设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 9053|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
" l" S6 C0 q- r5 C
& M+ w/ V+ F6 }# b7 G/ W public Object buildActions () {
- k  D8 @1 s$ G2 ]# m+ h, {    super.buildActions();
- c: u5 Y" r+ k% z   
4 o! {( O. O/ D    // Create the list of simulation actions. We put these in4 v) P( ?; p, d" _; p) m. |
    // an action group, because we want these actions to be
5 \4 j) a3 E  H    // executed in a specific order, but these steps should7 v) \; V4 e& G( W: ~
    // take no (simulated) time. The M(foo) means "The message
  A- L" ~- g5 N  ^% d2 W' |    // called <foo>". You can send a message To a particular
, a$ w  m& k6 B; V    // object, or ForEach object in a collection., m+ l1 c; l% l/ J/ c% H
        
  g* m0 o1 \& N- U* Q    // Note we update the heatspace in two phases: first run# D7 r) K3 u! _
    // diffusion, then run "updateWorld" to actually enact the5 j" K8 K- b- S8 s, s6 E
    // changes the heatbugs have made. The ordering here is9 c4 @# y! J  r* t
    // significant!0 V' y8 l+ p. |0 {
        
3 k1 p9 T8 ?2 S' ]" O6 y" N  w    // Note also, that with the additional$ I; Q' w* E4 ~, Q# i8 ~
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
  I* l: P- N9 \6 \( ?) v& {    // randomize the order in which the bugs actually run  _, A+ q4 e. z% w
    // their step rule.  This has the effect of removing any
" ~# k' A3 f) p3 k2 C    // systematic bias in the iteration throught the heatbug. E& e9 S9 J2 v
    // list from timestep to timestep
4 L/ ]  S0 T/ a; v3 r3 p8 ]  ?        
9 N3 u+ H6 {& _" C$ {    // By default, all `createActionForEach' modelActions have6 ~( v+ I$ |8 D1 c( U9 |. G  G
    // a default order of `Sequential', which means that the
* L8 |' U+ |& ?# g8 e$ H$ n    // order of iteration through the `heatbugList' will be: v$ G2 f) r1 l* c: s/ _  p$ ^% X5 `
    // identical (assuming the list order is not changed
$ p' a# F9 K  c6 k1 {    // indirectly by some other process).4 N* C) O( h& }6 C7 H% m
    0 Z, K5 m" i0 D5 }9 y
    modelActions = new ActionGroupImpl (getZone ());
4 [5 F, y5 i- e) X( Y8 O3 S
7 X; d( A+ C' x+ ^    try {
( A4 v7 [2 r$ N* S      modelActions.createActionTo$message( i3 I$ N- F6 h% ~* T
        (heat, new Selector (heat.getClass (), "stepRule", false));
; e# I. ?5 Q5 h    } catch (Exception e) {5 d  K0 x5 h5 K
      System.err.println ("Exception stepRule: " + e.getMessage ());1 H3 H8 R' h5 f) l( ]
    }
0 k& }$ J8 K0 v  H( R* d8 ]7 P( a  m" m. L) ]1 q  P  [9 G
    try {
+ i( u- K  M- Z6 t* k      Heatbug proto = (Heatbug) heatbugList.get (0);
& c7 U5 G6 D3 K7 I. c      Selector sel = ! v8 W# d, d6 j) t& e
        new Selector (proto.getClass (), "heatbugStep", false);  G$ R) g4 @/ R+ S! P) L
      actionForEach =
& d7 ^1 [# ^4 ~  i. j        modelActions.createFActionForEachHomogeneous$call8 |1 |7 `/ v- H) D
        (heatbugList,
; q* B& ~" {/ D6 w8 O: x% v' v         new FCallImpl (this, proto, sel,
8 T# a1 @( W* Y* N; ?+ ~                        new FArgumentsImpl (this, sel)));
( p: p& ^& Y7 O4 k- Y. ?    } catch (Exception e) {
+ u* P5 g" L9 c6 _5 r2 R. v      e.printStackTrace (System.err);
0 Y! w0 n$ ?6 M6 A  g( k+ T+ B    }
/ I/ [% N1 g, @    ! s0 \0 c+ @& J' m' `. ?) w
    syncUpdateOrder ();
! C5 b3 X% q# O1 e! _0 o1 N. |7 i
6 D" ?% u& |9 _0 L  V    try {
4 \2 E, C* B! N  G" q      modelActions.createActionTo$message + l6 w$ d- |( S% _4 M
        (heat, new Selector (heat.getClass (), "updateLattice", false));
3 z% v+ |, E+ `* q1 l9 ]6 x    } catch (Exception e) {# D3 B2 g  ?* @5 \
      System.err.println("Exception updateLattice: " + e.getMessage ());& x9 q" X4 z( ?7 r! @
    }
- G6 D9 s+ y- I8 _' ~        0 ^9 \1 V; w9 U$ H& f
    // Then we create a schedule that executes the
6 b2 @0 \# ]4 E- |3 U. T    // modelActions. modelActions is an ActionGroup, by itself it
3 T5 y  M4 V+ c; K2 j; N    // has no notion of time. In order to have it executed in  \" @! }" P$ v2 R- B
    // time, we create a Schedule that says to use the
/ E2 `- F6 m7 ^" w" e4 \9 @9 E    // modelActions ActionGroup at particular times.  This
# p1 f9 D+ b5 ]2 r6 T! {% X4 p7 @    // schedule has a repeat interval of 1, it will loop every
. `: j; v* H0 ]    // time step.  The action is executed at time 0 relative to$ d# e+ A9 k$ p
    // the beginning of the loop.6 _1 }( k. l! S

5 V+ D" Y! Z' ]8 a, b; D9 J    // This is a simple schedule, with only one action that is1 ?/ n5 w& h- A- P! N( W2 g
    // just repeated every time. See jmousetrap for more
. O* F5 E, p. Y6 a  a& h    // complicated schedules.; u4 B5 t, O& Q2 g; {/ a
  . M9 ?+ l9 w! I8 l' e
    modelSchedule = new ScheduleImpl (getZone (), 1);
# i3 Y# r0 L, @" Q    modelSchedule.at$createAction (0, modelActions);
1 J- [4 @2 T! |0 {$ E* K        ( w" B( C, E4 }7 q* a0 @# n
    return this;& @( t4 `4 Z5 c/ z  ^4 o5 J
  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-2-9 21:18 , Processed in 0.013866 second(s), 12 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表