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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:* a' ~4 F1 k5 M2 l0 y+ e

$ |# t) v1 F5 J public Object buildActions () {
6 W- W9 X: Y; @* e7 u    super.buildActions();
" x% C4 k7 v. @" O   
( t# T, `- s$ S# Y, h2 |' z% H    // Create the list of simulation actions. We put these in
2 A7 }# w/ j4 V6 b( Q  k, t5 a$ A    // an action group, because we want these actions to be- ^7 X4 |+ B' e' J
    // executed in a specific order, but these steps should- T, J' q0 u" U( b, L7 Z: r; M( M
    // take no (simulated) time. The M(foo) means "The message
/ w8 B+ W6 b/ Y1 Z    // called <foo>". You can send a message To a particular
! P9 G7 D/ L& ^1 F    // object, or ForEach object in a collection.8 [, K5 O( C8 y& I6 \) }) r
        8 L9 m& e0 w; c7 e' W
    // Note we update the heatspace in two phases: first run
  W9 x$ c1 ^' ^5 u  A    // diffusion, then run "updateWorld" to actually enact the
7 P, Z1 T, C! j2 e3 Y+ M    // changes the heatbugs have made. The ordering here is! f7 w# y; q: ~" q+ W; u2 s: e7 E& \
    // significant!
; Y: Z6 |7 ]* s' a( U5 j  G0 O7 _. H        
6 H: i* O/ z4 X0 w; b* W. L  K    // Note also, that with the additional
. A# F; h( U2 f+ ]+ V* r    // `randomizeHeatbugUpdateOrder' Boolean flag we can8 f8 k2 O8 Q+ B  L7 l. A( S
    // randomize the order in which the bugs actually run
% a! e0 V2 U1 Q2 \* D  N  @    // their step rule.  This has the effect of removing any
$ H5 O; n# w  t    // systematic bias in the iteration throught the heatbug, G# d# u- B6 S+ B
    // list from timestep to timestep
9 G2 U2 E: K% C* B$ f, V9 z( d+ X, n1 W        
6 g8 v/ ^2 J  M. w+ [8 q' w' H    // By default, all `createActionForEach' modelActions have
5 O  b/ e, U; L+ R    // a default order of `Sequential', which means that the& ^1 l+ K& d2 T; B% t
    // order of iteration through the `heatbugList' will be, c% p+ m% e& r- ]3 D
    // identical (assuming the list order is not changed9 _7 P* n3 A' i; u% {
    // indirectly by some other process)." M' z# d7 N. P
    . M& w8 X3 p' T1 Z8 Q
    modelActions = new ActionGroupImpl (getZone ());
5 L- z. [) b9 Y- n) d! v: }0 |! }& c
    try {/ Z- {' K) f- |9 K7 ]
      modelActions.createActionTo$message
! `; p: q, x! {% T. l# M. N. q% N! X        (heat, new Selector (heat.getClass (), "stepRule", false));/ e8 M3 m  r  G2 O
    } catch (Exception e) {. T1 D8 I6 J. k2 ]! R
      System.err.println ("Exception stepRule: " + e.getMessage ());
/ C: D# i% t9 K8 m# Y4 G0 y: g    }) |) H7 g" W5 }6 w

4 |" R; t1 O+ `* q    try {. k% h3 _: |2 W8 H
      Heatbug proto = (Heatbug) heatbugList.get (0);3 C8 `# ~4 S8 K
      Selector sel = ; y0 g/ n, F6 q& r4 t: t
        new Selector (proto.getClass (), "heatbugStep", false);  N% j7 T. V" s) K( c
      actionForEach =
6 I3 m# j5 c( {, M0 a4 B! w        modelActions.createFActionForEachHomogeneous$call
  L) {9 i9 o" n. f/ n8 _        (heatbugList,- p1 R# v6 E1 E. n. r
         new FCallImpl (this, proto, sel,8 Y* M+ N' _) C  w5 ~5 }0 O4 M, r  g/ ?
                        new FArgumentsImpl (this, sel)));$ i5 _+ R, b( r) W
    } catch (Exception e) {9 Z/ R' Q* R4 A3 S7 [
      e.printStackTrace (System.err);
7 n/ R( d9 t" S) h: t    }7 n- u( x; |  K
   
% T0 E7 K/ S0 l    syncUpdateOrder ();
5 [5 W$ \5 q( ~8 Q( [" ~) X: U% P. {8 j, j$ z5 V* j; q" @8 b
    try {
% ^6 r2 g4 v! L+ R  ]      modelActions.createActionTo$message
2 F' y! [( Z  g0 ~' g        (heat, new Selector (heat.getClass (), "updateLattice", false));( H; B2 K( k/ k. O0 G0 H- q4 U) C
    } catch (Exception e) {
0 m+ w! l" r4 p  `9 L      System.err.println("Exception updateLattice: " + e.getMessage ());! {  Q3 l8 y6 b: N
    }6 T/ v# e/ c) k! q' a5 Q3 ^
          \" v, J: B# d
    // Then we create a schedule that executes the
( C: q- F+ d* p# B* V( n0 A    // modelActions. modelActions is an ActionGroup, by itself it' c* q3 Q3 ^+ B+ @* j# ~$ b  A
    // has no notion of time. In order to have it executed in, G6 }: p% [, e- ^
    // time, we create a Schedule that says to use the
2 d4 g- R0 k% ?    // modelActions ActionGroup at particular times.  This5 H6 o/ T: W! c0 z
    // schedule has a repeat interval of 1, it will loop every, }" ~1 G/ o4 W8 M
    // time step.  The action is executed at time 0 relative to" ?+ G0 m) a/ `! r* R
    // the beginning of the loop.
$ f, `. h- s$ O, G7 B3 Q) G
( h+ o- V8 D1 w    // This is a simple schedule, with only one action that is# S5 q9 f; `/ B$ z5 B' F
    // just repeated every time. See jmousetrap for more
0 r5 ?1 W; r2 K4 v6 @$ g    // complicated schedules.) I" n9 }4 x0 T- Y' C
  
6 w. C5 D: R& ?" ~0 @    modelSchedule = new ScheduleImpl (getZone (), 1);
* L2 G. ~( U. d) S$ t+ ~. f) v: j    modelSchedule.at$createAction (0, modelActions);
- q1 l3 M) T# \& D# w' \; f1 `        
4 y$ s/ s7 }! f- o; b9 ~& C    return this;3 v- W. [; r* d0 h  A( K
  }
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