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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:6 s1 V% j6 U! h7 o; D7 s

1 r: [9 i, i) t0 U! K* I. k public Object buildActions () {" b0 ]! O6 a6 \9 E* _- L( ~3 C
    super.buildActions();( ~- M3 l, B7 A0 n/ N. h( H8 r
   
; X' C0 A# V) T) v; A; Z; f    // Create the list of simulation actions. We put these in4 z) i, D) G8 i" O1 s. r! \) _
    // an action group, because we want these actions to be$ a/ f. ^9 Y& K' I! S! y
    // executed in a specific order, but these steps should
( `! l& E1 E) u6 D7 _9 K    // take no (simulated) time. The M(foo) means "The message
+ Y- o6 f0 ~9 g+ ~7 }    // called <foo>". You can send a message To a particular
9 i0 |* i4 D. N% I5 W) m- Q& p# `    // object, or ForEach object in a collection.
% l3 O7 \* P! G' i" m        
) Z6 I- r7 h! O    // Note we update the heatspace in two phases: first run
9 W* t( m, u, m$ F  ~    // diffusion, then run "updateWorld" to actually enact the6 u( O( [. P% w$ W( a
    // changes the heatbugs have made. The ordering here is* [# ]# s- _5 G; Z* j
    // significant!6 w/ V3 E& T! Q6 n+ W
        
2 x9 W% f8 r2 c! H$ l$ N1 \    // Note also, that with the additional
0 X3 g( V) n* N1 Y9 g    // `randomizeHeatbugUpdateOrder' Boolean flag we can
& ^1 y9 V/ u! x: a    // randomize the order in which the bugs actually run
7 q$ e  e5 @- I8 I6 `9 p  f    // their step rule.  This has the effect of removing any
% u0 k# Z, g' h( i' h) r6 {    // systematic bias in the iteration throught the heatbug* T* V( n0 ~! J$ _( D
    // list from timestep to timestep
; o# I2 z0 v4 m* P8 x        
0 d3 }& @/ m3 S: o    // By default, all `createActionForEach' modelActions have
  d  j+ N2 V) ^    // a default order of `Sequential', which means that the* r, b6 [# R! O; y) t
    // order of iteration through the `heatbugList' will be- ~4 L& _$ t2 T% K/ X
    // identical (assuming the list order is not changed# t  W% b) y$ P0 K; I
    // indirectly by some other process).
  `& U6 X' ^+ g! E$ v   
$ u# B: [- D" Z* {. E7 O  ~    modelActions = new ActionGroupImpl (getZone ());
, y8 ~0 O" D4 l) k, `* M# T; O
4 H8 {0 h& ?! S! m2 {    try {# ?' U& h; U5 ]# ?2 ]7 o% d
      modelActions.createActionTo$message
9 }& x$ h9 {. [* {: l        (heat, new Selector (heat.getClass (), "stepRule", false));
* s" z! q6 E( M* x    } catch (Exception e) {1 _! T& F( u$ H3 ~) X+ E
      System.err.println ("Exception stepRule: " + e.getMessage ());
: C. _# r# ?0 b8 R+ z; [    }
7 u5 |' F% t, t$ ~, w: [
: [" s7 B2 `  s5 D3 L    try {
- b8 x% g$ R- Q2 e; s      Heatbug proto = (Heatbug) heatbugList.get (0);
" r' b+ U8 F! H9 W      Selector sel = 2 z  [+ u, x( Z3 y
        new Selector (proto.getClass (), "heatbugStep", false);% G9 l' X2 E! `; L
      actionForEach =
. ^# r! Z, a1 E. @5 M# H& C        modelActions.createFActionForEachHomogeneous$call
$ v" m0 p* O0 F) w8 K: n- R        (heatbugList,
1 m7 [' S: K+ H9 w1 z4 l' f2 W, Q         new FCallImpl (this, proto, sel,
. I4 u  d$ r: {- F                        new FArgumentsImpl (this, sel)));
7 t: }/ S# _0 T8 e3 C    } catch (Exception e) {  P5 R+ u9 ~, U: `8 u% v
      e.printStackTrace (System.err);& p) O: K5 b7 s& q& h
    }
! y7 g; C1 A+ N   
. H" l! P! |# }8 L2 y; n    syncUpdateOrder ();
7 ?) J6 f/ z( W# F5 F% v
7 K, k/ l6 E7 u+ M, ^$ p0 g  ^: w    try {! C) F+ N0 \2 W: E6 z  P5 c7 Z
      modelActions.createActionTo$message 1 c5 `4 s* n' k' c' s+ S& c$ c
        (heat, new Selector (heat.getClass (), "updateLattice", false));1 q/ {; Y: ^  G0 y1 N: O
    } catch (Exception e) {
" D, ]8 A- v) g) J      System.err.println("Exception updateLattice: " + e.getMessage ());
* ]8 m7 B+ e# G# V. ]  K    }
* H2 }1 C1 C5 ^: g, f$ b        3 p) z+ T3 u) L$ T& N
    // Then we create a schedule that executes the1 W' b: T4 C9 `7 Z/ X/ I8 v
    // modelActions. modelActions is an ActionGroup, by itself it5 a7 m+ e; t7 B- t% m, n& r: n
    // has no notion of time. In order to have it executed in' ^+ K% ?9 C3 C( z8 P, g# `4 D
    // time, we create a Schedule that says to use the
) T1 {& O3 v1 _6 r! i6 [    // modelActions ActionGroup at particular times.  This
* F4 s8 j+ v8 @5 B( S/ D    // schedule has a repeat interval of 1, it will loop every; I8 q$ o- F/ F
    // time step.  The action is executed at time 0 relative to  b0 w' |5 }5 {- [- i4 U
    // the beginning of the loop.6 a, x2 ^& W; G) ]

8 o7 N' v% R; ]% _- ]* l( _    // This is a simple schedule, with only one action that is: J# h1 I+ f( w* q# Y% {3 J) B2 q" @
    // just repeated every time. See jmousetrap for more; s6 D6 `) [- W$ W3 t
    // complicated schedules.
& h# l+ g  }! X- G8 t4 g- b  8 w6 d; E' r$ j1 a0 x8 r+ [3 |
    modelSchedule = new ScheduleImpl (getZone (), 1);* P+ I- [; `4 m7 D7 _
    modelSchedule.at$createAction (0, modelActions);. ?! b& s+ A6 T8 Q
        0 f+ L' v9 c" ?4 m( J2 f
    return this;: i) X4 j: N( N; Q6 i* ]/ z
  }
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