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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:3 y3 s/ q4 K" A$ c1 T5 Z9 B% m
1 k5 }0 _( T! r! h; Y* b  u
public Object buildActions () {
( {& |' E4 _& x8 e/ T9 A- L    super.buildActions();- ?$ _! n; x, h1 S7 C6 p
   
. j; a" Y' k/ J7 _# \/ S' N    // Create the list of simulation actions. We put these in
: ?1 J" N* r0 R& C/ G" A    // an action group, because we want these actions to be
- \# g5 N# q% L* c5 F' }    // executed in a specific order, but these steps should
9 g" {' b. M# N7 J/ k/ d# |    // take no (simulated) time. The M(foo) means "The message
/ r3 a; h/ L' O3 D) Y    // called <foo>". You can send a message To a particular! X& B+ _7 t3 }- |' ?8 {
    // object, or ForEach object in a collection.
+ M& j8 Y5 `* L) s  Y        
% {+ M% `3 T3 V$ Q# G; K. g    // Note we update the heatspace in two phases: first run
1 I9 z5 ?0 \+ j  a    // diffusion, then run "updateWorld" to actually enact the
4 y3 Q7 r. h  \  B/ Q# [    // changes the heatbugs have made. The ordering here is
2 C3 C/ Q' z( ^. v, c) Q+ x' E, Y    // significant!
% v% }6 n; [2 F' Q2 j( x. Z        : h+ m0 I, L# ^
    // Note also, that with the additional
3 E% ?/ }# l& j1 S. Y5 B0 t    // `randomizeHeatbugUpdateOrder' Boolean flag we can& l- {. A9 e1 y1 f! Z8 y
    // randomize the order in which the bugs actually run
4 x# U$ `3 E' ~" l    // their step rule.  This has the effect of removing any
2 y" d# x0 g: e$ u# x/ j8 A    // systematic bias in the iteration throught the heatbug
$ U3 I' x" v6 Q6 U- R    // list from timestep to timestep9 |8 u* _3 H5 R! X% U
        
* G( T# E/ ]. k  S1 i; \    // By default, all `createActionForEach' modelActions have/ B) v( G7 k8 ?% ^3 X+ k
    // a default order of `Sequential', which means that the
5 I5 [  X4 I4 q) w9 |' m    // order of iteration through the `heatbugList' will be( `4 m1 B; d5 F9 V8 j
    // identical (assuming the list order is not changed
+ @/ v+ Q: M# K0 K+ `    // indirectly by some other process)." c/ M3 e1 W* m1 {0 V- w
    % J3 W- k/ Z; Q2 C+ J
    modelActions = new ActionGroupImpl (getZone ());) o% W& s' p& O

/ d& _1 H3 P" S5 D! I$ m    try {  g6 o9 [- J$ |1 ]! `5 A, o! {
      modelActions.createActionTo$message) Z& ?1 [9 S8 ]' A7 z9 Z
        (heat, new Selector (heat.getClass (), "stepRule", false));, m. r0 l/ d! Q
    } catch (Exception e) {/ s. z1 G# o, z1 F) T* y6 K3 T/ R
      System.err.println ("Exception stepRule: " + e.getMessage ());
- F4 i* ^  P9 v; T! d' f; A/ {    }
4 r2 A" j/ h/ M% ?) [5 V; B3 I/ |, P! B
    try {
) v# ?! M# d7 i; _8 E1 [      Heatbug proto = (Heatbug) heatbugList.get (0);
% h3 [  p7 z8 P      Selector sel = $ A2 |  M4 `/ v) F3 g5 X) _; Y
        new Selector (proto.getClass (), "heatbugStep", false);: x: x3 |1 [+ j& o* \
      actionForEach =
7 V  w. j: \' z6 {) y: Q- H5 J; _7 H        modelActions.createFActionForEachHomogeneous$call8 v$ W9 H, Q$ h) {
        (heatbugList,+ i$ B; X7 Q) ~% {$ t  L
         new FCallImpl (this, proto, sel,
; g: [- ~; b+ z' `6 J: Y& T; N                        new FArgumentsImpl (this, sel)));) f: |' L1 N4 T  k
    } catch (Exception e) {
2 s  j$ w* s( c: ~( V5 K( d" X      e.printStackTrace (System.err);' [0 M& c$ q. E" [, l+ g. P
    }
& G: W: o0 E! j; K    + D8 U) I. e3 Q" H. c& M! c
    syncUpdateOrder ();
2 s" S; U+ ^0 c. ]: a9 N1 B! S+ u5 M' t; j4 S/ z8 |) d/ |
    try {) H7 `% d; V5 y' {* i3 x
      modelActions.createActionTo$message 3 ~! I! y0 L  ]
        (heat, new Selector (heat.getClass (), "updateLattice", false));( z% o5 R7 L$ y
    } catch (Exception e) {/ O$ n& _& u9 \; m4 j
      System.err.println("Exception updateLattice: " + e.getMessage ());
' H6 p4 T* N3 g    }/ T6 H0 ]/ J3 u9 J0 K7 P
        4 v! i8 X* a8 d: W7 Q( I
    // Then we create a schedule that executes the' h0 e/ K3 `1 t8 |! [+ m- M) t8 [
    // modelActions. modelActions is an ActionGroup, by itself it2 J. N; l3 c3 g$ T
    // has no notion of time. In order to have it executed in: H) [5 g3 ]8 U' T
    // time, we create a Schedule that says to use the
$ g- H! @7 E$ s2 Y) h$ n# _    // modelActions ActionGroup at particular times.  This; G8 \  z1 P# v
    // schedule has a repeat interval of 1, it will loop every  b4 }5 \8 _( i. q& ~
    // time step.  The action is executed at time 0 relative to
/ \. z5 j5 p( @4 C, T    // the beginning of the loop.
6 t- ?$ J! g8 ^- ~# {5 w% p6 s8 l& _: E  w1 h# q( T1 Y
    // This is a simple schedule, with only one action that is6 N0 z2 q7 G1 O, i; I2 y
    // just repeated every time. See jmousetrap for more  d4 w2 q7 X8 w6 r6 z. s2 v4 P
    // complicated schedules., Z  ?$ s' \) P4 [! e8 M/ w
  ( r+ E1 Y; Z5 J0 m6 l8 K
    modelSchedule = new ScheduleImpl (getZone (), 1);
4 E2 t' ?6 w) o' g    modelSchedule.at$createAction (0, modelActions);
, K! x4 V3 r0 E3 ?7 [' ~7 `) `        5 f5 i" ]; w4 e1 V2 P
    return this;
* Y/ B" X3 m0 ?; n7 e. h0 |  }
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