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发表于 2010-5-11 13:19:52
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用list吧7 d( E3 b1 p+ b H% V
patches-own [wealth rank]
! x; u6 W! p- z- b. G2 ]to setup
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ask patches [set wealth random 100 set pcolor green ]% `$ b" @6 l8 c& z% C+ ~
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to go
& z& I& u" R( N6 h: V! G2 ?3 Q1 p let mylist1 []6 p2 B2 {+ [) p d2 _" B* O, I
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches& Z$ l |" `0 E5 N) k5 C; t! I: ~
let mylist2 []
; v* {/ k( G7 H$ I8 A+ } set mylist2 n-values count patches [? + 1]1 p* ?$ E7 D1 P, ?' q
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( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
7 E3 ]+ \. M2 u) v" Z9 p" T show [rank] of ?13 j9 K) a1 \/ d4 p$ j j7 q
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]
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1 N$ r3 L7 t1 k1 E! a let mylist3 []) h5 d/ D. I( k7 e% x
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches# U; f% ^. p/ d' p) \8 N5 W
show count patches
# {0 T0 f1 `9 |* W& I3 J! D) J show mylist1 + U& w2 C7 v0 ]# H+ ]+ H! C
show mylist3
. M7 W; ^5 Q( a( f# W' Yend9 u' }, A4 L. W h# C. P9 L# x
5 W4 W8 d3 a6 j3 F2 P. s/ q; [这时的mylist1 和mylist3 应该是一样的 |
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