设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 9412|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:, F/ C# `7 P5 G
% H' J' O( _* O; K4 c* }% P( A( e
public Object buildActions () {
2 k( f5 G9 N& z# o7 b" t    super.buildActions();
3 q/ g3 P% Q2 M+ c   
9 ?2 w/ b$ p: T9 r+ R    // Create the list of simulation actions. We put these in- B0 C' n  C4 b" ?- ]
    // an action group, because we want these actions to be
0 \- B4 r+ t7 b    // executed in a specific order, but these steps should
, I. V- z# |) T  w8 G$ t* ]    // take no (simulated) time. The M(foo) means "The message0 ]+ n( T9 E' p+ ~" N/ v: |' w* x
    // called <foo>". You can send a message To a particular' K# x9 u9 h; T: X5 f) j
    // object, or ForEach object in a collection.
( g  L) h2 \2 L% {; [/ D- K        
. }7 M) K, Y. h+ [    // Note we update the heatspace in two phases: first run
8 D7 w  L# n+ L; S    // diffusion, then run "updateWorld" to actually enact the/ R( X1 L6 m1 }+ H8 R6 p1 m3 I# v
    // changes the heatbugs have made. The ordering here is2 `" r7 q0 B: y  G3 y$ A
    // significant!
4 w! z- R% H: k9 i( T4 z        # W; I4 Z, k5 E9 q7 u
    // Note also, that with the additional$ r) m- q; i+ J
    // `randomizeHeatbugUpdateOrder' Boolean flag we can( V' M# {( E1 C# {. U( H* F6 a
    // randomize the order in which the bugs actually run5 k% ~) P, Q, i5 T% D
    // their step rule.  This has the effect of removing any, B$ _, e" z2 Y% ^, \5 Y
    // systematic bias in the iteration throught the heatbug
8 p, r0 S5 u! \/ W    // list from timestep to timestep
# |0 N  M% @9 G# ]# V        & N/ ?! r2 @; q) I
    // By default, all `createActionForEach' modelActions have6 P- y6 V* O  ]4 w4 A# ^* p
    // a default order of `Sequential', which means that the/ Z) }  B( N8 f) s* {( ?
    // order of iteration through the `heatbugList' will be1 ]1 i1 ?7 b4 {1 e# Z& j. R
    // identical (assuming the list order is not changed
- G2 G( a3 p9 h$ E3 M    // indirectly by some other process).6 y' Z6 c3 X/ }8 V. {
    9 ^- `0 y8 c  k  g2 H: Y  R
    modelActions = new ActionGroupImpl (getZone ());
% P- z; r, Z( Z- x7 @) ~+ |
1 f- T$ X# a4 n* Q$ D4 d    try {( t1 Y) O; q% M& D8 C) D. y
      modelActions.createActionTo$message
, {% }6 ^" @# J1 `        (heat, new Selector (heat.getClass (), "stepRule", false));
' B3 d9 o; M( V0 e& P    } catch (Exception e) {
/ e  l0 `  h5 w& |+ z      System.err.println ("Exception stepRule: " + e.getMessage ());, }! C/ Q* {, M% s6 w/ L8 S
    }7 o; U! P3 S' G" g
9 y- {; N8 N3 E6 K+ G
    try {7 A% v/ x+ z$ o5 h. D
      Heatbug proto = (Heatbug) heatbugList.get (0);: q9 T9 k" V0 u4 W$ ^  ]: T2 m
      Selector sel =
! V0 n; q$ H( z) K, y        new Selector (proto.getClass (), "heatbugStep", false);0 l3 A% A7 ?% i7 V) c4 P
      actionForEach =
3 P1 D8 y# K( v- q        modelActions.createFActionForEachHomogeneous$call
* u1 ?! c! u8 N4 v5 N7 c        (heatbugList,8 [% O% A3 w6 X
         new FCallImpl (this, proto, sel,
2 M: a( {* L- V3 n* T. A                        new FArgumentsImpl (this, sel)));8 g, R* `5 L, }. J: G
    } catch (Exception e) {7 H2 r/ e9 e; a
      e.printStackTrace (System.err);
# z! K4 f; R4 ]2 v  b* u( ?    }7 t& m* H; t" w0 Z, E9 x
   
6 h" A& \! J0 k    syncUpdateOrder ();1 _; I. b" |0 s
8 F9 m. g1 N& z7 i+ a4 D# a; X8 C# M
    try {
* ]$ G: [  l( M" I- _2 n' c      modelActions.createActionTo$message $ Y+ A% E( {8 ~& l9 T
        (heat, new Selector (heat.getClass (), "updateLattice", false));
( B1 I" n3 H* D9 F3 Y! G; s4 {4 D- m    } catch (Exception e) {3 j6 y# K' q) @" X
      System.err.println("Exception updateLattice: " + e.getMessage ());
( Q/ E/ j( A( C2 i    }
6 V% u+ J2 o1 S! M/ w        
. }0 b# D6 J+ a. P- [! f: W    // Then we create a schedule that executes the5 `4 ]6 |3 w  r
    // modelActions. modelActions is an ActionGroup, by itself it. y+ f; D3 D2 N
    // has no notion of time. In order to have it executed in$ a& x5 s4 u0 B) a9 \
    // time, we create a Schedule that says to use the6 v" G( T9 K  }5 {9 b
    // modelActions ActionGroup at particular times.  This
0 P/ R3 v) p' r- W, S4 X* W    // schedule has a repeat interval of 1, it will loop every9 G* F5 y8 t- @9 w9 v
    // time step.  The action is executed at time 0 relative to7 z: E# P% d) ]& p; ^: k& s# U
    // the beginning of the loop.
; n! u: @, t" |! d/ g" X; q/ n) W. {# T# |  |2 `5 H6 K
    // This is a simple schedule, with only one action that is
) O/ {4 i9 T$ q; ?% V    // just repeated every time. See jmousetrap for more
0 N( U$ z9 k7 F% x    // complicated schedules.
' t' y, d4 t7 h0 g8 M: o7 L7 ]  9 s) E7 T) u; h5 T2 p
    modelSchedule = new ScheduleImpl (getZone (), 1);1 a& }" J+ S0 z- E' `  j' B8 k) z
    modelSchedule.at$createAction (0, modelActions);
* m& s9 ~0 a# v8 D" ]        
# \9 o+ P% W# @  Z2 Q/ `1 B; K# c    return this;$ }8 K2 n/ g; G9 c4 B1 D7 x
  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-3-1 08:04 , Processed in 0.019903 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表