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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
* Q6 b7 P# k! S* H' Z' _2 h/ T- \0 e( ~0 t9 T- I
public Object buildActions () {
8 ?. b2 l0 j1 Z: E% K  o    super.buildActions();" u( F8 Q6 S; x2 s& U* m" c5 }$ L9 V
    , f1 V6 c5 k# K9 ?1 Y+ x
    // Create the list of simulation actions. We put these in
8 I# F/ T) `- T% _    // an action group, because we want these actions to be
& V2 K) ]5 }5 u% e2 O$ D    // executed in a specific order, but these steps should8 |( h. f. |3 H1 r1 P( H+ H0 ?
    // take no (simulated) time. The M(foo) means "The message
5 u; p* k1 [* H    // called <foo>". You can send a message To a particular
! z% ^+ t, t  f) z5 C    // object, or ForEach object in a collection.
  k/ Z, d8 w# M' y* T        
, {0 F) K, h) ~' v2 M% O, {  g) W    // Note we update the heatspace in two phases: first run) o- a0 d! C$ `# w$ ~/ [
    // diffusion, then run "updateWorld" to actually enact the
" @: h" n) E9 J' t' J8 k    // changes the heatbugs have made. The ordering here is( Z: C; u# r: G! g4 O- I
    // significant!9 j/ B! f1 U6 k# B  T. {5 t8 {
        
* y' s9 a4 A. Z$ t- F) X& r, x    // Note also, that with the additional
; F, e/ ], T& P    // `randomizeHeatbugUpdateOrder' Boolean flag we can: x  H; I2 Q3 t6 D3 F
    // randomize the order in which the bugs actually run
# t4 m: n, O: p6 n7 T9 N    // their step rule.  This has the effect of removing any! x1 l3 {+ C8 g" Q- ^
    // systematic bias in the iteration throught the heatbug( X7 I, s8 o( B7 H( w
    // list from timestep to timestep
8 [* o- i8 u  _        ' Y. q$ r& l' v/ H/ l& Y
    // By default, all `createActionForEach' modelActions have7 A6 w5 R' C& q7 R
    // a default order of `Sequential', which means that the3 ^9 C% k7 H3 z% W1 N
    // order of iteration through the `heatbugList' will be
' I5 z8 S% A' i: D8 `: A/ r    // identical (assuming the list order is not changed" }* u  B" f( g3 I
    // indirectly by some other process).
* i- I9 q/ v4 i% [5 I   
0 j% @& M$ Q* Q. x% h    modelActions = new ActionGroupImpl (getZone ());
! F5 v* p5 w/ u) }) V8 L( s) e" U8 d) s/ f
    try {0 }! H9 k5 }; T
      modelActions.createActionTo$message
8 E* \" P+ \" K6 ~0 F        (heat, new Selector (heat.getClass (), "stepRule", false));
" q- A, d8 i( ~7 b2 z    } catch (Exception e) {
9 f8 Z# o" k* ~# M3 ?. O6 d9 E      System.err.println ("Exception stepRule: " + e.getMessage ());) |$ k- {% q" q: h
    }7 d+ F/ B' P  t3 e

8 n2 o3 N* @. P+ r5 f: v6 |+ B    try {3 z, j% l3 f8 V9 f. M" k
      Heatbug proto = (Heatbug) heatbugList.get (0);
" i/ E0 i6 @' ~. g5 m      Selector sel =
, ]6 {0 d" a9 U( r# \8 `        new Selector (proto.getClass (), "heatbugStep", false);7 X* e6 o" w+ o% C( t. q0 g' p
      actionForEach =
3 l% A$ p9 V, G; H        modelActions.createFActionForEachHomogeneous$call7 n/ c9 h: E1 X7 O" t
        (heatbugList,
/ S. @' O) K1 n; m5 k% z         new FCallImpl (this, proto, sel,7 g. V2 {, M4 T- [, [0 i% x/ A/ Q/ A
                        new FArgumentsImpl (this, sel)));
# S5 r- N, B$ M3 v% b6 o" r    } catch (Exception e) {5 ]8 ]: h3 w9 \4 J: {# O9 Z
      e.printStackTrace (System.err);6 B) ^  w. t* E- T+ ]- @$ y1 \9 z
    }
# b2 \) r% c% I    * Q8 z4 e8 U- {+ \/ K$ z
    syncUpdateOrder ();
1 j4 v( }4 y( @- m; N5 S3 R) ?3 W3 L8 ^% i2 ~  q
    try {
6 ?& \* }0 G8 U" M: x+ Q      modelActions.createActionTo$message
8 u& q8 e4 q' o$ Y        (heat, new Selector (heat.getClass (), "updateLattice", false));
# O5 H; x3 V9 j( t) ^6 O    } catch (Exception e) {1 D* P( L5 x2 `& j
      System.err.println("Exception updateLattice: " + e.getMessage ());
, g* E$ k; w; {. i    }
1 j5 }2 b& \  O1 c1 K0 y        + t2 `1 F5 ^- D+ B5 i
    // Then we create a schedule that executes the& h5 l2 W, t; |! s* z$ |$ r
    // modelActions. modelActions is an ActionGroup, by itself it
7 Q7 P6 f4 ~- g  v# B0 F    // has no notion of time. In order to have it executed in
4 A  Z/ p: ?. j& ?$ `1 i3 x. w    // time, we create a Schedule that says to use the
4 l4 u" P1 H4 m7 U7 D* U    // modelActions ActionGroup at particular times.  This
# Y7 j! }" ?, t9 D    // schedule has a repeat interval of 1, it will loop every8 o1 b$ D) ]1 m7 h/ T0 q/ a
    // time step.  The action is executed at time 0 relative to  m) p3 a7 w3 T2 U, |  X3 W
    // the beginning of the loop.% @; e+ Q9 G+ f4 U  q9 r

6 @3 ~2 R6 H3 W; n* H. n' E/ @$ t4 _+ R" G    // This is a simple schedule, with only one action that is7 n2 z$ Y- h# A/ k1 o6 {) Q; a! D
    // just repeated every time. See jmousetrap for more7 c, x( @3 X) w2 U
    // complicated schedules.
  c& F& |, }% }, \1 ]9 X  ; |* u) ?1 l7 E' r1 z
    modelSchedule = new ScheduleImpl (getZone (), 1);
( k2 {3 {4 M( ^1 V4 p) P. [    modelSchedule.at$createAction (0, modelActions);4 y9 \. k& d6 l6 A$ |
        
7 J$ `3 i8 J$ V    return this;+ {8 d1 I$ l' `8 c7 K1 b4 p
  }
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