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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:% }! J* C! F* P" x  ]9 z4 o$ j, ^
( ~# v9 N' i: T: E# D/ I
public Object buildActions () {
- O" u0 ~( g( U* H& h( m  v5 F    super.buildActions();
- y% G$ |& m) R8 @4 o5 y3 D   
1 j9 p6 s+ T! _    // Create the list of simulation actions. We put these in+ f3 z/ l# O$ O& J) J
    // an action group, because we want these actions to be: _8 \+ G8 M! T: d  r' K# K; {
    // executed in a specific order, but these steps should/ }+ p0 m% l1 K, V4 A& A2 o0 y
    // take no (simulated) time. The M(foo) means "The message2 k7 T" q# B" q' s6 J
    // called <foo>". You can send a message To a particular' m( G9 |  Q0 o2 p
    // object, or ForEach object in a collection.9 x/ H" t* g3 Y% w" P3 J
        ( F9 m' q$ N8 A5 Q# L; Z# a
    // Note we update the heatspace in two phases: first run) S' J7 H; m' h$ r) T
    // diffusion, then run "updateWorld" to actually enact the
4 m7 H7 n, ^$ a; l    // changes the heatbugs have made. The ordering here is
) H* K! {" \0 q* G" {* x( S    // significant!
  b4 [8 {' y% n  B+ r; N8 u        
" L9 J; u5 I+ r1 }1 I! k$ N, G) \+ [# n    // Note also, that with the additional+ e* ?& m2 ^9 i
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
& ^( K& x5 p9 O  ^3 m    // randomize the order in which the bugs actually run
; ?' T% \: _+ X$ e. c    // their step rule.  This has the effect of removing any0 C2 e$ b! @% Y! u' J
    // systematic bias in the iteration throught the heatbug9 i0 }' E4 V- h$ x
    // list from timestep to timestep7 ?, h3 @4 r& G! n) E  s
        
1 g& u- ~' K' {1 a, \4 w    // By default, all `createActionForEach' modelActions have
% ~  f1 Z4 ~6 ]3 [/ c9 Z) p( G    // a default order of `Sequential', which means that the
' c% q$ \1 M6 ?    // order of iteration through the `heatbugList' will be
$ ]( I' W4 g' z8 u0 h0 s+ Q    // identical (assuming the list order is not changed$ K! G1 P. R; z  @% Q- [- I
    // indirectly by some other process).
( Z: G# {  N6 {- Q+ q# b2 i: V   
- @( f; X( t) W/ W9 D( X5 y3 o    modelActions = new ActionGroupImpl (getZone ());/ Q( L) f+ Q1 ?. h$ W' y$ j

/ x' ^1 O+ b; K0 S7 m$ y    try {
4 x! S8 `! z$ G) }- g      modelActions.createActionTo$message
9 Y0 B" K' i, m5 h- F, Y- m        (heat, new Selector (heat.getClass (), "stepRule", false));/ \0 M' n) C6 q2 `4 `* N
    } catch (Exception e) {3 }8 ~1 x7 n( I) ?
      System.err.println ("Exception stepRule: " + e.getMessage ());3 h+ p. T5 l4 }; y9 [$ Q
    }
" Q) y  [! K; m$ K# U1 S' ~
2 ^6 q6 Z1 p3 }    try {
8 d+ R# ]1 r4 r) m0 g      Heatbug proto = (Heatbug) heatbugList.get (0);; Z3 k2 \% A7 H1 O" y
      Selector sel =
$ h1 B9 i2 ^  K        new Selector (proto.getClass (), "heatbugStep", false);  B( s9 q+ x+ }; y4 J
      actionForEach =
$ X: V. k$ \2 J% [+ A        modelActions.createFActionForEachHomogeneous$call: e0 w8 s. m7 R2 r, H1 _; d
        (heatbugList,, ^5 c2 A4 a( s1 g6 Y6 D
         new FCallImpl (this, proto, sel,
+ x& c- U2 Q: l                        new FArgumentsImpl (this, sel)));) I  g" C" j4 l; J: [
    } catch (Exception e) {
) l( X+ |, r/ j  R9 Q      e.printStackTrace (System.err);
# F. H* _: |+ x5 l, Q' m    }
, ], u( K1 C2 P! @6 I3 U    ' s( A0 K3 G, t( N, f
    syncUpdateOrder ();
/ P3 i1 C$ q1 Z0 R% e& m* {
' r" T% y+ P6 f6 P    try {
  I9 B0 X6 B- v4 J, }$ J: C      modelActions.createActionTo$message
" F) q$ v7 w1 e5 ]) u        (heat, new Selector (heat.getClass (), "updateLattice", false));6 q7 V0 l- r8 R3 ^- n
    } catch (Exception e) {
) f2 ]; @$ o6 `4 n+ k6 B! x0 B      System.err.println("Exception updateLattice: " + e.getMessage ());
( O) O6 [; a, y" P0 ]/ z8 [    }
, I. c  O9 q. i" @+ L        
7 C1 Q; d/ x% W, y; w    // Then we create a schedule that executes the
7 ^1 b) ^# v. d! x6 U! G    // modelActions. modelActions is an ActionGroup, by itself it
; B& Z# v' X! u' u    // has no notion of time. In order to have it executed in
+ _) o4 R% `  {) N. L    // time, we create a Schedule that says to use the
- T+ K  U! _$ h    // modelActions ActionGroup at particular times.  This
5 l* O* E* t9 I6 x    // schedule has a repeat interval of 1, it will loop every0 @) b( |6 @0 x9 {, m) V& o: q
    // time step.  The action is executed at time 0 relative to( B! ?4 F* Y$ e5 R/ m7 }- a3 X2 g
    // the beginning of the loop.5 x  M+ b0 H; l' v, D. K

( c% r' I! X4 k. E    // This is a simple schedule, with only one action that is
% q- x$ b. G& h7 M* i4 `9 T    // just repeated every time. See jmousetrap for more2 F; z- {6 |& D" o3 q
    // complicated schedules.8 C1 |# ]! O% U& L9 ?
  2 b6 O# a9 d) U2 C# T1 X
    modelSchedule = new ScheduleImpl (getZone (), 1);4 o  B8 c" N* X; d: H
    modelSchedule.at$createAction (0, modelActions);
. w1 {7 \8 `5 }5 k9 T        
6 h8 M! Q  ^7 Z4 M    return this;0 s1 i3 y, b/ v. n  w
  }
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