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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:: |; Y8 [4 U' T4 _

- w/ a* g1 S  Q+ R) A public Object buildActions () {
" K7 T( U0 H4 c. K8 ~. w    super.buildActions();
+ P) v/ |/ X" D/ t  K    2 m% i: c- ^3 b& f
    // Create the list of simulation actions. We put these in; \! f* S- O7 u& t. B/ ^, T
    // an action group, because we want these actions to be
' v. G$ {$ h) h! K" ^  {    // executed in a specific order, but these steps should
, Q7 I) Y4 a- w6 S' E    // take no (simulated) time. The M(foo) means "The message; {, V" f6 l2 @& k
    // called <foo>". You can send a message To a particular/ I# @8 p* z6 \
    // object, or ForEach object in a collection.
# b2 P4 u) m. m: }( U: L        4 h2 q* x6 p+ r' i
    // Note we update the heatspace in two phases: first run1 m+ S: E; _; x
    // diffusion, then run "updateWorld" to actually enact the
4 C  Q; s8 J0 ?. W" \5 X% ~. }    // changes the heatbugs have made. The ordering here is
. `! y6 X; |% M) O    // significant!3 |9 C' e3 g  I% U1 T+ X& A% o
        
) o6 m( r  v" r+ b5 {& K) q0 d  k" J7 E    // Note also, that with the additional1 c" e! @+ x9 }* f" b3 e
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
& d  G; x3 p  a. T    // randomize the order in which the bugs actually run. D& \+ W+ R8 I. x
    // their step rule.  This has the effect of removing any& c0 {6 O; ^' L( s& K% _" R
    // systematic bias in the iteration throught the heatbug5 i1 P$ \' ^$ U* [7 @' w
    // list from timestep to timestep7 R7 b) a5 |2 @2 R+ O6 f
        , @" G6 D; d% |0 T. N! k, |4 t
    // By default, all `createActionForEach' modelActions have9 \( ^$ \0 b6 B% }" G
    // a default order of `Sequential', which means that the: @0 G, N" w  @$ P+ O8 Y; u
    // order of iteration through the `heatbugList' will be
5 G9 K* V. h1 a+ g7 P. s' y, \    // identical (assuming the list order is not changed
! z/ w' X! `: R% X    // indirectly by some other process).
( k. [0 w2 X% ~1 h9 V2 q% O  ^    3 i# n& ?9 g8 i  Q6 s* T& v9 V
    modelActions = new ActionGroupImpl (getZone ());
' m2 d3 T' |# S. D+ u9 x$ P+ m- P  @( R8 b- l" T2 m
    try {
0 u6 g( X; w, s2 R& d      modelActions.createActionTo$message
: r9 g6 T  Q; [: _$ E& r        (heat, new Selector (heat.getClass (), "stepRule", false));
5 n% F9 d: k1 ^: i* x    } catch (Exception e) {& M! |5 c% ^  b7 s3 k) \  _+ [
      System.err.println ("Exception stepRule: " + e.getMessage ());2 }4 m( |3 L! A
    }
: C- n1 `5 t' F- ?0 A( n+ L
6 J: I4 F9 P6 E0 r    try {
& ]6 S1 R9 s$ m9 c      Heatbug proto = (Heatbug) heatbugList.get (0);
9 m* D! ^% [  x$ Y" s# _0 i& x      Selector sel = & {& ]1 o/ j. c6 x2 U
        new Selector (proto.getClass (), "heatbugStep", false);
9 j9 {& y3 i2 |$ Y      actionForEach =
2 F9 ~" |3 u% S4 ]' a! u2 J        modelActions.createFActionForEachHomogeneous$call& ?5 i! D2 R9 y' T4 j7 z# m
        (heatbugList,
. W( P$ p( e5 Y0 c# D8 a         new FCallImpl (this, proto, sel,
$ N7 P5 r& S! E9 Q$ `- A- e  Y' F& X                        new FArgumentsImpl (this, sel)));! j1 O6 ~* u7 D1 Q( b. `" N! y
    } catch (Exception e) {
) a- B' `( E. g0 e* W  w) @) q      e.printStackTrace (System.err);* [, V- n1 _5 {
    }9 z" V  N0 f, M2 b5 U
    ( {+ {' x' _; q& k3 c3 \
    syncUpdateOrder ();
. F, i* s2 b# U0 T6 D* w8 S- F+ V& \3 [# [+ R* ^
    try {+ S5 f# H- s& H. p2 ^& s! M( Y
      modelActions.createActionTo$message
# Z0 B+ Y* q+ i7 E0 Q        (heat, new Selector (heat.getClass (), "updateLattice", false));' ~/ \3 a; Q$ g7 w
    } catch (Exception e) {
9 c' n$ z8 u: o! V3 T2 B! Y0 [2 r      System.err.println("Exception updateLattice: " + e.getMessage ());
2 ~; A# y0 s/ I    }! }6 T( J- @. r4 j$ @
        & C- G! S! ?" {4 a5 Y, c0 ]
    // Then we create a schedule that executes the. \0 r3 g/ x9 P
    // modelActions. modelActions is an ActionGroup, by itself it5 I% J2 S$ h1 Q+ j* v- P
    // has no notion of time. In order to have it executed in4 ~& k& b& \" u
    // time, we create a Schedule that says to use the
6 L. ?' w. ?* V( D7 q5 R7 x1 z    // modelActions ActionGroup at particular times.  This4 B( c8 H/ `8 A1 _$ S7 S: O0 w
    // schedule has a repeat interval of 1, it will loop every: Q3 L% x5 a" q" _- X
    // time step.  The action is executed at time 0 relative to
4 T$ u) m5 ]8 K% T) n    // the beginning of the loop.
' P( A' L4 |7 [8 V+ L
1 s0 [4 C" g8 K8 `0 @    // This is a simple schedule, with only one action that is
& v) v" w6 `" ]5 s* @$ i    // just repeated every time. See jmousetrap for more( |+ V3 ]8 {% x7 g  J. {
    // complicated schedules.& G3 |; Q8 H, w5 H6 C$ o! ~
  ) ]* t4 I0 B9 ^" C  ]! U! _% P. z
    modelSchedule = new ScheduleImpl (getZone (), 1);
: n% X3 b7 G1 {  {( Q1 D    modelSchedule.at$createAction (0, modelActions);
$ X" p- k+ O3 \; Q- O. C8 D1 v        1 x  R& `4 `. o; e
    return this;) ~  q# f: G+ y0 e. x9 k
  }
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