设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 12255|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
& W$ Q" I  Q  I; @' \  N2 O9 o, `3 o2 ^$ C$ v
public Object buildActions () {( k. b! C2 q/ ?+ k* c
    super.buildActions();4 R: s" f# L; z
   
& M3 I/ o  M3 b    // Create the list of simulation actions. We put these in8 S# `7 D2 R' E0 C8 q! L
    // an action group, because we want these actions to be1 Z9 Y: `- B2 S3 E
    // executed in a specific order, but these steps should: a* d+ H7 ?: Y( M! F# v) w  B
    // take no (simulated) time. The M(foo) means "The message
: k8 S  ~/ M: c% \7 [4 t    // called <foo>". You can send a message To a particular' [5 e% ~6 p/ v. {( u% q& S
    // object, or ForEach object in a collection.
. F5 U; M/ k- t" r9 j        ; @0 N, E9 X8 s' b; J
    // Note we update the heatspace in two phases: first run
2 f7 b# k, q3 O    // diffusion, then run "updateWorld" to actually enact the
7 j8 {8 Z7 t5 O3 s    // changes the heatbugs have made. The ordering here is/ t9 G8 s& g" C3 b
    // significant!8 _* X8 k1 s* X/ L
        
) k  {! ^8 g. S: G, O    // Note also, that with the additional
6 J0 _1 y' M  |, D) K6 r- h    // `randomizeHeatbugUpdateOrder' Boolean flag we can
7 Y# m% T# Y0 c; B  |! ~) y" M    // randomize the order in which the bugs actually run) j: x  o1 q6 {; M5 V' Q) p: n) F# b
    // their step rule.  This has the effect of removing any
$ M. `1 k, f; _3 o. x    // systematic bias in the iteration throught the heatbug3 G& |# T1 q8 \0 e. J* w# D0 z
    // list from timestep to timestep) }% I5 `" `- R6 s( i$ m4 x# i& D
        ; }% m# J/ Z5 U  u2 f
    // By default, all `createActionForEach' modelActions have4 g( x5 K4 d, \! i6 n3 S
    // a default order of `Sequential', which means that the
" s2 k3 _8 ]: K% N1 r    // order of iteration through the `heatbugList' will be
, m3 D! d  e( d6 j( z2 p    // identical (assuming the list order is not changed  J/ q  H2 R$ M
    // indirectly by some other process)., Q+ s7 T5 @- ^# A  ?
   
! M3 I: Q% i& ~! i    modelActions = new ActionGroupImpl (getZone ());  F- ]3 A# |* i6 _1 K8 f" d$ [
/ e9 f- e% @1 x
    try {( q- w+ \( Y1 B2 _; F$ r9 m, Z0 f
      modelActions.createActionTo$message
& n1 Z& b; Z8 H( x        (heat, new Selector (heat.getClass (), "stepRule", false));
0 j2 U5 y* s4 ]7 N# Y    } catch (Exception e) {
; t6 R) h% I  K7 C; K* L8 S! ^3 I  P      System.err.println ("Exception stepRule: " + e.getMessage ());
8 t. ?5 p7 J+ f6 M& f2 Z    }
+ h# K: E% y$ l: k6 h: @# b& R/ }) K
    try {6 l9 G% e+ r5 C+ P- w
      Heatbug proto = (Heatbug) heatbugList.get (0);7 }/ j% w  l/ K- p" A; u" e% c
      Selector sel = ; d: X% ~0 u5 c) E2 Q1 I, c; g
        new Selector (proto.getClass (), "heatbugStep", false);
/ y* }" j, T+ K. p( O" L( G      actionForEach =
3 |- Q7 |$ y0 L9 u* t        modelActions.createFActionForEachHomogeneous$call* j7 n) {6 l5 l- j2 q
        (heatbugList,
1 i8 |) {* r) D. B8 f: F+ _         new FCallImpl (this, proto, sel,
3 j) _6 o( x4 p7 B                        new FArgumentsImpl (this, sel)));
9 f4 w) T  \! a- r    } catch (Exception e) {1 Y6 K0 @5 I5 Y
      e.printStackTrace (System.err);
3 r! L, _3 Z! }5 k7 n. d1 _    }2 k7 D; p2 s; {8 x4 E2 H
    . l/ g- X! V) j/ l7 r  b; G' @
    syncUpdateOrder ();" `0 b3 q; {0 z  B# y8 H% F( W" m; u# i3 l
$ ]* D* x+ m. |1 d! _
    try {
' P- M' o$ w  _      modelActions.createActionTo$message : m' L6 L8 z; b+ }3 g! P
        (heat, new Selector (heat.getClass (), "updateLattice", false));
9 e# [, p9 q; R8 A    } catch (Exception e) {
! U, G$ S, L: _" @& e6 i+ r9 H, ?      System.err.println("Exception updateLattice: " + e.getMessage ());) x  t4 F4 m3 z4 r" K
    }
1 f* N, ^( }- N) n! g" ]$ D        4 l1 g& S# J& x. ^: V" c
    // Then we create a schedule that executes the9 B9 Y+ Z6 P' c4 z0 t1 \
    // modelActions. modelActions is an ActionGroup, by itself it6 D: X7 [& r3 s- y$ T1 x) Q
    // has no notion of time. In order to have it executed in1 E/ K8 d) `6 @3 e/ h7 G& F" b% d2 d
    // time, we create a Schedule that says to use the
' r2 x& X3 [, H8 s    // modelActions ActionGroup at particular times.  This, `  Q0 T. s8 J
    // schedule has a repeat interval of 1, it will loop every+ f9 i0 P, X. O7 c% k* U" H
    // time step.  The action is executed at time 0 relative to) ?1 x1 |0 Q, C' c$ i+ X- j
    // the beginning of the loop.; l5 ]& E) o5 p9 b! r3 T$ A+ n

4 R0 c  C8 `3 I* l* j0 v. q, p    // This is a simple schedule, with only one action that is9 D4 q$ q3 t) ^/ ]% x+ J
    // just repeated every time. See jmousetrap for more
) ?6 d! v& d. P8 K2 Q    // complicated schedules." b4 w2 b# M9 y7 F
  ) n) @# s7 V" ?) X3 o
    modelSchedule = new ScheduleImpl (getZone (), 1);6 s0 @+ O9 ?1 {- {
    modelSchedule.at$createAction (0, modelActions);
- N0 r+ ~+ ^3 T0 S! w        ' s' N$ c* c* g, r7 U- g
    return this;
3 T4 T9 P* y% i) O- \  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-8-17 15:38 , Processed in 0.015163 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表