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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
0 S4 v/ l- I0 j' q9 |3 L2 U8 y% C$ ^+ ?; }2 m! `  z
public Object buildActions () {
5 L0 y% X: Y" w  ^1 y    super.buildActions();  g2 g: B4 o2 v  M
   
- A+ ^* x% F. o! _' {# R    // Create the list of simulation actions. We put these in
. M# m$ y  ]# k& q- E    // an action group, because we want these actions to be
5 F% A0 v! l: a' l8 D4 f# K% p    // executed in a specific order, but these steps should" t4 S" p# g( Q* e9 Y
    // take no (simulated) time. The M(foo) means "The message6 l! |7 K$ G/ B6 C4 p2 B- S5 Y) n+ L
    // called <foo>". You can send a message To a particular
* O  ]" Z, S; O" Q, O; K" V    // object, or ForEach object in a collection.) E2 X9 @' R. O: H3 J( t+ {7 Q/ L
        % i$ D2 p+ ?' O7 ]4 ~8 h
    // Note we update the heatspace in two phases: first run
0 X6 y& {- G; y3 c    // diffusion, then run "updateWorld" to actually enact the8 T3 K8 {: X9 a7 |! b5 b, ^
    // changes the heatbugs have made. The ordering here is
4 D' Y8 E* S9 l$ d! v    // significant!6 o% G, Z% I: {( `
        ) B3 O0 l' z  Y2 L* U
    // Note also, that with the additional
" f8 J# K* _/ ?  i/ |) d& c( e    // `randomizeHeatbugUpdateOrder' Boolean flag we can- \2 ^* G1 `! F$ {
    // randomize the order in which the bugs actually run; o- o1 `2 m6 o1 D
    // their step rule.  This has the effect of removing any+ a6 M) s& s) y- }
    // systematic bias in the iteration throught the heatbug9 z# s, K! V( [; G0 y. ]
    // list from timestep to timestep
4 B5 }4 ^2 s7 z        ( b$ _8 m4 ]. O+ T( J& W
    // By default, all `createActionForEach' modelActions have' [: C6 @. f1 m, I/ E6 f
    // a default order of `Sequential', which means that the
9 [2 W$ u' }. q2 h; h4 Q& r    // order of iteration through the `heatbugList' will be
  z% \; I9 F" p+ F/ g5 Y    // identical (assuming the list order is not changed2 [9 U4 ~' C+ {4 O7 ~+ m
    // indirectly by some other process).
. b+ P0 f; ]. B2 l   
' Z2 D. o$ e# S; w    modelActions = new ActionGroupImpl (getZone ());
3 C% K& M3 n; r# a: p  |- y
* u4 |+ d2 _- [0 W3 o    try {. z- Z% p) s& ]0 g) M/ s
      modelActions.createActionTo$message9 r0 G! _* g6 K) V+ [2 H4 q
        (heat, new Selector (heat.getClass (), "stepRule", false));
- ~* A. Q6 |" S# @4 k( Q    } catch (Exception e) {) f: U9 P. J' P7 V: e
      System.err.println ("Exception stepRule: " + e.getMessage ());4 h1 q" k4 X9 K  y, l, }9 b
    }2 @* j, R" u7 T' c5 f4 `
, n, p5 P* U  c* t5 E. x9 w
    try {3 _1 ~4 D; K; V1 G+ C8 b% E
      Heatbug proto = (Heatbug) heatbugList.get (0);
+ Y$ r4 S# i2 |# S      Selector sel = 6 s9 L" H: E. B- p" t4 ?( A5 `
        new Selector (proto.getClass (), "heatbugStep", false);5 A, ^0 j5 @( l% q- N1 h4 ~  t
      actionForEach =* U1 q8 e' F6 z' @
        modelActions.createFActionForEachHomogeneous$call, ^) ^: B9 o0 E6 t4 ~7 X
        (heatbugList,1 d" l* g, x( ?& |, y6 I# U- Q
         new FCallImpl (this, proto, sel,
& S, o2 a+ G' q) z* C" J                        new FArgumentsImpl (this, sel)));
8 Q  g' d% F, C: _" S5 I6 a    } catch (Exception e) {# {4 U) P: Q9 D
      e.printStackTrace (System.err);
8 H  R* P- i: O4 h) Z9 B    }9 @$ P# c$ q; ~% z: d' L+ l. P
    7 Y1 D' C# q7 `' |
    syncUpdateOrder ();1 Z; J3 N# S; I* u" n

7 ~- C+ k& z2 C6 Y$ N) d1 E, \' C    try {
$ ]+ S& I. n* ^) Z( j      modelActions.createActionTo$message
) [# d( \0 s) ?1 t6 k        (heat, new Selector (heat.getClass (), "updateLattice", false));6 x. e( T1 r5 p! C' ?
    } catch (Exception e) {0 I4 f5 x% z+ }4 B
      System.err.println("Exception updateLattice: " + e.getMessage ());1 T/ x' t7 _) C5 h& T
    }# }& A' M+ T8 }( W6 A7 Y, b
        " ?) n' l, X( I, o3 T; ~
    // Then we create a schedule that executes the
8 H" Y* o1 O- e! {    // modelActions. modelActions is an ActionGroup, by itself it# u( u. a3 A  {( [
    // has no notion of time. In order to have it executed in9 a3 g7 n# R& ?9 l# W, A( U
    // time, we create a Schedule that says to use the
4 j2 }. \" ?: w. q; k0 Q: Q, M    // modelActions ActionGroup at particular times.  This  ^8 x9 A. `: P: n  t
    // schedule has a repeat interval of 1, it will loop every
. R5 P- F% q3 v; ^( `    // time step.  The action is executed at time 0 relative to
3 w* T! U/ m, T  }" s" D4 q    // the beginning of the loop.
# G9 G. [' b9 L' V, j8 K
8 I$ J! I4 e7 I' R( v! _3 f& ]    // This is a simple schedule, with only one action that is$ ?& h9 o* o3 D1 u7 o. [
    // just repeated every time. See jmousetrap for more" n- y0 k5 U' v  ]1 P7 Q
    // complicated schedules.
- S) H/ r. K# z8 ?" I; ^. t, Q  & E. J# Q6 i/ J1 m
    modelSchedule = new ScheduleImpl (getZone (), 1);; T" j2 V  |/ v, q" u8 C$ {+ E
    modelSchedule.at$createAction (0, modelActions);+ G1 ]7 z: \* Y* U
        
: z% l* I( {* }* i; {  `    return this;8 ~' o/ y* N. @" j2 O4 K+ {
  }
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