设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 12228|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
  n2 n2 r; T5 l7 X! T# w9 \' @2 w
public Object buildActions () {
$ C  {/ Z# }3 j7 c    super.buildActions();
  J/ \( t. N  F( E' G$ {6 x   
- I) a- a$ M( N5 O  D; X    // Create the list of simulation actions. We put these in- x: z# j' ^( g/ i: T6 i1 s
    // an action group, because we want these actions to be
0 Q& ~/ T% c/ w9 [7 E' l. ]5 \. v    // executed in a specific order, but these steps should, ?: o/ b3 z- p
    // take no (simulated) time. The M(foo) means "The message$ \3 ~9 ?' w: f/ P
    // called <foo>". You can send a message To a particular
! Z+ B7 k+ o% ~) p  C! e2 V    // object, or ForEach object in a collection.4 X7 W  u( X# ~
        ! [5 z8 Y4 X1 w" ?
    // Note we update the heatspace in two phases: first run
3 {! k4 j8 }; R* M4 b. {% z% b5 r    // diffusion, then run "updateWorld" to actually enact the
5 w5 \( }* e% @    // changes the heatbugs have made. The ordering here is1 y6 b- }# m  e+ |( V8 H" Q
    // significant!
6 m4 t* E3 }0 d" w  @3 w# y* H+ u        , r$ u6 G7 D- u! E
    // Note also, that with the additional/ O7 f: M1 S5 _9 n4 G
    // `randomizeHeatbugUpdateOrder' Boolean flag we can& J3 \# K7 b- S$ m% u4 E& ^
    // randomize the order in which the bugs actually run
& q7 w/ W6 @9 s& \8 L! z. P$ R    // their step rule.  This has the effect of removing any& [2 z8 J, ?! P+ n
    // systematic bias in the iteration throught the heatbug0 }. O# o' b  K5 x2 Y
    // list from timestep to timestep
& V; i/ L! c! m4 [        
- T0 C# Z2 h! w$ E! t. X8 I+ S0 I6 j1 i    // By default, all `createActionForEach' modelActions have
- T) p6 H0 n6 k% m1 `; _- D0 Y    // a default order of `Sequential', which means that the- r) N8 p: d$ F5 \, X# u% P
    // order of iteration through the `heatbugList' will be
* R/ w9 w0 R: {; e8 ]3 @, ~    // identical (assuming the list order is not changed
: s2 x6 {9 v+ p9 F* \    // indirectly by some other process).
/ L* c8 Z- R$ B7 _: d    - Q* w" z& J) I6 \! G' l6 |
    modelActions = new ActionGroupImpl (getZone ());
( ?2 v: C; a5 V# S. t3 l% s( j! ?8 i, f6 v# b
    try {5 s/ P* I* x8 _9 i- k
      modelActions.createActionTo$message, h  k0 n* T9 v5 G3 n' y4 V" e) ^
        (heat, new Selector (heat.getClass (), "stepRule", false));
  e$ O6 |( w) b    } catch (Exception e) {% z6 X: u8 X2 e, Q
      System.err.println ("Exception stepRule: " + e.getMessage ());
( U  v+ f$ e9 C8 X3 q    }
; T  B1 a4 p$ v0 A' }' x' ?% N: U' N# ]4 W
    try {" [: L, }2 L& _+ w% _$ p
      Heatbug proto = (Heatbug) heatbugList.get (0);
/ T5 V$ I- I" m9 H' L6 L( s      Selector sel = & [" ^, J4 q$ O6 H7 A
        new Selector (proto.getClass (), "heatbugStep", false);/ w+ m+ C6 l/ f- i
      actionForEach =
* D# k3 `5 R+ \# z        modelActions.createFActionForEachHomogeneous$call& z$ Z7 ?" G: r/ k3 c$ s* h3 T
        (heatbugList,
: j: ^; K3 D7 N3 F: v7 w/ K         new FCallImpl (this, proto, sel,
6 `+ S+ c% q8 D' @% d                        new FArgumentsImpl (this, sel)));
: {, _3 V; s' ]& ^    } catch (Exception e) {
  i- p) E% x9 p7 v. `2 |& j. k, D' J3 b* W      e.printStackTrace (System.err);9 q" b  r" d" ^# F; {/ \4 @
    }# Z4 @; f9 j. z3 h" e
    % E* K" v: l* M' V; |
    syncUpdateOrder ();
! d( j& E' M6 _. u: ^& v( I) Q
* a8 n# Q' o7 _  U4 z3 s    try {
1 F+ s+ I! o" ]* F0 w0 s      modelActions.createActionTo$message
6 `. U" F" e( G& H/ b5 j        (heat, new Selector (heat.getClass (), "updateLattice", false));
* E. ~* h* q' j0 I- x% u, y" |& |    } catch (Exception e) {
' g' I' w  ?. V) E, a% o      System.err.println("Exception updateLattice: " + e.getMessage ());7 j, u: ]* }3 l. x5 z3 E% R8 I
    }9 j2 o* L2 @9 m8 R% }' Z
        
+ }) q0 T- L) \    // Then we create a schedule that executes the: ]! U: G/ }$ a' q) t/ Y
    // modelActions. modelActions is an ActionGroup, by itself it, R5 ?/ x2 ]/ e+ O
    // has no notion of time. In order to have it executed in8 _% E% \7 R5 Z  K+ u
    // time, we create a Schedule that says to use the
3 M1 k1 F1 H  |( L    // modelActions ActionGroup at particular times.  This
  F' H% @+ ~& ~& t2 j3 w    // schedule has a repeat interval of 1, it will loop every1 h! r7 U, P7 b" M5 {% y( C
    // time step.  The action is executed at time 0 relative to
0 y5 p$ o7 j! |. ~$ W; |    // the beginning of the loop.$ _4 Y/ ]  e: k+ N$ r+ ^  ^
6 @: _. H) f+ L3 l4 _
    // This is a simple schedule, with only one action that is0 B. C" ^. A* \: _
    // just repeated every time. See jmousetrap for more5 x7 Y8 G$ D3 R: c, D
    // complicated schedules.- G" V+ }8 z1 M3 Z7 N
  
4 A5 W. I5 z1 W1 |* c0 q    modelSchedule = new ScheduleImpl (getZone (), 1);
" m- l" J$ ^' O, I    modelSchedule.at$createAction (0, modelActions);: R) I  g* C+ y& G% g6 Z
        
+ L( x9 @- M% @" R8 ?* y6 U    return this;9 u8 j: }. }. E  r- Q8 \+ @
  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-8-15 14:18 , Processed in 0.018345 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表