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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:" d% s  S/ z0 `( v
# \' v+ r' Y+ h/ m
public Object buildActions () {
. A; _! u- Q% A$ z9 c- K0 f    super.buildActions();& g7 V, o3 e: r% _
   
. X) B" v. `! \. I" {* |( a    // Create the list of simulation actions. We put these in
  R( \: m* L; d$ K    // an action group, because we want these actions to be
! h# Y; r8 ]5 t) o3 t! D9 m7 a. U1 G    // executed in a specific order, but these steps should0 }/ R0 Y# E. h  b* I
    // take no (simulated) time. The M(foo) means "The message: e9 N, N. R) M: n; h: ~$ Q
    // called <foo>". You can send a message To a particular, x9 y7 [  X- T9 M& A! I
    // object, or ForEach object in a collection.6 V1 S' J/ h$ x4 n* a2 ~5 [$ u9 _5 V
        
% B) U. k: K) `6 q7 G: U9 a    // Note we update the heatspace in two phases: first run
/ D" X. B2 `5 O: }/ l/ V% P# l0 R    // diffusion, then run "updateWorld" to actually enact the
- l: x9 q5 r/ X2 @5 p/ D    // changes the heatbugs have made. The ordering here is7 C) U8 K7 j+ Y! c% V8 Q" S3 \
    // significant!2 a( |4 H; E: O
        
0 X6 u( ?, V" Z5 Y- ^8 p& r" M    // Note also, that with the additional' L& j( w3 r: V1 d9 u* b# q% @
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
3 T3 b0 X" \4 K  v2 k' Y1 R" x    // randomize the order in which the bugs actually run! f, ~# x, ?; Z" K; `, N
    // their step rule.  This has the effect of removing any* L0 E4 ~9 N! j. \* K
    // systematic bias in the iteration throught the heatbug4 ?- t7 ]9 f# t. m
    // list from timestep to timestep( H5 G1 K% s2 D# L0 J5 u8 u
        
9 |3 y0 I1 ^; X. P    // By default, all `createActionForEach' modelActions have* l  f5 a! U* d
    // a default order of `Sequential', which means that the
0 W5 P' G* `% r4 X0 Y    // order of iteration through the `heatbugList' will be
) `" y) Z7 ]; e" u    // identical (assuming the list order is not changed- I9 B- S! Q9 Q& Q& R) O
    // indirectly by some other process).: p$ z6 Y9 K. f! X3 K% F9 v
    ) c+ C3 [) y) u! Z9 t: |0 n
    modelActions = new ActionGroupImpl (getZone ());. V, E6 D- K7 I$ m( i

2 D  S1 x, J) ^" j3 v    try {
0 M  s; v8 Y  Z# E      modelActions.createActionTo$message; w" ^. i' }1 L  T  ]. x+ p1 T2 I
        (heat, new Selector (heat.getClass (), "stepRule", false));, i0 F1 B5 {( E+ l
    } catch (Exception e) {8 j% }, l% S7 G2 j6 I" E; \
      System.err.println ("Exception stepRule: " + e.getMessage ());& Y$ j4 k3 N  h. a( G
    }
' C8 W- P# i0 z: @' v5 D" ^6 h3 N" S6 g& w
    try {% n5 ~3 a+ ]: O' H! X, |
      Heatbug proto = (Heatbug) heatbugList.get (0);
" o) v! c6 d8 {4 {# f8 l      Selector sel =
# G# Z, M8 w5 C# W0 E8 l/ Z  f        new Selector (proto.getClass (), "heatbugStep", false);; \% {7 |% H7 L; p, i. u
      actionForEach =( r) ^$ |- Y- t( e
        modelActions.createFActionForEachHomogeneous$call
9 S3 I& J, T& a# B- l        (heatbugList,4 q0 S3 ]; D. {8 h+ t6 V
         new FCallImpl (this, proto, sel,
9 A0 D4 Y' ]8 m+ `                        new FArgumentsImpl (this, sel)));4 o9 j! H( U" d- {) U
    } catch (Exception e) {4 a& Z& P% t5 H& e7 ~4 c2 v
      e.printStackTrace (System.err);0 m+ T2 b: X4 K3 C& z8 M
    }
  b* z. S% m1 G, Q    ' p  R1 \) v5 C- C# H
    syncUpdateOrder ();
9 X: k( J" ^  a7 |5 U; K
$ m2 U# O6 h1 _    try {
7 v4 Q2 E, o- \      modelActions.createActionTo$message
% J& F, F# ~; ?; |* ?; g. {        (heat, new Selector (heat.getClass (), "updateLattice", false));" i$ e' D" X; k* b4 W" S3 u7 Y
    } catch (Exception e) {
; S4 D1 ?3 l1 Y' k. M" y! V% a2 I! @      System.err.println("Exception updateLattice: " + e.getMessage ());4 J" v4 n& i2 D: @6 o( p- C) O
    }9 F5 M$ j" \! {6 S' A
        
/ t5 X$ u+ e  g) ?    // Then we create a schedule that executes the: V' u6 y$ g- j8 ]2 t- H
    // modelActions. modelActions is an ActionGroup, by itself it
- j  T- R2 e/ Z2 w0 J$ @    // has no notion of time. In order to have it executed in
8 P# j& T. H4 Y- A    // time, we create a Schedule that says to use the) x% K. `# W9 B
    // modelActions ActionGroup at particular times.  This
* z5 ~% Q- x! t1 \2 S    // schedule has a repeat interval of 1, it will loop every
7 h6 n! R% C+ e    // time step.  The action is executed at time 0 relative to8 ^1 L3 P% d1 _. q: O
    // the beginning of the loop.
( |7 K* H0 U+ L9 D
" S* I6 c! @, t5 O  [, n    // This is a simple schedule, with only one action that is( m/ A: R$ g) L& q7 x
    // just repeated every time. See jmousetrap for more* T9 r0 B- H- L! r  A% [! f
    // complicated schedules.
% M  T; h# h' j0 g/ Y% }  
- y6 ~5 V. V# ~, p    modelSchedule = new ScheduleImpl (getZone (), 1);! [" _  ]. k  p
    modelSchedule.at$createAction (0, modelActions);
9 @8 t9 V6 r6 q3 \+ }2 J        
* Q" T, Z* l+ C5 ~% @    return this;
1 [+ e7 r* I: H  o% ?- K  }
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