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楼主 |
发表于 2008-4-19 16:11:18
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好像可以了
to go
* p2 T+ w2 X, u$ H. a) x* G set t t + 10 g* O2 `& _# T, H) g# L% l# `
grow
8 y- C: O2 W! l% p3 @+ V4 z update-list-of-m6 \! L& A. L; u
do-plots3 Z9 Z. p( \; b) _. P
tick
+ A7 ^- K' D4 f' n) B( P ifelse t > 8
$ Y& G9 K' ^2 u [if abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)))< 0.01 and9 l, u+ k4 N* a3 R4 z- }7 w+ W. `3 d
abs( mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 and
. h- ~( ^& Q, k; g abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01
" Z5 u" Y: x; V/ ] @ [stop]]/ d+ h4 y! \* [- d
[ ]
6 l% m& H/ F# H" p0 a W- s# a9 [end. b6 V: A/ E' s1 p
各位大虾帮忙看看,这样好像可以了。以前用while之所以不行,是不是因为如果报告为true,那么就会反复运行后面的命令导致死循环啊?
" l7 }2 H$ k3 ?- z U还有就是[ ]是不是意味着不执行任何操作,返回set t t + 1,然后再grow,再 update-list-of-m,再 do-plots,再 tick ..........这样一直按这种顺序循环直到停止。
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1 }! ^0 y& y% F& \- M0 B$ d[ 本帖最后由 wjcpcahu 于 2008-4-19 16:19 编辑 ] |
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