0 Y4 v& g* J
    modelSchedule = new ScheduleImpl (getZone (), 1);# X0 l0 l7 M" x* u7 W
    modelSchedule.at$createAction (0, modelActions);$ }7 }  {, E. b, M. U
        
( i; T; n' Y1 M" O7 H# O8 Z; l    return this;' u* q0 L) g! F) |$ {
  }
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