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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:' q+ z5 V4 @0 a/ j& j

/ t' F- U5 W& ^1 o  p! E; K) H1 ^* z public Object buildActions () {8 l) j& n; |6 ^( m) m2 g
    super.buildActions();
2 x) v2 s& i! _* `- w0 y   
* w. s6 W6 {# G4 ]    // Create the list of simulation actions. We put these in
7 p: y$ _( \6 n# u3 u  g    // an action group, because we want these actions to be
% j1 v0 q% ?) y! J5 Q* b3 |, {    // executed in a specific order, but these steps should
0 V1 |+ x* r8 E2 w. [    // take no (simulated) time. The M(foo) means "The message
1 }2 q" |0 @" A* [( r    // called <foo>". You can send a message To a particular
1 |2 x4 f! V: `    // object, or ForEach object in a collection.
: y3 @1 r6 v* r1 y, y        
7 Z% V+ L1 o- ^0 }5 X    // Note we update the heatspace in two phases: first run
% `1 G. x, J% g! o+ X7 ~    // diffusion, then run "updateWorld" to actually enact the
0 Z3 J8 t0 ]! c/ {) b7 R2 o( J0 z    // changes the heatbugs have made. The ordering here is
0 l. z) ~- y2 p, l* {    // significant!" G& _# A+ c4 W8 @* ]) ^: W
        2 h+ B' k1 _. y( D2 A& n3 V
    // Note also, that with the additional
5 H/ z5 \  |& `; j" m4 a; P    // `randomizeHeatbugUpdateOrder' Boolean flag we can
, B  y- ^, @' x" Y/ D" b    // randomize the order in which the bugs actually run
9 j8 U3 @, p5 I+ r% _    // their step rule.  This has the effect of removing any
9 E7 k) c5 E+ o+ \) W+ Q    // systematic bias in the iteration throught the heatbug1 k% _# M2 L* B
    // list from timestep to timestep, h4 |$ N! u4 l
        8 K/ |* H; n7 Z; w, q& n' \$ h( Q8 R
    // By default, all `createActionForEach' modelActions have1 L; W( K2 @4 c1 g# _) \1 |3 G
    // a default order of `Sequential', which means that the
  _  V/ R4 F# n7 j    // order of iteration through the `heatbugList' will be2 g* `; x; S8 y# G5 |* K' P! `, {
    // identical (assuming the list order is not changed
( {# ^: R) I" l    // indirectly by some other process).
" [" {7 I" U  j( w* j0 r6 O  P    1 K5 I# W# f0 O4 [: [
    modelActions = new ActionGroupImpl (getZone ());
' x/ q& m0 L+ V. D  f. c! w% h5 d3 z2 J$ S* }3 i4 n0 S6 `" u
    try {% A$ d+ G" m7 W$ Y* h
      modelActions.createActionTo$message  |. s1 C% G# [8 s9 Z8 r
        (heat, new Selector (heat.getClass (), "stepRule", false));
3 V$ ?4 E* s, u6 y4 p. e2 ?    } catch (Exception e) {
( k3 _1 i' k, N. e      System.err.println ("Exception stepRule: " + e.getMessage ());! @3 D# ^5 y' y
    }
8 [) p  S1 {$ [( d" E( Y7 c( M- E4 ~
" {' a1 p8 e/ z4 g+ E    try {
. ]6 x1 A5 v% L. R      Heatbug proto = (Heatbug) heatbugList.get (0);" I4 Y$ A& c! T. b/ o% s- n
      Selector sel = . @1 k  N" P" ]3 b; }, D
        new Selector (proto.getClass (), "heatbugStep", false);0 A/ I) y& S" M7 w/ p
      actionForEach =
9 R7 f. s- {  k' Q+ o8 Q5 L/ d0 e        modelActions.createFActionForEachHomogeneous$call- Y0 |2 e& t( h6 N
        (heatbugList,7 a9 t' b7 g5 ^' {& z% x: M/ @5 E$ y
         new FCallImpl (this, proto, sel,
' q! M$ M6 W3 s9 T                        new FArgumentsImpl (this, sel)));
4 }) n! O- i% c. Q; {    } catch (Exception e) {; n' |% J# ~' c% X3 K! E
      e.printStackTrace (System.err);
% M& e( ~- P& g4 q2 F) H! R    }
6 [0 V: Y  X9 e   
! M+ t$ E5 S+ k" m3 V. E/ q    syncUpdateOrder ();. l6 {* f5 B2 d- ^! M% A
* S0 U( H  D& w4 x4 p* q
    try {
# C+ L+ u, ^, |! f4 j% }1 I      modelActions.createActionTo$message
8 I: C0 g* P. O) |7 R' B        (heat, new Selector (heat.getClass (), "updateLattice", false));
6 Y9 t( a% b+ d8 y    } catch (Exception e) {
: b- I, B, Y9 o: u      System.err.println("Exception updateLattice: " + e.getMessage ());
( W8 ?+ j4 D  |- j5 L+ ]( R    }! d, n' U8 p2 ?' }$ N
        2 b6 h+ ~- F8 ^5 _
    // Then we create a schedule that executes the
% ?) z% w( @/ o9 e% I    // modelActions. modelActions is an ActionGroup, by itself it
5 V; R# i, o6 ?    // has no notion of time. In order to have it executed in
- `" I; b5 Q2 V, \" m    // time, we create a Schedule that says to use the
3 w6 ]+ `' u: U+ S4 Q    // modelActions ActionGroup at particular times.  This
9 v: I! O" c0 @' G* `    // schedule has a repeat interval of 1, it will loop every
& H6 ~: P; L. z; V6 y8 m2 w    // time step.  The action is executed at time 0 relative to  w2 C( \8 q' ]+ a6 a' Z( k
    // the beginning of the loop.
" T5 o: F  v0 f2 f+ w8 E6 {; E0 \3 a+ t0 `2 C& {0 b$ i, n* X4 Z
    // This is a simple schedule, with only one action that is
7 q  p# ]9 U: p; o5 o    // just repeated every time. See jmousetrap for more8 F, K8 G" R  O0 ]2 G
    // complicated schedules.
2 d4 Q) B8 @0 P9 Y  
; u/ h1 m7 H; Q- N  \    modelSchedule = new ScheduleImpl (getZone (), 1);
0 [  z9 J4 {( `, l% V0 |- f    modelSchedule.at$createAction (0, modelActions);
- x4 g& P& r2 V, F& B+ X        $ m2 J0 B5 Z/ n. z4 S
    return this;5 J+ C1 h. r, J2 c. B
  }
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