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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
& B: T  l' \. M) G, b0 w, b0 Y& H* d8 i" S) @
public Object buildActions () {1 d  D( h% U3 N9 L
    super.buildActions();' w2 P9 k1 N% y( N
    & F. Y2 ~( ~$ K% a2 q- ?) @
    // Create the list of simulation actions. We put these in
0 v5 Z( F  @1 \$ {6 w2 b( J    // an action group, because we want these actions to be+ e# a% Z/ I) Q/ Z- d* _
    // executed in a specific order, but these steps should
* k  j  f) k# S    // take no (simulated) time. The M(foo) means "The message
0 r# P5 s& U, y9 E9 \4 A2 i    // called <foo>". You can send a message To a particular6 V( p# C  L" k. y
    // object, or ForEach object in a collection.4 S: k9 |7 Q1 o% x" F2 T% @) P
        
' J6 |$ {7 Z. i. _# t0 U6 I    // Note we update the heatspace in two phases: first run
$ n% X0 N/ D; \0 g+ d3 ~    // diffusion, then run "updateWorld" to actually enact the
. s1 @$ q! w7 Y  H    // changes the heatbugs have made. The ordering here is
; `. N5 i0 O6 ?+ R. I1 ~; n    // significant!
/ L$ f# W: `! z# i        : ^6 q2 G% y/ M& S( I5 l
    // Note also, that with the additional- ?5 \% p2 v0 j' U
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
4 r& _: {6 v0 ~7 A7 ?/ }    // randomize the order in which the bugs actually run' t9 T$ y# G% q; k% c. e$ _
    // their step rule.  This has the effect of removing any, u- A" ?: T" E8 ^, {/ t0 i
    // systematic bias in the iteration throught the heatbug
4 h# k0 A3 I. X& ^    // list from timestep to timestep: E7 |; _2 n6 A& U( G
        & Y* q5 t) d6 t8 I
    // By default, all `createActionForEach' modelActions have* e+ d: W: u; f. s: u
    // a default order of `Sequential', which means that the& W# Z  P, U# d; Q2 K
    // order of iteration through the `heatbugList' will be# v- h* s  ~$ c$ c
    // identical (assuming the list order is not changed$ c6 F5 W4 s& {9 `; u
    // indirectly by some other process).
: w; Y7 c$ q: l    4 Z: d! L/ D! G. \$ @' ^
    modelActions = new ActionGroupImpl (getZone ());
1 j, [- X4 X! b' A( ?! Z" l3 i6 o% J4 |
    try {
) Z' p" m9 O+ y      modelActions.createActionTo$message
7 O1 l5 Y7 E5 d& S+ @! Z1 z" C        (heat, new Selector (heat.getClass (), "stepRule", false));
! ^1 S7 R8 z" v0 S# W/ e    } catch (Exception e) {4 [: @) [  W9 _8 i$ [) P
      System.err.println ("Exception stepRule: " + e.getMessage ());; B$ x) f" J. X4 d
    }* Y/ D; D( p  K
6 r( h' K, c3 {5 [
    try {" B$ e+ E8 J4 W1 o* O
      Heatbug proto = (Heatbug) heatbugList.get (0);3 `8 M9 f2 ?, y0 S  W  ^
      Selector sel =
: s" A* ~0 K1 o6 t8 F        new Selector (proto.getClass (), "heatbugStep", false);* J: C3 r6 |+ y% B
      actionForEach =
, b- E9 V$ [  @! q5 v( E2 {" [        modelActions.createFActionForEachHomogeneous$call; M3 ^6 n8 L; m5 W# v0 G
        (heatbugList,  ], t$ A  c) Q! r  V( C
         new FCallImpl (this, proto, sel,
3 `! v, y# N- c1 }, J8 t. e                        new FArgumentsImpl (this, sel)));) Z' e- t, a/ k/ e  @
    } catch (Exception e) {
4 q. N2 N& \4 K  T, N$ f% h0 z4 |      e.printStackTrace (System.err);  D+ H, r8 D: }; M0 n+ o$ G
    }
" ~8 c" o; ~7 X! i   
' k5 k; W' ~: U8 a    syncUpdateOrder ();3 d( u3 Q+ x3 N

' r: B. F; B0 P7 q. Z+ q    try {& C0 Q$ v" S& E4 e: [4 q
      modelActions.createActionTo$message
/ O) t9 f. b( w$ ?8 b6 o        (heat, new Selector (heat.getClass (), "updateLattice", false));
, i1 W7 x+ W% A2 \3 X& Q! N    } catch (Exception e) {/ Y8 C  J! U4 k' f+ g
      System.err.println("Exception updateLattice: " + e.getMessage ());; s. G. h" z7 `1 ^( _5 Y) P
    }
- S+ B: u0 l+ g: ~$ N: a        5 p5 c3 R4 |2 h- D7 S8 B5 p
    // Then we create a schedule that executes the( E( R+ R) I6 G  m5 p: k: Z
    // modelActions. modelActions is an ActionGroup, by itself it
3 k" t0 ~+ c9 h    // has no notion of time. In order to have it executed in
  f/ Y+ n, P6 R8 j    // time, we create a Schedule that says to use the
- {: L8 u1 D" F    // modelActions ActionGroup at particular times.  This
8 V& G9 ?4 P. w    // schedule has a repeat interval of 1, it will loop every
+ @" H6 U, ]# y- P2 z8 g    // time step.  The action is executed at time 0 relative to
, M8 w( U& A/ F/ N6 Q9 F    // the beginning of the loop.$ h3 \3 S) Z& Y
9 b8 f$ }, Y  z3 _3 q$ B
    // This is a simple schedule, with only one action that is( K/ _) t+ |6 F/ p: G  k' D
    // just repeated every time. See jmousetrap for more
( ?9 Q! z; [, q6 q4 k" q+ j. o    // complicated schedules.  J2 m) g+ ^5 X
    \, j5 a5 }: q& D) _! G& y
    modelSchedule = new ScheduleImpl (getZone (), 1);2 p5 X; w# C% {) l) p
    modelSchedule.at$createAction (0, modelActions);
+ w; c, G8 P3 c: n! ?3 x$ \3 X8 e7 E        - ?! W* z5 z' j3 \! S
    return this;
8 a- t% h- F- l  }
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