|
|

楼主 |
发表于 2008-4-19 16:11:18
|
显示全部楼层
好像可以了
to go
% c, L) g0 ?/ t: }. Y: g set t t + 1- R f! o. P4 I" W8 ]% K+ ? w; Y
grow
. {/ p6 x" A6 | update-list-of-m; c- U! |7 A' E
do-plots
* {1 ]- s$ O* F H$ t1 p! n tick - ]& q# r8 M, e' N+ T2 r
ifelse t > 8
+ {$ n: H. I9 U$ l5 v& e9 S [if abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)))< 0.01 and/ c" i4 |. r; i" b* v8 s. q* P6 S
abs( mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 and! [$ [0 P$ l# O, y/ G
abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01
) o) p1 U! N& b% l. X# N9 R. R9 } [stop]]- S. ^9 A3 i8 K! k5 ~& r1 o; _
[ ]
9 l4 W" g! o' e8 y; a9 ~) cend2 } L8 L: F1 h7 g& j( |( n9 M, K2 q
各位大虾帮忙看看,这样好像可以了。以前用while之所以不行,是不是因为如果报告为true,那么就会反复运行后面的命令导致死循环啊?$ d* R6 C5 R2 B+ {& I( ^5 k
还有就是[ ]是不是意味着不执行任何操作,返回set t t + 1,然后再grow,再 update-list-of-m,再 do-plots,再 tick ..........这样一直按这种顺序循环直到停止。
8 r% O1 Y! ~, m( w; L( S/ _; Y* y: g$ l
[ 本帖最后由 wjcpcahu 于 2008-4-19 16:19 编辑 ] |
|