设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 11979|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
2 o! y/ o, u' k# S, D: p9 n4 B( Q& W# k1 r
public Object buildActions () {* W+ z* v  S+ a  B* s" P
    super.buildActions();6 r8 `9 J  C& w+ h2 ?
    ( g, A; |0 h& f& y  R, \
    // Create the list of simulation actions. We put these in4 r( S1 H$ m! f: t. ^, d
    // an action group, because we want these actions to be4 c) z: P( T: h9 C& Z# L
    // executed in a specific order, but these steps should
7 n0 ^' s$ ]" P& E9 ?2 {    // take no (simulated) time. The M(foo) means "The message
5 J: d- Y# V/ }    // called <foo>". You can send a message To a particular. L6 K$ [# v/ I) w
    // object, or ForEach object in a collection.  u/ r4 U1 r$ @! h6 h: j
        
+ z7 ?. L0 r0 h6 ]    // Note we update the heatspace in two phases: first run3 k: U- {/ w7 D: ~
    // diffusion, then run "updateWorld" to actually enact the
' z6 K- L3 x& F4 c    // changes the heatbugs have made. The ordering here is+ K8 w, _0 b7 O# D* u) H
    // significant!
, l4 t' e$ M% |        " z, F$ f+ V7 B0 e7 v( Z/ L
    // Note also, that with the additional# Y$ f+ H. @/ U1 i; n! d# g- S! U* N+ H
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
2 T% Y+ p) c) ?# Y% R! O$ m    // randomize the order in which the bugs actually run3 Q6 c5 g% ^' }' ~4 H7 \9 i, ~
    // their step rule.  This has the effect of removing any
$ C. q3 x; N4 u" y" X) m    // systematic bias in the iteration throught the heatbug" ~: B$ g+ \( J) O; H
    // list from timestep to timestep& a7 L$ G7 m6 d  v* {4 j  P. ^
        
3 r3 V7 C, @) [9 v& x3 `6 n    // By default, all `createActionForEach' modelActions have
- q7 b" q8 e" r    // a default order of `Sequential', which means that the
6 ], g0 s' y; r7 a$ ^1 v    // order of iteration through the `heatbugList' will be1 P) l& b$ n) O7 M. l8 g# N! y
    // identical (assuming the list order is not changed
; z7 k2 l2 o6 W7 |    // indirectly by some other process).
8 `, f9 x5 r3 D: ]. D5 g" r   
8 ~  v, w! u1 l- j; n    modelActions = new ActionGroupImpl (getZone ());
$ V! h  A# f$ n6 S! R) E- S0 F+ T0 G2 B1 y$ u' {# V' O
    try {) [8 e  B- J% H2 J6 H
      modelActions.createActionTo$message; \9 I& b- F' u& W5 S- E4 v8 b
        (heat, new Selector (heat.getClass (), "stepRule", false));( R+ M/ Q) n2 u
    } catch (Exception e) {: k) g3 }0 Q& S, C7 O5 q0 P
      System.err.println ("Exception stepRule: " + e.getMessage ());
% x3 b- J- K! ?    }2 h/ j2 Y: [. j3 ?& {, T
8 M% g8 s' |! @' s+ o
    try {
# a6 z5 X: Z- h/ b8 L# S      Heatbug proto = (Heatbug) heatbugList.get (0);
4 f+ e  v' S0 I" |/ e      Selector sel =
0 F6 J. ?* t- Z2 w1 W: g        new Selector (proto.getClass (), "heatbugStep", false);
6 k  L6 k# a5 r      actionForEach =
# }9 [5 R8 n6 a! N& D& N        modelActions.createFActionForEachHomogeneous$call
# K2 W) g8 B8 _        (heatbugList,' f# e3 o. d# j+ t
         new FCallImpl (this, proto, sel,4 }- T/ n  g- E
                        new FArgumentsImpl (this, sel)));3 E& u4 u  c+ h$ J8 O
    } catch (Exception e) {1 _  d+ |6 s! A. f$ L4 W
      e.printStackTrace (System.err);3 q* z% t2 y0 j" c; [
    }
+ J, s, ?4 f  z    9 Y/ Z! m  ?1 y+ U' B
    syncUpdateOrder ();/ X% o$ `# B* x2 L# b  i8 o
8 b5 r% ~# S  X* ]/ ?; ~
    try {" v9 k& G9 g- J: y- O8 k8 t
      modelActions.createActionTo$message / ]) O+ |. s0 J/ T& A
        (heat, new Selector (heat.getClass (), "updateLattice", false));7 M; `! G. l3 r3 G% \
    } catch (Exception e) {
( Q' ^2 c5 P0 }, y- ]7 J$ w      System.err.println("Exception updateLattice: " + e.getMessage ());
% H9 ]1 e' a* g: f* O    }- {$ r! j& I; F; p5 Y) z5 a# E# r6 C+ u
        & l3 c3 t8 l3 w% U
    // Then we create a schedule that executes the0 X$ g: O# y; V2 Q
    // modelActions. modelActions is an ActionGroup, by itself it
* c4 Y* `) w# Q1 L    // has no notion of time. In order to have it executed in
* P% K- O5 o9 u2 x$ ~    // time, we create a Schedule that says to use the
; g4 b: x, ~9 L+ n0 n- t- x    // modelActions ActionGroup at particular times.  This
- m- C0 O7 J3 t. F' C8 M    // schedule has a repeat interval of 1, it will loop every" n# _1 B8 P( G7 p7 t
    // time step.  The action is executed at time 0 relative to
# n" z* }; B5 w% I/ V    // the beginning of the loop.
8 y. X+ w4 O- r# D! Z/ W, J, P+ q, G2 U9 K. T; U/ U0 J
    // This is a simple schedule, with only one action that is
' G- k( }3 ^! S, O" [    // just repeated every time. See jmousetrap for more
9 N$ f) f4 I8 J% l" X" o  u  K    // complicated schedules.9 L" ?1 b/ b/ o; n& C" ^
  
. E" a4 o- D  D' O8 {! T    modelSchedule = new ScheduleImpl (getZone (), 1);
' `8 ?8 ~, P. L/ t2 _    modelSchedule.at$createAction (0, modelActions);' u2 D( ?# t7 y" s
        
3 X: N$ z+ ?# O: g+ Q    return this;
1 ^: K8 g" H" p: T! r2 q  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-7-31 19:01 , Processed in 0.015178 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表