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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
9 _5 ?$ _' f. K
9 g: W3 t1 t2 y public Object buildActions () {
, J8 _1 }, W) J& U    super.buildActions();( }, ^7 m" v0 w4 {; r- Y
   
8 m! {. A( ~+ D; Z; n    // Create the list of simulation actions. We put these in: s2 S. X! Z8 X! z/ t# ]' ]$ E% F
    // an action group, because we want these actions to be
+ d- t% a1 {: A# M: H    // executed in a specific order, but these steps should8 ?# _7 Y* ~0 L) b! g( R6 i8 C" {
    // take no (simulated) time. The M(foo) means "The message& L7 ^4 {3 I/ F8 @: j; u1 {
    // called <foo>". You can send a message To a particular
; \( B" g7 i/ v8 i; g5 ~) p    // object, or ForEach object in a collection.
7 b) j# }0 r7 t0 V' w' q1 D        1 {% x( d0 f% d' g$ k8 y/ D7 c
    // Note we update the heatspace in two phases: first run
9 g. K- U* {" p2 Q    // diffusion, then run "updateWorld" to actually enact the
8 W' s/ z' _. l2 R5 c8 S    // changes the heatbugs have made. The ordering here is* L% I# J+ v0 `% ^2 t4 b- d
    // significant!- }/ @1 q3 I; x0 b5 ~
        
  D& r3 v# R5 a. ]    // Note also, that with the additional
: n# m+ {9 ~  ~" [* \3 A    // `randomizeHeatbugUpdateOrder' Boolean flag we can& W' K$ K3 @% X+ _* A& g* \
    // randomize the order in which the bugs actually run& S8 z9 Y! X5 c1 h$ r
    // their step rule.  This has the effect of removing any
+ J6 t" L* ]- P( ^5 Z5 t    // systematic bias in the iteration throught the heatbug
; t% Q  `$ N" L    // list from timestep to timestep
" d6 t: X* t# n( ?) _- V        - f3 _8 f5 E8 [- q- V
    // By default, all `createActionForEach' modelActions have& y  X% Q& \3 S) i& o3 H! x: o: o  ^
    // a default order of `Sequential', which means that the; b: |3 }7 P7 K6 y
    // order of iteration through the `heatbugList' will be
5 S; S9 P; s6 M7 A    // identical (assuming the list order is not changed/ z+ h/ a0 z, e: i  d7 H3 {* A- ~
    // indirectly by some other process).( D' b: \: L2 B7 v2 }% d! K
   
7 l- E* P  j4 M. v4 r; i: S- U; w    modelActions = new ActionGroupImpl (getZone ());
  i1 X* H+ j9 A( U6 D! q' y  U7 x' `
" D0 }$ q8 W& u* X8 D; F    try {; F6 F0 q& V0 w5 T
      modelActions.createActionTo$message
+ H0 Z8 M( v" H0 X2 T% s        (heat, new Selector (heat.getClass (), "stepRule", false));
; B+ s3 I0 {, ^  |    } catch (Exception e) {
- ^; w" N3 D" |      System.err.println ("Exception stepRule: " + e.getMessage ());
7 [+ {9 S+ f* Z4 x    }- \6 U) u# E# l" g$ y8 O0 `, O
; [7 C/ f% L" u. `
    try {( A6 m- h+ i5 K, p0 U
      Heatbug proto = (Heatbug) heatbugList.get (0);
+ l4 Q+ i- L: T/ `+ E      Selector sel = 3 ^% u* Y  d% Y6 H
        new Selector (proto.getClass (), "heatbugStep", false);
* l4 W) Q: w1 u. H      actionForEach =% N1 \0 D  h# E2 A- B& ?& I
        modelActions.createFActionForEachHomogeneous$call6 l/ x* e$ u. e" Y
        (heatbugList,  c- \+ O1 G, i  L: Z
         new FCallImpl (this, proto, sel,8 m. d# r7 X  a, _: Y
                        new FArgumentsImpl (this, sel)));
5 x' }3 G" g: Z6 q% q6 K# U$ Y    } catch (Exception e) {
1 ^9 p9 H. V1 M! \2 ^. @      e.printStackTrace (System.err);
0 b5 Y$ q1 O; u  |' z( }; Y    }
- M6 j& k; O$ f    $ a$ ~' ~* u& |8 {% q* K0 e
    syncUpdateOrder ();
; x7 r2 M) D, R5 V) u" N8 D9 ^- K( {* X6 K+ w1 m  Y
    try {$ C5 q% L9 ~; a0 Z2 @; B
      modelActions.createActionTo$message
* A  Q3 O: Q2 d4 o0 F        (heat, new Selector (heat.getClass (), "updateLattice", false));" C& J% W4 w# t) D8 U: k
    } catch (Exception e) {+ c1 N& E- j6 J; y# E
      System.err.println("Exception updateLattice: " + e.getMessage ());
$ L9 L+ g; P0 S: Z$ P# R" M5 O) @# o    }/ E7 v" I. x1 e" E& _7 ?' Y
        
$ n% s0 a: s% E    // Then we create a schedule that executes the
2 M6 `+ B  Q  n% }5 y    // modelActions. modelActions is an ActionGroup, by itself it
8 }& t; i5 y: p8 e    // has no notion of time. In order to have it executed in
9 ^* T% t* _5 I    // time, we create a Schedule that says to use the7 B2 ^9 U& [) k
    // modelActions ActionGroup at particular times.  This2 \6 ?' v% ^. ?% n7 ?8 g
    // schedule has a repeat interval of 1, it will loop every
! E4 ^4 {$ k0 Z  G0 z. w7 w2 d    // time step.  The action is executed at time 0 relative to; n5 s6 T; v! S4 P0 D- I3 q* q7 A) v
    // the beginning of the loop.
+ M0 q$ f+ O7 J7 g" m; V2 N. e( k7 m; W
    // This is a simple schedule, with only one action that is. U# x, s5 \3 S& Y6 V; b3 I, }
    // just repeated every time. See jmousetrap for more% x& \$ {: I/ _! w
    // complicated schedules.! P" Q5 q1 d$ f( s# a
  
3 f9 ^* E6 W- O+ j- U- r    modelSchedule = new ScheduleImpl (getZone (), 1);
2 C) P1 c0 l4 f+ U7 b* P" O    modelSchedule.at$createAction (0, modelActions);
  e/ a: Y6 m. L% H6 \        1 F( ]6 Z8 h' d" `- ^) v, Q
    return this;! u6 z4 P# N) N1 J$ h% F. G
  }
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