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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:/ X( ^: }& \% V$ V- q7 C4 P

5 \9 m& J4 s! v2 x1 { public Object buildActions () {
9 D  ]# a9 N' c* Y* O" M0 p    super.buildActions();
: L  b9 J7 o7 k$ u! e4 d    , R, c' w  L1 A& r2 p
    // Create the list of simulation actions. We put these in
/ x* Q! Z) p* D  t& d    // an action group, because we want these actions to be
& z" ]( j4 c: _  \) H4 d) k- g0 Y9 t    // executed in a specific order, but these steps should
# m* _" O  P5 {, _    // take no (simulated) time. The M(foo) means "The message% Y. T+ [$ v1 m9 A: L! b7 o5 F
    // called <foo>". You can send a message To a particular5 ^& f0 F' ~/ T) A0 E& Q2 u
    // object, or ForEach object in a collection.
! Q6 c+ O' C# F0 i8 j        , Z2 e# d* ]. `& R, d
    // Note we update the heatspace in two phases: first run, z+ v- U) C- ~$ }
    // diffusion, then run "updateWorld" to actually enact the
2 ?# e2 v. w! j. ?# M8 z    // changes the heatbugs have made. The ordering here is
: D8 s  Y3 R7 p+ J8 O3 ]    // significant!# \/ R' ^) W& o- N
        2 T+ m6 k+ ~! i, H
    // Note also, that with the additional2 m% o* q8 i0 x
    // `randomizeHeatbugUpdateOrder' Boolean flag we can- N9 e8 c; ^) v, t% ~7 w5 q, T
    // randomize the order in which the bugs actually run8 v+ e! i8 w/ L9 k8 V0 m
    // their step rule.  This has the effect of removing any- M# L+ k$ v: w, ~
    // systematic bias in the iteration throught the heatbug! b- p0 c/ u; ^9 M0 z% {/ y
    // list from timestep to timestep( J/ Q" \; c1 @; h& p
        
9 w+ c5 z! v$ B  H, U3 E    // By default, all `createActionForEach' modelActions have
" r$ E9 a" W; ~- A+ n    // a default order of `Sequential', which means that the. H4 x8 x7 m' `! }( K  s$ T
    // order of iteration through the `heatbugList' will be
' i/ }4 {  p! ^" e7 O& R* N9 w    // identical (assuming the list order is not changed5 p' j' N/ p- G) p
    // indirectly by some other process).
0 H1 U+ i# B" @. ~3 Z/ K( l    ! i9 r8 s9 P) H, p( o
    modelActions = new ActionGroupImpl (getZone ());! O2 ?+ s" Q! R5 p; u* B
' H: B6 e% S$ g& [
    try {# D  x" p& R8 ?) V: T5 `
      modelActions.createActionTo$message
+ c+ M8 l; _. W. [7 @        (heat, new Selector (heat.getClass (), "stepRule", false));( u) b4 Q+ U: s! P
    } catch (Exception e) {
3 z0 J# I5 ~! i; [: T      System.err.println ("Exception stepRule: " + e.getMessage ());/ Q% j( Z" `4 l8 g4 H
    }$ r" n" I/ n. E+ t/ o
$ t& u* [( G* s5 i. @
    try {
% N0 V" l2 U, v% t. ]$ \7 {  T2 u7 Y      Heatbug proto = (Heatbug) heatbugList.get (0);, w+ Y$ _" Z6 O# X6 b( O
      Selector sel = 8 @7 `: Q; s( d2 F. q% V
        new Selector (proto.getClass (), "heatbugStep", false);
, k. h6 Z& h7 c8 V( _      actionForEach =) g( h7 N' _" s! l/ W" G& X5 t2 w
        modelActions.createFActionForEachHomogeneous$call* e: l0 x, `+ k% A. \0 s
        (heatbugList,2 h6 n  h7 ?7 q7 @' q; y9 q
         new FCallImpl (this, proto, sel,/ [( e; d5 f+ F# g) C( k) {4 ^  v
                        new FArgumentsImpl (this, sel)));. R. H0 f& n/ q
    } catch (Exception e) {3 G$ Q. a. g/ L0 ]
      e.printStackTrace (System.err);
2 D9 s' T' W: ?8 x    }3 Z) Q+ L4 \( K) |4 o- n% k
    9 V2 S; S! y( x! `6 [
    syncUpdateOrder ();/ L7 E0 D$ C8 Z

# C' g1 ^4 V  ?6 ]2 {    try {
! L% u* h4 r; F# t8 S2 `      modelActions.createActionTo$message
* J8 }" a$ N9 c/ f3 q) A/ K        (heat, new Selector (heat.getClass (), "updateLattice", false));
) \- P. }( @% L4 I+ B9 u6 Q    } catch (Exception e) {
9 b# `- ~5 W$ R+ U      System.err.println("Exception updateLattice: " + e.getMessage ());
7 p% j6 H- X( W% h3 ~! A. [! M    }1 s* C. P- N0 H  ]# a3 q# D( X, x
        . r5 i8 i/ k0 Z  j$ w- n* X! \9 v
    // Then we create a schedule that executes the
, G2 \" Y8 x/ g/ O1 E5 D    // modelActions. modelActions is an ActionGroup, by itself it
- a& b4 a9 g- x, c. @5 \7 B1 o    // has no notion of time. In order to have it executed in6 n" x9 a, u3 [1 y6 H
    // time, we create a Schedule that says to use the
- v8 Y  s- ^" X8 c    // modelActions ActionGroup at particular times.  This
% @8 i1 i9 a7 `7 x3 }  e- o    // schedule has a repeat interval of 1, it will loop every
6 ^7 h2 w9 z/ b- E& [    // time step.  The action is executed at time 0 relative to  }. D; f, D2 O9 y
    // the beginning of the loop.
6 g' G0 J5 h) c+ E
* u0 v- c# y9 A0 j/ L    // This is a simple schedule, with only one action that is
, _+ }  Z: b5 B: _    // just repeated every time. See jmousetrap for more: r& Z. S. N5 u( s; U# }
    // complicated schedules.% M6 d7 A) f" c7 v) ^* C
  7 V7 W0 n& m5 d3 _) b7 }8 d  b
    modelSchedule = new ScheduleImpl (getZone (), 1);
3 `# E# V1 q1 H# y. A    modelSchedule.at$createAction (0, modelActions);
) H9 m% q; ~9 g7 C: O8 X        - y4 V6 {+ X+ o2 M) }
    return this;
, n8 e( e1 p: H9 Z7 Y  }
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