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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:" a0 q, }' C  ?$ ?; W8 N

- ~" F+ ?. p: t" o; Y public Object buildActions () {  c& `1 G: c9 u1 F& y0 P
    super.buildActions();
8 f! M/ k5 W& j2 |   
5 y6 ?+ J7 D7 d5 X% v  j9 t) T, u    // Create the list of simulation actions. We put these in+ ]( M1 X6 [2 {0 T$ W. A
    // an action group, because we want these actions to be8 i' ~: O$ e1 [$ K+ L7 d
    // executed in a specific order, but these steps should3 G+ U+ @% _1 C+ N2 f7 c
    // take no (simulated) time. The M(foo) means "The message
) E8 C# W3 G5 B1 Q" I    // called <foo>". You can send a message To a particular/ m6 K5 a- ?) [, T
    // object, or ForEach object in a collection.. ]! L; Q0 h! u/ \
        ! Y2 f* ?/ I, M, ~6 C; p. b
    // Note we update the heatspace in two phases: first run" \! n2 M$ ~/ h) T
    // diffusion, then run "updateWorld" to actually enact the
* n" o. u2 a. x1 p4 Y    // changes the heatbugs have made. The ordering here is/ ^3 ^" ?2 X  H6 C1 i& n& W+ \
    // significant!
& R+ F5 f, ]% Y9 C6 }5 |        $ |6 \8 _0 x, H& t9 ]& X1 A
    // Note also, that with the additional# z0 o# a/ Y" }# h$ U) T. F
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
3 h  K% C  s0 t: j9 Q$ j    // randomize the order in which the bugs actually run1 G2 w, L% ]0 Q9 ]% B" K- X
    // their step rule.  This has the effect of removing any
) u" T9 T+ n# I- T* l5 [. ?9 G    // systematic bias in the iteration throught the heatbug
0 g0 Z/ x, h. `6 D* ^  B% Z. r    // list from timestep to timestep
1 `, Y3 V4 n7 z        
9 N/ u6 N; F( [2 _7 p3 U4 j' F    // By default, all `createActionForEach' modelActions have
& E' {+ k! P+ x! J  M4 ?7 H/ S    // a default order of `Sequential', which means that the
2 \) b) j2 N4 S0 V% \    // order of iteration through the `heatbugList' will be' W5 g, q0 ^, n) q! x( p
    // identical (assuming the list order is not changed
( S- X+ H3 Z: b  `    // indirectly by some other process).2 [' E  ]$ q3 c' `
   
2 _' U6 p( b6 z5 X1 e% d    modelActions = new ActionGroupImpl (getZone ());
) j3 T6 U1 A8 i- |
# a' `' M8 @* J; `2 |, ?    try {- j1 A  }! o( o2 q
      modelActions.createActionTo$message
, [3 o) a9 p8 J: [+ _- G4 r9 ^* Z        (heat, new Selector (heat.getClass (), "stepRule", false));
0 {6 @6 C; K" A4 P$ I    } catch (Exception e) {
+ e! E5 V, e6 H& k  z9 L      System.err.println ("Exception stepRule: " + e.getMessage ());
: j/ K3 v6 U' }# g3 R8 @1 \; _    }0 e% @% R) h4 \
6 j' W! _. V0 y6 ?7 @
    try {& ~. L) Z: q0 @2 t/ w
      Heatbug proto = (Heatbug) heatbugList.get (0);" @7 l- R- p+ ^7 |3 [
      Selector sel = ; O3 A9 k$ V+ }6 a" Z0 Z
        new Selector (proto.getClass (), "heatbugStep", false);
" s8 t7 p# B' h% p! V$ ^) T3 m      actionForEach =
' P5 |7 f: b$ q8 N, ]" M        modelActions.createFActionForEachHomogeneous$call
3 w" f' i) q5 e, U- g# h  O* f        (heatbugList,* B1 G( ~- J" u, F# O+ {
         new FCallImpl (this, proto, sel,
$ {& ?4 m- b4 \0 W                        new FArgumentsImpl (this, sel)));
8 U6 G" T0 |5 h    } catch (Exception e) {5 _6 r# f! G% I  l
      e.printStackTrace (System.err);
2 y8 B" P7 w0 l6 l4 @    }# C3 |/ v! y  T/ c3 e% ?- H
   
8 K2 p' O2 T# }% M+ \5 y/ ^5 O    syncUpdateOrder ();
$ Z# e& O! G  Z' l/ I9 f$ h6 _- @7 S! U0 C! ~- M" W( F+ r* A" m
    try {
- R+ Z* D' u/ F* T# X; x, K, ?$ t      modelActions.createActionTo$message 4 N! d# D8 i0 d0 p2 K
        (heat, new Selector (heat.getClass (), "updateLattice", false));
8 J% a* Z0 V  O( H    } catch (Exception e) {
% P$ {( W) o' \2 ]) |$ N      System.err.println("Exception updateLattice: " + e.getMessage ());
: Y3 J- O/ U; p; L) j0 A    }4 S! Z! E0 V0 y+ e4 s
        2 R8 a, I: ^# R( g
    // Then we create a schedule that executes the
2 X& e, D1 R# _' d" J    // modelActions. modelActions is an ActionGroup, by itself it4 H2 N: z9 f) k6 R+ n8 _( j8 s0 y6 h
    // has no notion of time. In order to have it executed in
4 u: P8 R+ ~! T: N    // time, we create a Schedule that says to use the
6 A1 w) L/ c4 x' Z' z5 Y    // modelActions ActionGroup at particular times.  This' D2 h  l$ t: t* ~/ C, T+ M
    // schedule has a repeat interval of 1, it will loop every
; w0 q; p9 o4 O, e    // time step.  The action is executed at time 0 relative to- b/ O8 H8 w2 x1 z$ }
    // the beginning of the loop.
& w, N# S# g2 i
; Y7 V" z+ q# K3 P    // This is a simple schedule, with only one action that is
3 h; k+ g* K) @    // just repeated every time. See jmousetrap for more
3 l/ E# j' e! x    // complicated schedules.; u  D: R/ G( Z- ^
  ' X& \  O/ z; r$ r7 ^
    modelSchedule = new ScheduleImpl (getZone (), 1);
; T, F  }9 e: {9 w$ ]5 [- u    modelSchedule.at$createAction (0, modelActions);
0 k' v* ~; r" c+ O        
( n2 U* E: p2 A" V$ y3 I    return this;7 {0 l  d. x& u) B0 X: N
  }
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