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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
7 t$ k# V  M8 @( b: z: C
% `+ J) I1 {0 H# q public Object buildActions () {
8 E7 j6 J) W& p. q    super.buildActions();
2 ~4 \* Y) a6 e; t, b3 j9 @& B   
/ i, m& s% J* m. ^2 ~    // Create the list of simulation actions. We put these in
! I# M3 }4 N0 M" ~    // an action group, because we want these actions to be
5 V* O5 M4 G* ^: e    // executed in a specific order, but these steps should
% o. k! {$ B) a/ Z. p' r    // take no (simulated) time. The M(foo) means "The message
, n' g2 u1 P: _: i* t    // called <foo>". You can send a message To a particular
) h6 ?' |. a, j/ Q5 k    // object, or ForEach object in a collection.+ s; S5 [5 f% f5 L3 I0 H
        
- @: O& C- v3 }% q    // Note we update the heatspace in two phases: first run
- t! W5 m/ `" }2 x" ?    // diffusion, then run "updateWorld" to actually enact the, Q8 J, g* u# a3 z3 o6 U$ k
    // changes the heatbugs have made. The ordering here is
1 |2 }6 c7 f1 E% ^4 U5 D3 c4 P    // significant!. N0 T9 Y4 F) p+ S4 b; n& j
        5 X5 ]# h+ V+ d: q  R! L- X
    // Note also, that with the additional
7 y8 T  \( [, w3 t    // `randomizeHeatbugUpdateOrder' Boolean flag we can4 x) D$ W! s# j$ J) @: E( _
    // randomize the order in which the bugs actually run0 n" j$ W, n8 [" t! Y+ k4 g
    // their step rule.  This has the effect of removing any# F; w/ R7 l  t1 a
    // systematic bias in the iteration throught the heatbug
5 ]; [. G8 m$ c) I2 b& {  ]: }" }% K    // list from timestep to timestep* z  O' s  L8 {/ O
        4 {* \1 j  a, Y- B. V% V( B1 `
    // By default, all `createActionForEach' modelActions have0 N. i! x3 z3 ]7 Y8 H
    // a default order of `Sequential', which means that the
7 K8 T" @$ v$ g/ {, V6 s9 X  v    // order of iteration through the `heatbugList' will be
  M, N* R# @2 i" w7 N3 @    // identical (assuming the list order is not changed5 @' ]) [5 _& |* A, R- y  z
    // indirectly by some other process).5 ^( r. L3 {. d" C; d! \( `
    3 E+ V3 H5 ]7 B
    modelActions = new ActionGroupImpl (getZone ());
: W6 r0 [* k$ m* i* z  X6 N6 J& W" L5 Z! k, R
    try {' U3 p0 t; l. J+ m: J" s
      modelActions.createActionTo$message. Y' j5 h4 `, D! I
        (heat, new Selector (heat.getClass (), "stepRule", false));
3 P5 R& A0 z+ P8 T7 L2 s) }    } catch (Exception e) {
6 Q) {8 X3 {8 b! y* w4 |3 [      System.err.println ("Exception stepRule: " + e.getMessage ());- S. |2 q3 t7 @
    }
: _' N8 t7 A4 u/ _. y, \3 C# d
1 Z. O  P. v7 C# y+ |    try {
, ^& z0 I  y$ f$ h3 J      Heatbug proto = (Heatbug) heatbugList.get (0);
; m4 {% @- M9 M5 `& A1 F      Selector sel = & T; Y( [  t7 z1 e3 G8 Y" ]
        new Selector (proto.getClass (), "heatbugStep", false);
: q5 z' @3 ~! v8 w+ n      actionForEach =
& \+ Z8 @; ]& }9 b- B- G6 |        modelActions.createFActionForEachHomogeneous$call
' E) t3 G5 S3 L& w- x        (heatbugList,
2 }0 m4 k: ]8 q+ M& X         new FCallImpl (this, proto, sel,$ R$ w' t9 N9 _& m
                        new FArgumentsImpl (this, sel)));. y: K; Z) F* J7 P6 T' |3 [( R0 a; O
    } catch (Exception e) {
' s# R6 c, w  R, Z2 U; c2 g! ]( e      e.printStackTrace (System.err);
& @4 j  ~3 S; J    }
/ d. a$ \; d4 c4 L( Z- j; f   
: |# i: C$ c1 R    syncUpdateOrder ();& w! Z" h: N1 r

. B. H4 Y) p2 p# c% N; s. `- F    try {3 c) q) z/ X4 [9 d) T
      modelActions.createActionTo$message ' e* ~6 O$ Q& f! ~0 x2 z
        (heat, new Selector (heat.getClass (), "updateLattice", false));" H, _9 j! c! O- @: O0 n
    } catch (Exception e) {
* S1 S* n+ r6 S5 T( |8 B  n      System.err.println("Exception updateLattice: " + e.getMessage ());
* q( l' E- a6 |+ A5 M" [0 B    }3 j) Y0 g: v) F7 ?( R% N
        
+ n' o* [6 e3 w& F- X. O    // Then we create a schedule that executes the
0 A3 A( v/ G0 e* @    // modelActions. modelActions is an ActionGroup, by itself it
7 l4 t5 y3 V. B% Z  J% G( t8 m3 v9 W    // has no notion of time. In order to have it executed in
1 L+ C% I# K6 ?    // time, we create a Schedule that says to use the
9 O0 b( [+ ^- J1 y5 R0 Y5 y    // modelActions ActionGroup at particular times.  This
5 {6 [+ C' B- \. w5 _. q    // schedule has a repeat interval of 1, it will loop every* t! C; q3 F2 L" f! K- C
    // time step.  The action is executed at time 0 relative to9 _; r+ X* J- ^2 ^3 q: ?
    // the beginning of the loop.6 {0 N7 h8 k4 K) U

, X0 Y: O  h, M" X3 a    // This is a simple schedule, with only one action that is
% L1 C6 J1 h. R3 \! R    // just repeated every time. See jmousetrap for more
6 D+ R8 J9 b6 }/ N' s2 @8 Y    // complicated schedules.+ v8 P5 G, S' |; Y' e! Y
  
3 r( }7 k  X- J9 f" ?. U& W9 Q: x    modelSchedule = new ScheduleImpl (getZone (), 1);
" W5 A( T4 u  p- H    modelSchedule.at$createAction (0, modelActions);
& l" K9 P4 ]% s5 G4 W3 `$ N        5 o0 Y/ G1 N) V8 L
    return this;
& ]4 v. L& E) N3 W' ^  }
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