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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
' Q7 D& R  x4 ^8 J* H
# U4 d' C  D0 b2 D" t3 J: A public Object buildActions () {5 n2 @* x2 p; y8 j
    super.buildActions();4 d3 t7 p' H( D6 S# _6 O0 C
   
+ [. k$ J# C% P# k    // Create the list of simulation actions. We put these in/ O- L" ~7 ]# ^" C1 k
    // an action group, because we want these actions to be
' v5 p0 H1 l' y7 s4 u2 M  g$ o    // executed in a specific order, but these steps should
' J+ K5 k  i+ `" n; F, O0 j    // take no (simulated) time. The M(foo) means "The message
5 t# A( G! ?; [6 `/ `    // called <foo>". You can send a message To a particular
/ }' e# |/ q- p) j" L) l0 t    // object, or ForEach object in a collection.
+ z, t  l+ n/ K, k5 @* K: e/ ~        
/ ^, H7 ?2 l! `4 O% S+ M& t    // Note we update the heatspace in two phases: first run  q. e- E, g# }/ U  K; Z
    // diffusion, then run "updateWorld" to actually enact the2 |; {# p% i4 w5 a  \% q* L% g
    // changes the heatbugs have made. The ordering here is
1 g" {- I( C, ~9 s" N0 t8 g    // significant!& a8 R7 D, u- i& y* H4 C( u
        
4 `5 F/ d, p) Z- O3 t" s7 I    // Note also, that with the additional$ H' |6 f  S4 L* B3 o( f1 [
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
- I. D" b* k; b    // randomize the order in which the bugs actually run
9 I  M/ M2 q* ?2 ^! p- y0 J. m. u( F6 J    // their step rule.  This has the effect of removing any- F$ m4 ]/ z" t8 W  x5 y  |9 @
    // systematic bias in the iteration throught the heatbug
4 h9 @8 Y  g' R8 _' l4 `( r6 {    // list from timestep to timestep' R& K% q1 C7 O9 v/ E$ b1 l
        
9 A7 }( K* p& W/ D. V  c    // By default, all `createActionForEach' modelActions have
3 e& R! @) K8 Y. m' G; k! p' y    // a default order of `Sequential', which means that the
' P8 ~5 P8 B( v8 l8 f    // order of iteration through the `heatbugList' will be
" }) h; M4 U$ ~; ?! d5 q$ g    // identical (assuming the list order is not changed
( d' V# I0 Y) b- I2 Z    // indirectly by some other process).
" i, B: ]0 ?  I. K/ p   
* j& L5 ]! ~( _9 o1 A" o* F    modelActions = new ActionGroupImpl (getZone ());: S/ v3 l+ _8 V) M3 T
' |( u! G, Y' [: M8 u
    try {
& Q' t5 }: ]; J$ ~, b! g1 L& ^6 i      modelActions.createActionTo$message
, ~' A4 N  ]" w9 ]9 ?        (heat, new Selector (heat.getClass (), "stepRule", false));
; ^# l. X; d0 H' D    } catch (Exception e) {% k: r5 ?% x, u/ U% ?
      System.err.println ("Exception stepRule: " + e.getMessage ());3 Z% R4 M4 I3 Y
    }
1 o$ F3 K  s, F! E1 D
3 |8 q4 ~% C& @) K6 v4 `. [    try {0 Q; G* B  w: g1 K( I/ s9 e# o
      Heatbug proto = (Heatbug) heatbugList.get (0);
* x7 H/ S2 k# R, U; X" A' J2 S1 J      Selector sel = + C; E( v% B7 x* ^$ ^
        new Selector (proto.getClass (), "heatbugStep", false);$ o  D# Q6 k7 h
      actionForEach =/ h$ t5 p8 {" ~, [
        modelActions.createFActionForEachHomogeneous$call; P: O# z- ?8 k! a' M
        (heatbugList,- O7 O4 t1 N( e6 W
         new FCallImpl (this, proto, sel,
5 a! ~/ S+ o7 @9 Y' c7 T                        new FArgumentsImpl (this, sel)));' x, t2 [" [4 A4 v: i
    } catch (Exception e) {
1 B/ p3 q: {% ?0 p      e.printStackTrace (System.err);0 u8 }3 \' }6 c0 H7 T0 |
    }
* a: g5 E8 b' ]& X; h$ i! S( \6 g   
7 `: {; M2 V' t" v    syncUpdateOrder ();
% T: Y8 \3 V: b. C' `: m4 d* V4 j: f9 X: s  u* `1 C9 H2 H1 ?* P
    try {
$ l' n% I9 S( E" q6 _      modelActions.createActionTo$message
; ^' E1 `9 f& ]. a  Y4 \        (heat, new Selector (heat.getClass (), "updateLattice", false));
5 d7 G3 V5 L4 G& D' c, w    } catch (Exception e) {
3 a6 N' w9 J5 Y( X      System.err.println("Exception updateLattice: " + e.getMessage ());& P+ c- g$ ?0 n
    }7 B" O& d! s& g! W* a
        
0 B8 @' O' [* |    // Then we create a schedule that executes the0 E9 i; |3 N& C4 _
    // modelActions. modelActions is an ActionGroup, by itself it- b0 J+ S& @8 ~0 p7 B
    // has no notion of time. In order to have it executed in
2 P' v4 l8 }! P    // time, we create a Schedule that says to use the: A% ^( h5 Q& E% ~( f8 ]* y6 c
    // modelActions ActionGroup at particular times.  This
5 Z' N& M7 Q( ^( D8 o0 Z    // schedule has a repeat interval of 1, it will loop every2 z5 \# M0 S4 L7 ?% V* C
    // time step.  The action is executed at time 0 relative to+ l+ ^; n! D$ V- o5 D5 E4 j5 H/ m
    // the beginning of the loop.; l$ m6 B9 i# l& l5 t
. _$ N) F8 U. \7 i: ^
    // This is a simple schedule, with only one action that is
- A$ ~( r# N3 d: u# Y/ L    // just repeated every time. See jmousetrap for more
) v) o3 T' ~" E# ^. i0 x    // complicated schedules.$ W* R* E& g- m' O8 n# `
  
7 [- f! r, o/ x  w    modelSchedule = new ScheduleImpl (getZone (), 1);' M/ A' B3 ?. |- C. [
    modelSchedule.at$createAction (0, modelActions);
) w" w6 r9 X4 d/ W5 p# U# v  ~6 w        4 ]' E/ a( n! Y! v9 @# {
    return this;2 D" c6 U  Y3 p2 T
  }
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