HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
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' ?6 N n Q2 g: ? y public Object buildActions () {" L0 ^7 q# M* [+ b; }
super.buildActions();
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* h5 G$ h w7 [& o // Create the list of simulation actions. We put these in4 C5 N, I$ s2 h) }
// an action group, because we want these actions to be) a6 a. p6 }. L3 ~
// executed in a specific order, but these steps should
( Z* X0 |2 n. D. u // take no (simulated) time. The M(foo) means "The message
; W8 n, B# u8 _- N // called <foo>". You can send a message To a particular
0 c1 H, z; R: V) T // object, or ForEach object in a collection./ }% G3 B" Z- f! M8 x# V) j' O
A: q9 Z R0 M* G6 C9 h4 s // Note we update the heatspace in two phases: first run/ i2 m0 _7 B/ _0 @5 w9 L2 f/ T4 x
// diffusion, then run "updateWorld" to actually enact the7 `! J. X. [" W) m4 \/ p9 d
// changes the heatbugs have made. The ordering here is4 n( c: {) K- Z+ r2 g* h. D
// significant!- _; d- j k' J: [
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// Note also, that with the additional2 f u1 \& B/ h) Z9 G
// `randomizeHeatbugUpdateOrder' Boolean flag we can B R4 J6 s- }2 @
// randomize the order in which the bugs actually run
. n. Z" x& t: I // their step rule. This has the effect of removing any
! z1 }& k7 a4 x+ `! M // systematic bias in the iteration throught the heatbug
8 T, L& E9 v2 y, I* a0 T$ d // list from timestep to timestep0 C2 U# D: d/ o5 I8 o) _) m# c
' z& v. U/ v( {5 w/ \ // By default, all `createActionForEach' modelActions have$ V- e. @& e; p8 B d; y1 P' F1 A' n
// a default order of `Sequential', which means that the+ T4 U, ?1 W3 k# p& s9 A l
// order of iteration through the `heatbugList' will be
; m7 e- L$ V% g( ] // identical (assuming the list order is not changed
2 u8 p5 ^. N! {8 D9 W% i% a // indirectly by some other process).( d( d, D+ }5 q! L
0 j5 b; `7 `; x1 y modelActions = new ActionGroupImpl (getZone ());# J) X: t# |0 N w# q# W3 V
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modelActions.createActionTo$message
e4 R# P+ k2 \2 H% ~ (heat, new Selector (heat.getClass (), "stepRule", false));4 N. J5 K/ A( T, Q; w
} catch (Exception e) {
" T0 \3 T$ t$ O% _ System.err.println ("Exception stepRule: " + e.getMessage ());0 X5 e9 |9 ^( ~* P4 }0 T: Z. r F
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Heatbug proto = (Heatbug) heatbugList.get (0);& h: O# }3 o3 v
Selector sel = + P8 }1 G* F3 r( t" M6 G& j9 }9 a
new Selector (proto.getClass (), "heatbugStep", false);/ J4 p+ K+ V( @1 z, I% j
actionForEach =
/ {0 s% b% r# G% t modelActions.createFActionForEachHomogeneous$call
0 H1 L3 L! H& @. ~% {% [ (heatbugList,
6 F8 l. W7 z1 X: F3 q new FCallImpl (this, proto, sel,9 A1 o5 v5 [( ?) J8 \" F' Q
new FArgumentsImpl (this, sel)));9 a, ~/ v0 ?7 q) r9 M) U9 K: g
} catch (Exception e) {7 n7 d5 \2 c5 K* U* } t
e.printStackTrace (System.err);/ \, D1 D1 @' E/ n9 s- k. F$ x
}
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syncUpdateOrder ();7 c. q" d' i, `
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try {# M$ _* X0 h1 z$ I8 R* \4 F) n
modelActions.createActionTo$message 5 L; P6 p8 m( o. j
(heat, new Selector (heat.getClass (), "updateLattice", false));8 @) x6 \6 b' l
} catch (Exception e) {9 r* ~3 q) W. X! s% z0 |
System.err.println("Exception updateLattice: " + e.getMessage ());
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// Then we create a schedule that executes the: I1 g+ Y0 @; l0 X
// modelActions. modelActions is an ActionGroup, by itself it+ x& {3 Y! o" C
// has no notion of time. In order to have it executed in
" @0 k5 L5 T5 ^) n3 m' D o( ?9 t // time, we create a Schedule that says to use the. a, E! A0 s5 i$ u; m
// modelActions ActionGroup at particular times. This
/ ~0 T* ]9 J4 w( p // schedule has a repeat interval of 1, it will loop every
2 L" U7 w3 K* h# l; D _ // time step. The action is executed at time 0 relative to% I. M: d6 g4 _
// the beginning of the loop." E. A2 P* [6 ?, |' E
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// This is a simple schedule, with only one action that is5 N d8 i2 D/ s0 L7 i2 @
// just repeated every time. See jmousetrap for more7 S* B% b& j! F5 k
// complicated schedules.2 ?: n$ J) `/ h; j+ E
+ l8 s, Y$ D1 U modelSchedule = new ScheduleImpl (getZone (), 1);
/ O3 b9 _- Q( K' F) o: | modelSchedule.at$createAction (0, modelActions);
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return this;$ x s) n0 {) k4 [% h/ j# \$ K! ^
} |