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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
: k1 H$ B8 T6 J$ a+ F* j; N
% p) c# }4 l/ E public Object buildActions () {
# t% @; ?8 ?6 v- Z+ T6 R, _    super.buildActions();0 i/ W# [$ s+ j2 z: E% e
    , z/ W: F2 @2 U  x2 I
    // Create the list of simulation actions. We put these in7 e* i( q1 X# G. a& m  n
    // an action group, because we want these actions to be  r- ~; B; F2 r( E+ u1 E
    // executed in a specific order, but these steps should$ `* H% C: z; O. s9 t% y# \* q
    // take no (simulated) time. The M(foo) means "The message
+ r* }6 \- v% Q$ @* j, C( [* l( ~    // called <foo>". You can send a message To a particular1 [9 K+ r' v- B8 X) u
    // object, or ForEach object in a collection.. V. t+ l# O  i' O9 G9 g6 v, Q
        7 l* `8 {: m. K$ G% r- c
    // Note we update the heatspace in two phases: first run# \: h: Q# l, r6 v+ U' Q0 a) Z% r* Y
    // diffusion, then run "updateWorld" to actually enact the4 Y6 l8 f& P7 B) h  m
    // changes the heatbugs have made. The ordering here is1 z1 k( D' h3 ^6 F
    // significant!$ }2 ?) `: H6 J9 ]
        6 q2 n9 R$ G5 a  _5 l- b
    // Note also, that with the additional
- R! \! S; {; _3 m/ b: y    // `randomizeHeatbugUpdateOrder' Boolean flag we can
( `* Z/ j6 W8 P; `# t    // randomize the order in which the bugs actually run- C) ~) Q1 F  [' X, k
    // their step rule.  This has the effect of removing any" G5 ?2 M3 y* P8 W
    // systematic bias in the iteration throught the heatbug! p% t; w, t2 L
    // list from timestep to timestep
! G+ y2 k- m( ?4 v/ f/ n: q/ a        5 W+ `3 `* W; Q7 m/ g6 {
    // By default, all `createActionForEach' modelActions have4 _# }& |) t; V1 x6 ]: k1 `7 a
    // a default order of `Sequential', which means that the) D& B3 ^; B+ |1 U/ y& P, k
    // order of iteration through the `heatbugList' will be
  d3 X8 W1 O% B" u    // identical (assuming the list order is not changed: G- Y& I% |, P, j, }* b- P
    // indirectly by some other process).
( H9 d  |  r! l   
+ C3 ]. w$ f  H2 s) Z    modelActions = new ActionGroupImpl (getZone ());+ I7 b: o: l( d0 I/ q1 n5 w/ a

! x& _0 t3 P3 |9 L6 j- ?    try {
5 [5 x1 b. d4 t: i" K3 J7 b5 h  r      modelActions.createActionTo$message& m0 L) @0 I9 B1 K  s; K1 P  t, x
        (heat, new Selector (heat.getClass (), "stepRule", false));
7 b' _: S. Y" ^( b5 L5 F6 |    } catch (Exception e) {
: v" b* h, l& }. `) C      System.err.println ("Exception stepRule: " + e.getMessage ());
1 m5 a" c; V7 e4 \. e' b0 ^: T, ?    }
% L2 C# j, C" R. V+ @/ m- f7 I  A% h2 @
    try {
' _; [8 q" D; ~      Heatbug proto = (Heatbug) heatbugList.get (0);
- _: Y$ ~% f3 G% x$ O      Selector sel =
3 N. }7 @& J0 }: ?0 _        new Selector (proto.getClass (), "heatbugStep", false);
( E) L/ J* W) g: s9 S) b      actionForEach =- ~3 g! `7 O9 }# G/ G2 F% `2 s: ?! Y
        modelActions.createFActionForEachHomogeneous$call9 z8 @, U9 U1 ?& @) M2 }
        (heatbugList,& P) d5 v( T3 K2 ~' f: I0 x. q
         new FCallImpl (this, proto, sel,
* W, J' G; o6 _( E                        new FArgumentsImpl (this, sel)));+ S5 F2 X' G9 l. S' n$ n
    } catch (Exception e) {
6 s7 \# e$ i8 T% E. M      e.printStackTrace (System.err);
6 r. [* R) Z( M# z    }3 D) R6 M$ w/ V3 L3 R7 z5 i
    + @+ K& ~* |) o% F. A
    syncUpdateOrder ();& l3 @8 T9 R4 D# y) @9 U! p

# T) B1 @/ m6 s    try {, e' J0 K" e0 Y) J  m6 P5 ]
      modelActions.createActionTo$message
2 N& h+ d0 V$ W        (heat, new Selector (heat.getClass (), "updateLattice", false));
* `1 u/ i4 t; `' r0 T& K3 m    } catch (Exception e) {
+ T' ^4 W  {! |$ V& E1 v+ }* c      System.err.println("Exception updateLattice: " + e.getMessage ());2 u6 {: R; L4 `. m: X8 J
    }* M2 ]+ u/ z. ]/ g- U& r. ~0 l
        $ D4 [0 U5 @. X; G' A4 m
    // Then we create a schedule that executes the6 Q6 O4 H- f$ r- ]' y/ [  T
    // modelActions. modelActions is an ActionGroup, by itself it
& ]9 A' b& s9 n    // has no notion of time. In order to have it executed in' j! @" J: |8 O8 z- L  K
    // time, we create a Schedule that says to use the
5 s0 g% J3 I* u4 d: i" n    // modelActions ActionGroup at particular times.  This0 y; E, }' D) v4 |( j6 F$ F
    // schedule has a repeat interval of 1, it will loop every9 [8 e5 X5 t$ }3 m$ D
    // time step.  The action is executed at time 0 relative to+ N% \, F9 ?) D
    // the beginning of the loop.4 O: w7 s1 ]8 m& o2 N3 H& z

  W& R7 n% t3 H; s$ N& H! {    // This is a simple schedule, with only one action that is* t0 K% v: p8 G. c
    // just repeated every time. See jmousetrap for more! A; q- j$ v% @5 O# P  t
    // complicated schedules.% a0 B: P+ o& A' T3 ^! C1 Z& F3 q
  6 W, l: I; r& e( }
    modelSchedule = new ScheduleImpl (getZone (), 1);' @2 G5 f4 @, y8 E* k, i
    modelSchedule.at$createAction (0, modelActions);
- w* h" X6 d: h        
2 n& ^7 z4 a4 G) e6 I4 ?) |  N. ?. F    return this;
# ^0 [3 L  @! e) H9 Q  }
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